Unit 2: Curvature, Torsion & The Frenet-Serret Frame
Exhaustive treatment of differential geometry of space curves: the TNB moving trihedron, general parametric and Cartesian curvature formulas, osculating circles, evolutes, torsion, and the Frenet-Serret equations.
ยง2.1 The Moving Trihedron (TNB Frame) and Fundamental Planes
At each point along a smooth curve $C$ in $\mathbb{R}^3$, we can attach a moving, right-handed orthonormal coordinate system known as the Frenet-Serret Moving Trihedron (or TNB Frame).
1. Construction of the TNB Frame
1. Unit Tangent Vector $\vec{T}(t)$:
Points in the instantaneous direction of motion:
2. Principal Unit Normal Vector $\vec{N}(t)$:
Because $|\vec{T}(t)| = 1$ is constant, $\vec{T}'(t)$ is orthogonal to $\vec{T}(t)$ ($\vec{T} \cdot \vec{T}' = 0$). The unit vector in this orthogonal direction is:
$\vec{N}(t)$ points directly in the direction that the curve is turning.
3. Binormal Unit Vector $\vec{B}(t)$:
Defined by the vector cross product to complete a right-handed orthonormal triad:
Because $\vec{T}$ and $\vec{N}$ are orthogonal unit vectors, $|\vec{B}| = |\vec{T}| |\vec{N}| \sin(\pi/2) = 1$, and $\vec{B}$ is perpendicular to both $\vec{T}$ and $\vec{N}$.
2. The Three Fundamental Osculating Planes
At any point $P$ on the curve, the three mutually orthogonal pairs of vectors define three fundamental planes:
1. The Osculating Plane (Spanned by $\vec{T}$ and $\vec{N}$):
- Normal Vector: $\vec{B}(t)$
- Equation: $(\vec{r} - \vec{r}_0) \cdot \vec{B} = 0$
- Geometric Meaning: The plane that comes closest to containing the curve locally; it contains the instantaneous circle of curvature.
2. The Normal Plane (Spanned by $\vec{N}$ and $\vec{B}$):
- Normal Vector: $\vec{T}(t)$
- Equation: $(\vec{r} - \vec{r}_0) \cdot \vec{T} = 0$
- Geometric Meaning: The plane orthogonal to the curve; all lines normal to the curve lie in this plane.
3. The Rectifying Plane (Spanned by $\vec{T}$ and $\vec{B}$):
- Normal Vector: $\vec{N}(t)$
- Equation: $(\vec{r} - \vec{r}_0) \cdot \vec{N} = 0$
ยง2.2 Curvature Formulas, Radius of Curvature and Osculating Circles
1. Geometric Definition of Curvature $\kappa$
The curvature $\kappa$ of a smooth curve measures how rapidly the curve changes its direction per unit change in arc length:
Using the chain rule with parameter $t$:
2. General Parametric Curvature Formula in $\mathbb{R}^3$
Theorem: For any smooth space curve parameterized by $\vec{r}(t)$:
Proof:
Since $\vec{v}(t) = \vec{r}'(t) = v \vec{T}$ where $v = |\vec{r}'(t)| = \frac{ds}{dt}$: Differentiating velocity to get acceleration:
Since $\frac{d\vec{T}}{ds} = \kappa \vec{N} \implies \vec{T}'(t) = \frac{ds}{dt} \frac{d\vec{T}}{ds} = v \kappa \vec{N}$:
Now compute the cross product $\vec{r}'(t) \times \vec{r}''(t)$:
Since $\vec{T} \times \vec{T} = \vec{0}$ and $\vec{T} \times \vec{N} = \vec{B}$:
Taking the norm of both sides (since $|\vec{B}| = 1$):
Dividing by $|\vec{r}'|^3$:
3. Special Curvature Formulas
1. Plane Curve in Cartesian Form $y = f(x)$:
Parameterize as $\vec{r}(x) = \langle x, \; f(x), \; 0 \rangle$. Then $\vec{r}'(x) = \langle 1, \; y', \; 0 \rangle$ and $\vec{r}''(x) = \langle 0, \; y'', \; 0 \rangle$. $\vec{r}' \times \vec{r}'' = \langle 0, \; 0, \; y'' \rangle \implies |\vec{r}' \times \vec{r}''| = |y''|$. $|\vec{r}'| = \sqrt{1 + y'^2}$.
2. Plane Curve in Polar Coordinates $r = f(\theta)$:
4. Radius of Curvature, Center of Curvature and Evolutes
- Radius of Curvature $\rho$: The reciprocal of curvature:
- Osculating Circle (Circle of Curvature): The circle in the osculating plane that has the same tangent, normal, and curvature as the curve at that point. Its radius is $\rho$.
- Center of Curvature $(\alpha, \beta)$ for plane curves:
- Evolute: The locus of the centers of curvature of a given curve is called its evolute.
ยง2.3 Torsion, the Frenet-Serret Formulas & Acceleration Components
1. Torsion $\tau$ of a Space Curve
While curvature $\kappa$ measures the rate at which $\vec{T}$ turns away from the tangent line, torsion $\tau$ measures how sharply the space curve twists out of its osculating plane.
Because $\vec{B}(s) \cdot \vec{B}(s) = 1$, $\frac{d\vec{B}}{ds}$ is perpendicular to $\vec{B}$. Furthermore, differentiating $\vec{B} \cdot \vec{T} = 0$:
Thus, $\frac{d\vec{B}}{ds}$ is perpendicular to both $\vec{B}$ and $\vec{T}$, which means it must be parallel to $\vec{N}$. We define the scalar torsion $\tau$ by:
The negative sign is conventional so that a right-handed screw has positive torsion.
General Parametric Formula for Torsion:
Criterion for Planar Curves: A space curve is a plane curve if and only if $\tau(t) \equiv 0$ for all $t$.
2. The Complete Frenet-Serret Formulas
The rate of change of the moving frame $\{\vec{T}, \vec{N}, \vec{B}\}$ with respect to arc length $s$ is governed by the celebrated Frenet-Serret Formulas:
In matrix notation:
Notice that the coefficient matrix (the Darboux matrix) is skew-symmetric, which is a mathematical guarantee that the orthonormal nature of the basis is preserved along the entire curve.
3. Tangential and Normal Components of Acceleration
In physical kinematics, the acceleration of a particle can be decomposed uniquely into orthogonal components along the tangent and principal normal:
where:
- Tangential Acceleration: Rate of change of speed:
- Normal (Centripetal) Acceleration: Tendency to change direction:
Notice that the binormal component of acceleration is always identically zero ($a_B = 0$). Acceleration always lies entirely in the osculating plane!
Step-by-Step Solved Examination Problems
Comprehensive analytical derivations, multi-tier solutions (Foundational, Intermediate Exam, and Honors/Proof Challenge) with complete line-by-line verification.
Find the curvature $\kappa$, radius of curvature $\rho$, and center of curvature of the parabola $y = x^2$ at its vertex $(0, 0)$.
Step 1: Compute derivatives of $y = x^2$
At the vertex $x = 0$:
Step 2: Compute curvature $\kappa$ Using the Cartesian curvature formula:
Substitute $x = 0$:
Step 3: Compute radius of curvature $\rho$
Step 4: Compute center of curvature $(\alpha, \beta)$ Using the center of curvature formulas:
Thus, the center of curvature is $(0, 1/2)$. The equation of the osculating circle at the vertex is:
For the canonical ellipse parameterized by:
(a) Find the curvature $\kappa(t)$ as an explicit function of parameter $t$. (b) Find the maximum and minimum curvatures and the points where they occur. (c) Deduce the radii of curvature at the major and minor vertices.
Part (a): Compute Curvature Formula Compute first and second derivatives:
Compute the cross product $\vec{r}' \times \vec{r}''$:
Magnitude:
Now compute $|\vec{r}'(t)|$:
Thus, the curvature is:
Part (b): Extreme Values of Curvature Rewrite the denominator:
Since $a > b$, this denominator is minimized when $\sin t = 0$ ($t = 0, \pi$) and maximized when $\sin^2 t = 1$ ($t = \pi/2, 3\pi/2$).
- Maximum Curvature: Occurs at $t = 0, \pi$ (vertices $(\pm a, 0)$):
- Minimum Curvature: Occurs at $t = \pi/2, 3\pi/2$ (vertices $(0, \pm b)$):
Part (c): Radii of Curvature at Vertices
- At major vertices $(\pm a, 0)$: $\rho = \frac{1}{\kappa_{max}} = \mathbf{\frac{b^2}{a}}$.
- At minor vertices $(0, \pm b)$: $\rho = \frac{1}{\kappa_{min}} = \mathbf{\frac{a^2}{b}}$.
For the general circular helix:
(a) Compute the complete Frenet-Serret apparatus: $\vec{T}(t), \vec{N}(t), \vec{B}(t)$, curvature $\kappa$, and torsion $\tau$. (b) Prove that both curvature and torsion are constant along the entire helix. (c) Verify Lancret's Theorem by demonstrating that the ratio $\tau / \kappa$ is constant, and determine the angle that the tangent vector makes with the $z$-axis.
Part (a): Derivation of Frenet-Serret Vectors and Invariants
1. Velocity and Unit Tangent:
2. Principal Normal:
Notice that $\vec{N}$ points horizontally toward the $z$-axis!
3. Curvature:
4. Binormal Vector:
5. Torsion:
Differentiate $\vec{B}(t)$ with respect to $t$:
By the third Frenet-Serret relation, $\frac{d\vec{B}}{dt} = \frac{ds}{dt} \frac{d\vec{B}}{ds} = \sqrt{a^2+b^2}(-\tau \vec{N})$. Equating:
Part (b): Constancy of Invariants
Since neither $\kappa$ nor $\tau$ contains the parameter $t$, both invariants are constant everywhere. $\blacksquare$
Part (c): Lancret's Theorem and Axis Incline Evaluate the ratio of torsion to curvature:
By Lancret's Theorem (1806), a space curve is a general helix (its tangent vector makes a constant angle with a fixed direction) if and only if the ratio $\tau / \kappa$ is constant.
The angle $\phi$ between $\vec{T}$ and the $z$-axis ($\hat{k}$) is:
Thus, $\phi = \arccos\left(\frac{b}{\sqrt{a^2+b^2}}\right)$ is strictly constant along the entire curve. $\blacksquare$