Circuit Analysis & Network Theorems
Comprehensive network analysis methods: Thevenin's theorem and equivalent voltage generators, Norton's theorem and dual current generators, the Superposition theorem, Maximum Power Transfer theorem with impedance matching proofs, and second-order RLC transient dynamics (underdamped, critically damped, overdamped).
§8.1 Thevenin's Theorem and Equivalent Voltage Generators
1. Statement of Thevenin's Theorem
Any linear, bilateral, two-terminal electrical network containing independent voltage sources, current sources, and linear resistors can be replaced, across its two open terminals $A$ and $B$, by an equivalent circuit consisting of a single ideal voltage source $V_{\text{th}}$ in series with a single internal resistance $R_{\text{th}}$.
2. Determination of Thevenin Parameters
- Thevenin Equivalent Voltage ($V_{\text{th}}$): The open-circuit potential difference appearing across terminals $A$ and $B$ when the load resistor $R_L$ is completely disconnected: $$V_{\text{th}} = V_{AB,\text{open}}$$
- Thevenin Equivalent Resistance ($R_{\text{th}}$):
The equivalent resistance measured between terminals $A$ and $B$ with the load removed and all independent energy sources **deactivated**:
- Independent voltage sources are replaced by **short circuits** (zero internal resistance, $V = 0$).
- Independent current sources are replaced by **open circuits** (infinite internal resistance, $I = 0$).
3. Calculation of Load Current and Voltage
When an arbitrary load resistance $R_L$ is connected across terminals $A$ and $B$, the load current $I_L$ and terminal voltage $V_L$ are given instantly by Ohm's law: $$I_L = \frac{V_{\text{th}}}{R_{\text{th}} + R_L}, \quad V_L = I_L R_L = V_{\text{th}} \left( \frac{R_L}{R_{\text{th}} + R_L} \right)$$ This eliminates the need to resolve the entire multi-loop system every time the load resistor changes.§8.2 Norton's Theorem and Source Transformations
1. Statement of Norton's Theorem
Any linear, bilateral, two-terminal electrical network can be replaced across its terminals by an equivalent circuit consisting of a single ideal current source $I_N$ connected in parallel with a single internal resistance $R_N$.
2. Determination of Norton Parameters
- Norton Equivalent Current ($I_N$): The short-circuit current that flows between terminals $A$ and $B$ when a zero-resistance conductor connects them: $$I_N = I_{AB,\text{short}}$$
- Norton Resistance ($R_N$): The equivalent resistance between terminals $A$ and $B$ with all independent sources deactivated. Fundamental Identity: $$R_N = R_{\text{th}}$$
3. Thevenin-Norton Source Transformation Equivalence
Thevenin and Norton circuits are dual mathematical representations of the exact same physical reality: $$V_{\text{th}} = I_N R_{\text{th}}, \quad I_N = \frac{V_{\text{th}}}{R_{\text{th}}}$$ For load resistor $R_L$: By the current divider rule across parallel resistors $R_N$ and $R_L$: $$I_L = I_N \left( \frac{R_N}{R_N + R_L} \right) = \left( \frac{V_{\text{th}}}{R_{\text{th}}} \right) \left( \frac{R_{\text{th}}}{R_{\text{th}} + R_L} \right) = \frac{V_{\text{th}}}{R_{\text{th}} + R_L}$$ Both theorems yield identical load current and voltage.§8.3 The Superposition Theorem and Maximum Power Transfer
1. The Superposition Theorem
In any linear, bilateral electrical network energized by multiple independent sources, the net current or voltage in any branch equals the algebraic sum of the currents or voltages produced by each independent source acting alone, with all other independent sources turned off.
- Turn off independent voltage sources $\to$ Replace with short circuits.
- Turn off independent current sources $\to$ Replace with open circuits.
2. The Maximum Power Transfer Theorem
Consider a linear source characterized by Thevenin equivalent parameters $V_{\text{th}}$ and $R_{\text{th}}$ driving an adjustable load resistance $R_L$. The power delivered to the load resistor is: $$P_L = I_L^2 R_L = \left( \frac{V_{\text{th}}}{R_{\text{th}} + R_L} \right)^2 R_L = \frac{V_{\text{th}}^2 R_L}{(R_{\text{th}} + R_L)^2}$$ To maximize power with respect to $R_L$, differentiate and set to zero: $$\frac{dP_L}{dR_L} = V_{\text{th}}^2 \left[ \frac{(R_{\text{th}} + R_L)^2 - 2 R_L (R_{\text{th}} + R_L)}{(R_{\text{th}} + R_L)^4} \right] = 0$$ $$(R_{\text{th}} + R_L) - 2 R_L = 0 \implies R_{\text{th}} - R_L = 0$$ $$R_L = R_{\text{th}}$$ Theorem: A resistive load absorbs maximum power from a linear network when its resistance equals the Thevenin resistance of the network (**impedance matching**). The maximum power delivered is: $$P_{L,\max} = \frac{V_{\text{th}}^2 R_{\text{th}}}{(2 R_{\text{th}})^2} = \frac{V_{\text{th}}^2}{4 R_{\text{th}}}$$ Efficiency at Maximum Power: $$\eta = \frac{P_{\text{load}}}{P_{\text{total}}} = \frac{I_L^2 R_L}{I_L^2 (R_{\text{th}} + R_L)} = \frac{R_L}{2 R_L} = 50.0\%$$ While essential in communications and weak-signal electronics to extract maximum signal power, maximum power transfer is deliberately avoided in electrical power grid distribution (where engineers aim for $R_L \gg R_{\text{th}}$ to achieve $> 98\%$ transmission efficiency).§8.4 Transient Currents in Second-Order RLC Circuits
1. The Governing Differential Equation
Applying Kirchhoff's voltage law to a series RLC loop discharging from initial charge $Q_0$: $$L \frac{di}{dt} + R i + \frac{q}{C} = 0$$ Since $i = \frac{dq}{dt}$: $$L \frac{d^2 q}{dt^2} + R \frac{dq}{dt} + \frac{1}{C} q = 0 \implies \frac{d^2 q}{dt^2} + 2\gamma \frac{dq}{dt} + \omega_0^2 q = 0$$ where $\gamma = \frac{R}{2L}$ is the damping factor (s⁻¹) and $\omega_0 = \frac{1}{\sqrt{LC}}$ is the natural undamped frequency. Auxiliary equation: $$\lambda^2 + 2\gamma \lambda + \omega_0^2 = 0 \implies \lambda = -\gamma \pm \sqrt{\gamma^2 - \omega_0^2}$$2. The Three Transient Regimes
- Underdamped Oscillatory Regime ($R < 2\sqrt{L/C} \iff \gamma < \omega_0$): The roots are complex conjugates $\lambda = -\gamma \pm i \omega_d$, where $\omega_d = \sqrt{\omega_0^2 - \gamma^2}$. $$q(t) = Q_0 e^{-\gamma t} \cos(\omega_d t + \phi)$$ The charge oscillates back and forth between capacitor plates while dying out exponentially.
- Critically Damped Regime ($R = 2\sqrt{L/C} \iff \gamma = \omega_0$): $R_{\text{crit}} = 2\sqrt{\frac{L}{C}}$. $$q(t) = (C_1 + C_2 t) e^{-\gamma t}$$ The capacitor discharges in the shortest possible time without ringing or overshoot.
- Overdamped Aperiodic Regime ($R > 2\sqrt{L/C} \iff \gamma > \omega_0$): Two real negative roots. Non-oscillatory sluggish decay: $$q(t) = C_1 e^{-(\gamma - \sqrt{\gamma^2-\omega_0^2})t} + C_2 e^{-(\gamma + \sqrt{\gamma^2-\omega_0^2})t}$$
Rigorous Analytical & Numerical Solved Problems
Comprehensive step-by-step mathematical proofs, dimensional evaluations, and calculations matching B.Sc. Honors university examinations.
A linear DC circuit consists of an independent voltage source $\mathcal{E} = 36.0\text{ V}$ connected across a resistive T-network: resistor $R_1 = 12.0\ \Omega$ in series with the source, a shunt resistor $R_2 = 24.0\ \Omega$ across the line, and an output resistor $R_3 = 8.00\ \Omega$ leading to output terminals $A$ and $B$. A variable load resistor $R_L$ is connected between $A$ and $B$.\n(a) Determine the Thevenin equivalent voltage $V_{\text{th}}$ and Thevenin resistance $R_{\text{th}}$,\n(b) Find the Norton equivalent current $I_N$, and\n(c) Calculate the load current $I_L$ and power dissipated in $R_L$ when $R_L = 16.0\ \Omega$.
The entire network simplifies to a 24.0 V voltage source in series with 16.0 ohms.
The Norton equivalent is a 1.50 A current source in parallel with 16.0 ohms.
Because $R_L = R_{\text{th}} = 16\ \Omega$, this represents the exact maximum power transfer condition ($P_{\max} = 9.00$ W).
A linear network contains an independent DC voltage source $\mathcal{E}_1 = 28.0\text{ V}$, an independent DC current source $I_s = 3.00\text{ A}$, and three resistors: $R_1 = 4.00\ \Omega$, $R_2 = 6.00\ \Omega$, and $R_3 = 12.0\ \Omega$. The voltage source is in series with $R_1$. The current source is in parallel with $R_3$. Resistor $R_2$ connects between the common nodes.\n(a) Use the Superposition Theorem to determine the current $I_2$ through resistor $R_2$ by activating each source individually, and\n(b) Verify the result using nodal analysis.
The voltage source acting alone drives 1.27 A through resistor $R_2$.
The current source drives 1.64 A in the opposite direction through $R_2$.
Superposing the two states yields a net current of 364 mA flowing upward against the voltage source.
A series RLC circuit has an inductor $L = 50.0\text{ mH}$ and a capacitor $C = 2.00\ \mu\text{F}$.\n(a) Calculate the critical damping resistance $R_{\text{crit}}$,\n(b) If the actual resistance in the circuit is $R = 60.0\ \Omega$, determine whether the transient discharge is underdamped, overdamped, or critically damped, and\n(c) Calculate the damped oscillation frequency $\omega_d$ and the logarithmic decrement $\delta$.
Critical damping requires a resistance of 316.2 ohms.
Because $R < R_{\text{crit}}$, the circuit oscillates with decaying amplitude.
The circuit rings at 494 Hz with a logarithmic decrement $\delta = 1.21$.