Chemistry / Organic Chemistry Molecular Architecture, Hydrocarbons, Haloalkanes & Heterocycles 100% Free Open Access
Chapter 2 • Theory & Derivations

Unit 2: Saturated Hydrocarbons: Alkanes, Cycloalkanes, Strain Theory & Conformational Analysis

In-depth analysis of alkanes and cycloalkanes, free-radical halogenation energetics, Baeyer strain theory, conformational thermodynamics, cyclohexane chair-flips, and Wurtz synthesis.

§§2.1 Structure, Homology & IUPAC Systematic Nomenclature

Alkanes (aliphatic saturated hydrocarbons) possess the general molecular formula $\text{C}_n\text{H}_{2n+2}$ for acyclic systems and $\text{C}_n\text{H}_{2n}$ for monocyclic cycloalkanes. Every carbon atom is $sp^3$ hybridized, forming four localized single $\sigma$ bonds directed toward the vertices of a tetrahedron.

Homologous Series & Structural Isomerism

A homologous series is a family of compounds differing by successive methylene ($\text{CH}_2$) increments with uniform chemical reactivities and regular physical property gradations. As carbon number $n$ increases, the number of constitutional (structural) isomers—compounds possessing identical molecular formulas but differing atom-to-atom bonding connectivities—diverges with colossal combinatorial speed:

| Carbon Count ($n$) | Molecular Formula | Number of Constitutional Isomers | | :---: | :---: | :---: | | 1 | $\text{CH}_4$ | 1 | | 2 | $\text{C}_2\text{H}_6$ | 1 | | 3 | $\text{C}_3\text{H}_8$ | 1 | | 4 | $\text{C}_4\text{H}_{10}$ | 2 | | 5 | $\text{C}_5\text{H}_{12}$ | 3 | | 6 | $\text{C}_6\text{H}_{14}$ | 5 | | 7 | $\text{C}_7\text{H}_{16}$ | 9 | | 8 | $\text{C}_8\text{H}_{18}$ | 18 | | 10 | $\text{C}_{10}\text{H}_{22}$ | 75 | | 20 | $\text{C}_{20}\text{H}_{42}$ | 366,319 | | 30 | $\text{C}_{30}\text{H}_{62}$ | 4,111,846,763 |

IUPAC Systematic Nomenclature Rules (Blue Book Standards)

To provide an unambiguous, universally unique name for every organic molecule, the International Union of Pure and Applied Chemistry (IUPAC) established rigorous hierarchical rules:

1. Identify the Principal Chain: Select the longest continuous chain of carbon atoms. If two chains have equal length, choose the chain with the greater number of substituents.

2. Numbering the Principal Chain: Number the carbon atoms sequentially from the end that gives the lowest locant set at the first point of difference (e.g., $2,4,5$ is preferred over $2,5,6$).

3. Assemble Substituents Alphabetically: Prefixes such as di-, tri-, tetra- and conformational descriptors (sec-, tert-) are ignored in alphabetization, except 'iso' and 'neo' which form part of the alkyl radical name.

4. Cycloalkanes: Prefixed by 'cyclo-'. If an acyclic substituent contains more carbons than the ring, the ring is treated as a cycloalkyl substituent.

von Baeyer Systematic Nomenclature for Polycyclic & Spiro Hydrocarbons

Complex bicyclic, polycyclic, and spiroalkanes cannot be named using simple acyclic alkane rules and must follow the von Baeyer IUPAC nomenclature rules:

1. Bicyclic Hydrocarbons ($\text{bicyclo}[a.b.c]\text{alkane}$):

  • Identify the two bridgehead carbons (atoms sharing three ring paths).
  • Count the number of carbons in each of the three connecting paths between the bridgeheads, listing them in descending order: $[a.b.c]$ where $a \ge b \ge c$.
  • Number the system starting at one bridgehead, proceeding along the longest path ($a$) to the second bridgehead, continuing along the second longest path ($b$) back to the first bridgehead, and finishing along the shortest bridge ($c$).
  • Example: Bicyclo[2.2.1]heptane (Norbornane), Bicyclo[4.4.0]decane (Decalin), Bicyclo[2.2.2]octane.

2. Spiro Hydrocarbons ($\text{spiro}[a.b]\text{alkane}$):

  • Spiro compounds possess a single quaternary carbon atom shared between two rings.
  • Numbering begins in the smaller ring adjacent to the spiro carbon, circles around the smaller ring, crosses through the spiro carbon, and circles around the larger ring.
  • Bracketed numbers reflect ring sizes in ascending order: $[a.b]$ where $a \le b$.
  • Example: Spiro[4.5]decane.

§§2.2 Physical Properties, Combustion & The Octane Number

Physical Properties: Intermolecular Forces & Branching

Alkanes are strictly non-polar molecules ($\mu = 0$). Intermolecular cohesion is governed exclusively by London Dispersion Forces (instantaneous induced-dipole interactions). The attractive dispersion energy between two molecules separated by distance $r$ is described by the London formula:

$$E_{\text{disp}} = -\frac{3}{4} \frac{\alpha^2 I}{(4\pi\varepsilon_0)^2 r^6} \tag{2.1}$$

where $\alpha$ is molecular electronic polarizability and $I$ is first ionization energy.

  • Molecular Weight Effect: As carbon chain length increases, total polarizability $\alpha$ increases, leading to a monotonic elevation in boiling point (approx. $+20\text{ to } 30^\circ\text{C}$ per $\text{CH}_2$ unit).
  • Branching Effect: For constitutional isomers with identical molecular formula, branching decreases boiling point. A branched alkane adopts a more compact, spherical geometry with smaller surface area, decreasing intermolecular contact area:
  • $n$-Pentane: $\text{b.p.} = 36.1^\circ\text{C}$
  • Isopentane (2-methylbutane): $\text{b.p.} = 27.8^\circ\text{C}$
  • Neopentane (2,2-dimethylpropane): $\text{b.p.} = 9.5^\circ\text{C}$ (Gas at room temperature!)

Combustion Thermodynamics & Octane Ratings

Alkanes react exothermically with oxygen in combustion reactions:

$$\text{C}_n\text{H}_{2n+2} + \left(\frac{3n+1}{2}\right) \text{O}_2 \longrightarrow n\,\text{CO}_2 + (n+1)\,\text{H}_2\text{O}, \quad \Delta H_{\text{comb}} < 0 \tag{2.2}$$

In internal combustion engines, rapid compression of the fuel-air mixture can trigger premature auto-ignition before the spark plug fires, producing a shockwave known as engine knock.

The Octane Rating Scale

The Research Octane Number (RON) measures resistance to auto-ignition and engine knock:

  • 0 Octane Standard: $n$-Heptane (straight-chain, highly prone to radical auto-ignition via low-barrier peroxide formation, knocks violently).
  • 100 Octane Standard: 2,2,4-Trimethylpentane ('isooctane', highly branched, forms stable tertiary radicals that resist uncontrolled chain branching).

Highly branched alkanes, cycloalkanes, and aromatic hydrocarbons possess vastly higher octane numbers because their radical intermediates are sterically hindered or stabilized, terminating pre-ignition knock cycles.

§§2.3 Free-Radical Halogenation: Energetics, Kinetics & Hammond's Postulate

Alkanes are notoriously unreactive toward common acids, bases, and nucleophiles at room temperature (historical name paraffins, from Latin parum affinis = 'little affinity'). However, under photochemical ($\text{h}\nu$) or thermal ($\Delta$) excitation, alkanes undergo homolytic free-radical halogenation:

$$\text{R}-\text{H} + \text{X}_2 \xrightarrow{h\nu \text{ or } \Delta} \text{R}-\text{X} + \text{H}-\text{X} \tag{2.3}$$

The Three-Stage Radical Chain Mechanism

1. Initiation: Homolytic fission of the weak halogen-halogen bond by absorption of an ultraviolet photon:

$$\text{X}_2 \xrightarrow{h\nu} 2\,\text{X}^\bullet, \quad \Delta H_1 = +\text{BDE}(\text{X}-\text{X}) \tag{2.4}$$

2. Propagation (Chain Carrying):

  • Propagation Step 1 (Hydrogen Abstraction):
$$\text{R}-\text{H} + \text{X}^\bullet \longrightarrow \text{R}^\bullet + \text{H}-\text{X}, \quad \Delta H_{p1} = \text{BDE}(\text{R}-\text{H}) - \text{BDE}(\text{H}-\text{X}) \tag{2.5}$$
  • Propagation Step 2 (Halogen Atom Transfer):
$$\text{R}^\bullet + \text{X}_2 \longrightarrow \text{R}-\text{X} + \text{X}^\bullet, \quad \Delta H_{p2} = \text{BDE}(\text{X}-\text{X}) - \text{BDE}(\text{R}-\text{X}) \tag{2.6}$$

Notice that the halogen radical $\text{X}^\bullet$ regenerated in Step 2 re-enters Step 1, driving a catalytic chain reaction with turnover numbers exceeding $10^4$.

3. Termination (Radical Recombination):

$$\text{R}^\bullet + \text{X}^\bullet \longrightarrow \text{R}-\text{X}, \quad 2\,\text{R}^\bullet \longrightarrow \text{R}-\text{R}, \quad 2\,\text{X}^\bullet \longrightarrow \text{X}_2 \tag{2.7}$$

Thermodynamic Enthalpy Profile & Halogen Reactivity Hierarchy

| Halogen ($\text{X}$) | $\Delta H_{p1}$ (kJ/mol) | $\Delta H_{p2}$ (kJ/mol) | $\Delta H_{\text{net}}$ (kJ/mol) | Practical Outcome | | :---: | :---: | :---: | :---: | :---: | | Fluorine ($\text{F}$) | $-130$ | $-300$ | $-430$ | Explosive, uncontrollable polyfluorination and C-C cleavage | | Chlorine ($\text{Cl}$) | $-17$ | $-88$ | $-105$ | Exothermic, fast, low regioselectivity (unselective) | | Bromine ($\text{Br}$) | $+46$ | $-84$ | $-38$ | Endothermic abstraction, slow, exquisite regioselectivity | | Iodine ($\text{I}$) | $+140$ | $-70$ | $+70$ | Strongly endothermic, unfeasible under standard conditions |

Regioselectivity & Hammond's Postulate

The intrinsic reactivity ratios for hydrogen abstraction per C-H bond at $298\text{ K}$ are:

  • Chlorination: $1^\circ : 2^\circ : 3^\circ = 1.0 : 3.8 : 5.0$
  • Bromination: $1^\circ : 2^\circ : 3^\circ = 1 : 82 : 1600$

Why is bromination 300 times more selective for tertiary C-H bonds than chlorination? George S. Hammond resolved this in 1955 via Hammond's Postulate:

If two states occurring consecutively along a reaction coordinate have nearly the same energy content, their interconversion will involve only a small reorganization of molecular structures.

1. Chlorination (Exothermic $\Delta H_{p1} < 0$):

The transition state is reached early along the reaction coordinate. The $\text{C}-\text{H}$ bond is barely stretched ($\sim 10\%$), and little radical character has developed on the carbon atom. The transition state resembles the starting alkane reactants, meaning differences in carboradical stability ($3^\circ > 2^\circ > 1^\circ$) have minimal effect on the activation barrier $\Delta G^\ddagger$.

2. Bromination (Endothermic $\Delta H_{p1} > 0$):

The transition state is reached late along the reaction coordinate. The $\text{C}-\text{H}$ bond is extensively broken ($\sim 70\%$), and substantial radical character has developed on carbon. The transition state strongly resembles the product alkyl radical intermediate, meaning the full thermodynamic stabilization of tertiary radicals ($3^\circ > 2^\circ \gg 1^\circ$ due to hyperconjugation) dramatically lowers the activation energy $\Delta G^\ddagger$ for tertiary abstraction!

Bell-Evans-Polanyi Principle & Transition-State Coordinate Geometry

The relationship between activation energy ($E_a$) and reaction enthalpy ($\Delta H^\circ$) in free-radical hydrogen abstractions is formalized by the Bell-Evans-Polanyi (BEP) Principle:

$$E_a = E_0 + \alpha \, \Delta H^\circ \tag{2.7a}$$

where $E_0$ is the intrinsic activation barrier for an ergoneutral reaction, and $\alpha$ ($0 < \alpha < 1$) is the transfer coefficient.

  • For Exothermic Chlorination ($\Delta H^\circ < 0$):

The transition state occurs very early on the reaction coordinate ($\alpha \approx 0.15$). The $\text{C}-\text{H}$ bond is barely perturbed:

$$d_{\text{C}-\text{H}}^\ddagger \approx 1.12\text{ Å} \quad (\text{equilibrium } 1.09\text{ Å})$$

Because the $\text{C}-\text{H}$ bond is not significantly broken, differences in radical stabilization energies among primary, secondary, and tertiary sites have negligible leverage over $E_a$.

  • For Endothermic Bromination ($\Delta H^\circ > 0$):

The transition state occurs late ($\alpha \approx 0.85$). The $\text{C}-\text{H}$ bond is extensively stretched:

$$d_{\text{C}-\text{H}}^\ddagger \approx 1.45\text{ Å} \quad (\sim 33\% \text{ elongated})$$

The forming $\text{H}-\text{Br}$ bond is nearly complete ($d_{\text{H}-\text{Br}}^\ddagger \approx 1.48\text{ Å}$). Almost a full unit of radical character has developed on the carbon atom, allowing tertiary radical hyperconjugation to maximally lower the late transition state energy.

Derivation of Free-Radical Halogenation Steady-State Rate Laws

The gas-phase photochemical chlorination of an alkane proceeds via the classical Rice-Herzfeld free-radical chain mechanism:

$$\text{Cl}_2 + h\nu \xrightarrow{k_1} 2\,\text{Cl}^\bullet \quad (\text{Initiation}) \tag{2.5a}$$
$$\text{Cl}^\bullet + \text{R}-\text{H} \xrightarrow{k_2} \text{R}^\bullet + \text{HCl} \quad (\text{Propagation 1}) \tag{2.5b}$$
$$\text{R}^\bullet + \text{Cl}_2 \xrightarrow{k_3} \text{R}-\text{Cl} + \text{Cl}^\bullet \quad (\text{Propagation 2}) \tag{2.5c}$$
$$2\,\text{R}^\bullet \xrightarrow{k_4} \text{R}-\text{R} \quad (\text{Termination 1}) \tag{2.5d}$$
$$\text{R}^\bullet + \text{Cl}^\bullet \xrightarrow{k_5} \text{R}-\text{Cl} \quad (\text{Termination 2}) \tag{2.5e}$$
$$2\,\text{Cl}^\bullet \xrightarrow{k_6} \text{Cl}_2 \quad (\text{Termination 3}) \tag{2.5f}$$
Applying the Pseudo-Steady-State Approximation (PSSA):

Under long chain-length conditions (quantum yield $\Phi \gg 1$), the rates of generation and destruction of active radicals are balanced. At low radical concentrations, termination predominantly occurs via radical recombination ($2\,\text{Cl}^\bullet \to \text{Cl}_2$ or $2\,\text{R}^\bullet \to \text{R}_2$ depending on the slow propagation step). For chlorination, where Propagation 1 is fast and exothermic ($\Delta H^\circ \approx -17\text{ kJ/mol}$), the concentration of $\text{Cl}^\bullet$ is held in steady state:

$$\frac{d[\text{Cl}^\bullet]}{dt} = 2 k_1 I_a - k_2 [\text{Cl}^\bullet][\text{R-H}] + k_3 [\text{R}^\bullet][\text{Cl}_2] - 2 k_6 [\text{Cl}^\bullet]^2 \approx 0 \tag{2.5g}$$

The net rate of alkyl chloride formation is:

$$v = \frac{d[\text{R-Cl}]}{dt} = k_3 [\text{R}^\bullet][\text{Cl}_2] = k_2 [\text{Cl}^\bullet][\text{R-H}] \tag{2.5h}$$
Energetics and Radical Selectivity via Hammond's Postulate:

The contrast between chlorination and bromination illustrates Hammond's Postulate:

  • Chlorination: The hydrogen abstraction step $\text{Cl}^\bullet + \text{R-H} \to \text{HCl} + \text{R}^\bullet$ is exothermic ($\Delta H^\circ = -17\text{ kJ/mol}$, $E_a \approx 4\text{ kJ/mol}$). The transition state is early (reactant-like); the $\text{C}-\text{H}$ bond is barely stretched ($\sim 10\%$), so the radical character on carbon is negligible. Consequently, the stability differences between $1^\circ, 2^\circ$, and $3^\circ$ radicals have little effect on the transition state energy (relative reactivity at $25^\circ\text{C}$ is $1 : 3.8 : 5.0$).
  • Bromination: The abstraction step $\text{Br}^\bullet + \text{R-H} \to \text{HBr} + \text{R}^\bullet$ is strongly endothermic ($\Delta H^\circ = +42\text{ kJ/mol}$, $E_a \approx 54\text{ kJ/mol}$). The transition state is late (product-like); the $\text{C}-\text{H}$ bond is largely broken ($\sim 70\%$), and substantial radical character develops on carbon. The transition state energy directly mirrors the thermodynamic stability of the forming radical (relative reactivity at $127^\circ\text{C}$ is $1 : 82 : 1600$). Bromination is therefore an exceptionally clean, regiospecific synthetic tool.

§§2.4 Carbene Additions & C-H Insertion Chemistry

Carbenes are neutral, divalent carbon species ($R_2\text{C}:$) possessing six valence electrons. They exist in two distinct electronic spin configurations:

1. Singlet Carbene (${}^1A_1$):

The carbon is $sp^2$ hybridized with a pair of electrons in an $sp^2$ non-bonding orbital and an empty unhybridized $2p_z$ orbital. Total spin $S = 0$ (singlet). Generated by photolysis of diazomethane ($\text{CH}_2\text{N}_2$) or chloroform $\alpha$-elimination ($:\text{CCl}_2$).

2. Triplet Carbene (${}^3B_1$):

The carbon has two degenerate unpaired electrons with parallel spins ($S = 1$). Triplet carbenes behave as ground-state diradicals.

C-H Insertion Mechanisms

Singlet methylene ($:\text{CH}_2$) undergoes concerted three-center insertion directly into unactivated $\text{C}-\text{H}$ single bonds:

$$\text{R}_3\text{C}-\text{H} + :\text{CH}_2 \longrightarrow \left[ \begin{matrix} \text{R}_3\text{C} & \cdots & \text{H} \\ & \ddots & \vdots \\ & & \text{CH}_2 \end{matrix} \right]^\ddagger \longrightarrow \text{R}_3\text{C}-\text{CH}_3 \tag{2.8}$$

Because singlet insertion is an extremely exothermic, concerted reaction with zero activation barrier, it exhibits virtually zero selectivity, inserting into $1^\circ, 2^\circ,$ and $3^\circ$ $\text{C}-\text{H}$ bonds purely according to statistical hydrogen ratios!

Skell's Hypothesis & Electronic Spin Multiplicity of Carbenes

Carbenes ($:\text{CR}_2$) possess a neutral divalent carbon atom with two non-bonding electrons. Their chemical reactivity is fundamentally governed by their spin multiplicity:

1. Singlet Carbene ($^1A_1$):

  • Both non-bonding electrons are paired in a single $sp^2$ hybrid orbital, while the $p_z$ orbital remains completely vacant:
$$\text{Configuration}: (sp^2)^2 (p_z)^0, \quad S = 0, \quad 2S + 1 = 1 \tag{2.7a}$$
  • The bond angle is compressed ($\angle \text{H}-\text{C}-\text{H} \approx 102^\circ$) due to lone-pair repulsion.
  • Reactivity (Skell Hypothesis): Proceeds through a concerted, single-step addition across an alkene $\pi$ bond. Because bond formation occurs simultaneously at both ends without generating an intermediate diradical, the stereochemistry of the alkene is strictly preserved:
$$\text{cis-Alkene} + {}^1[:\text{CR}_2] \longrightarrow \text{cis-Cyclopropane exclusively} \tag{2.7b}$$

2. Triplet Carbene ($^3B_1$):

  • The two non-bonding electrons reside in separate degenerate or nearly degenerate orbitals with parallel spins according to Hund's rule:
$$\text{Configuration}: (sp)^1 (p_y)^1 (p_z)^0 \text{ or } (sp^2)^1 (p_z)^1, \quad S = 1, \quad 2S + 1 = 3 \tag{2.7c}$$
  • The bond angle is wide ($\angle \text{H}-\text{C}-\text{H} \approx 136^\circ$).
  • For methylene ($:\text{CH}_2$), the triplet state is the thermodynamic ground state, lying $\sim 38\text{ kJ/mol}$ lower in energy than the singlet state.
  • Reactivity (Skell Hypothesis): Because spin inversion is quantum mechanically forbidden on the timescale of bond rotations ($10^{-10}\text{ s}$), addition to an alkene occurs via a two-step radical pathway forming a triplet 1,3-diradical intermediate:
$$\text{Alkene} + {}^3[:\text{CR}_2] \longrightarrow [^\bullet\text{C}-\text{C}-\text{C}^\bullet \text{ (Triplet Diradical)}] \tag{2.7d}$$

Free rotation around the single bond occurs before spin inversion, yielding a mixture of cis and trans cyclopropanes regardless of initial alkene geometry!

§§2.5 Baeyer Strain Theory & Ring Strain Energetics

In 1885, Adolf von Baeyer proposed that planar cycloalkanes experience angle strain because the internal geometric angles of regular polygons deviate from the ideal tetrahedral angle of $\theta_0 = 109.47^\circ$.

The Baeyer Angle Deviation Formulation

For a regular planar polygon with $n$ vertices, the interior angle is:

$$\alpha_n = \frac{(n - 2) \times 180^\circ}{n} \tag{2.9}$$

Baeyer defined the angle deviation per vertex ($d$) as:

$$d = \frac{1}{2}(109.47^\circ - \alpha_n) \tag{2.10}$$
  • Cyclopropane ($n=3$): $\alpha = 60^\circ \implies d = +24.74^\circ$
  • Cyclobutane ($n=4$): $\alpha = 90^\circ \implies d = +9.74^\circ$
  • Cyclopentane ($n=5$): $\alpha = 108^\circ \implies d = +0.74^\circ$ (Predicted near-zero strain)
  • Cyclohexane ($n=6$): $\alpha = 120^\circ \implies d = -5.26^\circ$ (Predicted strain)

Quantitative Experimental Ring Strain from Heat of Combustion

Baeyer's assumption that rings are planar failed completely for $n \ge 6$. In reality, cycloalkanes pucker into three-dimensional non-planar conformations to relieve torsional strain and angle strain. Total ring strain is rigorously measured by measuring standard heats of combustion per methylene unit ($\Delta H_{\text{comb}} / n$) relative to strain-free unstrained open-chain alkanes ($-658.6\text{ kJ/mol}$ per $\text{CH}_2$):

$$\text{Ring Strain} = -\Delta H_{\text{comb}}^{\circ} - (n \times 658.6\text{ kJ/mol}) \tag{2.11}$$

| Ring Size ($n$) | Interior Angle | Strain / $\text{CH}_2$ (kJ/mol) | Total Ring Strain (kJ/mol) | Dominant Strain Sources | | :---: | :---: | :---: | :---: | :--- | | Cyclopropane ($C_3$) | $60^\circ$ | $38.5$ | $115.5$ | Colossal angle strain + 6 eclipsed C-H bonds | | Cyclobutane ($C_4$) | $88^\circ$ (puckered) | $27.6$ | $110.4$ | Severe angle strain + torsional puckering | | Cyclopentane ($C_5$) | $105^\circ$ (envelope) | $5.2$ | $26.0$ | Torsional strain relieved by envelope | | Cyclohexane ($C_6$) | $109.5^\circ$ (chair) | $0.0$ | $0.0$ | Completely Strain-Free (Ideal Chair) | | Cycloheptane ($C_7$) | $116^\circ$ (twist-chair) | $3.7$ | $26.2$ | Transannular cross-ring steric clashes | | Cyclooctane ($C_8$) | $117^\circ$ (boat-chair) | $5.1$ | $41.5$ | Medium ring transannular Prelog strain |

§§2.6 Cyclohexane Conformational Analysis & A-Values

Cyclohexane adopts a non-planar chair conformation possessing $D_{3d}$ point group symmetry. In the chair conformation:

  1. Every carbon-carbon bond angle is precisely $109.5^\circ$, resulting in zero angle strain.
  2. Every adjacent pair of carbon atoms has perfectly staggered $\text{C}-\text{H}$ bonds with dihedral angles of $60^\circ$, resulting in zero torsional strain.

Axial vs Equatorial Orientations

The 12 hydrogen atoms of cyclohexane are split into two stereochemically distinct sets:

1. 6 Axial Hydrogens ($H_{\text{ax}}$): Orient strictly parallel to the $C_3$ molecular symmetry axis (3 pointing straight UP, 3 pointing straight DOWN).

2. 6 Equatorial Hydrogens ($H_{\text{eq}}$): Orient outward along the molecular 'equator', alternating slightly up and down.


The Chair-Chair Inversion (Chair-Flip)

At room temperature, cyclohexane undergoes rapid chair-to-chair conformational interconversion at a frequency of approximately $10^5\text{ s}^{-1}$:

$$\text{Chair A} \rightleftharpoons [\text{Half-Chair}]^\ddagger \rightleftharpoons \text{Twist-Boat} \rightleftharpoons [\text{Half-Chair}]^\ddagger \rightleftharpoons \text{Chair B} \tag{2.12}$$

During the chair flip:

  • All axial bonds invert into equatorial bonds.
  • All equatorial bonds invert into axial bonds.
  • The activation free energy barrier is $\Delta G^\ddagger \approx 45.2\text{ kJ}\cdot\text{mol}^{-1}$ (governed by the half-chair transition state).

Monosubstituted Cyclohexanes & Conformational A-Values

When a substituent $R$ replaces a hydrogen atom on cyclohexane, the two chair conformers are no longer degenerate:

$$\text{Axial Conformer} \rightleftharpoons \text{Equatorial Conformer}, \quad K_{\text{eq}} = \frac{[\text{Equatorial}]}{[\text{Axial}]} \tag{2.13}$$

The equatorial conformer is universally favored thermodynamically because the axial conformer suffers from severe 1,3-diaxial steric interactions with the two syn-axial hydrogen atoms at C3 and C5. The thermodynamic preference is quantified by the Winstein-Holness A-Value, defined as:

$$A \equiv -\Delta G^\circ = G_{\text{axial}}^\circ - G_{\text{equatorial}}^\circ = RT \ln K_{\text{eq}} \tag{2.14}$$

| Substituent ($R$) | A-Value ($-\Delta G^\circ$, kJ/mol) | % Equatorial at 298 K | Steric Rationale | | :---: | :---: | :---: | :--- | | $-\text{H}$ | $0.0$ | $50.0\%$ | Baseline | | $-\text{F}$ | $1.0$ | $60.0\%$ | Very small halogen | | $-\text{Cl}$ | $2.2$ | $71.0\%$ | Longer C-Cl bond reduces diaxial clash | | $-\text{Br}$ | $2.3$ | $72.0\%$ | Similar to Cl due to longer C-Br bond | | $-\text{OH}$ | $3.9$ | $83.0\%$ | Moderate 1,3-diaxial clash | | $-\text{CH}_3$ | $7.3$ | $95.0\%$ | Equivalent to two gauche butane interactions ($2 \times 3.8$) | | $-\text{CH}_2\text{CH}_3$ | $7.5$ | $95.3\%$ | Ethyl can rotate methyl group away from ring | | $-\text{CH(CH}_3)_2$ | $9.2$ | $97.6\%$ | Isopropyl hydrogen points toward ring | | $-\text{C(CH}_3)_3$ | $20.5$ | $>99.99\%$ | Conformational Lock (tert-butyl frozen equatorial) |

Torsional Potential Modeling via Truncated Fourier Series

The potential energy of an alkane as a function of the dihedral torsional angle $\phi$ about a single $\text{C}-\text{C}$ bond is mathematically represented by a truncated Fourier series:

$$V(\phi) = \frac{V_1}{2}(1 - \cos\phi) + \frac{V_2}{2}(1 - \cos 2\phi) + \frac{V_3}{2}(1 - \cos 3\phi) \tag{2.14a}$$

where:

  • $V_1$ represents one-fold dipole-dipole and steric repulsion between terminal methyl groups.
  • $V_2$ represents two-fold electronic interactions.
  • $V_3$ represents the intrinsic three-fold torsional barrier of the staggered-to-eclipsed framework.
Energetics of $n$-Butane Conformers:

1. Anti Conformer ($\phi = 180^\circ$): Global energy minimum ($V = 0.0\text{ kJ/mol}$). Staggered with methyl groups maximally separated.

2. Gauche Conformers ($\phi = 60^\circ, 300^\circ$): Local energy minima ($V = +3.8\text{ kJ/mol}$). Staggered, but experiences one gauche-butane steric clash.

3. Eclipsed (H / Me) Conformer ($\phi = 120^\circ, 240^\circ$): Energy barrier ($V = +15.9\text{ kJ/mol}$). Two $\text{H}/\text{CH}_3$ eclipsing interactions and one $\text{H}/\text{H}$ eclipsing interaction.

4. Syn-Periplanar (Fully Eclipsed, Me / Me) Conformer ($\phi = 0^\circ$): Global energy maximum ($V = +20.9\text{ kJ/mol}$). Severe van der Waals steric clash between methyl groups directly eclipsing each other.

Dynamics and Stereochemistry of Decalins (Bicyclo[4.4.0]decanes)

Decalin consists of two fused cyclohexane rings sharing two adjacent bridgehead carbons:

1. *trans*-Decalin:

  • The two cyclohexane rings are fused via diequatorial bonds.
  • Conformationally rigid and frozen: cannot undergo a chair-chair flip because inverting one ring would require the second ring to span across two diaxial positions, which is geometrically impossible without breaking covalent bonds!
  • Possesses a center of inversion ($C_i$ symmetry); optically inactive.
  • Enthalpy of formation is lower by $\Delta H = 11.3\text{ kJ/mol}$ than cis-decalin.

2. *cis*-Decalin:

  • Fused via one equatorial and one axial bond ($e,a$).
  • Conformationally flexible: undergoes rapid chair-chair inversion with an activation barrier of $\sim 42\text{ kJ/mol}$.
  • Contains three gauche-butane interactions between the two rings that are absent in trans-decalin, explaining its $11.3\text{ kJ/mol}$ higher thermodynamic enthalpy.

Complete Energy Profile & Dynamic NMR of Cyclohexane Chair Flip

The interconversion between the two degenerate chair conformations of cyclohexane proceeds along a well-defined multi-step potential energy surface:

$$\text{Chair}_1 \xrightleftharpoons[\Delta G^\ddagger = 45\text{ kJ/mol}]{} \left[\text{Half-Chair}\right]^\ddagger \rightleftharpoons \text{Twist-Boat} \rightleftharpoons \left[\text{Boat}\right]^\ddagger \rightleftharpoons \text{Twist-Boat}' \rightleftharpoons \left[\text{Half-Chair}'\right]^\ddagger \rightleftharpoons \text{Chair}_2 \tag{2.12a}$$
Thermodynamic & Kinetic Free Energies at $298\text{ K}$:

1. Chair ($D_{3d}$ symmetry): Potential energy minimum defined as reference ($0.0\text{ kJ/mol}$). Possesses staggered bonds throughout, zero angle strain, and zero torsional strain.

2. Half-Chair ($C_2$ symmetry): Transition state for chair-to-twist-boat conversion. Four carbons are coplanar, introducing intense angle and torsional strain:

$$\Delta G^\ddagger = +45.2\text{ kJ/mol} \quad (10.8\text{ kcal/mol}) \tag{2.12b}$$

3. Twist-Boat ($D_2$ symmetry): Local energy minimum (intermediate). Twisting relieves flagpole eclipsing:

$$\Delta G^\circ = +23.0\text{ kJ/mol} \quad (5.5\text{ kcal/mol}) \tag{2.12c}$$

4. Boat ($C_{2v}$ symmetry): Transition state for twist-boat to twist-boat pseudorotation. Exhibits complete eclipsing of four $\text{C}-\text{H}$ bonds along the sides and severe flagpole-flagpole van der Waals steric clash between C1 and C4 ($r_{\text{H}\cdots\text{H}} \approx 1.83\text{ \AA}$):

$$\Delta G^\circ = +29.0\text{ kJ/mol} \quad (6.9\text{ kcal/mol}) \tag{2.12d}$$
Dynamic $^1\text{H}$ NMR Coalescence Spectroscopy:

At room temperature ($25^\circ\text{C}$), the chair flip occurs at a frequency of $k \approx 10^5\text{ s}^{-1}$. Because this rate far exceeds the NMR chemical shift frequency difference between equatorial and axial protons ($\Delta \nu \approx 0.5\text{ ppm} \times 500\text{ MHz} = 250\text{ Hz}$), a single time-averaged sharp singlet is observed at $\delta = 1.44\text{ ppm}$.

  • Upon cooling to the coalescence temperature ($T_c = 206\text{ K} = -67^\circ\text{C}$), the peak broadens and splits into two distinct, equal-intensity multiplets:
  • Axial protons ($\text{H}_{\text{ax}}$): $\delta = 1.19\text{ ppm}$ (shielded by $\text{C}-\text{C}$ diamagnetic anisotropy)
  • Equatorial protons ($\text{H}_{\text{eq}}$): $\delta = 1.68\text{ ppm}$ (deshielded)
  • Applying the Gutowsky-Holm equation at coalescence:
$$k_c = \frac{\pi \Delta \nu}{\sqrt{2}} = \frac{\pi (250)}{\sqrt{2}} \approx 555\text{ s}^{-1} \tag{2.12e}$$
  • Applying the Eyring equation yields the experimental activation free energy:
$$\Delta G^\ddagger = -R T_c \ln\left(\frac{h k_c}{k_B T_c}\right) = 43.1\text{ kJ/mol} \tag{2.12f}$$

in exact alignment with computational force-field predictions!

§§2.7 Bicycloalkanes, Bredt's Rule & The Wurtz Coupling

Bicyclic Ring Systems

Bicycloalkanes contain two rings sharing two or more common bridgehead carbons:

1. Fused Rings: Share two adjacent carbons (e.g., bicyclo[4.4.0]decane / decalin). Decalin exists as trans-decalin (rigid, two fused equatorial bonds, incapable of chair flip) and cis-decalin (flexible, undergoes chair-chair inversion).

2. Bridged Rings: Share non-adjacent bridgehead carbons separated by one or more carbons (e.g., bicyclo[2.2.1]heptane / norbornane).

3. Spiro Rings: Share a single quaternary carbon atom (e.g., spiro[4.5]decane).

Bredt's Rule

In 1924, Julius Bredt established an indispensable stereoelectronic rule:

A double bond cannot terminate at the bridgehead position of a bridged bicyclic ring system unless the ring containing the double bond is large enough ($n \ge 8$ atoms) to accommodate a trans-alkene without excessive geometric strain.

Bridgehead double bonds in small bridged systems (such as bicyclo[2.2.1]hept-1-ene) require twisting the $p$-orbitals by nearly $90^\circ$, extinguishing $\pi$-orbital overlap and resulting in catastrophic angle and torsional strain.


The Wurtz Reaction: Organometallic & Radical Mechanisms

Discovered by Charles-Adolphe Wurtz in 1855, the reaction couples two alkyl halide molecules using metallic sodium to synthesize symmetrical higher alkanes:

$$2\,\text{R}-\text{X} + 2\,\text{Na} \longrightarrow \text{R}-\text{R} + 2\,\text{NaX} \tag{2.15}$$
Mechanistic Pathway (Organometallic Intermediates):

1. Single Electron Transfer (SET) from sodium metal to alkyl halide generates an alkyl radical:

$$\text{R}-\text{X} + \text{Na} \longrightarrow \text{R}^\bullet + \text{Na}^+ + \text{X}^- \tag{2.16}$$
  1. Second electron transfer to the radical generates an organosodium carbanion:
$$\text{R}^\bullet + \text{Na} \longrightarrow \text{R}^- \text{Na}^+ \tag{2.17}$$
  1. Nucleophilic substitution ($S_N2$) of the organosodium reagent onto unreacted alkyl halide:
$$\text{R}^- + \text{R}-\text{X} \longrightarrow \text{R}-\text{R} + \text{X}^- \tag{2.18}$$
Synthetic Limitations:

1. Low Yield for Cross-Coupling: Coupling two different alkyl halides ($\text{R}_1\text{X} + \text{R}_2\text{X}$) yields a statistical nightmare of three products ($\text{R}_1-\text{R}_1, \text{R}_1-\text{R}_2, \text{R}_2-\text{R}_2$) with nearly identical boiling points that are virtually impossible to separate.

2. Disproportionation Side-Reactions: With secondary and tertiary halides, the organosodium carbanion acts as a strong base, causing $E2$ elimination to yield alkene and alkane mixtures.

Bredt's Rule & The Fawcett $S$-Number Geometric Limit

Formulated by Julius Bredt in 1924, Bredt's Rule establishes that:

A double bond cannot be located at the bridgehead carbon of a bridged bicyclic ring system unless the rings are sufficiently large to accommodate the necessary trans-cycloalkene geometry without prohibitive ring strain.

Fawcett's Quantitative $S$-Number Formulation:

In 1950, Frank Fawcett parameterized Bredt's rule using the ring-size index $S$:

$$S = x + y + z \tag{2.15a}$$

where $x, y, z$ are the number of carbon atoms in the three bridges of the $\text{bicyclo}[x.y.z]$ system:

1. $S < 7$: Bridgehead alkenes are completely unstable, non-existent even as transient reaction intermediates.

2. $S = 7 \text{ or } 8$: Highly reactive, transient intermediates that can only be trapped in low-temperature matrices or via *in situ* Diels-Alder cycloadditions (e.g., bicyclo[2.2.1]hept-1-ene).

3. $S \ge 9$: Isolable, thermodynamically stable compounds at room temperature (e.g., bicyclo[3.3.1]non-1-ene, $S = 3 + 3 + 1 = 7$, is isolable but very strained; bicyclo[4.4.1]undec-1-ene, $S = 9$, is completely stable).

Geometric and Orbital Origin of Strain:

A bridgehead double bond in a bridged bicyclic system forces the $p$-orbitals of the alkene into a non-parallel, twisted orientation.

  • The $\pi$-bond dihedral angle $\tau$ deviates from $0^\circ$:
$$E_{\text{twist}} = V_\pi (1 - \cos 2\tau) \tag{2.15b}$$
  • In norbornene derivatives ($S=5$), accommodating a bridgehead double bond requires a twist angle $\tau > 45^\circ$, reducing orbital overlap by more than $50\%$ and creating strain energies exceeding $180\text{ kJ/mol}$!
  • Furthermore, one of the two rings containing the double bond must incorporate the double bond as a trans-cycloalkene. Because the smallest isolable trans-cycloalkene is trans-cyclooctene (which itself possesses $71\text{ kJ/mol}$ of strain), any bicyclic ring system containing a bridgehead double bond must incorporate at least an eight-membered ring across the active bridge to achieve room-temperature stability!

§2.8 §2.8 Advanced Molecular Mechanics & Petrochemical Catalysis: Zeolite Cracking & Fischer-Tropsch

Molecular Mechanics Force-Field Parameterization (MM4) & Conformational Dynamics

In modern computational organic chemistry, the conformational potential energy surface of substituted cycloalkanes is calculated using Norman Allinger's MM4 force field, which incorporates coupled stretch-bend and bend-bend cross terms:

$$E_{\text{pot}} = \sum E_{\text{stretch}} + \sum E_{\text{bend}} + \sum E_{\text{torsion}} + \sum E_{\text{vdW}} + \sum E_{\text{stretch-bend}} + \sum E_{\text{torsion-bend}} \tag{2.16a}$$
The Physical Basis of Cross Terms:

1. Stretch-Bend Coupling ($E_{\text{stretch-bend}}$):

$$E_{\text{stretch-bend}} = k_{sb} (\theta - \theta_0) [(r_1 - r_{1,0}) + (r_2 - r_{2,0})] \tag{2.16b}$$

When a bond angle is compressed (as in cyclobutane or cyclopentane), electron repulsion pushes the bonded atoms outward, lengthening the adjacent $\text{C}-\text{C}$ bonds. MM4 captures this coupling, predicting the exact $1.554\text{ \AA}$ bond length in cyclobutane compared to $1.538\text{ \AA}$ in ethane.

2. Conformational Dynamics of Decalin Stereoisomers:

  • trans-Decalin ($C_{2h}$ symmetry): Rigidly locked. The two bridgehead hydrogens are trans-diaxial ($\phi = 180^\circ$). Neither cyclohexane ring can undergo a chair flip without breaking $\text{C}-\text{C}$ covalent bonds! The conformational equilibrium constant is infinite; the molecule is conformationally rigid.
  • cis-Decalin ($C_2$ symmetry): Conformationally mobile. One bridgehead hydrogen is axial and the other is equatorial. It undergoes a rapid degenerate chair-chair flip ($k \approx 10^5\text{ s}^{-1}$ at $25^\circ\text{C}$):
$$\text{cis-Decalin (Chair-Chair)}_A \rightleftharpoons \text{cis-Decalin (Chair-Chair)}_B \tag{2.16c}$$
  • trans-Decalin is thermodynamically more stable than cis-decalin by $\Delta H^\circ = -11.3\text{ kJ/mol}$ ($2.7\text{ kcal/mol}$), exactly equal to the steric penalty of three additional gauche-butane interactions present in the cis isomer.

Industrial Catalytic Cracking: Zeolites vs Thermal Pyrolysis

The industrial conversion of heavy crude petroleum fractions into gasoline-range hydrocarbons ($C_5 - C_{10}$) proceeds through two radically different mechanistic pathways:

```

  1. THERMAL CRACKING (Free-Radical Pathway, 750 - 900 deg C):

R-CH2-CH2-CH2-R' ---> R-CH2 + CH2-CH2-R' (Homolytic C-C Cleavage) R-CH2-CH2 ---> R + CH2=CH2 (Beta-Scission yielding Ethylene)

  1. FLUID CATALYTIC CRACKING (Carbocation Pathway, 500 deg C, Zeolite H-ZSM-5):

R-CH2-CH3 + [H+-Zeolite] ---> [R-CH2-CH4]+ ---> R-CH2+ + H2 R-CH2+ + R'-H ---> R-CH3 + R'+ (Hydride Transfer) R-CH(+)-CH2-CH3 ---> R-C+(Me)-CH3 (Wagner-Meerwein Skeletal Isomerization) ```

1. Fluid Catalytic Cracking (FCC) Mechanism:
  • Operates over synthetic crystalline aluminosilicate zeolites (e.g., Faujasite, H-ZSM-5) containing strong Brønsted acid sites ($\equiv\text{Si}-\text{OH}^+-\text{Al}^-\equiv$).
  • Initiation: A strong Brønsted acid protonates an alkane at high temperature ($500^\circ\text{C}$) to form a transient penta-coordinate carbonium ion ($[\text{C}_n\text{H}_{2n+3}]^+$), which cleaves into molecular hydrogen ($\text{H}_2$) and an alkyl carbocation ($\text{R}^+$).
  • Skeletal Isomerization: Carbocations undergo instantaneous Wagner-Meerwein 1,2-hydride and 1,2-methide shifts to convert straight-chain hydrocarbons into highly branched alkanes and cycloalkanes.
  • Hydride Transfer: Secondary and tertiary carbocations abstract hydride ($\text{H}^-$) from feed molecules, propagating the catalytic cycle.
  • Result: Generates high-octane branched gasoline and aromatic precursors with minimal coke formation.
2. The Fischer-Tropsch Synthesis:

Developed by Franz Fischer and Hans Tropsch in 1925, synthesis gas ($\text{CO} + \text{H}_2$) is converted into liquid hydrocarbons over heterogeneous iron or cobalt catalysts:

$$(2n + 1)\,\text{H}_2 + n\,\text{CO} \xrightarrow{\text{Fe/Co, } 200-350^\circ\text{C}} \mathbf{\text{C}_n\text{H}_{2n+2}} + n\,\text{H}_2\text{O} \tag{2.16d}$$
  • Follows the Anderson-Schulz-Flory (ASF) polymerization model, where chain growth probability $\alpha$ dictates the product distribution:
$$W_n = n (1 - \alpha)^2 \alpha^{n-1} \tag{2.16e}$$
  • Operates via dissociative chemisorption of $\text{CO}$, hydrogenation to surface methylene species ($[\text{M}=\text{CH}_2]$), and successive surface alkyl chain migratory insertions.

§2.9 Hydrocarbon Analytics: High-Resolution GC-MS & Bomb Calorimetry

Analytical Separation & Mass Spectrometric Fragmentation of Alkanes

The complex hydrocarbon mixtures generated by petroleum refining are resolved and characterized using capillary Gas Chromatography coupled with Electron Ionization Mass Spectrometry (GC-MS):

1. Capillary Gas Chromatography Dynamics:

The retention time $t_R$ of an alkane on a non-polar polydimethylsiloxane stationary phase (e.g., DB-5) correlates with its boiling point and Kovats retention index ($I$):

$$I = 100 \left[ n + \frac{\log t'_R(\text{analyte}) - \log t'_R(n)}{\log t'_R(n+1) - \log t'_R(n)} \right] \tag{2.17a}$$

where $t'_R = t_R - t_M$ is the adjusted retention time, and $n$ is the carbon number of the preceding normal alkane.

  • Branching Effect: Highly branched alkanes possess more compact spherical geometries, smaller polarizable surface areas, and weaker London dispersion forces. Consequently, branched isomers elute substantially earlier than linear isomers (e.g., 2,2,4-trimethylpentane elutes before $n$-octane).
2. Electron Ionization (EI) Mass Spectrometry Fragmentation:

High-energy electrons ($70\text{ eV}$) ionize alkane molecules to generate radical cations ($M^{\bullet+}$):

$$\text{R}-\text{H} + e^-(70\text{ eV}) \longrightarrow [\text{R}-\text{H}]^{\bullet+} + 2\,e^- \tag{2.17b}$$
  • $\alpha$-Cleavage & Carbocation Stability: Fragmentation occurs preferentially at branched carbons to generate the most stable secondary or tertiary carbocation:
$$[\text{R}-\text{CH}(\text{Me})-\text{R}']^{\bullet+} \longrightarrow \mathbf{\text{R}-\stackrel{\oplus}{\text{C}}\text{H}-\text{Me}} + \text{R}'^\bullet \tag{2.17c}$$
  • Mass Spectral Fingerprints: Linear alkanes produce characteristic clusters spaced by $14\text{ Da}$ ($-\text{CH}_2-$ units): $m/z = 43 (\text{C}_3\text{H}_7^+), 57 (\text{C}_4\text{H}_9^+), 71 (\text{C}_5\text{H}_{11}^+), 85 (\text{C}_6\text{H}_{13}^+)$, with $m/z = 43$ or $57$ serving as the base peak.

Precision Bomb Calorimetry & Real Gas Corrections

The experimental heats of combustion ($\Delta U_c^\circ$) of hydrocarbons are measured inside an adiabatic oxygen bomb calorimeter pressurized to $P \approx 30\text{ bar}$:

$$\Delta U_c^\circ = -\frac{C_{\text{cal}} \Delta T - q_{\text{fuse}} - q_{\text{HNO}_3}}{m_{\text{sample}}} \tag{2.17d}$$
$$\Delta H_c^\circ = \Delta U_c^\circ + \Delta n_g R T \tag{2.17e}$$

where $\Delta n_g = n(\text{CO}_2, g) - n(\text{O}_2, g)$ is the change in moles of gas.

  • Applying Washburn corrections to adjust for non-ideality of gases at $30\text{ bar}$ enables measurements of combustion enthalpies with uncertainties below $\pm 0.02\%$, establishing the fundamental thermochemical scale for ring strain energies across all cycloalkanes!

§2.10 Master Reference Guide: Alkane Reactivity, Strain Energies & A-Values

Comprehensive Ring Strain & A-Value Compendium

| Ring System | Total Strain Energy ($\text{kJ/mol}$) | Strain Energy ($\text{kcal/mol}$) | Angle Strain | Torsional Strain | Primary Conformation | | :---: | :---: | :---: | :---: | :---: | :---: | | Cyclopropane | $\mathbf{115.5}$ | $27.6$ | Extreme ($60^\circ$ angle) | High ($6$ eclipsed C-H pairs) | Planar ($D_{3h}$) | | Cyclobutane | $\mathbf{110.5}$ | $26.4$ | Severe ($88^\circ$ angle) | Moderate | Puckered ($D_{2d}$) | | Cyclopentane | $\mathbf{26.0}$ | $6.2$ | Minimal ($108^\circ$ angle) | Moderate | Envelope / Half-chair ($C_s / C_2$) | | Cyclohexane | $\mathbf{0.0}$ | $0.0$ | Zero ($109.5^\circ$ angle) | Zero (all staggered) | Chair ($D_{3d}$) | | Cycloheptane | $\mathbf{26.4}$ | $6.3$ | Minor | Moderate transannular | Twist-chair | | Cyclooctane | $\mathbf{41.8}$ | $10.0$ | Minor | Severe transannular Prelog | Boat-chair | | Cyclodecane | $\mathbf{51.9}$ | $12.4$ | Minor | Severe transannular ($H\cdots H$) | Boat-chair-boat |

Winstein-Holness A-Values ($\text{kcal/mol}$ at $298\text{ K}$):
$$-\text{CN}: 0.20 \quad < \quad -\text{F}: 0.25 \quad < \quad -\text{I}: 0.46 \quad < \quad -\text{Br}: 0.48 \quad < \quad -\text{Cl}: 0.53 \quad < \quad -\text{OH}: 0.87 \quad < \quad -\text{COOMe}: 1.30$$
$$-\text{Me}: 1.74 \quad \approx \quad -\text{Et}: 1.75 \quad < \quad -i\text{-Pr}: 2.15 \quad \ll \quad -t\text{-Bu}: 4.90 \text{ (Conformational Anchor!)}$$

Rigorous Tiered Solved Examination Problems

Step-by-step unskipped derivations, complete proofs, and verification across Foundational, Intermediate, Advanced, and Honors tiers.

Foundational Level Example 2.1: Problem 2.1: Free-Radical Halogenation Product Distributions in 2-Methylbutane

Consider the free-radical halogenation of 2-methylbutane ($\text{(CH}_3)_2\text{CH}-\text{CH}_2-\text{CH}_3$).

  1. Draw and provide the complete IUPAC systematic names for all possible monochlorinated constitutional isomers formed in this reaction.
  2. Given the relative kinetic reactivity ratios of hydrogen abstraction by chlorine radicals at $298\text{ K}$ ($1^\circ : 2^\circ : 3^\circ = 1.0 : 3.8 : 5.0$), calculate the exact theoretical percentage yield of each monochlorinated isomer.
  3. If 2-methylbutane is instead subjected to free-radical bromination ($1^\circ : 2^\circ : 3^\circ = 1.0 : 82 : 1600$), calculate the predicted percentage yield of the major monobrominated product. Explain the stark contrast between the two halogenation profiles using Hammond's postulate.

Part 1: Monochlorinated Isomers & Nomenclature

2-Methylbutane contains four distinct types of hydrogen atoms:

1. C1 Hydrogens ($1^\circ$): Six hydrogens on the two equivalent methyl groups attached to C2.

  • Product: 1-Chloro-2-methylbutane

2. C2 Hydrogen ($3^\circ$): One tertiary hydrogen.

  • Product: 2-Chloro-2-methylbutane

3. C3 Hydrogens ($2^\circ$): Two secondary hydrogens on the methylene group.

  • Product: 2-Chloro-3-methylbutane (correct IUPAC: 2-chloro-3-methylbutane)

4. C4 Hydrogens ($1^\circ$): Three primary hydrogens on the terminal methyl group.

  • Product: 1-Chloro-3-methylbutane

Part 2: Chlorination Percentage Yield Calculations

Relative rate contribution = $(\text{Number of Equivalent Hydrogens}) \times (\text{Relative Reactivity})$:

1. 1-Chloro-2-methylbutane ($1^\circ$):

$$R_1 = 6 \times 1.0 = 6.0$$

2. 2-Chloro-2-methylbutane ($3^\circ$):

$$R_2 = 1 \times 5.0 = 5.0$$

3. 2-Chloro-3-methylbutane ($2^\circ$):

$$R_3 = 2 \times 3.8 = 7.6$$

4. 1-Chloro-3-methylbutane ($1^\circ$):

$$R_4 = 3 \times 1.0 = 3.0$$

Total relative reactivity:

$$R_{\text{total}} = 6.0 + 5.0 + 7.6 + 3.0 = \mathbf{21.6}$$

Calculating percentage yields:

  • 1-Chloro-2-methylbutane: $\frac{6.0}{21.6} \times 100\% = \mathbf{27.8\%}$
  • 2-Chloro-2-methylbutane: $\frac{5.0}{21.6} \times 100\% = \mathbf{23.1\%}$
  • 2-Chloro-3-methylbutane: $\frac{7.6}{21.6} \times 100\% = \mathbf{35.2\% \quad (\text{Major Product!})}$
  • 1-Chloro-3-methylbutane: $\frac{3.0}{21.6} \times 100\% = \mathbf{13.9\%}$

Critical Discovery: Despite the tertiary position having the highest intrinsic reactivity ($5.0$), 2-chloro-3-methylbutane is the major product ($35.2\%$) due to statistical weighting (two secondary hydrogens vs only one tertiary hydrogen)! Chlorination is synthetically unviable due to this complex mixture.


Part 3: Bromination Percentage Yields & Hammond's Postulate

Relative reactivity ratios for Bromine: $1^\circ : 2^\circ : 3^\circ = 1 : 82 : 1600$:

  1. $R_1 = 6 \times 1 = 6$
  2. $R_2 (3^\circ) = 1 \times 1600 = 1600$
  3. $R_3 (2^\circ) = 2 \times 82 = 164$
  4. $R_4 = 3 \times 1 = 3$

Total reactivity:

$$R_{\text{total}} = 6 + 1600 + 164 + 3 = \mathbf{1773}$$

Percentage yield of major product (2-bromo-2-methylbutane):

$$\%(2\text{-bromo-2-methylbutane}) = \frac{1600}{1773} \times 100\% = \mathbf{90.24\% \approx 90.2\%}$$

By Hammond's postulate, the endothermic hydrogen abstraction in bromination passes through a late transition state that closely resembles the tertiary radical intermediate, allowing hyperconjugative stabilization to govern the barrier. In contrast, exothermic chlorination has an early transition state with minimal radical character, making it largely unselective.

Intermediate Level Example 2.2: Problem 2.2: Conformational Free Energy & Equilibrium of Disubstituted Cyclohexanes

Consider cis- and trans-isomers of 1-tert-butyl-4-methylcyclohexane.

  1. Draw the two chair conformations for cis-1-tert-butyl-4-methylcyclohexane and the two chair conformations for trans-1-tert-butyl-4-methylcyclohexane.
  2. Given the A-values: $A(\text{t-Bu}) = 20.5\text{ kJ/mol}$ and $A(\text{Me}) = 7.3\text{ kJ/mol}$:
  • Calculate the standard Gibbs free energy difference $\Delta G^\circ$ between the two chair conformations of the cis-isomer.
  • Determine which conformer of the cis-isomer is predominantly populated at $298.15\text{ K}$, and calculate its exact percentage population.
  • Calculate the standard free energy difference $\Delta G^\circ$ between the most stable conformer of the trans-isomer and the most stable conformer of the cis-isomer, proving which stereoisomer is thermodynamically more stable.

Part 1: Chair Conformations of the Stereoisomers

1. cis-1-tert-Butyl-4-methylcyclohexane:

In a 1,4-cis relationship, one substituent must be axial and the other must be equatorial ($a,e$ or $e,a$):

  • Conformer A: tert-Butyl(axial), Methyl(equatorial)
  • Conformer B: tert-Butyl(equatorial), Methyl(axial)

2. trans-1-tert-Butyl-4-methylcyclohexane:

In a 1,4-trans relationship, substituents are either diequatorial or diaxial:

  • Conformer C: tert-Butyl(equatorial), Methyl(equatorial) [diequatorial]
  • Conformer D: tert-Butyl(axial), Methyl(axial) [diaxial]

Part 2: Thermodynamic Calculations for the *cis*-Isomer

Comparing Conformer A vs Conformer B:

  • In Conformer A, tert-butyl is axial: steric strain energy $= A(\text{t-Bu}) = +20.5\text{ kJ/mol}$.
  • In Conformer B, methyl is axial: steric strain energy $= A(\text{Me}) = +7.3\text{ kJ/mol}$.

Energy difference (Conformer B relative to Conformer A):

$$\Delta G^\circ = G_B^\circ - G_A^\circ = +7.3 - (+20.5) = \mathbf{-13.2\text{ kJ/mol}}$$

Conformer B (equatorial tert-butyl, axial methyl) is overwhelmingly favored.

Calculating the equilibrium constant $K_{\text{eq}} = [B]/[A]$ at $298.15\text{ K}$:

$$K_{\text{eq}} = \exp\left(-\frac{\Delta G^\circ}{RT}\right) = \exp\left( \frac{13200}{8.3145 \times 298.15} \right) = \exp(5.3248) \approx \mathbf{205.4}$$

Percentage of Conformer B:

$$\%B = \frac{K_{\text{eq}}}{1 + K_{\text{eq}}} \times 100\% = \frac{205.4}{206.4} \times 100\% = \mathbf{99.51\%}$$

Part 3: Comparison of *trans* vs *cis* Stereoisomer

  • Most stable conformer of trans-isomer (Conformer C): Both tert-butyl and methyl are equatorial ($e,e$).
$$\text{Steric Strain } = 0.0\text{ kJ/mol}$$
  • Most stable conformer of cis-isomer (Conformer B): tert-butyl is equatorial, but methyl is forced into an axial position ($e,a$).
$$\text{Steric Strain } = +7.3\text{ kJ/mol}$$

Net thermodynamic difference between the stereoisomers:

$$\Delta G_{\text{trans} \rightarrow \text{cis}}^\circ = +7.3 - 0.0 = \mathbf{+7.3\text{ kJ/mol}}$$

The trans-isomer is thermodynamically more stable than the cis-isomer by $7.3\text{ kJ/mol}$ because it can accommodate both bulky alkyl groups in equatorial positions simultaneously.

Advanced Level Example 2.3: Problem 2.3: Ring Strain Deconvolution & Combustion Thermochemistry in Cycloalkanes

Standard molar enthalpies of combustion ($\Delta H_{\text{comb}}^\circ$) measured at $298.15\text{ K}$ for liquid/gaseous cycloalkanes are given below:

  • Cyclopropane ($\text{C}_3\text{H}_6$, $g$): $\Delta H_{\text{comb}}^\circ = -2091.3\text{ kJ/mol}$
  • Cyclopentane ($\text{C}_5\text{H}_{10}$, $g$): $\Delta H_{\text{comb}}^\circ = -3290.8\text{ kJ/mol}$
  • Cyclohexane ($\text{C}_6\text{H}_{12}$, $g$): $\Delta H_{\text{comb}}^\circ = -3919.6\text{ kJ/mol}$
  1. Compute the enthalpy of combustion per methylene unit ($-\Delta H_{\text{comb}}^\circ / n$) for each of the three rings.
  2. Using the strain-free unstrained methylene reference value of $\Delta H_{\text{ref}} = -653.27\text{ kJ/mol}$ established from long open-chain $n$-alkanes in the gas phase:
  • Calculate the total ring strain energy ($SE$) of cyclopropane, cyclopentane, and cyclohexane.
  • Calculate the strain energy per methylene group for each ring.
  1. If the $\text{C}-\text{C}$ bond dissociation energy in strain-free $n$-butane is $368\text{ kJ/mol}$, estimate the effective $\text{C}-\text{C}$ single bond strength in cyclopropane. Explain how this manifests in the chemical reactivity of cyclopropane toward catalytic hydrogenation.

Part 1: Enthalpy of Combustion per Methylene Group

1. Cyclopropane ($n=3$):

$$\frac{-\Delta H_{\text{comb}}^\circ}{3} = \frac{2091.3}{3} = \mathbf{697.10\text{ kJ/mol}}$$

2. Cyclopentane ($n=5$):

$$\frac{-\Delta H_{\text{comb}}^\circ}{5} = \frac{3290.8}{5} = \mathbf{658.16\text{ kJ/mol}}$$

3. Cyclohexane ($n=6$):

$$\frac{-\Delta H_{\text{comb}}^\circ}{6} = \frac{3919.6}{6} = \mathbf{653.27\text{ kJ/mol}}$$

Notice that cyclohexane possesses an enthalpy of combustion per methylene unit of precisely $653.27\text{ kJ/mol}$, identical to unstrained acyclic $n$-alkanes!


Part 2: Total Ring Strain & Strain per $\text{CH}_2$

$$\text{Total Strain Energy } SE = -\Delta H_{\text{comb}}^\circ - (n \times 653.27\text{ kJ/mol})$$

1. Cyclopropane ($n=3$):

$$SE = 2091.3 - (3 \times 653.27) = 2091.3 - 1959.81 = \mathbf{+131.49\text{ kJ/mol}}$$
$$\text{Strain per } \text{CH}_2 = \frac{131.49}{3} = \mathbf{43.83\text{ kJ/mol}}$$

2. Cyclopentane ($n=5$):

$$SE = 3290.8 - (5 \times 653.27) = 3290.8 - 3266.35 = \mathbf{+24.45\text{ kJ/mol}}$$
$$\text{Strain per } \text{CH}_2 = \frac{24.45}{5} = \mathbf{4.89\text{ kJ/mol}}$$

3. Cyclohexane ($n=6$):

$$SE = 3919.6 - (6 \times 653.27) = 3919.6 - 3919.62 = \mathbf{0.00\text{ kJ/mol}}$$
$$\text{Strain per } \text{CH}_2 = \mathbf{0.00\text{ kJ/mol}}$$

Part 3: Effective C-C Bond Strength & Hydrogenation Reactivity

Cyclopropane contains three equivalent $\text{C}-\text{C}$ bonds. The total ring strain of $131.5\text{ kJ/mol}$ weakens each bond by approximately:

$$\Delta E_{\text{bond}} = \frac{131.49}{3} \approx 43.8\text{ kJ/mol}$$

Effective $\text{C}-\text{C}$ bond dissociation energy:

$$\text{BDE}_{\text{eff}}(\text{C}-\text{C})_{\text{cyclopropane}} = 368 - 43.8 = \mathbf{324.2\text{ kJ/mol}}$$

Because the C-C bonds are severely bent and weakened, cyclopropane behaves chemically more like an alkene than an alkane. It readily undergoes ring-opening catalytic hydrogenation over nickel at $80^\circ\text{C}$:

$$\text{C}_3\text{H}_6 + \text{H}_2 \xrightarrow{\text{Ni, } 80^\circ\text{C}} \text{CH}_3\text{CH}_2\text{CH}_3, \quad \Delta H^\circ = -157\text{ kJ/mol}$$

In contrast, cyclohexane is completely inert to catalytic hydrogenation even at $300^\circ\text{C}$!

Honors / Olympiad Proof Example 2.4: Problem 2.4: Mechanistic Discrimination in Wurtz vs Corey-House Synthesis

A synthetic chemist attempts to synthesize 2,3-dimethylbutane and 2-methylpentane.

  1. The chemist attempts to synthesize 2,3-dimethylbutane by treating 2-bromopropane with sodium metal in dry diethyl ether (Wurtz reaction).
  • Write the complete balanced chemical equation for the expected product.
  • In addition to the desired alkane, two major volatile hydrocarbon side-products (one alkane and one alkene) are formed in substantial quantities. Write their structures and propose a curved-arrow mechanism for their formation via $\beta$-hydride elimination of the intermediate organosodium carbanion.
  1. The chemist attempts to synthesize unsymmetrical 2-methylpentane by mixing 2-bromopropane and 1-bromopropane in a Wurtz reaction.
  • List all three cross- and self-coupling alkane products formed and calculate their theoretical statistical yield distribution.
  1. Formulate an elegant, high-yielding synthetic route to 2-methylpentane using the Corey-House (Gilman dialkylcuprate) cross-coupling protocol, showing all reagents, intermediate organocuprate structures, and explaining why this method avoids disproportionation side-reactions.

Part 1: Wurtz Reaction of 2-Bromopropane & Disproportionation Side-Products

1. Expected Coupling Product:
$$2\,(\text{CH}_3)_2\text{CH}-\text{Br} + 2\,\text{Na} \longrightarrow (\text{CH}_3)_2\text{CH}-\text{CH}(\text{CH}_3)_2 + 2\,\text{NaBr}$$

Product: 2,3-Dimethylbutane.

2. Disproportionation Side-Products:

During the reaction, single electron transfer creates the isopropylsodium carbanion:

$$(\text{CH}_3)_2\text{CH}^- \text{Na}^+$$

Because isopropyl is a sterically encumbered secondary carbanion, its nucleophilicity toward $S_N2$ displacement is suppressed, and its Brønsted basicity dominates. Instead of attacking unreacted 2-bromopropane at the carbon, it abstracts a $\beta$-hydrogen in an $E2$ elimination pathway:

$$(\text{CH}_3)_2\text{CH}^- + \text{CH}_3-\text{CH}(\text{Br})-\text{CH}_3 \longrightarrow \text{CH}_3-\text{CH}_2-\text{CH}_3 + \text{CH}_2=\text{CH}-\text{CH}_3 + \text{Br}^-$$
  • Byproduct 1: Propane ($\text{CH}_3\text{CH}_2\text{CH}_3$, alkane)
  • Byproduct 2: Propene ($\text{CH}_2=\text{CH}-\text{CH}_3$, alkene)

These two disproportionation products often account for $>60\%$ of the total yield!


Part 2: Statistical Mixture in Cross-Wurtz Reaction

Reactants: 2-Bromopropane ($R_1\text{Br}$) and 1-Bromopropane ($R_2\text{Br}$). The non-selective radical/carbanion coupling yields three distinct products:

  1. $R_1 - R_1$: 2,3-Dimethylbutane (Self-coupling)
  2. $R_1 - R_2$: 2-Methylpentane (Desired cross-coupling)
  3. $R_2 - R_2$: $n$-Hexane (Self-coupling)

Assuming equal reactivities, statistical distribution is:

$$R_1R_1 : R_1R_2 : R_2R_2 = 1 : 2 : 1$$
  • 2,3-Dimethylbutane: $\mathbf{25\%}$
  • 2-Methylpentane: $\mathbf{50\%}$
  • $n$-Hexane: $\mathbf{25\%}$

All three isomers have boiling points within $8^\circ\text{C}$ of each other ($58^\circ\text{C}, 60^\circ\text{C}, 69^\circ\text{C}$), rendering fractional distillation separation practically impossible.


Part 3: Corey-House (Gilman) Synthesis of 2-Methylpentane

The Corey-House cross-coupling employs a Lithium Dialkylcuprate (Gilman reagent) $\text{R}_2\text{CuLi}$, which couples selectively with primary alkyl halides via a soft organometallic pathway without basic elimination:

1. Step 1: Preparation of Organolithium:

$$(\text{CH}_3)_2\text{CH}-\text{Br} + 2\,\text{Li} \xrightarrow{\text{dry pentane}} (\text{CH}_3)_2\text{CH}-\text{Li} + \text{LiBr}$$

2. Step 2: Generation of Lithium Diisopropylcuprate:

$$2\,(\text{CH}_3)_2\text{CH}-\text{Li} + \text{CuI} \xrightarrow{\text{dry } \text{Et}_2\text{O}, -78^\circ\text{C}} [(\text{CH}_3)_2\text{CH}]_2\text{CuLi} + \text{LiI}$$

3. Step 3: Cross-Coupling with 1-Bromopropane:

$$[(\text{CH}_3)_2\text{CH}]_2\text{CuLi} + \text{CH}_3\text{CH}_2\text{CH}_2-\text{Br} \xrightarrow{0^\circ\text{C}} \mathbf{(\text{CH}_3)_2\text{CH}-\text{CH}_2\text{CH}_2\text{CH}_3} + (\text{CH}_3)_2\text{CH}-\text{Cu} + \text{LiBr}$$

Product: 2-Methylpentane (isolated yield $>85\%$).

Why this succeeds: Organocuprates are 'soft' nucleophiles that undergo oxidative addition followed by reductive elimination at primary alkyl carbons, completely eliminating competitive $E2$ elimination and self-coupling side-products.

Advanced Honors Problem Example 2.5: Conformational Free Energy & Population of trans-1,4-Di-tert-butylcyclohexane

For trans-1,4-di-tert-butylcyclohexane, one tert-butyl group must be equatorial and the other must be axial if the ring adopts a chair conformation. Given that the A-value for a tert-butyl group is 4.90 kcal/mol (20.5 kJ/mol) and the twist-boat conformation of cyclohexane lies 5.50 kcal/mol (23.0 kJ/mol) above the chair conformation: (1) Calculate the free energy difference between the chair conformation (with one axial t-Bu) and the twist-boat conformation (where both t-Bu groups occupy equatorial-like pseudo-equatorial positions). (2) Determine the equilibrium mole fraction of twist-boat molecules present in a liquid sample at 298 K. (3) State the dynamic physical implications of this balance.

Part 1: Free Energy Calculation for Both Conformations

1. Chair Conformation ($\text{Chair}_{e,a}$):

  • One tert-butyl group is equatorial ($0.0\text{ kcal/mol}$).
  • The second tert-butyl group is forced into the axial position, incurring the full 1,3-diaxial steric strain penalty:
$$E(\text{Chair}_{e,a}) = A(\text{tert-butyl}) = \mathbf{+4.90\text{ kcal/mol}} \quad (+20.50\text{ kJ/mol})$$

2. Twist-Boat Conformation ($\text{Twist-Boat}_{e',e'}$):

  • In the twist-boat conformation, both the C1 and C4 positions can simultaneously accommodate bulky substituents in pseudo-equatorial positions with virtually zero 1,3-diaxial steric clash!
  • However, the cyclohexane ring skeleton itself incurs the intrinsic ring strain of the twist-boat:
$$E(\text{Twist-Boat}_{e',e'}) = \Delta G_{\text{twist-boat}} + 2 \times E_{\text{strain}}(\text{pseudo-eq}) = 5.50 + 2(0.10) = \mathbf{+5.70\text{ kcal/mol}} \quad (+23.85\text{ kJ/mol})$$

3. Net Free Energy Difference:

$$\Delta G^\circ = E(\text{Twist-Boat}) - E(\text{Chair}) = 5.70 - 4.90 = \mathbf{+0.80\text{ kcal/mol}} \quad (\mathbf{+3.35\text{ kJ/mol}})$$

The chair conformation remains favored by only $0.80\text{ kcal/mol}$!

Part 2: Equilibrium Mole Fraction at $298\text{ K}$

Using the Boltzmann distribution:

$$K = \frac{[\text{Twist-Boat}]}{[\text{Chair}]} = \exp\left(-\frac{\Delta G^\circ}{R T}\right)$$

Using $R = 1.987 \times 10^{-3}\text{ kcal}/(\text{mol}\cdot\text{K})$ and $T = 298.15\text{ K}$:

$$R T = (1.987 \times 10^{-3})(298.15) \approx 0.5924\text{ kcal/mol}$$
$$K = \exp\left(-\frac{0.80}{0.5924}\right) = \exp(-1.350) \approx \mathbf{0.259}$$

The mole fraction of the twist-boat conformer ($x_{\text{TB}}$) is:

$$x_{\text{TB}} = \frac{K}{1 + K} = \frac{0.259}{1 + 0.259} = \frac{0.259}{1.259} \approx \mathbf{0.206} \quad (\mathbf{20.6\%})$$
Part 3: Physical Organic Significance

In trans-1,4-di-tert-butylcyclohexane, over $20\%$ of all molecules exist in the non-chair twist-boat conformation at room temperature! This is one of the rare instances where extreme steric clash overrides the thermodynamic preference of the cyclohexane ring for the chair conformation, providing a classic system for measuring pure twist-boat activation barriers via dynamic low-temperature NMR.

Graduate Level Derivation Example 2.6: Rice-Herzfeld Steady-State Radical Chain Derivation for Alkane Thermal Cracking

Derive the theoretical rate equation for the thermal decomposition of ethane (C2H6 -> C2H4 + H2) at 850 K using the classic Rice-Herzfeld free-radical mechanism: (1) Initiation: C2H6 -> 2 CH3 (k1); (2) Transfer: CH3 + C2H6 -> CH4 + C2H5 (k2); (3) Propagation: C2H5 -> C2H4 + H (k3); (4) Propagation: H + C2H6 -> H2 + C2H5 (k4); (5) Termination: H + C2H5* -> C2H6 (k5). Prove that under steady-state conditions, the rate of ethylene production is first-order in ethane concentration: v = k_eff [C2H6]. Express k_eff in terms of elementary rate constants.

Step 1: Write Elementary Reaction Rates
  1. Initiation: $r_1 = k_1 [\text{C}_2\text{H}_6]$
  2. Transfer: $r_2 = k_2 [\text{CH}_3^\bullet][\text{C}_2\text{H}_6]$
  3. Propagation 1: $r_3 = k_3 [\text{C}_2\text{H}_5^\bullet]$
  4. Propagation 2: $r_4 = k_4 [\text{H}^\bullet][\text{C}_2\text{H}_6]$
  5. Termination: $r_5 = k_5 [\text{H}^\bullet][\text{C}_2\text{H}_5^\bullet]$
Step 2: Pseudo-Steady-State Approximations (PSSA)

For active radical intermediates ($\text{CH}_3^\bullet, \text{H}^\bullet, \text{C}_2\text{H}_5^\bullet$):

1. Methyl Radical $[\text{CH}_3^\bullet]$:

$$\frac{d[\text{CH}_3^\bullet]}{dt} = 2 k_1 [\text{C}_2\text{H}_6] - k_2 [\text{CH}_3^\bullet][\text{C}_2\text{H}_6] = 0 \implies k_2 [\text{CH}_3^\bullet][\text{C}_2\text{H}_6] = 2 k_1 [\text{C}_2\text{H}_6] \tag{1}$$

2. Hydrogen Atom $[\text{H}^\bullet]$:

$$\frac{d[\text{H}^\bullet]}{dt} = k_3 [\text{C}_2\text{H}_5^\bullet] - k_4 [\text{H}^\bullet][\text{C}_2\text{H}_6] - k_5 [\text{H}^\bullet][\text{C}_2\text{H}_5^\bullet] = 0 \tag{2}$$

3. Ethyl Radical $[\text{C}_2\text{H}_5^\bullet]$:

$$\frac{d[\text{C}_2\text{H}_5^\bullet]}{dt} = k_2 [\text{CH}_3^\bullet][\text{C}_2\text{H}_6] - k_3 [\text{C}_2\text{H}_5^\bullet] + k_4 [\text{H}^\bullet][\text{C}_2\text{H}_6] - k_5 [\text{H}^\bullet][\text{C}_2\text{H}_5^\bullet] = 0 \tag{3}$$
Step 3: Radical Concentration Balancing

Adding Equation (2) and Equation (3) and substituting Equation (1):

$$2 k_1 [\text{C}_2\text{H}_6] - 2 k_5 [\text{H}^\bullet][\text{C}_2\text{H}_5^\bullet] = 0$$
$$[\text{H}^\bullet][\text{C}_2\text{H}_5^\bullet] = \frac{k_1}{k_5} [\text{C}_2\text{H}_6] \tag{4}$$

For long chain lengths ($\text{chain length} \gg 1$), the propagation rate $r_4 \gg r_5$:

$$k_3 [\text{C}_2\text{H}_5^\bullet] \approx k_4 [\text{H}^\bullet][\text{C}_2\text{H}_6] \implies [\text{H}^\bullet] \approx \frac{k_3 [\text{C}_2\text{H}_5^\bullet]}{k_4 [\text{C}_2\text{H}_6]} \tag{5}$$

Substitute Equation (5) into Equation (4):

$$\left( \frac{k_3 [\text{C}_2\text{H}_5^\bullet]}{k_4 [\text{C}_2\text{H}_6]} \right) [\text{C}_2\text{H}_5^\bullet] = \frac{k_1}{k_5} [\text{C}_2\text{H}_6]$$
$$[\text{C}_2\text{H}_5^\bullet]^2 = \frac{k_1 k_4}{k_3 k_5} [\text{C}_2\text{H}_6]^2 \implies \mathbf{[\text{C}_2\text{H}_5^\bullet] = \sqrt{\frac{k_1 k_4}{k_3 k_5}} [\text{C}_2\text{H}_6]} \tag{6}$$
Step 4: Net Rate of Ethylene Formation

The net rate of ethylene production is the propagation step $r_3$:

$$v = \frac{d[\text{C}_2\text{H}_4]}{dt} = k_3 [\text{C}_2\text{H}_5^\bullet] = k_3 \sqrt{\frac{k_1 k_4}{k_3 k_5}} [\text{C}_2\text{H}_6] = \mathbf{\sqrt{\frac{k_1 k_3 k_4}{k_5}} [\text{C}_2\text{H}_6]} \tag{7}$$

Thus, $v = k_{\text{eff}} [\text{C}_2\text{H}_6]$ where:

$$\mathbf{k_{\text{eff}} = \left(\frac{k_1 k_3 k_4}{k_5}\right)^{1/2}}$$

The reaction is strictly first-order in ethane, exactly matching experimental gas-phase pyrolytic measurements!

Research Level Problem Example 2.7: Boltzmann Conformational Partition Function for 1-Fluoro-4-methylcyclohexane

For cis-1-fluoro-4-methylcyclohexane, both substituents cannot be equatorial simultaneously: Conformer A has an equatorial methyl and an axial fluorine, while Conformer B has an axial methyl and an equatorial fluorine. Given A(Me) = 1.74 kcal/mol and A(F) = 0.25 kcal/mol: (1) Calculate the standard Gibbs free energy difference Delta G° between Conformer A and Conformer B. (2) Calculate the canonical conformational partition function q_conf and the exact percentage of Conformer A at 195 K (dry ice/acetone) versus 298 K.

Part 1: Standard Free Energy Difference $\Delta G^\circ$

1. Conformer A (Equatorial Methyl, Axial Fluorine):

  • Energy penalty: $E_A = A(\text{F}) = \mathbf{+0.25\text{ kcal/mol}}$

2. Conformer B (Axial Methyl, Equatorial Fluorine):

  • Energy penalty: $E_B = A(\text{Me}) = \mathbf{+1.74\text{ kcal/mol}}$

3. Difference:

$$\Delta G^\circ = E_B - E_A = 1.74 - 0.25 = \mathbf{+1.49\text{ kcal/mol}} \quad (\mathbf{+6.23\text{ kJ/mol}})$$

Conformer A is thermodynamically more stable by $1.49\text{ kcal/mol}$!

Part 2: Partition Function and Conformational Populations

Using the canonical conformational partition function:

$$q_{\text{conf}} = 1 + \exp\left(-\frac{\Delta G^\circ}{R T}\right) \tag{1}$$

The equilibrium constant is $K = [A] / [B] = \exp(+\Delta G^\circ / RT)$.

1. At $T = 298.15\text{ K}$:

$$R T = (1.987 \times 10^{-3})(298.15) \approx 0.5924\text{ kcal/mol}$$
$$K_{298} = \exp\left(\frac{1.49}{0.5924}\right) = \exp(2.515) \approx \mathbf{12.37}$$
$$P(A)_{298} = \frac{K}{1 + K} = \frac{12.37}{13.37} \approx \mathbf{0.925} \quad (\mathbf{92.5\%})$$

2. At $T = 195.0\text{ K}$ (Cryogenic NMR conditions):

$$R T = (1.987 \times 10^{-3})(195.0) \approx 0.3875\text{ kcal/mol}$$
$$K_{195} = \exp\left(\frac{1.49}{0.3875}\right) = \exp(3.845) \approx \mathbf{46.77}$$
$$P(A)_{195} = \frac{46.77}{47.77} \approx \mathbf{0.979} \quad (\mathbf{97.9\%})$$
  • Cooling to $195\text{ K}$ purifies the conformational population of Conformer A to nearly $98\%$, allowing clean, unperturbed NMR spectral resolution of axial versus equatorial fluorine coupling!
Retrosynthesis & Physical Analysis Example 2.8: Retrosynthetic Analysis & Cage Symmetry of Adamantane (Tricyclo[3.3.1.1^3,7]decane)

Adamantane (C10H16) is a rigid, strain-free diamondoid hydrocarbon possessing tetrahedral Td point group symmetry: (1) Prove using Newman projections that all ten carbon-carbon bonds in adamantane are locked into perfectly staggered chair cyclohexane conformations with zero angle and zero torsional strain. (2) Track Paul von Ragué Schleyer's historic 1957 one-step Lewis-acid catalyzed synthesis of adamantane from endo-tetrahydrodicyclopentadiene. (3) Why does the thermodynamic cascade yield adamantane in over 70% yield despite requiring dozens of carbocation rearrangements?

Part 1: Diamondoid Symmetry and Zero Strain

1. Cage Architecture:

  • Adamantane consists of four fused cyclohexane rings arranged in a three-dimensional cage resembling the crystal lattice of diamond.
  • It possesses four bridgehead tertiary ($\text{C}-\text{H}$) carbons and six secondary ($-\text{CH}_2-$) carbons.

2. Conformational Analysis:

  • Sighting down every single $\text{C}-\text{C}$ bond reveals a perfectly staggered dihedral angle ($\phi = 60^\circ$).
  • Every carbon atom has an internuclear bond angle of $\theta = 109.5^\circ$, exactly matching the ideal tetrahedral angle.
  • Consequently, both angle strain and torsional strain are identically zero!
  • Its standard enthalpy of formation ($\Delta H_f^\circ = -134.6\text{ kJ/mol}$) confirms it is the most thermodynamically stable $\text{C}_{10}\text{H}_{16}$ isomer in existence.
Part 2: Schleyer's Catalyzed Rearrangement

In 1957, Paul von Ragué Schleyer discovered that hydrogenating dicyclopentadiene yields endo-tetrahydrodicyclopentadiene:

$$\text{endo-Tetrahydrodicyclopentadiene} \xrightarrow{\text{catalytic } \text{AlCl}_3 \text{ or } \text{AlBr}_3, \; 150^\circ\text{C}} \mathbf{\text{Adamantane}} \tag{1}$$
  • Mechanistic Cascade:
  1. The strong Lewis acid $\text{AlCl}_3$ abstracts a hydride ion ($\text{H}^-$) from the strained precursor to initiate a cascade of carbocation generation.
  2. The carbocation traverses a labyrinth of over twenty consecutive Wagner-Meerwein 1,2-alkyl and 1,2-hydride shifts.
  3. Every intermediate carbocation exists in dynamic equilibrium with other ring systems.
Part 3: Thermodynamic Driving Force (The "Thermodynamic Sink")
  • Because all reversible carbocation shifts are in rapid dynamic equilibrium under strong Lewis acidic conditions, the reaction is entirely governed by thermodynamic control.
  • The starting material endo-tetrahydrodicyclopentadiene contains substantial ring strain ($\sim 45\text{ kJ/mol}$).
  • Adamantane represents the absolute global potential energy minimum on the $\text{C}_{10}\text{H}_{16}$ potential energy surface.
  • Once a molecule rearranges into the strain-free adamantyl skeleton, it drains into an irrecoverable thermodynamic energy well and crystallizes from the reaction mixture ($mp = 270^\circ\text{C}$ in a sealed capillary), pulling the entire equilibrium cascade forward into $>70\%$ isolated yield!