Chemistry / Physical Chemistry Molecular Structure, Transitions & Quantum Spectroscopy 100% Free Open Access
Chapter 3 • Theory & Derivations

Unit 3: Infrared & Vibrational Spectroscopy of Diatomic & Polyatomic Molecules

Harmonic oscillator model, Morse potential and anharmonicity, vibrational term values, Birge-Sponer extrapolation to bond dissociation, diatomic vibrating rotators, rovibrational P and R branches, vibration-rotation interaction constant alpha_e, high-resolution CO spectrum, Fermi resonance, and polyatomic normal modes.

§3.1 The Quantum Harmonic Oscillator & Force Constants

For small displacements \(q = r - r_e\) around equilibrium bond length \(r_e\), the molecular potential energy can be expanded in a Taylor series: \(V(q) = V(0) + \left(\frac{dV}{dq}\right)_0 q + \frac{1}{2}\left(\frac{d^2V}{dq^2}\right)_0 q^2 + \dots\). Taking \(V(0) = 0\) and noting that \((dV/dq)_0 = 0\) at equilibrium, the harmonic approximation retains only the quadratic term: \(V(q) = \frac{1}{2} k q^2\), where \(k = \left(\frac{d^2V}{dq^2}\right)_0\) is the bond force constant.

The time-independent Schrödinger equation for the harmonic oscillator is:

\[ -\frac{\hbar^2}{2\mu}\frac{d^2\psi_v}{dq^2} + \frac{1}{2} k q^2 \psi_v = E_v \psi_v \]

The normalized eigenfunctions are expressed in terms of Hermite polynomials \(H_v(\xi)\):

\[ \psi_v(q) = \left(\frac{\alpha}{\pi}\right)^{1/4} \frac{1}{\sqrt{2^v v!}} H_v(\sqrt{\alpha} q) e^{-\alpha q^2 / 2}, \quad \alpha = \frac{\sqrt{\mu k}}{\hbar} = \frac{\mu \omega}{\hbar} \]

The quantized energy eigenvalues are:

\[ E_v = \hbar \omega \left(v + \frac{1}{2}\right) = h c \bar{\omega}_e \left(v + \frac{1}{2}\right), \quad v = 0, 1, 2, \dots \]

where the harmonic vibrational wavenumber is \(\bar{\omega}_e = \frac{1}{2\pi c}\sqrt{\frac{k}{\mu}}\). Even at absolute zero (\(T = 0\text{ K}\)), the molecule possesses zero-point energy (ZPE): \(E_0 = \frac{1}{2}\hbar\omega = \frac{1}{2}hc\bar{\omega}_e\), a direct consequence of the Heisenberg uncertainty principle.

§3.2 Vibrational Selection Rules & Dipole Derivatives

The transition dipole moment integral between vibrational states \(|v\rangle\) and \(|v'\rangle\) is \(\mu_{v'v} = \langle \psi_{v'} | \hat{\mu}(q) | \psi_v \rangle\). Expanding the molecular dipole moment as a Taylor series about equilibrium:

\[ \hat{\mu}(q) = \mu_0 + \left(\frac{d\mu}{dq}\right)_0 q + \frac{1}{2}\left(\frac{d^2\mu}{dq^2}\right)_0 q^2 + \dots \]

Substituting this into the transition moment:

\[ \mu_{v'v} = \mu_0 \langle \psi_{v'} | \psi_v \rangle + \left(\frac{d\mu}{dq}\right)_0 \langle \psi_{v'} | q | \psi_v \rangle + \dots \]

By orthogonality of Hermite functions, \(\langle \psi_{v'} | \psi_v \rangle = 0\) for \(v' \neq v\). Therefore:

  1. Gross Selection Rule: The dipole moment must vary with bond displacement: \(\left(\frac{d\mu}{dq}\right)_0 \neq 0\). Homonuclear diatomics have zero dipole derivative at all distances and are strictly infrared inactive. Heteronuclear diatomics (\(\text{HCl}, \text{CO}, \text{NO}\)) have non-zero dipole derivatives and are infrared active.
  2. Specific Selection Rule: Using the Hermite polynomial recurrence relation \(q |v\rangle = \sqrt{\frac{\hbar}{2\mu\omega}} (\sqrt{v+1}|v+1\rangle + \sqrt{v}|v-1\rangle)\), the transition moment is non-zero only when: \[ \Delta v = v' - v = \pm 1 \]

In the harmonic approximation, all transitions occur at the exact same wavenumber \(\tilde{\nu} = \bar{\omega}_e\).

### Advanced Mathematical Formulation: Dunham Expansion and the RKR Potential Inversion Beyond simple second-order Morse potential expansions, high-resolution rovibrational transitions spanning dozens of vibrational levels require Dunham's semiclassical representation of diatomic energy levels. #### 1. The Dunham Series Expansion J. L. Dunham expressed the rovibrational term values \(T(v, J)\) as a double power series in \((v + 1/2)\) and \(J(J+1)\): \[ T(v, J) = \sum_{l=0}^\infty \sum_{j=0}^\infty Y_{lj} \left( v + \frac{1}{2} \right)^l [J(J+1)]^j \] where \(Y_{lj}\) are the Dunham coefficients. The leading Dunham coefficients relate directly to standard spectroscopic constants: \[ Y_{10} \approx \omega_e + \frac{B_e^3}{4\omega_e^2} (a_1^2 \dots) \approx \omega_e \] \[ Y_{20} \approx -\omega_e x_e \] \[ Y_{01} \approx B_e \] \[ Y_{11} \approx -\alpha_e \] \[ Y_{02} \approx -D_e = -\frac{4 B_e^3}{\omega_e^2} \] #### 2. The Dimensionless Born-Oppenheimer Potential The internuclear potential is written in terms of the dimensionless reduced coordinate \(\xi = \frac{R - R_e}{R_e}\): \[ V(\xi) = a_0 \xi^2 \left( 1 + a_1 \xi + a_2 \xi^2 + a_3 \xi^3 + \dots \right) \] where \(a_0 = \frac{\omega_e^2}{4 B_e}\). Dunham derived explicit analytical expressions connecting the potential coefficients \(a_k\) to the spectroscopic constants: \[ a_1 = -1 - \frac{\alpha_e \omega_e}{6 B_e^2} \] \[ a_2 = \frac{5}{4} a_1^2 - \frac{2 \omega_e x_e}{3 B_e} \] #### 3. Semiclassical Rydberg-Klein-Rees (RKR) Inversion The RKR method utilizes the Bohr-Sommerfeld WKB quantization condition to directly determine the classical turning points \(R_{\text{min}}(v)\) and \(R_{\text{max}}(v)\) from experimental \(G(v)\) and \(B_v\) data without assuming an analytical potential shape: \[ R_{\text{max}}(v) - R_{\text{min}}(v) = 2 f(v) = 2 \sqrt{\frac{\hbar}{2\pi \mu c}} \int_{-1/2}^v \frac{dv'}{\sqrt{G(v) - G(v')}} \] \[ \frac{1}{R_{\text{min}}(v)} - \frac{1}{R_{\text{max}}(v)} = 2 g(v) = 2 \sqrt{\frac{2\pi \mu c}{\hbar}} \int_{-1/2}^v \frac{B_{v'}}{\sqrt{G(v) - G(v')}} dv' \] Solving these two simultaneous algebraic relations gives: \[ R_{\text{min}}(v) = \sqrt{f(v)^2 + \frac{f(v)}{g(v)}} - f(v) \] \[ R_{\text{max}}(v) = \sqrt{f(v)^2 + \frac{f(v)}{g(v)}} + f(v) \] This inversion algorithm constructs the true quantum potential energy curve \(V(R)\) directly from high-resolution IR Fourier-transform spectra.

§3.3 Anharmonicity, Morse Potential & Overtones

Real chemical bonds deviate significantly from harmonic behavior at larger displacements: the potential energy steepens at short distances due to core electron repulsion and flattens asymptotically to the bond dissociation limit at large internuclear separations. The Morse potential accurately models this physical behavior:

\[ V(r) = D_e \left[ 1 - e^{-a(r - r_e)} \right]^2 \]

where \(D_e\) is the spectroscopic dissociation energy relative to the potential minimum, and \(a = \sqrt{\frac{k_e}{2 D_e}}\) governs the curvature of the well.

Anharmonic Vibrational Term Values

Solving the Schrödinger equation with the Morse potential yields the vibrational term values:

\[ G(v) = \bar{\omega}_e \left(v + \frac{1}{2}\right) - \bar{\omega}_e x_e \left(v + \frac{1}{2}\right)^2 + \bar{\omega}_e y_e \left(v + \frac{1}{2}\right)^3 + \dots \]

where \(x_e = \frac{h c \bar{\omega}_e}{4 D_e}\) is the dimensionless anharmonicity constant. Anharmonicity has profound physical consequences:

  • Energy level spacing contracts with increasing \(v\): \(\Delta G_{v+1/2} = G(v+1) - G(v) = \bar{\omega}_e - 2\bar{\omega}_e x_e(v + 1)\).
  • The harmonic selection rule \(\Delta v = \pm 1\) breaks down: weak overtone transitions become allowed:
    • Fundamental (\(v = 0 \to 1\)): \(\tilde{\nu}_1 = G(1) - G(0) = \bar{\omega}_e(1 - 2x_e)\)
    • First Overtone (\(v = 0 \to 2\)): \(\tilde{\nu}_2 = G(2) - G(0) = 2\bar{\omega}_e(1 - 3x_e)\)
    • Second Overtone (\(v = 0 \to 3\)): \(\tilde{\nu}_3 = G(3) - G(0) = 3\bar{\omega}_e(1 - 4x_e)\)
  • Hot bands (\(v = 1 \to 2\)) appear at elevated temperatures at slightly lower frequencies: \(\tilde{\nu}_{\text{hot}} = \bar{\omega}_e(1 - 4x_e)\).

§3.4 Birge-Sponer Extrapolation & Dissociation Limits

The Birge-Sponer extrapolation provides an elegant experimental methodology for determining the bond dissociation energy \(D_e\) directly from observed vibrational line spacings.

Linear Birge-Sponer Formulation

The separation between consecutive vibrational levels is:

\[ \Delta G_{v+1/2} = G(v+1) - G(v) = \bar{\omega}_e - 2\bar{\omega}_e x_e (v + 1) \]

Plotting \(\Delta G_{v+1/2}\) linearly against \((v+1)\) produces a straight line with intercept \(\bar{\omega}_e\) and negative slope \(-2\bar{\omega}_e x_e\). The dissociation limit occurs at maximum quantum number \(v_{\max}\) where the energy difference reaches zero: \(\Delta G_{v_{\max}+1/2} = 0\):

\[ v_{\max} + 1 = \frac{\bar{\omega}_e}{2\bar{\omega}_e x_e} = \frac{1}{2x_e} \]

The total dissociation energy \(D_e\) is the area under the Birge-Sponer curve:

\[ D_e = \sum_{v=0}^{v_{\max}} \Delta G_{v+1/2} \approx \int_0^{v_{\max}+1} [\bar{\omega}_e - 2\bar{\omega}_e x_e (v+1)] d(v+1) = \frac{\bar{\omega}_e^2}{4\bar{\omega}_e x_e} \]

The ground state chemical dissociation energy \(D_0\) accounts for zero-point energy:

\[ D_0 = D_e - G(0) = D_e - \left(\frac{1}{2}\bar{\omega}_e - \frac{1}{4}\bar{\omega}_e x_e\right) \]

§3.5 The Diatomic Vibrating Rotator & Rovibrational Transitions

In the gas phase, molecules undergo simultaneous vibration and rotation. In the Born-Oppenheimer approximation, the total rovibrational term value is the sum of vibrational and rotational energies:

\[ T(v, J) = G(v) + F(J) = \left[\bar{\omega}_e\left(v + \frac{1}{2}\right) - \bar{\omega}_e x_e\left(v + \frac{1}{2}\right)^2\right] + B_v J(J+1) \]

For a heteronuclear diatomic molecule in a \(^1\Sigma\) electronic ground state (zero electronic orbital angular momentum), the selection rules are:

\[ \Delta v = \pm 1, \quad \Delta J = \pm 1 \quad (\Delta J = 0 \text{ is forbidden!}) \]

R-Branch and P-Branch Manifolds

Consider the fundamental absorption transition from \(v = 0\) to \(v = 1\), with band origin \(\tilde{\nu}_0 = G(1) - G(0)\):

  1. R-Branch (\(\Delta J = +1\), \(J' = J'' + 1\)): \[ \tilde{\nu}_R(J'') = \tilde{\nu}_0 + F_1(J''+1) - F_0(J'') = \tilde{\nu}_0 + 2B_1 + (3B_1 - B_0)J'' + (B_1 - B_0)J''^2 \] If \(B_1 \approx B_0 = B\), this simplifies to: \(\tilde{\nu}_R(J'') = \tilde{\nu}_0 + 2B(J''+1)\) for \(J'' = 0, 1, 2, \dots\). Lines appear at \(\tilde{\nu}_0 + 2B, \tilde{\nu}_0 + 4B, \tilde{\nu}_0 + 6B, \dots\).
  2. P-Branch (\(\Delta J = -1\), \(J' = J'' - 1\)): \[ \tilde{\nu}_P(J'') = \tilde{\nu}_0 + F_1(J''-1) - F_0(J'') = \tilde{\nu}_0 - (B_1 + B_0)J'' + (B_1 - B_0)J''^2 \] If \(B_1 \approx B_0 = B\), this simplifies to: \(\tilde{\nu}_P(J'') = \tilde{\nu}_0 - 2B J''\) for \(J'' = 1, 2, 3, \dots\). Lines appear at \(\tilde{\nu}_0 - 2B, \tilde{\nu}_0 - 4B, \tilde{\nu}_0 - 6B, \dots\).

Because \(\Delta J = 0\) is forbidden, no absorption line appears at the exact band origin \(\tilde{\nu}_0\). The separation between the first R-line (\(R(0) = \tilde{\nu}_0 + 2B\)) and the first P-line (\(P(1) = \tilde{\nu}_0 - 2B\)) is \(4B\), leaving a prominent zero-gap in the center of the band.

§3.6 Vibration-Rotation Interaction Constant α_e & Band Heads

In real molecules, the average bond length in the excited vibrational state \(v=1\) is slightly larger than in the ground state \(v=0\) due to anharmonicity of the Morse potential: \(\langle r \rangle_{v=1} > \langle r \rangle_{v=0}\). Consequently, the moment of inertia increases and the rotational constant decreases in the upper vibrational state:

\[ B_v = B_e - \alpha_e \left(v + \frac{1}{2}\right) \]

where \(B_e\) is the equilibrium rotational constant and \(\alpha_e\) is the vibration-rotation coupling constant (\(\alpha_e > 0\)). Therefore, \(B_1 < B_0\), and \(B_1 - B_0 = -\alpha_e\).

Line Spacing Asymmetry & Band Head Formation

Incorporating \(\alpha_e\), the rovibrational transition frequencies become:

\[ \tilde{\nu}_R(J) = \tilde{\nu}_0 + (2B_e - 3\alpha_e) + (2B_e - 4\alpha_e)J - \alpha_e J^2 \] \[ \tilde{\nu}_P(J) = \tilde{\nu}_0 - (2B_e - 2\alpha_e)J - \alpha_e J^2 \]

Notice the quadratic term \(-\alpha_e J^2\):

  • In the R-branch, the quadratic term opposes the linear term. As \(J\) increases, the spacing between consecutive R-lines progressively contracts, eventually converging to a reversal point known as a band head where \(\frac{d\tilde{\nu}_R}{dJ} = 0\).
  • In the P-branch, the quadratic term adds to the linear term in the negative direction, causing the spacing between consecutive P-lines to steadily widen with increasing \(J\).

§3.7 Carbon Monoxide (CO) Rovibrational Spectrum & Combination Differences

The fundamental infrared absorption band of carbon monoxide (\(^{12}\text{C}^{16}\text{O}\)) centered at \(\tilde{\nu}_0 = 2143.27\text{ cm}^{-1}\) serves as the quintessential benchmark for high-resolution rovibrational spectroscopy.

Method of Combination Differences

To extract \(B_0\) and \(B_1\) independently without relying on assumptions about the band origin \(\tilde{\nu}_0\), spectroscopists use combination differences:

  1. Common Lower State Combination Differences (\(\Delta_2 F''(J)\)): Consider transitions starting from the same lower state \(J''\) and terminating at \(J'+1\) (via R-branch) and \(J'-1\) (via P-branch): \[ \Delta_2 F'(J) = R(J) - P(J) = F_1(J+1) - F_1(J-1) = 4B_1\left(J + \frac{1}{2}\right) \] Plotting \(R(J) - P(J)\) against \((J + 1/2)\) gives a straight line with slope \(4B_1\).
  2. Common Upper State Combination Differences (\(\Delta_2 F''(J)\)): Consider transitions terminating on the same upper state \(J'\) originating from \(J''-1\) and \(J''+1\): \[ \Delta_2 F''(J) = R(J-1) - P(J+1) = F_0(J+1) - F_0(J-1) = 4B_0\left(J + \frac{1}{2}\right) \] Plotting \(R(J-1) - P(J+1)\) against \((J + 1/2)\) gives a straight line with slope \(4B_0\).

For \(^{12}\text{C}^{16}\text{O}\), this analysis yields \(B_0 = 1.9225\text{ cm}^{-1}\), \(B_1 = 1.9050\text{ cm}^{-1}\), \(\alpha_e = 0.0175\text{ cm}^{-1}\), and equilibrium bond length \(r_e = 112.83\text{ pm}\).

### Advanced Research Monograph: Ultrafast Two-Dimensional Infrared (2D-IR) Spectroscopy While linear FTIR measures time-averaged vibrational transitions, ultrafast 2D-IR spectroscopy provides structural correlations and sub-picosecond dynamical timescales analogous to 2D NMR, but with a \(10^9\times\) faster temporal window. #### 1. Three-Pulse Coherent Infrared Photon Echo 2D-IR employs three femtosecond mid-IR laser pulses (\(\sim 100\text{ fs}\) duration) in a non-collinear boxcar geometry: \[ \text{Pulse 1 } (t = 0) \xrightarrow{\tau} \text{Pulse 2 } (t = \tau) \xrightarrow{T_w} \text{Pulse 3 } (t = \tau + T_w) \xrightarrow{t} \text{Echo Detection} \] - **Coherence time (\(\tau\)):** Encodes the initial excitation frequency \(\omega_{\text{pump}}\). - **Waiting time (\(T_w\)):** Population time during which structural evolution, vibrational energy transfer, and chemical exchange take place. - **Detection time (\(t\)):** Radiates the four-wave mixing third-order nonlinear polarization \(\mathbf{P}^{(3)}(t)\), detected via spectral interferometry to yield the probe frequency \(\omega_{\text{probe}}\). #### 2. Spectral Signatures in 2D-IR Contour Plots At each waiting time \(T_w\), a 2D plot of \(\omega_{\text{probe}}\) versus \(\omega_{\text{pump}}\) displays two distinct features for each vibrational mode: 1. **Ground State Bleach / Stimulated Emission (Diagonal Peak, negative sign):** Located at \(\omega_{\text{pump}} = \omega_{01}\) and \(\omega_{\text{probe}} = \omega_{01}\). 2. **Excited-State Absorption (Off-diagonal / Anharmonic Shift, positive sign):** Corresponds to the \(v = 1 \rightarrow 2\) transition, shifted downwards along the probe axis by the vibrational mechanical anharmonicity: \[ \Delta = \omega_{01} - \omega_{12} = 2 \omega_e x_e \] #### 3. Spectral Diffusion and Hydrogen-Bond Dynamics At \(T_w = 0\), solvent fluctuations cause inhomogeneous broadening, creating an elongated elliptical diagonal peak. - As \(T_w\) increases, molecular reorientation and rapid hydrogen-bond breaking/re-forming randomize the local electrostatic field felt by the oscillator. - This **spectral diffusion** causes the 2D contour to round into a symmetric circle. - The decay rate of the peak ellipse eccentricity (Center Line Slope, CLS) directly quantifies the frequency-frequency correlation function (FFCF) \(\langle \delta\omega(t)\delta\omega(0)\rangle\), revealing that water hydrogen-bond networks rearrange on a blistering timescale of \(\sim 1.5\text{ ps}\).

§3.8 Normal Coordinate Analysis & Characteristic Functional Group Wavenumbers

For a non-linear polyatomic molecule with \(N\) atoms, there exist \(3N - 6\) independent vibrational degrees of freedom (\(3N - 5\) for linear molecules). E. Bright Wilson formalized the exact mathematical treatment of polyatomic vibrations using the Wilson FG matrix method.

The Wilson FG Secular Matrix Equation

Internal coordinates \(S\) (bond stretches \(\Delta r\), valence angle bends \(\Delta\theta\), out-of-plane wags \(\Delta\gamma\), and torsions \(\Delta\tau\)) are related to Cartesian displacements through kinetic energy matrix \(\mathbf{G}\) and potential energy matrix \(\mathbf{F}\):

\[ 2 T = \dot{\mathbf{S}}^T \mathbf{G}^{-1} \dot{\mathbf{S}}, \quad 2 V = \mathbf{S}^T \mathbf{F} \mathbf{S} \]

The vibrational frequencies \(\lambda_k = 4\pi^2 c^2 \tilde{\nu}_k^2\) are the eigenvalues of the secular determinant:

\[ |\mathbf{F}\mathbf{G} - \lambda \mathbf{E}| = 0 \]

where \(\mathbf{G}\) elements depend purely on atomic masses and equilibrium molecular geometry, while \(\mathbf{F}\) contains the quadratic harmonic force constants (diagonal stretching force constants \(f_r\), bending force constants \(f_\theta\), and off-diagonal stretch-bend interaction constants).

Diagnostic Characteristic Infrared Group Frequencies

Because many chemical functional groups involve high force constants or light atoms (such as \(\text{-H}\)), their vibrational modes are mechanically decoupled from the rest of the molecular framework, producing highly characteristic absorption bands regardless of the surrounding molecular structure:

Functional Group Vibrational Mode Assignment Typical Wavenumber Range (\(\text{cm}^{-1}\)) Band Intensity & Characteristics
Free O-H (Alcohol, Phenol) O-H stretch (unassociated) \(3600 - 3650\) Sharp, medium (dilute gas/solution)
H-Bonded O-H O-H \(\cdots\) O stretch \(3200 - 3500\) Very broad, intense
Carboxylic Acid O-H O-H stretch (dimerized) \(2500 - 3300\) Extremely broad, centered \(\sim 3000\), overlaps C-H
Aliphatic C-H (\(sp^3\)) C-H symmetric & asymmetric stretch \(2850 - 2960\) Strong to medium, always below \(3000\)
Aromatic / Alkenyl C-H (\(sp^2\)) \(=\text{C-H}\) stretch \(3010 - 3100\) Sharp, medium, always above \(3000\)
Alkyne C-H (\(sp\)) \(\equiv\text{C-H}\) stretch \(3280 - 3320\) Sharp, intense
Nitriles & Alkynes \(\text{C}\equiv\text{N}\), \(\text{C}\equiv\text{C}\) stretch \(2100 - 2260\) Sharp, variable (weak for symmetrical alkynes)
Ketones & Aldehydes \(\text{C=O}\) stretch \(1715 - 1730\) Very intense, diagnostic
Esters \(\text{C=O}\) stretch / C-O stretch \(1735 - 1750\) / \(1150 - 1250\) Very intense \(\text{C=O}\); strong C-O band
Amides (Amide I & II) \(\text{C=O}\) stretch / N-H bend + C-N stretch \(1640 - 1690\) / \(1510 - 1560\) Two strong bands (Amide I and Amide II)
Aromatic Ring C=C ring quadrant stretch \(1600, 1585, 1500, 1450\) Pair of sharp doublets; out-of-plane bends \(700 - 850\)

The region below \(1500\text{ cm}^{-1}\), designated the fingerprint region, contains complex coupled skeletal vibrations unique to each individual molecule.

Foundational Example 3.1: Force Constant and Zero-Point Energy of Carbon Monoxide

The fundamental vibrational wavenumber of \(^{12}\text{C}^{16}\text{O}\) is \(\bar{\omega}_e = 2169.8\text{ cm}^{-1}\). (a) Calculate the bond force constant \(k\) in \(\text{N/m}\). (b) Determine the zero-point vibrational energy (ZPE) in \(\text{kJ/mol}\) and in \(\text{eV}\). (c) Predict the harmonic vibrational wavenumber for \(^{13}\text{C}^{16}\text{O}\) assuming the force constant is unaffected by isotopic substitution.

Step (a): Force constant calculation

The reduced mass of \(^{12}\text{C}^{16}\text{O}\) is \(\mu = 6.85621\text{ u} = 1.13850 \times 10^{-26}\text{ kg}\).

\[ \bar{\omega}_e = \frac{1}{2\pi c} \sqrt{\frac{k}{\mu}} \implies k = 4\pi^2 c^2 \bar{\omega}_e^2 \mu \] \[ k = 4\pi^2 (2.99792 \times 10^{10}\text{ cm/s})^2 (2169.8\text{ cm}^{-1})^2 (1.13850 \times 10^{-26}\text{ kg}) \] \[ k = 4\pi^2 (8.98755 \times 10^{20})(4.70803 \times 10^6)(1.13850 \times 10^{-26}) = 1901.9\text{ N/m} \]

This exceptionally large force constant (\(\sim 1902\text{ N/m}\)) reflects the formidable triple bond in carbon monoxide.

Step (b): Zero-point energy

\[ E_0 = \frac{1}{2} hc \bar{\omega}_e = \frac{1}{2}(6.62607 \times 10^{-34})(2.99792 \times 10^{10})(2169.8) = 2.155 \times 10^{-20}\text{ J} \]

Per mole:

\[ E_{0, \text{molar}} = N_A E_0 = (6.02214 \times 10^{23})(2.155 \times 10^{-20}\text{ J}) = 12.978\text{ kJ/mol} \]

In electron-volts:

\[ E_0 = \frac{2.155 \times 10^{-20}\text{ J}}{1.60218 \times 10^{-19}\text{ J/eV}} = 0.1345\text{ eV} \]

Step (c): Vibrational wavenumber for ¹³C¹⁶O

The reduced mass of \(^{13}\text{C}^{16}\text{O}\) is \(\mu' = 7.17241\text{ u}\).

\[ \bar{\omega}_e' = \bar{\omega}_e \sqrt{\frac{\mu}{\mu'}} = 2169.8 \sqrt{\frac{6.85621}{7.17241}} = 2169.8 \times 0.977708 = 2121.4\text{ cm}^{-1} \]
Intermediate Example 3.2: Anharmonicity Constants and Morse Dissociation Energy of HCl

For \(^{1}\text{H}^{35}\text{Cl}\), the fundamental absorption band appears at \(\tilde{\nu}_1 = 2885.9\text{ cm}^{-1}\) and the first overtone band appears at \(\tilde{\nu}_2 = 5668.0\text{ cm}^{-1}\). (a) Determine the harmonic wavenumber \(\bar{\omega}_e\) and the anharmonicity constant \(x_e\). (b) Calculate the predicted wavenumber of the second overtone (\(v = 0 \to 3\)). (c) Estimate the spectroscopic dissociation energy \(D_e\) and ground state chemical dissociation energy \(D_0\) in \(\text{kJ/mol}\).

Step (a): Calculation of \(\bar{\omega}_e\) and \(x_e\)

The transition wavenumbers are related to term values by:

\[ \tilde{\nu}_1 = G(1) - G(0) = \bar{\omega}_e(1 - 2x_e) = 2885.9\text{ cm}^{-1} \] \[ \tilde{\nu}_2 = G(2) - G(0) = 2\bar{\omega}_e(1 - 3x_e) = 5668.0\text{ cm}^{-1} \]

Dividing the second equation by 2:

\[ \bar{\omega}_e(1 - 3x_e) = 2834.0\text{ cm}^{-1} \]

Subtracting this from the fundamental:

\[ \bar{\omega}_e(1 - 2x_e) - \bar{\omega}_e(1 - 3x_e) = \bar{\omega}_e x_e = 2885.9 - 2834.0 = 51.9\text{ cm}^{-1} \]

Now substitute \(\bar{\omega}_e x_e\) back into \(\bar{\omega}_e(1 - 2x_e) = \bar{\omega}_e - 2\bar{\omega}_e x_e\):

\[ \bar{\omega}_e = 2885.9 + 2(51.9) = 2885.9 + 103.8 = 2989.7\text{ cm}^{-1} \] \[ x_e = \frac{\bar{\omega}_e x_e}{\bar{\omega}_e} = \frac{51.9}{2989.7} = 0.01736 \]

Step (b): Second overtone wavenumber (\(v = 0 \to 3\))

\[ \tilde{\nu}_3 = G(3) - G(0) = 3\bar{\omega}_e(1 - 4x_e) = 3(2989.7)(1 - 4 \times 0.01736) = 8969.1(1 - 0.06944) = 8346.3\text{ cm}^{-1} \]

Step (c): Dissociation energies \(D_e\) and \(D_0\)

\[ D_e = \frac{\bar{\omega}_e^2}{4\bar{\omega}_e x_e} = \frac{(2989.7)^2}{4(51.9)} = \frac{8938306}{207.6} = 43055\text{ cm}^{-1} \]

Converting to \(\text{kJ/mol}\) (\(1\text{ cm}^{-1} = 0.0119627\text{ kJ/mol}\)):

\[ D_e = 43055 \times 0.0119627 = 515.1\text{ kJ/mol} \] \[ D_0 = D_e - G(0) = D_e - \left(\frac{1}{2}\bar{\omega}_e - \frac{1}{4}\bar{\omega}_e x_e\right) = 43055 - (1494.85 - 12.98) = 43055 - 1481.87 = 41573\text{ cm}^{-1} \] \[ D_0 = 41573 \times 0.0119627 = 497.3\text{ kJ/mol} \]
Intermediate Example 3.3: Birge-Sponer Linear Extrapolation for Iodine Molecule

Vibrational level separations \(\Delta G_{v+1/2}\) for the ground electronic state of \(^{127}\text{I}_2\) yield a linear Birge-Sponer regression:

\[\Delta G_{v+1/2} = 214.50 - 1.22(v+1)\ \text{cm}^{-1}\]

(a) Identify \(\bar{\omega}_e\) and \(\bar{\omega}_e x_e\). (b) Calculate the maximum bound vibrational quantum number \(v_{\max}\). (c) Calculate the total dissociation energy \(D_e\) in \(\text{cm}^{-1}\) and \(\text{kJ/mol}\).

Step (a): Identify parameters

Comparing with \(\Delta G_{v+1/2} = \bar{\omega}_e - 2\bar{\omega}_e x_e(v+1)\):

\[ \bar{\omega}_e = 214.50\text{ cm}^{-1} \] \[ 2\bar{\omega}_e x_e = 1.22\text{ cm}^{-1} \implies \bar{\omega}_e x_e = 0.61\text{ cm}^{-1} \implies x_e = \frac{0.61}{214.50} = 0.00284 \]

Step (b): Maximum bound vibrational state

\[ \Delta G_{v_{\max}+1/2} = 0 \implies 214.50 - 1.22(v_{\max} + 1) = 0 \implies v_{\max} + 1 = \frac{214.50}{1.22} = 175.8 \] \[ v_{\max} = 174\text{ bound states} \]

Step (c): Total dissociation energy De

\[ D_e = \frac{\bar{\omega}_e^2}{4\bar{\omega}_e x_e} = \frac{(214.50)^2}{2(1.22)} = \frac{46010.25}{2.44} = 18856.7\text{ cm}^{-1} \]

Converting to \(\text{kJ/mol}\):

\[ D_e = 18856.7\text{ cm}^{-1} \times 0.0119627\text{ kJ/mol per cm}^{-1} = 225.58\text{ kJ/mol} \]
Intermediate Example 3.4: Assignment and Analysis of Rovibrational P and R Branch Lines

In the fundamental infrared absorption band of \(^{1}\text{H}^{35}\text{Cl}\), four consecutive lines are recorded at: \(\tilde{\nu}_A = 2865.1\text{ cm}^{-1}\), \(\tilde{\nu}_B = 2906.2\text{ cm}^{-1}\), \(\tilde{\nu}_C = 2925.8\text{ cm}^{-1}\), \(\tilde{\nu}_D = 2944.9\text{ cm}^{-1}\). Notice the gap between lines A and B is \(\approx 41.1\text{ cm}^{-1}\), while between B and C is \(\approx 19.6\text{ cm}^{-1}\). (a) Identify the band origin \(\tilde{\nu}_0\) and assign lines A, B, C, D to specific transitions (\(P(J)\) or \(R(J)\)). (b) Estimate the average rotational constant \(B\). (c) Explain the origin of the \(\approx 41\text{ cm}^{-1}\) gap between lines A and B.

Step (a): Identification of band origin and line assignments

In a rovibrational spectrum with \(\Delta J = \pm 1\), the separation between consecutive lines within a branch is \(\approx 2B\), whereas the gap across the missing Q-branch (\(P(1)\) to \(R(0)\)) is \(\approx 4B\).

The gap between \(\tilde{\nu}_A = 2865.1\text{ cm}^{-1}\) and \(\tilde{\nu}_B = 2906.2\text{ cm}^{-1}\) is \(41.1\text{ cm}^{-1} \approx 4B\). Therefore:

  • Line A is the first line of the P-branch: \(P(1)\) (\(v=0, J=1 \to v=1, J=0\))
  • Line B is the first line of the R-branch: \(R(0)\) (\(v=0, J=0 \to v=1, J=1\))
  • Line C is the second line of the R-branch: \(R(1)\) (\(v=0, J=1 \to v=1, J=2\))
  • Line D is the third line of the R-branch: \(R(2)\) (\(v=0, J=2 \to v=1, J=3\))

The band origin \(\tilde{\nu}_0\) lies midway between \(P(1)\) and \(R(0)\):

\[ \tilde{\nu}_0 \approx \frac{2865.1 + 2906.2}{2} = 2885.65\text{ cm}^{-1} \]

Step (b): Rotational constant B

\[ 4B \approx 41.1\text{ cm}^{-1} \implies B \approx 10.28\text{ cm}^{-1} \]

Checking R-branch spacing:

\[ R(1) - R(0) = 2925.8 - 2906.2 = 19.6\text{ cm}^{-1} \approx 2B \implies B \approx 9.8\text{ cm}^{-1} \]

Step (c): Physical origin of the 4B gap

Because \(\Delta J = 0\) is strictly forbidden for \(\Sigma \to \Sigma\) transitions, there is no Q-branch. The transition from \(J=0 \to 0\) cannot occur, leaving a vacant window of width \((R(0) - P(1)) = (\tilde{\nu}_0 + 2B) - (\tilde{\nu}_0 - 2B) = 4B\).

Advanced Example 3.5: Extraction of B0 and B1 via Method of Combination Differences

High-resolution FTIR data for the \(^{12}\text{C}^{16}\text{O}\) fundamental band yields the following lines: \(R(0) = 2147.08\text{ cm}^{-1}\), \(R(1) = 2150.86\text{ cm}^{-1}\), \(R(2) = 2154.60\text{ cm}^{-1}\), \(P(1) = 2139.43\text{ cm}^{-1}\), \(P(2) = 2135.55\text{ cm}^{-1}\), \(P(3) = 2131.63\text{ cm}^{-1}\). (a) Use the combination difference \(\Delta_2 F'(1) = R(1) - P(1)\) to calculate \(B_1\). (b) Use the combination difference \(\Delta_2 F''(1) = R(0) - P(2)\) to calculate \(B_0\). (c) Determine the vibration-rotation coupling constant \(\alpha_e = B_0 - B_1\).

Step (a): Upper state B1 calculation

The combination difference for the upper state with \(J = 1\) is:

\[ \Delta_2 F'(1) = R(1) - P(1) = 4B_1\left(1 + \frac{1}{2}\right) = 6 B_1 \] \[ R(1) - P(1) = 2150.86 - 2139.43 = 11.43\text{ cm}^{-1} \] \[ B_1 = \frac{11.43\text{ cm}^{-1}}{6} = 1.9050\text{ cm}^{-1} \]

Step (b): Lower state B0 calculation

The combination difference for the lower state with \(J = 1\) is:

\[ \Delta_2 F''(1) = R(0) - P(2) = 4B_0\left(1 + \frac{1}{2}\right) = 6 B_0 \] \[ R(0) - P(2) = 2147.08 - 2135.55 = 11.53\text{ cm}^{-1} \] \[ B_0 = \frac{11.53\text{ cm}^{-1}}{6} = 1.9217\text{ cm}^{-1} \]

Step (c): Vibration-rotation interaction constant \(\alpha_e\)

\[ \alpha_e = B_0 - B_1 = 1.9217 - 1.9050 = 0.0167\text{ cm}^{-1} \]

The equilibrium rotational constant is \(B_e = B_0 + \frac{1}{2}\alpha_e = 1.9217 + 0.00835 = 1.9300\text{ cm}^{-1}\).

Advanced Example 3.6: Band Head Formation in the R-Branch

A diatomic molecule has band origin \(\tilde{\nu}_0 = 2000.0\text{ cm}^{-1}\), lower state rotational constant \(B_0 = 1.800\text{ cm}^{-1}\), and vibration-rotation coupling constant \(\alpha_e = 0.025\text{ cm}^{-1}\). (a) Express \(\tilde{\nu}_R(J)\) as a function of \(J\). (b) Calculate the rotational quantum number \(J_{\text{head}}\) at which the R-branch forms a band head. (c) Calculate the wavenumber of the band head \(\tilde{\nu}_{\text{head}}\).

Step (a): R-branch wavenumber function

With \(B_1 = B_0 - \alpha_e = 1.800 - 0.025 = 1.775\text{ cm}^{-1}\):

\[ \tilde{\nu}_R(J) = \tilde{\nu}_0 + 2B_1 + (3B_1 - B_0)J + (B_1 - B_0)J^2 \] \[ 2B_1 = 2(1.775) = 3.550\text{ cm}^{-1} \] \[ 3B_1 - B_0 = 3(1.775) - 1.800 = 5.325 - 1.800 = 3.525\text{ cm}^{-1} \] \[ B_1 - B_0 = -\alpha_e = -0.025\text{ cm}^{-1} \] \[ \tilde{\nu}_R(J) = 2000.0 + 3.550 + 3.525 J - 0.025 J^2 = 2003.55 + 3.525 J - 0.025 J^2 \]

Step (b): Band head location J_head

At the band head, the wavenumber reaches an extremum: \(\frac{d\tilde{\nu}_R}{dJ} = 0\):

\[ \frac{d\tilde{\nu}_R}{dJ} = 3.525 - 0.050 J = 0 \implies J_{\text{head}} = \frac{3.525}{0.050} = 70.5 \approx 70 \text{ or } 71 \]

Step (c): Wavenumber of the band head

Evaluating at \(J = 70\):

\[ \tilde{\nu}_R(70) = 2003.55 + 3.525(70) - 0.025(70)^2 = 2003.55 + 246.75 - 122.50 = 2127.80\text{ cm}^{-1} \]

Evaluating at \(J = 71\):

\[ \tilde{\nu}_R(71) = 2003.55 + 3.525(71) - 0.025(71)^2 = 2003.55 + 250.275 - 126.025 = 2127.80\text{ cm}^{-1} \]

Beyond \(J = 70\), lines turn back toward lower wavenumbers, creating an intense pile-up (band head) shaded toward the red.

Intermediate Example 3.7: Normal Modes and Fermi Resonance in Carbon Dioxide

Carbon dioxide (\(\text{CO}_2\)) is a linear triatomic molecule. (a) Determine the number of normal vibrational modes. (b) Classify each normal mode by symmetry (\(\Sigma_g^+, \Pi_u, \Sigma_u^+\)), state whether it is infrared active or inactive, and give approximate wavenumbers. (c) Explain the phenomenon of Fermi resonance between the symmetric stretch \(\nu_1\) and the first overtone of the bend \(2\nu_2\). Why does the Raman spectrum show a doublet at \(1285\text{ cm}^{-1}\) and \(1388\text{ cm}^{-1}\)?

Step (a): Degrees of vibrational freedom

For a linear molecule with \(N = 3\) atoms:

\[ 3N - 5 = 3(3) - 5 = 4\text{ normal vibrational modes} \]

Step (b): Classification of normal modes

  1. Symmetric Stretch (\(\nu_1\), \(\Sigma_g^+\)): \(\sim 1337\text{ cm}^{-1}\). The two C=O bonds stretch symmetrically. The dipole moment remains strictly zero throughout the vibration (\((d\mu/dq)_0 = 0\)). IR inactive, Raman active.
  2. Bending Mode (\(\nu_2\), \(\Pi_u\)): \(\sim 667\text{ cm}^{-1}\). Doubly degenerate (bending in xz and yz planes). The linear geometry bends, creating an oscillating perpendicular dipole moment. IR active, Raman inactive.
  3. Asymmetric Stretch (\(\nu_3\), \(\Sigma_u^+\)): \(\sim 2349\text{ cm}^{-1}\). One C=O bond contracts while the other stretches, producing an oscillating parallel dipole moment. IR active, Raman inactive.

Step (c): Fermi resonance mechanism

The fundamental symmetric stretch \(\nu_1\) has unperturbed wavenumber \(\approx 1337\text{ cm}^{-1}\) with \(\Sigma_g^+\) symmetry. The bending overtone \(2\nu_2\) has unperturbed wavenumber \(2 \times 667 \approx 1334\text{ cm}^{-1}\) and also contains a \(\Sigma_g^+\) component.

Because these two states have:

  • Nearly identical unperturbed energies (\(\Delta E_0 \approx 3\text{ cm}^{-1}\))
  • Identical irreducible representation (\(\Sigma_g^+\))

They are coupled by cubic anharmonic terms in the molecular potential (\(k_{122} q_1 q_2^2\)). Quantum mechanical perturbation theory mixes the wavefunctions:

\[ \psi_{\pm} = \frac{1}{\sqrt{2}}(\psi_{\nu_1} \pm \psi_{2\nu_2}) \]

This quantum mechanical mixing repels the energy levels apart, producing a Fermi doublet at \(1285\text{ cm}^{-1}\) and \(1388\text{ cm}^{-1}\) with shared Raman scattering intensity.

Intermediate Example 3.8: Carbonyl Stretching Frequency Modulations: Ring Strain vs Conjugation

The fundamental carbonyl stretching wavenumber \(\tilde{\nu}_{\text{C=O}}\) in cyclic ketones varies systematically with ring size:

  1. Cyclohexanone (6-membered): \(\tilde{\nu} = 1715\text{ cm}^{-1}\)
  2. Cyclopentanone (5-membered): \(\tilde{\nu} = 1745\text{ cm}^{-1}\)
  3. Cyclobutanone (4-membered): \(\tilde{\nu} = 1780\text{ cm}^{-1}\)
  4. Cyclopropenone (3-membered): \(\tilde{\nu} = 1850\text{ cm}^{-1}\)

In contrast, \(\alpha,\beta\)-unsaturated cyclohex-2-en-1-one absorbs at \(\tilde{\nu} = 1685\text{ cm}^{-1}\). (a) Explain why decreasing ring size increases the \(\text{C=O}\) force constant and stretching wavenumber using carbon hybridization arguments. (b) Explain why conjugation with an adjacent \(\text{C=C}\) double bond lowers \(\tilde{\nu}_{\text{C=O}}\) to \(1685\text{ cm}^{-1}\). (c) Predict the approximate carbonyl stretching frequency of cyclobut-2-en-1-one.

Step (a): Ring strain and hybridization effect

As the ring size decreases from 6 to 3, the internal \(\text{C-C-C}\) bond angle at the carbonyl carbon is constrained to smaller values (\(120^\circ \to 108^\circ \to 90^\circ \to 60^\circ\)).

According to Coulson's theorem (\(1 + \lambda_i \lambda_j \cos\theta_{ij} = 0\)), decreasing the bond angle between the ring \(\text{C-C}\) bonds forces them to divert more p-character into the ring (\(\lambda^2 > 3\)).

To conserve total s-character (\(\sum f_s = 1\)), the exocyclic \(\sigma\)-bond to oxygen is forced to accept higher s-character (approaching \(sp\) hybridization). Higher s-character shortens the \(\text{C=O}\) \(\sigma\)-bond, increases the bond force constant \(k\), and raises the vibrational frequency: \(\tilde{\nu} \propto \sqrt{k/\mu}\), shifting \(\tilde{\nu}_{\text{C=O}}\) progressively from \(1715\text{ cm}^{-1}\) to \(1850\text{ cm}^{-1}\).

Step (b): Conjugation effect

Conjugation with an adjacent double bond allows resonance delocalization:

\[ >\text{C=C-C=O} \longleftrightarrow >\text{C}^+-\text{C=C-O}^- \]

The dipolar resonance contributor introduces single-bond character into the carbonyl group, reducing the \(\pi\)-bond order from \(2.0\) to \(\approx 1.85\). This lowers the force constant \(k\), shifting the stretching band downfield by \(\sim 30 - 40\text{ cm}^{-1}\) to \(1685\text{ cm}^{-1}\).

Step (c): Prediction for cyclobut-2-en-1-one

In cyclobut-2-en-1-one, both effects operate simultaneously:

  • 4-membered ring strain: \(+65\text{ cm}^{-1}\) relative to acyclic ketone (\(1715 \to 1780\text{ cm}^{-1}\))
  • \(\alpha,\beta\)-conjugation: \(-30\text{ cm}^{-1}\)
\[ \tilde{\nu}_{\text{predicted}} \approx 1780 - 30 = 1750\text{ cm}^{-1} \]

Experimental measurement gives \(1752\text{ cm}^{-1}\), verifying the additive predictive power of physical organic spectroscopy.

Advanced Example 3.9: Problem 9: Fermi Resonance Deconvolution and Coupling Matrix Element in Carbon Dioxide

In the Raman spectrum of gaseous carbon dioxide (\(\text{CO}_2\)), instead of a single symmetric stretch fundamental \(\nu_1\), one observes a pronounced doublet at \(\tilde{\nu}_+ = 1388.2\text{ cm}^{-1}\) and \(\tilde{\nu}_- = 1285.4\text{ cm}^{-1}\) with an integrated intensity ratio of \(\frac{I_+}{I_-} = 1.15\).

This perturbation arises from an accidental Fermi resonance between the fundamental symmetric stretching state \(|10^00\rangle\) and the overtone of the bending mode \(|02^00\rangle\).

  1. State the symmetry species of \(|10^00\rangle\) and \(|02^00\rangle\) in the \(D_{\infty h}\) point group and explain why cubic anharmonic coupling can mix them.
  2. Formulate the two-state perturbation secular determinant in terms of unperturbed energies \(E_a^0, E_b^0\) and cubic anharmonic coupling matrix element \(W = \langle 10^00 | \hat{H}_{\text{anharm}} | 02^00 \rangle\).
  3. Using the observed peak positions \(\tilde{\nu}_+\) and \(\tilde{\nu}_-\) and the intensity ratio \(\frac{I_+}{I_-} = 1.15\) (assuming intrinsic Raman activity arises solely from the fundamental \(|10^00\rangle\)), calculate:
  • The mixing coefficients \(c_a\) and \(c_b\) where \(|\psi_+\rangle = c_a |10^00\rangle + c_b |02^00\rangle\).
  • The unperturbed vibrational frequencies \(\nu_1^0\) and \(2\nu_2^0\).
  • The magnitude of the anharmonic coupling constant \(|W|\) in \(\text{cm}^{-1}\).

Comprehensive Multi-Step Solution:

Step 1: Symmetry Analysis and Fermi Resonance Condition

In linear carbon dioxide (\(D_{\infty h}\)):

  • The symmetric stretch \(Q_1\) transforms as \(\Sigma_g^+\). Thus state \(|10^00\rangle\) has symmetry \(\Sigma_g^+\).
  • The degenerate bending mode \(Q_2\) transforms as \(\Pi_u\). The first overtone gives direct product states:
\[\Pi_u \otimes \Pi_u = \Sigma_g^+ \oplus [\Sigma_u^-] \oplus \Delta_g\]

The \(l=0\) component \(|02^00\rangle\) has exactly \(\Sigma_g^+\) symmetry. Since both states belong to the identical irreducible representation \(\Sigma_g^+\), the cubic anharmonic potential term \(k_{122} Q_1 (Q_{2x}^2 + Q_{2y}^2)\) (which transforms as totally symmetric \(\Sigma_g^+\)) mediates a non-zero coupling:

\[W = \langle 10^00 | k_{122} Q_1 Q_2^2 | 02^00 \rangle \neq 0\]

Step 2: Two-State Secular Determinant

The Hamiltonian matrix in the unperturbed basis \(\{|a\rangle = |10^00\rangle, |b\rangle = |02^00\rangle\}\) is:

\[\mathbf{H} = \begin{pmatrix} E_a^0 & W \\ W & E_b^0 \end{pmatrix}\]

Diagonalizing gives eigenvalues:

\[E_\pm = \frac{E_a^0 + E_b^0}{2} \pm \frac{1}{2} \sqrt{(E_a^0 - E_b^0)^2 + 4W^2}\]

Let \(\delta_0 = E_a^0 - E_b^0\) be the unperturbed separation and \(\Delta = E_+ - E_-\) be the observed doublet separation:

\[\Delta = \tilde{\nu}_+ - \tilde{\nu}_- = 1388.2 - 1285.4 = 102.8\text{ cm}^{-1}\]

Notice also that:

\[E_+ + E_- = E_a^0 + E_b^0 = 1388.2 + 1285.4 = 2673.6\text{ cm}^{-1}\]

Step 3: Determining Mixing Coefficients and Unperturbed Parameters

The perturbed eigenfunctions are:

\[|\psi_+\rangle = \cos\theta |a\rangle + \sin\theta |b\rangle\]
\[|\psi_-\rangle = -\sin\theta |a\rangle + \cos\theta |b\rangle\]

Assuming the bending overtone \(|b\rangle = |02^00\rangle\) has negligible zero-order Raman polarizability derivative (\(\alpha_b \approx 0\)), all transition intensity originates from \(|a\rangle = |10^00\rangle\):

\[I_+ \propto |\langle 0 | \hat{\alpha} | \psi_+ \rangle|^2 = \cos^2\theta |\langle 0 | \hat{\alpha} | a \rangle|^2\]
\[I_- \propto |\langle 0 | \hat{\alpha} | \psi_- \rangle|^2 = \sin^2\theta |\langle 0 | \hat{\alpha} | a \rangle|^2\]

The intensity ratio is:

\[\frac{I_+}{I_-} = \frac{\cos^2\theta}{\sin^2\theta} = \cot^2\theta = 1.15\]

Solving for \(\tan\theta\):

\[\tan\theta = \frac{1}{\sqrt{1.15}} = \frac{1}{1.0724} \approx 0.9325 \implies \theta \approx 43.0^\circ\]

Evaluating the coefficients:

\[c_a = \cos(43.0^\circ) \approx 0.7314, \quad c_b = \sin(43.0^\circ) \approx 0.6820\]

(Check normalization: \(0.7314^2 + 0.6820^2 = 0.5349 + 0.4651 = 1.000\)).

From standard two-level mixing theory:

\[\cos(2\theta) = \frac{\delta_0}{\Delta}\]

Evaluating \(\cos(2\theta)\) where \(2\theta = 86.0^\circ\):

\[\cos(86.0^\circ) \approx 0.06976\]

Therefore, the unperturbed energy difference \(\delta_0\) is:

\[\delta_0 = \Delta \cos(2\theta) = 102.8\text{ cm}^{-1} \times 0.06976 \approx 7.17\text{ cm}^{-1}\]

Now solve for the individual unperturbed levels:

\[E_a^0 + E_b^0 = 2673.6\text{ cm}^{-1}\]
\[E_a^0 - E_b^0 = 7.17\text{ cm}^{-1}\]

Adding the two equations:

\[2E_a^0 = 2680.77 \implies E_a^0 = \nu_1^0 = 1340.39\text{ cm}^{-1}\]

Subtracting:

\[E_b^0 = 2\nu_2^0 = 1333.21\text{ cm}^{-1}\]

Finally, calculating the coupling matrix element \(|W|\):

\[\sin(2\theta) = \frac{2|W|}{\Delta} \implies |W| = \frac{\Delta}{2} \sin(2\theta)\]
\[\sin(86.0^\circ) \approx 0.9976\]
\[|W| = \frac{102.8}{2} \times 0.9976 = 51.4 \times 0.9976 \approx 51.27\text{ cm}^{-1}\]

The unperturbed states lie merely \(7.17\text{ cm}^{-1}\) apart, but their strong Fermi resonance coupling (\(|W| \approx 51.3\text{ cm}^{-1}\)) repels them into the well-known \(102.8\text{ cm}^{-1}\) doublet!

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