Transcendental Functions & Hyperbolic Trigonometry
Comprehensive theory of transcendental mathematics: exponential functions, Euler's number e, natural logarithms, unit circle trigonometry, principal branch inverse trigonometric functions, hyperbolic geometry on x^2 - y^2 = 1, and rigorous logarithmic derivations of inverse hyperbolic functions.
§2.1 Exponential Functions, Euler's Number e & Logarithmic Foundations
1. Exponential Functions
For a fixed positive base $a > 0$ with $a \ne 1$, the exponential function with base $a$ is defined for all $x \in \mathbb{R}$ by $f(x) = a^x$.
Fundamental Exponential Laws: For all $x, y \in \mathbb{R}$ and $a, b > 0$:
The function is strictly positive: $\operatorname{Range}(a^x) = (0, \infty)$. It is strictly increasing if $a > 1$, and strictly decreasing if $0 < a < 1$.
2. Euler's Number $e$ & The Natural Exponential
The base of the natural exponential function, Euler's number $e \approx 2.718281828459...$, is uniquely defined by the fundamental limit:
Geometrically, $y = e^x$ is the unique exponential curve whose tangent line at the $y$-intercept $(0, 1)$ has a slope of exactly $1$.
3. Logarithmic Functions
Because $f(x) = a^x$ is strictly monotonic on $\mathbb{R}$, it is a bijection from $\mathbb{R}$ to $(0, \infty)$. Its inverse function is the logarithm to base $a$:
The inverse of the natural exponential $e^x$ is the natural logarithm $\ln(x) = \log_e(x)$:
Logarithmic Properties & Change of Base:
§2.2 Trigonometric Functions, Exact Identities & Unit Circle Geometry
1. The Unit Circle Definition of Trigonometric Functions
In analytical calculus, angles are measured strictly in radians. Let $(x, y)$ be the terminal coordinates of an angle $\theta \in \mathbb{R}$ on the unit circle $x^2 + y^2 = 1$ measured counterclockwise from $(1, 0)$:
The reciprocal functions are $\sec\theta = 1/\cos\theta$, $\csc\theta = 1/\sin\theta$, and $\cot\theta = 1/\tan\theta = \cos\theta/\sin\theta$.
2. Fundamental Trigonometric Identities
From the Pythagorean theorem $x^2 + y^2 = 1$ on the unit circle:
Angle Addition & Double-Angle Formulas:
Power-Reduction (Half-Angle) Formulas: Crucial for integration in calculus:
§2.3 Inverse Trigonometric Functions & Principal Value Branches
1. Restriction of Domains & Principal Branches
Because trigonometric functions are periodic, they fail the horizontal line test across $\mathbb{R}$. To construct inverses, we restrict each function to a standard principal interval on which it is strictly monotonic and surjective onto its range:
2. Fundamental Identities of Inverse Trigonometric Functions
Cancellation Cautions:
For arguments outside the principal range, symmetry must be utilized: e.g., $\arcsin(\sin(5\pi/6)) = \arcsin(1/2) = \pi/6 \ne 5\pi/6$.
§2.4 Hyperbolic Functions: Symmetries, Identities & The Unit Hyperbola
1. Formal Definitions of Hyperbolic Functions
The hyperbolic functions are defined as the symmetric and antisymmetric linear combinations of the exponential functions $e^x$ and $e^{-x}$:
Reciprocals: $\operatorname{sech} x = \frac{1}{\cosh x}$, $\operatorname{csch} x = \frac{1}{\sinh x}$, $\operatorname{coth} x = \frac{\cosh x}{\sinh x}$.
2. The Fundamental Hyperbolic Identity & The Unit Hyperbola
Geometric Analogy: Just as $(\cos t, \sin t)$ parametrizes the unit circle $x^2 + y^2 = 1$, the parametric coordinates $(x, y) = (\cosh t, \sinh t)$ trace the right branch of the unit equilateral hyperbola:
Derived Identities:
§2.5 Inverse Hyperbolic Functions & Derivation of Explicit Logarithmic Forms
1. Invertibility of Hyperbolic Functions
- $\sinh x$ is strictly increasing on $\mathbb{R}$ with range $\mathbb{R}$. Its inverse $\operatorname{arsinh} x$ is defined for all $x \in \mathbb{R}$.
- $\cosh x$ is even on $\mathbb{R}$ with range $[1, \infty)$. Restricting to $x \ge 0$ yields the principal branch of $\operatorname{arcosh} x$ for $x \ge 1$, with range $[0, \infty)$.
- $\tanh x$ is strictly increasing with range $(-1, 1)$. Its inverse $\operatorname{artanh} x$ is defined on $(-1, 1)$.
2. Rigorous Derivation of Logarithmic Closed Forms
Theorem: For all $x \in \mathbb{R}$, $\operatorname{arsinh} x = \ln(x + \sqrt{x^2 + 1})$.
Proof: Let $y = \operatorname{arsinh} x$. Then $x = \sinh y = \frac{e^y - e^{-y}}{2}$. Multiplying by $2e^y$ yields:
This is a quadratic equation in $u = e^y$. By the quadratic formula:
Since $e^y > 0$ for all real $y$, and $\sqrt{x^2+1} > \sqrt{x^2} = |x| \ge x$, the minus sign yields a strictly negative value $x - \sqrt{x^2+1} < 0$, which is inadmissible. Thus:
Complete Logarithmic Catalog:
Step-by-Step Solved Examination Problems
Comprehensive analytical derivations, multi-tier solutions (Foundational, Intermediate Exam, and Honors/Proof Challenge) with complete line-by-line verification.
Find the exact real values of: (a) $\arcsin\left(\sin\left(\frac{7\pi}{6}\right)\right)$, (b) $\cos\left(2\arcsin\left(-\frac{3}{5}\right)\right)$, and (c) $\tan\left(\arccos\left(\frac{5}{13}\right)\right)$.
Because $7\pi/6 otin [-\pi/2, \pi/2]$, we cannot simply cancel. We evaluate the inner sine first to get $-1/2$, whose principal arcsine value is $-\pi/6$.
Substitute $\sin heta$: $\cos(2 heta) = 1 - 2\left(-\frac{3}{5}\right)^2 = 1 - 2\left(\frac{9}{25}\right) = 1 - \frac{18}{25} = \frac{7}{25}$.
Then $ an\alpha = \frac{\sin\alpha}{\cos\alpha} = \frac{12/13}{5/13} = \frac{12}{5}$.
\text{(a) } -\frac{\pi}{6}, \qquad \text{(b) } \frac{7}{25}, \qquad \text{(c) } \frac{12}{5}
Let $y = \operatorname{artanh}(x)$ for $x \in (-1, 1)$. (a) Starting from the definition $\tanh(y) = \frac{e^{2y} - 1}{e^{2y} + 1} = x$, derive the closed logarithmic formula $\operatorname{artanh}(x) = \frac{1}{2}\ln\left(\frac{1 + x}{1 - x}\right)$. (b) Use this formula to compute the exact value of $\operatorname{artanh}(3/5)$ and $\operatorname{artanh}(0)$.
Expand and isolate the exponential term $e^{2y}$.
Since $-1 < x < 1$, both $1+x > 0$ and $1-x > 0$, so the ratio is strictly positive.
Dividing by 2 yields the exact logarithmic formula.
For $x = 0$: $\operatorname{artanh}(0) = \frac{1}{2}\ln(1/1) = 0$.
\operatorname{artanh}(x) = \frac{1}{2}\ln\left(\frac{1 + x}{1 - x}\right), \qquad \operatorname{artanh}(3/5) = \ln(2), \qquad \operatorname{artanh}(0) = 0
In special relativity, the velocity $v$ of a particle is related to its rapidity $\theta \in \mathbb{R}$ by $v/c = \tanh\theta$. (a) Using the definitions of $\sinh$ and $\cosh$, prove the general hyperbolic addition formula: $\tanh(\theta_1 + \theta_2) = \frac{\tanh\theta_1 + \tanh\theta_2}{1 + \tanh\theta_1 \tanh\theta_2}$. (b) Deduce that the relativistic velocity addition law $v_{12} = \frac{v_1 + v_2}{1 + v_1 v_2 / c^2}$ corresponds to the simple linear addition of rapidities: $\theta_{12} = \theta_1 + \theta_2$. (c) Prove that if $v_1 < c$ and $v_2 < c$, then $v_{12} < c$ strictly.
Expanding $e^{( heta_1+ heta_2)} \pm e^{-( heta_1+ heta_2)}$ directly from definition proves these two addition identities.
Dividing numerator and denominator by $\cosh heta_1 \cosh heta_2$ establishes the identity.
Because $\operatorname{Range}( anh heta) = (-1, 1)$ for all finite real rapidities $ heta \in (-\infty, \infty)$, the combined velocity $v_{12}/c = anh( heta_1 + heta_2)$ lies strictly in $(-1, 1)$, proving $v_{12} < c$ for all subluminal speeds.
\tanh(\theta_1 + \theta_2) = \frac{\tanh\theta_1 + \tanh\theta_2}{1 + \tanh\theta_1 \tanh\theta_2}, \quad \theta_{12} = \theta_1 + \theta_2, \quad |v_{12}| < c \text{ strictly}