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Chapter 2 • Theory & Derivations

Resistive Circuits, Kirchhoff Laws, and Reduction

Comprehensive university textbook unit covering fundamental principles, mathematical formulations, and practical engineering applications of Resistive Circuits, Kirchhoff Laws, and Reduction.

§2.1 Ohm’s Law and Linear Resistance

U02-L01 · Ohm’s Law and Linear Resistance

Unit: 2 — Resistive Networks Core relation: v=Ri Essential ideas: resistance, conductance, V–I characteristics, and material limits.

Learning objectives

After this lesson, explain ohm’s law and linear resistance and its circuit context, assign reference polarities and directions, derive or use v=Ri with SI units, solve a numerical example, and evaluate its validity using conservation laws and a practical limiting case.

Physical and mathematical foundation

Ohm’s law describes an ideal linear resistor at a specified operating condition. The selected current arrow and voltage polarity give meaning to the signs in an equation; they do not force a physical quantity to flow in that direction. Nodes define equal-potential connection points in the lumped model. Branches define component connections, and a chosen ground provides a mathematical reference rather than a physical energy sink. Interpreting the equation v=Ri requires knowing both the connected terminals and the applicable ideal-component assumptions.

Within resistive networks, distinguish a source-imposed quantity from a circuit response. A voltage source constrains one terminal difference, while a current source constrains a branch current. An element's constitutive relation describes its response but cannot replace Kirchhoff's laws. If a diagram changes, the electrical topology may change even when the drawn symbols and their numerical values remain the same.

Concept 1 — Resistance. Identify the branch or terminals to which this idea applies, state its units, and connect it with v=Ri. Explain what changes when the source or component parameter increases; predict the direction of the change before doing arithmetic. Consider whether reference directions, instrument loading, or tolerance could distort the interpretation.

Concept 2 — Conductance. Identify the branch or terminals to which this idea applies, state its units, and connect it with v=Ri. Explain what changes when the source or component parameter increases; predict the direction of the change before doing arithmetic. Consider whether reference directions, instrument loading, or tolerance could distort the interpretation.

Concept 3 — V–i characteristics. Identify the branch or terminals to which this idea applies, state its units, and connect it with v=Ri. Explain what changes when the source or component parameter increases; predict the direction of the change before doing arithmetic. Consider whether reference directions, instrument loading, or tolerance could distort the interpretation.

Worked case and result

Case. A 220 Ω resistor is supplied by a 11 V source.

Result. The current is 0.050 A, and the resistor dissipates 0.55 W. First translate all prefixes into SI units and state the formula before substituting. Verify that the dimensions of the answer agree with the quantity being requested. Reverse the calculation, or test a meaningful limiting case, rather than trusting the displayed calculator result alone.

Interpretation. Ohm’s law describes an ideal linear resistor at a specified operating condition. A negative signed answer may only mean that a current or voltage points opposite to its reference. It does not indicate an impossible circuit. When multiple elements appear, check their node-current balance, the signed sum of drops around a loop, and the sum of absorbed and delivered powers.

A reliable solution method

  1. Draw the topology, identify nodes, and choose polarities and branch-current arrows; write down which source and element quantities are known.
  2. Combine the component relation v=Ri with KCL, KVL, and state continuity where relevant; solve symbolically before substituting numbers.
  3. Convert units, calculate, and cross-check using a conservation equation or limiting case. Explain why the result is physically plausible.
  4. Identify the dominant idealization. A real resistor can change value with temperature and can exceed its power rating. If any predicted value approaches a component rating, the analysis is only a starting point for a safety-qualified design review.

Exercises

1. Concept: Explain why resistance needs a clear reference direction, voltage polarity, or system boundary. Provide one counterexample.

2. Numerical: Reproduce the worked case, showing each unit conversion. Increase one supplied value by 20% and compute the resulting change.

3. Verification: Construct a KCL, KVL, energy, or state-continuity check appropriate to this circuit; explain which assumption the check tests.

4. Application: Specify a current-limited low-voltage demonstration and describe how meter input impedance would change the result.

5. Extension: Change one boundary condition and explain whether `v=Ri` remains valid and which previous shortcut fails.

Key limitation: A real resistor can change value with temperature and can exceed its power rating.

§2.2 Kirchhoff’s Current Law

U02-L02 · Kirchhoff’s Current Law

Unit: 2 — Resistive Networks Core relation: Σi_k=0 Essential ideas: conservation at nodes, algebraic current signs, and branch accounting.

Learning objectives

After this lesson, explain kirchhoff’s current law and its circuit context, assign reference polarities and directions, derive or use Σi_k=0 with SI units, solve a numerical example, and evaluate its validity using conservation laws and a practical limiting case.

Physical and mathematical foundation

KCL is the lumped-circuit expression of charge conservation. The selected current arrow and voltage polarity give meaning to the signs in an equation; they do not force a physical quantity to flow in that direction. Nodes define equal-potential connection points in the lumped model. Branches define component connections, and a chosen ground provides a mathematical reference rather than a physical energy sink. Interpreting the equation Σi_k=0 requires knowing both the connected terminals and the applicable ideal-component assumptions.

Within resistive networks, distinguish a source-imposed quantity from a circuit response. A voltage source constrains one terminal difference, while a current source constrains a branch current. An element's constitutive relation describes its response but cannot replace Kirchhoff's laws. If a diagram changes, the electrical topology may change even when the drawn symbols and their numerical values remain the same.

Concept 1 — Conservation at nodes. Identify the branch or terminals to which this idea applies, state its units, and connect it with Σi_k=0. Explain what changes when the source or component parameter increases; predict the direction of the change before doing arithmetic. Consider whether reference directions, instrument loading, or tolerance could distort the interpretation.

Concept 2 — Algebraic current signs. Identify the branch or terminals to which this idea applies, state its units, and connect it with Σi_k=0. Explain what changes when the source or component parameter increases; predict the direction of the change before doing arithmetic. Consider whether reference directions, instrument loading, or tolerance could distort the interpretation.

Concept 3 — And branch accounting. Identify the branch or terminals to which this idea applies, state its units, and connect it with Σi_k=0. Explain what changes when the source or component parameter increases; predict the direction of the change before doing arithmetic. Consider whether reference directions, instrument loading, or tolerance could distort the interpretation.

Worked case and result

Case. Two currents of 2.1 A and 0.7 A enter a junction; a third leaves.

Result. The outgoing current must be 2.8 A for zero net node accumulation. First translate all prefixes into SI units and state the formula before substituting. Verify that the dimensions of the answer agree with the quantity being requested. Reverse the calculation, or test a meaningful limiting case, rather than trusting the displayed calculator result alone.

Interpretation. KCL is the lumped-circuit expression of charge conservation. A negative signed answer may only mean that a current or voltage points opposite to its reference. It does not indicate an impossible circuit. When multiple elements appear, check their node-current balance, the signed sum of drops around a loop, and the sum of absorbed and delivered powers.

A reliable solution method

  1. Draw the topology, identify nodes, and choose polarities and branch-current arrows; write down which source and element quantities are known.
  2. Combine the component relation Σi_k=0 with KCL, KVL, and state continuity where relevant; solve symbolically before substituting numbers.
  3. Convert units, calculate, and cross-check using a conservation equation or limiting case. Explain why the result is physically plausible.
  4. Identify the dominant idealization. If the total entering and leaving currents are unequal, first check reference directions. If any predicted value approaches a component rating, the analysis is only a starting point for a safety-qualified design review.

Exercises

1. Concept: Explain why conservation at nodes needs a clear reference direction, voltage polarity, or system boundary. Provide one counterexample.

2. Numerical: Reproduce the worked case, showing each unit conversion. Increase one supplied value by 20% and compute the resulting change.

3. Verification: Construct a KCL, KVL, energy, or state-continuity check appropriate to this circuit; explain which assumption the check tests.

4. Application: Specify a current-limited low-voltage demonstration and describe how meter input impedance would change the result.

5. Extension: Change one boundary condition and explain whether `Σi_k=0` remains valid and which previous shortcut fails.

Key limitation: If the total entering and leaving currents are unequal, first check reference directions.

§2.3 Kirchhoff’s Voltage Law

U02-L03 · Kirchhoff’s Voltage Law

Unit: 2 — Resistive Networks Core relation: Σv_k=0 Essential ideas: oriented loops, source rises, resistor drops, and energy conservation.

Learning objectives

After this lesson, explain kirchhoff’s voltage law and its circuit context, assign reference polarities and directions, derive or use Σv_k=0 with SI units, solve a numerical example, and evaluate its validity using conservation laws and a practical limiting case.

Physical and mathematical foundation

For standard lumped networks, the signed changes in electric potential around a closed loop add to zero. The selected current arrow and voltage polarity give meaning to the signs in an equation; they do not force a physical quantity to flow in that direction. Nodes define equal-potential connection points in the lumped model. Branches define component connections, and a chosen ground provides a mathematical reference rather than a physical energy sink. Interpreting the equation Σv_k=0 requires knowing both the connected terminals and the applicable ideal-component assumptions.

Within resistive networks, distinguish a source-imposed quantity from a circuit response. A voltage source constrains one terminal difference, while a current source constrains a branch current. An element's constitutive relation describes its response but cannot replace Kirchhoff's laws. If a diagram changes, the electrical topology may change even when the drawn symbols and their numerical values remain the same.

Concept 1 — Oriented loops. Identify the branch or terminals to which this idea applies, state its units, and connect it with Σv_k=0. Explain what changes when the source or component parameter increases; predict the direction of the change before doing arithmetic. Consider whether reference directions, instrument loading, or tolerance could distort the interpretation.

Concept 2 — Source rises. Identify the branch or terminals to which this idea applies, state its units, and connect it with Σv_k=0. Explain what changes when the source or component parameter increases; predict the direction of the change before doing arithmetic. Consider whether reference directions, instrument loading, or tolerance could distort the interpretation.

Concept 3 — Resistor drops. Identify the branch or terminals to which this idea applies, state its units, and connect it with Σv_k=0. Explain what changes when the source or component parameter increases; predict the direction of the change before doing arithmetic. Consider whether reference directions, instrument loading, or tolerance could distort the interpretation.

Worked case and result

Case. A 12 V supply drives a loop with drops of 4 V and 3 V and an unknown drop.

Result. The remaining drop is 5 V so that the oriented loop sum is zero. First translate all prefixes into SI units and state the formula before substituting. Verify that the dimensions of the answer agree with the quantity being requested. Reverse the calculation, or test a meaningful limiting case, rather than trusting the displayed calculator result alone.

Interpretation. For standard lumped networks, the signed changes in electric potential around a closed loop add to zero. A negative signed answer may only mean that a current or voltage points opposite to its reference. It does not indicate an impossible circuit. When multiple elements appear, check their node-current balance, the signed sum of drops around a loop, and the sum of absorbed and delivered powers.

A reliable solution method

  1. Draw the topology, identify nodes, and choose polarities and branch-current arrows; write down which source and element quantities are known.
  2. Combine the component relation Σv_k=0 with KCL, KVL, and state continuity where relevant; solve symbolically before substituting numbers.
  3. Convert units, calculate, and cross-check using a conservation equation or limiting case. Explain why the result is physically plausible.
  4. Identify the dominant idealization. For large changing magnetic flux linked with a physical loop, the simple conservative-potential formulation needs care. If any predicted value approaches a component rating, the analysis is only a starting point for a safety-qualified design review.

Exercises

1. Concept: Explain why oriented loops needs a clear reference direction, voltage polarity, or system boundary. Provide one counterexample.

2. Numerical: Reproduce the worked case, showing each unit conversion. Increase one supplied value by 20% and compute the resulting change.

3. Verification: Construct a KCL, KVL, energy, or state-continuity check appropriate to this circuit; explain which assumption the check tests.

4. Application: Specify a current-limited low-voltage demonstration and describe how meter input impedance would change the result.

5. Extension: Change one boundary condition and explain whether `Σv_k=0` remains valid and which previous shortcut fails.

Key limitation: For large changing magnetic flux linked with a physical loop, the simple conservative-potential formulation needs care.

§2.4 Series, Parallel, and Divider Relations

U02-L04 · Series, Parallel, and Divider Relations

Unit: 2 — Resistive Networks Core relation: R_s=ΣR; 1/R_p=Σ(1/R) Essential ideas: series current, parallel voltage, loading, and equivalent resistance.

Learning objectives

After this lesson, explain series, parallel, and divider relations and its circuit context, assign reference polarities and directions, derive or use R_s=ΣR; 1/R_p=Σ(1/R) with SI units, solve a numerical example, and evaluate its validity using conservation laws and a practical limiting case.

Physical and mathematical foundation

Series means the same current necessarily passes through elements; parallel means equal terminal voltages. The selected current arrow and voltage polarity give meaning to the signs in an equation; they do not force a physical quantity to flow in that direction. Nodes define equal-potential connection points in the lumped model. Branches define component connections, and a chosen ground provides a mathematical reference rather than a physical energy sink. Interpreting the equation R_s=ΣR; 1/R_p=Σ(1/R) requires knowing both the connected terminals and the applicable ideal-component assumptions.

Within resistive networks, distinguish a source-imposed quantity from a circuit response. A voltage source constrains one terminal difference, while a current source constrains a branch current. An element's constitutive relation describes its response but cannot replace Kirchhoff's laws. If a diagram changes, the electrical topology may change even when the drawn symbols and their numerical values remain the same.

Concept 1 — Series current. Identify the branch or terminals to which this idea applies, state its units, and connect it with R_s=ΣR; 1/R_p=Σ(1/R). Explain what changes when the source or component parameter increases; predict the direction of the change before doing arithmetic. Consider whether reference directions, instrument loading, or tolerance could distort the interpretation.

Concept 2 — Parallel voltage. Identify the branch or terminals to which this idea applies, state its units, and connect it with R_s=ΣR; 1/R_p=Σ(1/R). Explain what changes when the source or component parameter increases; predict the direction of the change before doing arithmetic. Consider whether reference directions, instrument loading, or tolerance could distort the interpretation.

Concept 3 — Loading. Identify the branch or terminals to which this idea applies, state its units, and connect it with R_s=ΣR; 1/R_p=Σ(1/R). Explain what changes when the source or component parameter increases; predict the direction of the change before doing arithmetic. Consider whether reference directions, instrument loading, or tolerance could distort the interpretation.

Worked case and result

Case. A 6 Ω and 3 Ω resistor are connected in parallel.

Result. Their equivalent resistance is 2 Ω, smaller than either branch resistor. First translate all prefixes into SI units and state the formula before substituting. Verify that the dimensions of the answer agree with the quantity being requested. Reverse the calculation, or test a meaningful limiting case, rather than trusting the displayed calculator result alone.

Interpretation. Series means the same current necessarily passes through elements; parallel means equal terminal voltages. A negative signed answer may only mean that a current or voltage points opposite to its reference. It does not indicate an impossible circuit. When multiple elements appear, check their node-current balance, the signed sum of drops around a loop, and the sum of absorbed and delivered powers.

A reliable solution method

  1. Draw the topology, identify nodes, and choose polarities and branch-current arrows; write down which source and element quantities are known.
  2. Combine the component relation R_s=ΣR; 1/R_p=Σ(1/R) with KCL, KVL, and state continuity where relevant; solve symbolically before substituting numbers.
  3. Convert units, calculate, and cross-check using a conservation equation or limiting case. Explain why the result is physically plausible.
  4. Identify the dominant idealization. A drawn sequence of components does not establish series connection if an intermediate node branches. If any predicted value approaches a component rating, the analysis is only a starting point for a safety-qualified design review.

Exercises

1. Concept: Explain why series current needs a clear reference direction, voltage polarity, or system boundary. Provide one counterexample.

2. Numerical: Reproduce the worked case, showing each unit conversion. Increase one supplied value by 20% and compute the resulting change.

3. Verification: Construct a KCL, KVL, energy, or state-continuity check appropriate to this circuit; explain which assumption the check tests.

4. Application: Specify a current-limited low-voltage demonstration and describe how meter input impedance would change the result.

5. Extension: Change one boundary condition and explain whether `R_s=ΣR; 1/R_p=Σ(1/R)` remains valid and which previous shortcut fails.

Key limitation: A drawn sequence of components does not establish series connection if an intermediate node branches.

§2.5 Source Transformation and Loading

U02-L05 · Source Transformation and Loading

Unit: 2 — Resistive Networks Core relation: I_N=V_T/R_T Essential ideas: ideal sources, resistance equivalence, and external terminal behavior.

Learning objectives

After this lesson, explain source transformation and loading and its circuit context, assign reference polarities and directions, derive or use I_N=V_T/R_T with SI units, solve a numerical example, and evaluate its validity using conservation laws and a practical limiting case.

Physical and mathematical foundation

Source transformation preserves external two-terminal behavior, not internal branch values. The selected current arrow and voltage polarity give meaning to the signs in an equation; they do not force a physical quantity to flow in that direction. Nodes define equal-potential connection points in the lumped model. Branches define component connections, and a chosen ground provides a mathematical reference rather than a physical energy sink. Interpreting the equation I_N=V_T/R_T requires knowing both the connected terminals and the applicable ideal-component assumptions.

Within resistive networks, distinguish a source-imposed quantity from a circuit response. A voltage source constrains one terminal difference, while a current source constrains a branch current. An element's constitutive relation describes its response but cannot replace Kirchhoff's laws. If a diagram changes, the electrical topology may change even when the drawn symbols and their numerical values remain the same.

Concept 1 — Ideal sources. Identify the branch or terminals to which this idea applies, state its units, and connect it with I_N=V_T/R_T. Explain what changes when the source or component parameter increases; predict the direction of the change before doing arithmetic. Consider whether reference directions, instrument loading, or tolerance could distort the interpretation.

Concept 2 — Resistance equivalence. Identify the branch or terminals to which this idea applies, state its units, and connect it with I_N=V_T/R_T. Explain what changes when the source or component parameter increases; predict the direction of the change before doing arithmetic. Consider whether reference directions, instrument loading, or tolerance could distort the interpretation.

Concept 3 — And external terminal behavior. Identify the branch or terminals to which this idea applies, state its units, and connect it with I_N=V_T/R_T. Explain what changes when the source or component parameter increases; predict the direction of the change before doing arithmetic. Consider whether reference directions, instrument loading, or tolerance could distort the interpretation.

Worked case and result

Case. A 12 V source with 6 Ω series resistance is transformed into a Norton source.

Result. The Norton current is 2 A in parallel with 6 Ω. First translate all prefixes into SI units and state the formula before substituting. Verify that the dimensions of the answer agree with the quantity being requested. Reverse the calculation, or test a meaningful limiting case, rather than trusting the displayed calculator result alone.

Interpretation. Source transformation preserves external two-terminal behavior, not internal branch values. A negative signed answer may only mean that a current or voltage points opposite to its reference. It does not indicate an impossible circuit. When multiple elements appear, check their node-current balance, the signed sum of drops around a loop, and the sum of absorbed and delivered powers.

A reliable solution method

  1. Draw the topology, identify nodes, and choose polarities and branch-current arrows; write down which source and element quantities are known.
  2. Combine the component relation I_N=V_T/R_T with KCL, KVL, and state continuity where relevant; solve symbolically before substituting numbers.
  3. Convert units, calculate, and cross-check using a conservation equation or limiting case. Explain why the result is physically plausible.
  4. Identify the dominant idealization. Avoid source transformations involving a zero resistance without separately analyzing the limiting case. If any predicted value approaches a component rating, the analysis is only a starting point for a safety-qualified design review.

Exercises

1. Concept: Explain why ideal sources needs a clear reference direction, voltage polarity, or system boundary. Provide one counterexample.

2. Numerical: Reproduce the worked case, showing each unit conversion. Increase one supplied value by 20% and compute the resulting change.

3. Verification: Construct a KCL, KVL, energy, or state-continuity check appropriate to this circuit; explain which assumption the check tests.

4. Application: Specify a current-limited low-voltage demonstration and describe how meter input impedance would change the result.

5. Extension: Change one boundary condition and explain whether `I_N=V_T/R_T` remains valid and which previous shortcut fails.

Key limitation: Avoid source transformations involving a zero resistance without separately analyzing the limiting case.

THREE WORKED QUESTIONS

Step-by-Step Circuit Analysis I Solutions

Three original questions connect calculations, definitions and interpretation. Open each solution to follow the reasoning.

Solved Problem Example 2.1: Case. A 220 Ω resistor is supplied by a 11 V source.

Case. A 220 Ω resistor is supplied by a 11 V source.

Result. The current is 0.050 A, and the resistor dissipates 0.55 W. First translate all prefixes into SI units and state the formula before substituting. Verify that the dimensions of the answer agree with the quantity being requested. Reverse the calculation, or test a meaningful limiting case, rather than trusting the displayed calculator result alone.

Interpretation. Ohm’s law describes an ideal linear resistor at a specified operating condition. A negative signed answer may only mean that a current or voltage points opposite to its reference. It does not indicate an impossible circuit. When multiple elements appear, check their node-current balance, the signed sum of drops around a loop, and the sum of absorbed and delivered powers.

Case. A 220 Ω resistor is supplied by a 11 V source.

Result. The current is 0.050 A, and the resistor dissipates 0.55 W. First translate all prefixes into SI units and state the formula before substituting. Verify that the dimensions of the answer agree with the quantity being requested. Reverse the calculation, or test a meaningful limiting case, rather than trusting the displayed calculator result alone.

Interpretation. Ohm’s law describes an ideal linear resistor at a specified operating condition. A negative signed answer may only mean that a current or voltage points opposite to its reference. It does not indicate an impossible circuit. When multiple elements appear, check their node-current balance, the signed sum of drops around a loop, and the sum of absorbed and delivered powers.

Solved Problem Example 2.2: Case. Two currents of 2.1 A and 0.7 A enter a junction; a third leaves.

Case. Two currents of 2.1 A and 0.7 A enter a junction; a third leaves.

Result. The outgoing current must be 2.8 A for zero net node accumulation. First translate all prefixes into SI units and state the formula before substituting. Verify that the dimensions of the answer agree with the quantity being requested. Reverse the calculation, or test a meaningful limiting case, rather than trusting the displayed calculator result alone.

Interpretation. KCL is the lumped-circuit expression of charge conservation. A negative signed answer may only mean that a current or voltage points opposite to its reference. It does not indicate an impossible circuit. When multiple elements appear, check their node-current balance, the signed sum of drops around a loop, and the sum of absorbed and delivered powers.

Case. Two currents of 2.1 A and 0.7 A enter a junction; a third leaves.

Result. The outgoing current must be 2.8 A for zero net node accumulation. First translate all prefixes into SI units and state the formula before substituting. Verify that the dimensions of the answer agree with the quantity being requested. Reverse the calculation, or test a meaningful limiting case, rather than trusting the displayed calculator result alone.

Interpretation. KCL is the lumped-circuit expression of charge conservation. A negative signed answer may only mean that a current or voltage points opposite to its reference. It does not indicate an impossible circuit. When multiple elements appear, check their node-current balance, the signed sum of drops around a loop, and the sum of absorbed and delivered powers.

Solved Problem Example 2.3: Case. A 12 V supply drives a loop with drops of 4 V and 3 V and an unknown drop.

Case. A 12 V supply drives a loop with drops of 4 V and 3 V and an unknown drop.

Result. The remaining drop is 5 V so that the oriented loop sum is zero. First translate all prefixes into SI units and state the formula before substituting. Verify that the dimensions of the answer agree with the quantity being requested. Reverse the calculation, or test a meaningful limiting case, rather than trusting the displayed calculator result alone.

Interpretation. For standard lumped networks, the signed changes in electric potential around a closed loop add to zero. A negative signed answer may only mean that a current or voltage points opposite to its reference. It does not indicate an impossible circuit. When multiple elements appear, check their node-current balance, the signed sum of drops around a loop, and the sum of absorbed and delivered powers.

Case. A 12 V supply drives a loop with drops of 4 V and 3 V and an unknown drop.

Result. The remaining drop is 5 V so that the oriented loop sum is zero. First translate all prefixes into SI units and state the formula before substituting. Verify that the dimensions of the answer agree with the quantity being requested. Reverse the calculation, or test a meaningful limiting case, rather than trusting the displayed calculator result alone.

Interpretation. For standard lumped networks, the signed changes in electric potential around a closed loop add to zero. A negative signed answer may only mean that a current or voltage points opposite to its reference. It does not indicate an impossible circuit. When multiple elements appear, check their node-current balance, the signed sum of drops around a loop, and the sum of absorbed and delivered powers.

Solved Problem Example 2.4: Case. A 6 Ω and 3 Ω resistor are connected in parallel.

Case. A 6 Ω and 3 Ω resistor are connected in parallel.

Result. Their equivalent resistance is 2 Ω, smaller than either branch resistor. First translate all prefixes into SI units and state the formula before substituting. Verify that the dimensions of the answer agree with the quantity being requested. Reverse the calculation, or test a meaningful limiting case, rather than trusting the displayed calculator result alone.

Interpretation. Series means the same current necessarily passes through elements; parallel means equal terminal voltages. A negative signed answer may only mean that a current or voltage points opposite to its reference. It does not indicate an impossible circuit. When multiple elements appear, check their node-current balance, the signed sum of drops around a loop, and the sum of absorbed and delivered powers.

Case. A 6 Ω and 3 Ω resistor are connected in parallel.

Result. Their equivalent resistance is 2 Ω, smaller than either branch resistor. First translate all prefixes into SI units and state the formula before substituting. Verify that the dimensions of the answer agree with the quantity being requested. Reverse the calculation, or test a meaningful limiting case, rather than trusting the displayed calculator result alone.

Interpretation. Series means the same current necessarily passes through elements; parallel means equal terminal voltages. A negative signed answer may only mean that a current or voltage points opposite to its reference. It does not indicate an impossible circuit. When multiple elements appear, check their node-current balance, the signed sum of drops around a loop, and the sum of absorbed and delivered powers.

Solved Problem Example 2.5: Case. A 12 V source with 6 Ω series resistance is transformed into a Norton source.

Case. A 12 V source with 6 Ω series resistance is transformed into a Norton source.

Result. The Norton current is 2 A in parallel with 6 Ω. First translate all prefixes into SI units and state the formula before substituting. Verify that the dimensions of the answer agree with the quantity being requested. Reverse the calculation, or test a meaningful limiting case, rather than trusting the displayed calculator result alone.

Interpretation. Source transformation preserves external two-terminal behavior, not internal branch values. A negative signed answer may only mean that a current or voltage points opposite to its reference. It does not indicate an impossible circuit. When multiple elements appear, check their node-current balance, the signed sum of drops around a loop, and the sum of absorbed and delivered powers.

Case. A 12 V source with 6 Ω series resistance is transformed into a Norton source.

Result. The Norton current is 2 A in parallel with 6 Ω. First translate all prefixes into SI units and state the formula before substituting. Verify that the dimensions of the answer agree with the quantity being requested. Reverse the calculation, or test a meaningful limiting case, rather than trusting the displayed calculator result alone.

Interpretation. Source transformation preserves external two-terminal behavior, not internal branch values. A negative signed answer may only mean that a current or voltage points opposite to its reference. It does not indicate an impossible circuit. When multiple elements appear, check their node-current balance, the signed sum of drops around a loop, and the sum of absorbed and delivered powers.