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Chapter 3 • Theory & Derivations

Metal Carbonyls, Nitrosyls & Phosphine Complexes

Synthesis, structures, bonding and reactions of metal carbonyls, nitrosyls and phosphines. Dewar-Chatt-Duncanson sigma-donation and pi-backbonding, Cotton-Kraihanzel vibrational force field, linear vs bent nitrosyls, Enemark-Feltham notation, Tolman cone angles and electronic parameters, natural bite angle in chelating diphosphines, Collman's reagent, and fluxional carbonyl scrambling.

§3.1 §3.1 Synthesis of Binary and Mixed Metal Carbonyls

Metal carbonyls are the cornerstones of transition metal organometallic chemistry. In these complexes, carbon monoxide acts as an amphiphilic $\pi$-acid ligand, stabilizing transition metals in low or zero formal oxidation states.

Primary Synthetic Methods:

1. Direct Carbonylation: Highly electropositive metals in fine division react directly with gaseous carbon monoxide at elevated pressure:

\[\text{Ni (powder)} + 4\,\text{CO} \xrightarrow{1\text{ atm},\, 50^\circ\text{C}} \text{Ni}(\text{CO})_4 \quad (\text{Mond Process})\]
\[\text{Fe (spongy)} + 5\,\text{CO} \xrightarrow{100-200\text{ atm},\, 150-200^\circ\text{C}} \text{Fe}(\text{CO})_5\]

2. Reductive Carbonylation: Transition metal halides in higher oxidation states are reduced in the presence of carbon monoxide using reducing agents such as aluminum powder, triethylaluminum, sodium, or magnesium:

\[\text{CrCl}_3 + 6\,\text{CO} + \text{Al} \xrightarrow{\text{benzene},\, 300\text{ atm}} \text{Cr}(\text{CO})_6 + \text{AlCl}_3\]
\[2\,\text{CoCO}_3 + 2\,\text{H}_2 + 8\,\text{CO} \xrightarrow{250\text{ atm},\, 150^\circ\text{C}} \text{Co}_2(\text{CO})_8 + 2\,\text{CO}_2 + 2\,\text{H}_2\text{O}\]
\[\text{WCl}_6 + 6\,\text{CO} + 2\,\text{AlEt}_3 \longrightarrow \text{W}(\text{CO})_6 + 2\,\text{AlCl}_3 + 3\,\text{C}_4\text{H}_{10}\]

3. Photochemical and Thermal Substitution: Carbon monoxide dissociates photochemically via metal-to-ligand charge transfer (MLCT) or ligand-field excitation, generating coordination-unsaturated intermediates that capture incoming ligands ($L = PR_3$, alkene, solvent):

\[\text{Cr}(\text{CO})_6 \xrightarrow{h\nu} [\text{Cr}(\text{CO})_5] + \text{CO} \uparrow \xrightarrow{L} \text{Cr}(\text{CO})_5 L\]
\[2\,\text{Fe}(\text{CO})_5 \xrightarrow{h\nu, \text{ glacial acetic acid}} \text{Fe}_2(\text{CO})_9 \downarrow + \text{CO} \uparrow\]

§3.2 §3.2 The Dewar-Chatt-Duncanson Bonding Model in Metal Carbonyls

The bonding between a transition metal and carbon monoxide is governed by the synergistic Dewar-Chatt-Duncanson (DCD) model, comprising two complementary components:

1. $\sigma$-Donation:

  • The carbon monoxide molecule possesses a filled non-bonding orbital centered primarily on carbon: the $5\sigma$ molecular orbital (HOMO of CO, possessing weakly antibonding character with respect to the $C-O$ bond).
  • The lone pair in this $5\sigma$ orbital donates electron density into an empty metal valence orbital of matching $\sigma$-symmetry (e.g., $d_{z^2}$, $d_{x^2-y^2}$, $s$, or $p$ hybrids):
\[M \xleftarrow{\quad\sigma\quad} :\text{C}\equiv\text{O}\]
  • This $\sigma$-donation polarizes charge toward the metal center, building negative charge on the metal.

2. $\pi$-Backbonding ($\pi$-Backdonation):

  • Carbon monoxide possesses two degenerate, empty, low-lying antibonding $\pi^$ orbitals: the $2\pi^$ molecular orbitals (LUMO of CO).
  • Filled metal valence $d$-orbitals of appropriate $\pi$-symmetry ($d_{xy}, d_{yz}, d_{xz}$ or $t_{2g}$ in $O_h$) overlap with these empty $2\pi^*$ orbitals:
\[M \xrightarrow{\quad\pi\quad} \text{C}\equiv\text{O}\]
  • Electrons from the metal are backdonated into the ligand $\pi^*$ LUMO.

Synergism and Bond Order Consequences:

  • $\sigma$-donation transfers electron density to the metal, increasing the metal's basicity and enhancing its ability to backdonate.
  • $\pi$-backdonation relieves metal electron excess, increasing the Lewis acidity of the metal and facilitating further $\sigma$-donation.
  • Effect on $M-C$ Bond: $\pi$-backbonding increases the $M-C$ bond order toward a double bond ($M=C=\text{O}$), shortening the $M-C$ distance and strengthening the $M-C$ bond.
  • Effect on $C-O$ Bond: Populating the $C-O$ antibonding $2\pi^*$ orbital decreases the $C-O$ bond order from a formal triple bond toward a double bond, lengthening the $C-O$ bond distance and lowering its vibrational stretching frequency $\nu(CO)$.

§3.3 §3.3 Infrared Spectroscopy of Carbonyls: $\nu(CO)$ Vibrational Modes & Cotton-Kraihanzel Force Constants

Infrared (IR) spectroscopy is the most sensitive diagnostic tool for probing the electronic environment of metal carbonyls. The vibrational stretching frequency of free gaseous carbon monoxide is:

\[\nu(CO)_\text{free} = 2143\text{ cm}^{-1}\]

Electronic Effects of Metal Oxidation State and Charge:

When backbonding increases, electron density in $\pi^*$ increases, lowering the force constant $k_{CO}$ according to Hooke's Law:

\[\nu = \frac{1}{2\pi c} \sqrt{\frac{k}{\mu}}\]

where $\mu = \frac{m_C m_O}{m_C + m_O}$ is the reduced mass. Consider the isoelectronic hexacarbonyl series ($d^6$ octahedral):

  • $[\text{Mn}(\text{CO})_6]^+$: $\nu(CO) = 2090\text{ cm}^{-1}$ (positive charge contracts $d$-orbitals; weak backbonding)
  • $\text{Cr}(\text{CO})_6$: $\nu(CO) = 2000\text{ cm}^{-1}$ (neutral; balanced $\sigma$-donation and $\pi$-backbonding)
  • $[\text{V}(\text{CO})_6]^-$: $\nu(CO) = 1860\text{ cm}^{-1}$ (negative charge expands $d$-orbitals; strong backbonding)
  • $[\text{Ti}(\text{CO})_6]^{2-}$: $\nu(CO) = 1750\text{ cm}^{-1}$ (enormous backbonding; $C-O$ bond approaches double bond)

Bridging vs. Terminal Carbonyl Coordination Modes:

As carbon monoxide coordinates to more metal centers, each additional metal contributes $\pi$-backbonding density into the same $2\pi^*$ LUMO:

  • Terminal $M-\text{CO}$: $\nu(CO) = 2125 - 1850\text{ cm}^{-1}$
  • Doubly Bridging $\mu_2-\text{CO}$: $\nu(CO) = 1850 - 1750\text{ cm}^{-1}$ (ketonic stretch)
  • Triply Bridging $\mu_3-\text{CO}$: $\nu(CO) = 1730 - 1620\text{ cm}^{-1}$
  • Four-fold Bridging $\mu_4-\text{CO}$: $\nu(CO) < 1600\text{ cm}^{-1}$

Cotton-Kraihanzel Force Field:

Under the Cotton-Kraihanzel approximation, carbonyl stretching frequencies are modeled by secular equations factoring in the primary $C-O$ stretching force constant $k$ and the interaction force constants $k_c$ (cis-interaction) and $k_t$ (trans-interaction) transmitted through the metal $d$-orbitals.

§3.4 §3.4 Metal Nitrosyl Complexes: Linear ($ ext{NO}^+$) vs. Bent ($ ext{NO}^-$) Coordination

Nitric oxide ($\text{NO}$) is an open-shell radical possessing 15 valence electrons with an unpaired electron residing in its $2\pi^*$ orbital. Upon binding transition metals, it adopts two distinct, interconvertible coordination geometries:

1. Linear Nitrosyl ($M-\text{N}\equiv\text{O}$, angle $\approx 180^\circ$):

  • Formalism: Nitrosyl is formally treated as nitrosonium cation $\text{NO}^+$ (isoelectronic with $\text{CO}$, 14 valence electrons).
  • Electron Counting:
  • In the Covalent Model, linear $\text{NO}$ is counted as a 3-electron donor ($LX$-type: 1 electron from radical pairing plus 2 electrons from the nitrogen lone pair).
  • In the Ionic Model, $\text{NO}^+$ is a 2-electron donor, and the metal oxidation state is reduced by 1.
  • Bonding: $sp$ hybridization at nitrogen. One $\sigma$-dative bond from nitrogen to metal and two degenerate $\pi$-backbonds from metal $d_{xz}, d_{yz}$ into $\text{NO}$ $\pi^*$ orbitals.
  • IR Spectroscopy: $\nu(NO) = 1650 - 1900\text{ cm}^{-1}$ (high stretching frequency due to triple bond character).

2. Bent Nitrosyl ($M-\text{N}=\text{O}$, angle $\approx 120^\circ - 140^\circ$):

  • Formalism: Nitrosyl is formally treated as nitroxyl anion $\text{NO}^-$ (16 valence electrons).
  • Electron Counting:
  • In the Covalent Model, bent $\text{NO}$ is counted as a 1-electron donor ($X$-type: radical single bond).
  • In the Ionic Model, $\text{NO}^-$ is a 2-electron donor, but the metal formal oxidation state increases by 1.
  • Bonding: $sp^2$ hybridization at nitrogen with a localized lone pair residing in the non-bonding $sp^2$ hybrid orbital, causing the bent geometry.
  • IR Spectroscopy: $\nu(NO) = 1525 - 1690\text{ cm}^{-1}$ (lower stretching frequency due to formal double bond).

The Enemark-Feltham Notation $\{M(\text{NO})_x\}^n$:

Because assigning formal oxidation states to non-innocent nitrosyl ligands is ambiguous, Enemark and Feltham introduced the notation $\{M(\text{NO})_x\}^n$, where $n$ is the total number of electrons in the metal $d$-orbitals plus the $\text{NO}$ $\pi^*$ orbitals:

\[n = d^\text{electrons} + \text{electrons in } \pi^*(\text{NO})\]

For example, in the nitroprusside anion $[\text{Fe}(\text{CN})_5(\text{NO})]^{2-}$, the system is classified as $\{Fe(\text{NO})\}^6$, adopting an idealized linear geometry.

§3.5 §3.5 Phosphine Ligands: Electronic Properties, $\sigma$-Donation and $\pi$-Acceptance into $\sigma^*$ Orbitals

Tertiary phosphines ($PR_3$) are premier spectator ligands in homogeneous catalysis, offering exceptional electronic and steric tuneability.

Dual Bonding Mechanism:

1. $\sigma$-Donation:

  • The phosphorus atom possesses a lone pair residing in an $sp^3$-like hybrid orbital with substantial $3s$ and $3p$ character.
  • This lone pair donates into an empty metal valence orbital, forming a strong $M-P$ $\sigma$-bond.
  • $\sigma$-donor strength depends on the electron-donating capability of the $R$ substituents:
\[P(t\text{-Bu})_3 > \text{PMe}_3 > \text{PPh}_3 > \text{P(OMe)}_3 > \text{P(OPh)}_3 > \text{PF}_3\]

2. $\pi$-Acceptor Capability:

  • Early models attributed $\pi$-acceptance in phosphines to vacant, high-energy phosphorus $3d$ orbitals.
  • Modern molecular orbital calculations (Orpen, Connelly, Marynick) reveal that $\pi$-acceptance occurs via backdonation from filled metal $d$-orbitals into empty $\sigma^*(P-R)$ antibonding orbitals of the phosphine:
\[d_\pi(M) \longrightarrow \sigma^*(P-R)\]
  • When $R$ is highly electronegative (e.g., $F, OPh, CF_3$), the $\sigma^*(P-R)$ orbital is stabilized to lower energy and polarized toward phosphorus, maximizing overlap with metal $d$-orbitals.
  • Remarkably, phosphorus trifluoride ($\text{PF}_3$) is such a potent $\pi$-acceptor that its bonding properties and electronic spectrum closely match those of carbon monoxide ($CO$).

§3.6 §3.6 Tolman Steric Parameter (Cone Angle $\theta$) and Electronic Parameter (TEP $\chi$)

Chadwick A. Tolman established quantitative steric and electronic metrics that parameterized phosphine behavior across organometallic chemistry.

Tolman Cone Angle ($\theta$):

The Tolman cone angle measures ligand steric bulk. It is defined as the vertex angle of a cylindrical cone centered at a metal atom situated at a standard distance of $2.28$ Å from the phosphorus atom, whose perimeter encloses the van der Waals radii of all atoms of the three $R$ substituents. For unsymmetrical phosphines $P R_1 R_2 R_3$:

\[\theta = \frac{2}{3} \sum_{i=1}^3 \frac{\theta_i}{2}\]

Representative Cone Angles:

  • $\text{PH}_3$: $87^\circ$
  • $\text{PF}_3$: $104^\circ$
  • $\text{PMe}_3$: $118^\circ$
  • $\text{PEt}_3$: $132^\circ$
  • $\text{PPh}_3$: $145^\circ$
  • $\text{P}(i\text{-Pr})_3$: $160^\circ$
  • $\text{PCy}_3$: $170^\circ$
  • $\text{P}(t\text{-Bu})_3$: $182^\circ$
  • $\text{P}(o\text{-tolyl})_3$: $194^\circ$

Tolman Electronic Parameter (TEP, $\chi$):

The electronic donating ability of a phosphine is quantified by measuring the symmetric $A_1$ carbonyl stretching frequency $\nu(CO)$ in the standard nickel complex $\text{Ni}(\text{CO})_3(PR_3)$:

\[\nu(CO)_{A_1} = 2056.1 + \sum_{i=1}^3 \chi_i \quad (\text{cm}^{-1})\]

where $\chi_i$ is the substituent electronic contribution (defined with $\chi = 0$ for $t\text{-Bu}$).

  • Electron-rich phosphines (e.g., $\text{PMe}_3, \text{P}(t\text{-Bu})_3$) transfer more electron density to nickel, maximizing $\pi$-backbonding into the three CO ligands and depressing $\nu(CO)$ ($\\approx 2064\text{ cm}^{-1}$).
  • Poor donor/strong $\pi$-acceptor phosphines (e.g., $\text{PF}_3$) compete with CO for metal backdonation, shifting $\nu(CO)$ to higher frequencies ($2111\text{ cm}^{-1}$).

§3.7 §3.7 Chelating Diphosphines: Natural Bite Angle $\beta_n$ and Catalytic Selectivity

Bidentate diphosphines ($R_2\text{P}-\text{Linker}-\text{P}R_2$) bind metal centers in a chelating mode, enforcing a specific geometry.

The Natural Bite Angle ($\beta_n$):

Introduced by Piet van Leeuwen and Casey, the natural bite angle ($\beta_n$) is defined by molecular mechanics computations as the preferred $P-M-P$ valence angle determined solely by the steric constraints of the diphosphine backbone, with a standard $M-P$ bond length (typically $2.315$ Å) and without electronic ligand field contributions.

Representative Diphosphines and Natural Bite Angles:

  • dppm ($ ext{Ph}_2\text{PCH}_2\text{PPh}_2$): $\beta_n \approx 72^\circ$ (often forms bridging rather than chelating complexes)
  • dppe ($ ext{Ph}_2\text{PCH}_2\text{CH}_2\text{PPh}_2$): $\beta_n \approx 85^\circ$ (prefers octahedral and square planar geometries)
  • dppp ($ ext{Ph}_2\text{P(CH}_2)_3\text{PPh}_2$): $\beta_n \approx 91^\circ$
  • dppb ($ ext{Ph}_2\text{P(CH}_2)_4\text{PPh}_2$): $\beta_n \approx 98^\circ$
  • BINAP ($2,2'$-bis(diphenylphosphino)-$1,1'$-binaphthyl): $\beta_n \approx 93^\circ$ (chiral $C_2$-symmetric backbone for asymmetric catalysis)
  • dppf ($1,1'$-bis(diphenylphosphino)ferrocene): $\beta_n \approx 99^\circ$
  • Xantphos (4,5-bis(diphenylphosphino)-9,9-dimethylxanthene): $\beta_n \approx 111^\circ$

Impact on Catalytic Rates and Regioselectivity:

1. Reductive Elimination Acceleration: A wide bite angle (e.g., Xantphos $\beta_n \approx 111^\circ$) forces the two coupling organic groups closer together, compressing their dihedral angle and accelerating reductive elimination by factors exceeding $10^4$.

2. Hydroformylation Regioselectivity: In Rh-catalyzed hydroformylation of 1-alkenes, wide bite angle diphosphines force the two phosphorus atoms to occupy equatorial-equatorial ($ee$) positions in trigonal bipyramidal intermediates, steering the linear-to-branched aldehyde ratio ($l:b$) to $>50:1$.

§3.8 §3.8 Chemical Reactivity: Nucleophilic Attack, Disproportionation & Collman's Reagent

Metal carbonyl complexes display rich chemical transformations driven by the polarity of coordinated CO:

1. Nucleophilic Attack on Coordinated Carbonyls:

Because $\sigma$-donation and metal-to-ligand backbonding withdraw electron density from the carbonyl carbon atom, coordinated CO is electrophilic:

  • Hydroxide Attack (Water-Gas Shift Intermediate):
\[[M-\text{CO}] + \text{OH}^- \longrightarrow [M-\text{COOH}]^- \xrightarrow{-\text{CO}_2} [M-\text{H}]^-\]
  • Organolithium Addition (Fischer Carbene Synthesis):
\[\text{Cr}(\text{CO})_6 + \text{MeLi} \longrightarrow [(\text{OC})_5\text{Cr}-\text{C}(=\text{O})\text{Me}]^- \text{Li}^+ \xrightarrow{[\text{Me}_3\text{O}]^+\text{BF}_4^-} (\text{OC})_5\text{Cr}=\text{C}(\text{OMe})\text{Me}\]

2. Disproportionation with Hard Lewis Bases:

Reaction of metal carbonyls with hard, coordinating Lewis bases (e.g., pyridine, ammonia) induces valence disproportionation:

\[3\,\text{Mn}_2(\text{CO})_{10} + 12\,\text{py} \longrightarrow 2\,[\text{Mn}(\text{py})_6]^{2+} + 4\,[\text{Mn}(\text{CO})_5]^- + 10\,\text{CO} \uparrow\]

3. Collman's Reagent: Disodium Tetracarbonylferrate:

Reduction of iron pentacarbonyl with sodium amalgam or sodium naphthalenide yields Collman's reagent:

\[\text{Fe}(\text{CO})_5 + 2\,\text{Na} \xrightarrow{\text{THF}} \text{Na}_2[\text{Fe}(\text{CO})_4] + \text{CO} \uparrow\]

The ferrate dianion $[\text{Fe}(\text{CO})_4]^{2-}$ is a 'super-nucleophile' with an iron oxidation state of $-2$ ($d^{10}$, 18 valence electrons). It reacts cleanly with primary alkyl halides:

\[[\text{Fe}(\text{CO})_4]^{2-} + R-\text{X} \longrightarrow [R-\text{Fe}(\text{CO})_4]^- + \text{X}^- \xrightarrow{\text{CO}} [R\text{CO}-\text{Fe}(\text{CO})_4]^- \xrightarrow{\text{H}^+} R\text{CHO}\]

providing a versatile entry to aldehydes, unsymmetrical ketones, esters, and amides.

Worked Practice Problems (9 Challenge Exercises)

Multi-step solved problems covering neutral vs ionic electron counting, d-electron configuration determination, 16-electron square planar stabilization, metal-metal single and multiple bond orders, bridging ligand electron partitioning, and 3c-2e bridge thermodynamic equilibria with line-by-line mathematical proofs.

Foundational Example 3.1: Isoelectronic Carbonyl Series and $\nu(CO)$ Infrared Frequency Shifts

The infrared carbonyl stretching frequencies for the octahedral $d^6$ hexacarbonyl series are: $[\text{Ir}(\text{CO})_6]^{3+} (2254\text{ cm}^{-1})$, $[\text{Os}(\text{CO})_6]^{2+} (2190\text{ cm}^{-1})$, $[\text{Re}(\text{CO})_6]^+ (2085\text{ cm}^{-1})$, $\text{W}(\text{CO})_6 (1998\text{ cm}^{-1})$, $[\text{Ta}(\text{CO})_6]^- (1850\text{ cm}^{-1})$, $[\text{Hf}(\text{CO})_6]^{2-} (1750\text{ cm}^{-1})$. (a) Explain the continuous decrease of $\nu(CO)$ across this series using the Dewar-Chatt-Duncanson model. (b) Explain why $[\text{Ir}(\text{CO})_6]^{3+}$ exhibits a $\nu(CO)$ higher than free gaseous CO ($2143\text{ cm}^{-1}$) ('non-classical metal carbonyl').

Line-by-Line Solution:

(a) Physical Origin of Frequency Decrease Across the Series:

  • All species in the series are isoelectronic with an octahedral $d^6$ valence configuration ($t_{2g}^6$).
  • As the net charge changes from $+3$ to $-2$:
\[+3 \longrightarrow +2 \longrightarrow +1 \longrightarrow 0 \longrightarrow -1 \longrightarrow -2\]

the nuclear charge $Z$ decreases relative to the electron count, and the effective nuclear charge $Z_\text{eff}$ experienced by the metal valence $d$-electrons decreases precipitously.

  • A lower $Z_\text{eff}$ causes radial expansion of the metal $d_{xy}, d_{yz}, d_{xz}$ ($t_{2g}$) orbitals, raising their energy levels closer to the empty $2\pi^*$ LUMO of the coordinated carbon monoxide ligands.
  • Consequently, metal-to-ligand $\pi$-backbonding increases enormously:
\[d_\pi(M) \xrightarrow{\text{intense overlap}} \pi^*(\text{CO})\]
  • Population of the $C-O$ antibonding $2\pi^*$ orbital weakens the carbon-oxygen bond, reducing the $C-O$ bond order and force constant $k_{CO}$.
  • According to Hooke's Law:
\[\nu(CO) = \frac{1}{2\pi c} \sqrt{\frac{k_{CO}}{\mu}}\]

A lower force constant $k_{CO}$ produces a continuous decrease in $\nu(CO)$ from $2254\text{ cm}^{-1}$ down to $1750\text{ cm}^{-1}$.

(b) The 'Non-Classical Carbonyl' Phenomenon in $[\text{Ir}(\text{CO})_6]^{3+}$:

  • In $[\text{Ir}(\text{CO})_6]^{3+}$, the high $+3$ positive charge contracts the iridium $5d$ orbitals so tightly that their energetic match and spatial overlap with CO $2\pi^*$ are virtually eliminated.
  • Consequently, $\pi$-backbonding is essentially zero.
  • Bonding consists almost purely of $\sigma$-donation from the $5\sigma$ HOMO of CO into empty iridium valence orbitals.
  • The $5\sigma$ orbital of carbon monoxide is weakly antibonding with respect to the $C-O$ bond (due to polarization toward carbon).
  • Donating electron density out of this weakly antibonding $5\sigma$ orbital depopulates antibonding character, slightly strengthening and shortening the $C-O$ bond!
  • Furthermore, the strong electric field generated by the tricationic metal center polarizes the $C-O$ electron cloud (electrostatic Stark effect), increasing the force constant $k_{CO}$.
  • Therefore, $k_{CO}$ exceeds that of free CO, shifting $\nu(CO)$ to $2254\text{ cm}^{-1}$ ($+111\text{ cm}^{-1}$ above free CO).
Foundational Example 3.2: Group Theoretical Prediction of IR-Active Modes in Carbonyl Isomers

Determine the number of IR-active carbonyl stretching bands for: (a) Octahedral hexacarbonyl $\text{Cr}(\text{CO})_6$ ($O_h$ symmetry), (b) trans-dicarbonyl complex trans-$M(\text{CO})_2 L_4$ ($D_{4h}$ symmetry), (c) cis-dicarbonyl complex cis-$M(\text{CO})_2 L_4$ ($C_{2v}$ symmetry). Use symmetry group representations.

Line-by-Line Solution:

(a) Chromium Hexacarbonyl $\text{Cr}(\text{CO})_6$ ($O_h$ Symmetry):

  1. Define a basis of six $C-O$ stretch vectors $\Gamma_{CO}$:
\[\Gamma_{CO}(E) = 6, \quad \Gamma_{CO}(C_3) = 0, \quad \Gamma_{CO}(C_2) = 0, \quad \Gamma_{CO}(C_4) = 2, \quad \Gamma_{CO}(C_2') = 0\]
\[\Gamma_{CO}(i) = 0, \quad \Gamma_{CO}(S_4) = 0, \quad \Gamma_{CO}(S_6) = 0, \quad \Gamma_{CO}(\sigma_h) = 4, \quad \Gamma_{CO}(\sigma_d) = 2\]
  1. Reducing $\Gamma_{CO}$ into irreducible representations of $O_h$:
\[\Gamma_{CO} = A_{1g} + E_g + T_{1u}\]
  1. Selection Rules for IR Activity:
  • In $O_h$, electric dipole moments transform as the Cartesian coordinates $(x,y,z)$, which span the $T_{1u}$ representation.
  • $A_{1g}$ and $E_g$ have gerade ($g$) symmetry and are IR-inactive (centrosymmetric rule of mutual exclusion).
  • Only $T_{1u}$ is ungerade ($u$) and IR-active.
  • Result: Exactly one IR-active band ($T_{1u}$).

(b) trans-$M(\text{CO})_2 L_4$ ($D_{4h}$ Symmetry):

  1. The two $C-O$ bond vectors lie collinear along the $z$-axis:
\[\Gamma_{CO} = A_{1g} + A_{2u}\]
  1. Selection Rules in $D_{4h}$:
  • Electric dipole $z$ transforms as $A_{2u}$.
  • $A_{1g}$ is symmetric stretching (no net dipole change, IR-inactive).
  • Result: Exactly one IR-active band ($A_{2u}$, asymmetric stretch).

(c) cis-$M(\text{CO})_2 L_4$ ($C_{2v}$ Symmetry):

  1. The two $C-O$ bond vectors lie at $90^\circ$ in the $xz$-plane:
  • Under $E$: both remain fixed $\implies \chi(E) = 2$.
  • Under $C_2(z)$: vectors swap $\implies \chi(C_2) = 0$.
  • Under $\sigma_v(xz)$: both remain in plane $\implies \chi(\sigma_v) = 2$.
  • Under $\sigma_v'(yz)$: vectors swap $\implies \chi(\sigma_v') = 0$.
  1. Reducing $\Gamma_{CO}$:
\[\Gamma_{CO} = A_1 + B_1\]
  1. Selection Rules in $C_{2v}$:
  • $z$ transforms as $A_1$ (symmetric stretch, dipole along $z$, IR-active).
  • $x$ transforms as $B_1$ (asymmetric stretch, dipole along $x$, IR-active).
  • Result: Exactly two IR-active bands ($A_1$ and $B_1$). This allows unambiguous spectroscopic differentiation between cis and trans isomers!
Foundational Example 3.3: Tolman Cone Angles and Steric Crowding Calculations

Rank the following tertiary phosphines in order of increasing Tolman cone angle ($\theta$): $\text{PMe}_3, \text{P}(t\text{-Bu})_3, \text{PPh}_3, \text{PF}_3, \text{P}(i\text{-Pr})_3, \text{P}(o\text{-tolyl})_3$. Explain why $\text{P}(o\text{-tolyl})_3$ has a significantly larger cone angle than $\text{PPh}_3$ despite having the same aromatic core.

Line-by-Line Solution:

(a) Ranking of Tolman Cone Angles: Based on Chadwick Tolman's experimental measurements:

  1. $\text{PF}_3$: $\theta = 104^\circ$
  2. $\text{PMe}_3$: $\theta = 118^\circ$
  3. $\text{PPh}_3$: $\theta = 145^\circ$
  4. $\text{P}(i\text{-Pr})_3$: $\theta = 160^\circ$
  5. $\text{P}(t\text{-Bu})_3$: $\theta = 182^\circ$
  6. $\text{P}(o\text{-tolyl})_3$: $\theta = 194^\circ$

Order of increasing steric bulk:

\[\text{PF}_3 < \text{PMe}_3 < \text{PPh}_3 < \text{P}(i\text{-Pr})_3 < \text{P}(t\text{-Bu})_3 < \text{P}(o\text{-tolyl})_3\]

(b) Steric Comparison Between $\text{PPh}_3$ and $\text{P}(o\text{-tolyl})_3$:

  • Triphenylphosphine $\text{PPh}_3$ contains three phenyl rings attached to phosphorus. In the coordinated complex, the phenyl rings can twist like propeller blades around the $P-\text{C}_{ipso}$ bond to minimize steric interference with the metal coordination sphere, yielding an effective cone angle of $145^\circ$.
  • Tri($o$-tolyl)phosphine $\text{P}(o\text{-tolyl})_3$ contains a methyl substituent at the ortho position of each phenyl ring (adjacent to the coordinating carbon).
  • The ortho-methyl groups severely hinder free rotation of the aromatic rings around the $P-\text{C}_{ipso}$ bonds.
  • To avoid steric clash between the three methyl groups, the rings are forced into a rigid, splayed conformation where the methyl groups project outward into the coordination sphere of the metal.
  • This creates an enormous effective cone angle of $194^\circ$, making $\text{P}(o\text{-tolyl})_3$ one of the bulkiest monophosphines, capable of enforcing low coordination numbers (e.g., forming 2-coordinate $\text{PdL}_2$ complexes).
Intermediate Example 3.4: Cotton-Kraihanzel Force Constant Derivation for $cis$- and $trans$-$M(\text{CO})_4 L_2$

In the Cotton-Kraihanzel approximation for a cis-disubstituted octahedral tetracarbonyl complex cis-$M(\text{CO})_4 L_2$ ($C_{2v}$ symmetry), four IR bands are observed: $A_1^{(1)}, A_1^{(2)}, B_1, B_2$. (a) Formulate the secular equations relating the observed vibrational frequencies to the axial force constant $k_1$, equatorial force constant $k_2$, and trans-interaction force constant $k_t$. (b) For cis-$[\text{Mo}(\text{CO})_4(\text{PEt}_3)_2]$, the observed bands are $2015, 1915, 1895, 1880\text{ cm}^{-1}$. Calculate the force constants $k_1$ and $k_2$.

Line-by-Line Solution:

(a) Secular Equations in Cotton-Kraihanzel Formulation: In cis-$M(\text{CO})_4 L_2$:

  • Two CO ligands lie trans to each other along the $z$-axis (axial CO, force constant $k_1$).
  • Two CO ligands lie trans to the two $L$ ligands in the $xy$-plane (equatorial CO, force constant $k_2$).
  • The trans interaction force constant between mutually trans CO ligands is $k_t$; the cis interaction force constant is $k_c$.

The symmetry coordinates yield four vibrational modes:

  1. $B_1$ mode (asymmetric stretch of the two axial trans CO ligands):
\[\lambda(B_1) = \mu (k_1 - k_t)\]
  1. $B_2$ mode (asymmetric stretch of the two equatorial CO ligands):
\[\lambda(B_2) = \mu (k_2 - k_c)\]
  1. The two $A_1$ modes couple via the secular determinant:
\[\begin{vmatrix} \mu(k_1 + k_t) - \lambda & \sqrt{2}\,\mu k_c \\ \sqrt{2}\,\mu k_c & \mu(k_2 + k_c) - \lambda \end{vmatrix} = 0\]

where $\lambda = 4\pi^2 c^2 \nu^2$ and $\mu = \frac{m_C + m_O}{m_C m_O} = 1.144 \times 10^{-26}\text{ kg}^{-1}$. In energy units:

\[k = 4.040 \times 10^{-6} \nu^2 \quad (\text{mdyn/Å with } \nu \text{ in cm}^{-1})\]

(b) Force Constant Calculation for cis-$[\text{Mo}(\text{CO})_4(\text{PEt}_3)_2]$: Observed frequencies:

  • $\nu(A_1^{(1)}) = 2015\text{ cm}^{-1}$
  • $\nu(B_1) = 1915\text{ cm}^{-1}$
  • $\nu(A_1^{(2)}) = 1895\text{ cm}^{-1}$
  • $\nu(B_2) = 1880\text{ cm}^{-1}$
  1. Compute parameter $\lambda_i$:
  • $\lambda(B_1) = 4.040 \times 10^{-6} (1915)^2 = 4.040 \times 10^{-6} (3.667 \times 10^6) = 14.815\text{ mdyn/Å}$
  • $\lambda(B_2) = 4.040 \times 10^{-6} (1880)^2 = 4.040 \times 10^{-6} (3.534 \times 10^6) = 14.279\text{ mdyn/Å}$
  • $\lambda(A_1^{(1)}) = 4.040 \times 10^{-6} (2015)^2 = 16.403\text{ mdyn/Å}$
  • $\lambda(A_1^{(2)}) = 4.040 \times 10^{-6} (1895)^2 = 14.508\text{ mdyn/Å}$
  1. Trans-interaction constant approximation:

In metal carbonyls, Cotton and Kraihanzel observed empirically that $k_t \approx 2 k_c \approx 0.60-0.75\text{ mdyn/Å}$. Using trace theorem for the $A_1$ secular matrix:

\[\lambda(A_1^{(1)}) + \lambda(A_1^{(2)}) = (k_1 + k_t) + (k_2 + k_c)\]

Sum: $16.403 + 14.508 = 30.911\text{ mdyn/Å}$. From $B_1$: $k_1 - k_t = 14.815 \implies k_1 = 14.815 + k_t$. Substituting into $(k_1 + k_t)$: $(14.815 + 2k_t)$. With standard $k_t \approx 0.65\text{ mdyn/Å}$ and $k_c \approx 0.35\text{ mdyn/Å}$:

\[k_1 = 14.815 + 0.65 = 15.47\text{ mdyn/Å}\]
\[k_2 = 14.279 + 0.35 = 14.63\text{ mdyn/Å}\]
  • Physical Interpretation: $k_1 > k_2$ ($15.47$ vs $14.63\text{ mdyn/Å}$) reveals that the equatorial CO ligands (trans to the strongly electron-donating $\text{PEt}_3$ phosphines) receive substantially greater $\pi$-backdonation from molybdenum than the axial CO ligands (trans to each other), weakening their force constant by $0.84\text{ mdyn/Å}$.
Intermediate Example 3.5: Electronic and Structural Ambiguity in Metal Nitrosyl Complexes

Consider the brown-ring complex $[\text{Fe}(\text{H}_2\text{O})_5(\text{NO})]^{2+}$. (a) Calculate the Enemark-Feltham notation $\{M(\text{NO})_x\}^n$ for this species. (b) The complex displays an effective magnetic moment $\mu_{eff} = 3.90\ \mu_B$, and its $\nu(NO)$ stretch appears at $1780\text{ cm}^{-1}$. Reconcile these experimental observations with the formal oxidation states $\text{Fe}(\text{I})-\text{NO}^+$ versus $\text{Fe}(\text{III})-\text{NO}^-$.

Line-by-Line Solution:

(a) Enemark-Feltham Notation:

  • The metal is iron (Group 8, 8 valence electrons).
  • Five neutral water ligands: $\text{H}_2\text{O}$.
  • Net complex charge: $+2$.
  • The Enemark-Feltham formula is $\{M(\text{NO})_x\}^n$ where $n = n_v(M) - q + \text{electrons in } \pi^*(\text{NO})$.
  • For iron ($n_v = 8$) with charge $+2$:
\[n = 8 - 2 + 1 = 7\]
  • Notation: $\{\text{Fe}(\text{NO})\}^7$.

(b) Reconciling Experimental Magnetic and Spectroscopic Data:

1. Magnetic Moment Interpretation:

  • $\mu_{eff} = 3.90\ \mu_B$.
  • The spin-only magnetic moment formula is $\mu_{so} = \sqrt{n(n+2)}\,\mu_B$.
  • For $n=3$ unpaired electrons: $\mu_{so} = \sqrt{3(5)} = \sqrt{15} \approx 3.87\ \mu_B$.
  • The observed moment of $3.90\ \mu_B$ unequivocally corresponds to $S = 3/2$ (three unpaired electrons).

2. Analysis of the Competing Formalisms:

  • Hypothesis 1: $\text{Fe}(\text{I})-\text{NO}^+$:
  • $\text{Fe}(\text{I})$ has a $d^7$ configuration. In a high-spin octahedral weak water field, $t_{2g}^5 e_g^2$ gives $S = 3/2$ (three unpaired electrons).
  • $\text{NO}^+$ is a closed-shell diamagnetic ligand ($S=0$).
  • The high $\nu(NO) = 1780\text{ cm}^{-1}$ indicates significant triple bond character, consistent with linear $\text{NO}^+$.
  • Hypothesis 2: $\text{Fe}(\text{III})-\text{NO}^-$:
  • $\text{Fe}(\text{III})$ has a $d^5$ configuration ($S=5/2$, five unpaired electrons in high-spin).
  • $\text{NO}^-$ has a triplet ground state ($S=1$, two unpaired electrons in $\pi^*$).
  • Strong antiferromagnetic coupling between the high-spin $\text{Fe}(\text{III})$ ($S=5/2$) and the triplet $\text{NO}^-$ ($S=1$) results in a net spin:
\[S_\text{total} = \frac{5}{2} - 1 = \frac{3}{2}\]

3. Mössbauer Spectroscopy and Modern DFT Resolution:

  • $^{57}\text{Fe}$ Mössbauer isomer shifts ($\delta \approx 0.72\text{ mm/s}$) show that the electron density at the iron nucleus matches high-spin $\text{Fe}(\text{III})$ ($S_1 = 5/2$) antiferromagnetically coupled to an $\text{NO}^-$ radical anion ($S_2 = 1$).
  • Thus, the physical ground state is best described as high-spin $\text{Fe}(\text{III})$ antiferromagnetically exchange-coupled to $\text{NO}^-$, while historically formulated as $\text{Fe}(\text{I})-\text{NO}^+$.
Intermediate Example 3.6: Natural Bite Angle Influence on Reductive Elimination Kinetics

In the reductive elimination of ethane from diphosphine complexes $[(\text{diphosphine})\text{Pd}(\text{CH}_3)_2]$, the relative reaction rates at $25^\circ\text{C}$ vary dramatically with the diphosphine backbone: (a) dppm ($\beta_n = 72^\circ$): relative rate $= 1$; (b) dppe ($\beta_n = 85^\circ$): relative rate $= 10^2$; (c) dppf ($\beta_n = 99^\circ$): relative rate $= 6 \times 10^4$; (d) Xantphos ($\beta_n = 111^\circ$): relative rate $= 4 \times 10^7$. Explain the physical and orbital origins of this $10^7$-fold rate enhancement.

Line-by-Line Solution:

(a) Geometric Ground-State Destabilization:

  • In the square planar reactant $[(\text{diphosphine})\text{Pd}(\text{CH}_3)_2]$, the ideal unconstrained valence angle around the $d^8$ $\text{Pd}(\text{II})$ center is $90^\circ$.
  • The total angular span in the coordination plane must sum to $360^\circ$:
\[\angle(P-\text{Pd}-P) + \angle(C-\text{Pd}-C) + 2\,\angle(P-\text{Pd}-C) = 360^\circ\]
  • When a diphosphine with a wide natural bite angle (e.g., Xantphos, $\beta_n = 111^\circ$) is coordinated:
  1. The $P-\text{Pd}-P$ angle is forced open from $90^\circ$ to $>105^\circ$.
  2. This widening exerts a mechanical scissors action on the coordination sphere, compressing the opposite methyl-palladium-methyl angle $\angle(C-\text{Pd}-C)$ from $90^\circ$ down to $<80^\circ$.
  3. Bringing the two methyl carbons into closer spatial proximity substantially raises the ground-state steric and electronic energy of the reactant, pre-organizing it toward the transition state.

(b) Frontier Molecular Orbital Overlap in the Transition State:

  • Reductive elimination of ethane ($ ext{H}_3\text{C}-\text{CH}_3$) requires direct orbital overlap between the two filled $\sigma(\text{Pd}-\text{C})$ bonding orbitals:
\[\text{HOMO} = c_1 \sigma_1 + c_2 \sigma_2\]
  • As the $C-\text{Pd}-C$ angle $\alpha$ decreases toward zero, the spatial overlap integral $S_{CC}$ between the $sp^3$ hybrid orbitals on the two methyl carbons increases exponentially:
\[S_{CC}(\alpha) \propto \exp(-R_{CC} / a_0)\]
  • Simultaneously, widening the $P-\text{Pd}-P$ bite angle raises the energy of the occupied metal $d_{x^2-y^2}$ and $d_{xy}$ orbitals, facilitating the required two-electron transfer from the $Pd-C$ bonds back into a non-bonding metal $d$-orbital ($ ext{Pd}(\text{II}) \to \text{Pd}(0)$).

(c) Activation Free Energy Reduction:

  • The activation barrier $\Delta G^\ddagger$ is the difference between transition state energy and ground state energy:
\[\Delta G^\ddagger = G_{TS} - G_{GS}\]
  • Wide bite angle diphosphines simultaneously raise $G_{GS}$ (via ground-state steric strain) and lower $G_{TS}$ (via superior orbital overlap), drastically lowering $\Delta G^\ddagger$:
\[\Delta\Delta G^\ddagger = RT \ln(4 \times 10^7) = (8.314)(298) \ln(4 \times 10^7) \approx (2478)(17.5) \approx 43.4\text{ kJ/mol}\]
  • A reduction of $43.4\text{ kJ/mol}$ in activation barrier accelerates the reaction by over seven orders of magnitude ($4 \times 10^7$).
Advanced Example 3.7: Quantitative Tolman Electronic Parameter (TEP) Derivation and Carbonyl Coupling

The symmetric $A_1$ stretching frequency of $\text{Ni}(\text{CO})_3 L$ complexes defines the Tolman Electronic Parameter. (a) For $L = \text{P}(t\text{-Bu})_3$, $\nu(CO) = 2056.1\text{ cm}^{-1}$; for $L = \text{PMe}_3$, $\nu(CO) = 2064.1\text{ cm}^{-1}$; for $L = \text{PPh}_3$, $\nu(CO) = 2068.9\text{ cm}^{-1}$; for $L = \text{PF}_3$, $\nu(CO) = 2110.8\text{ cm}^{-1}$. Calculate the Tolman $\chi$ parameters for methyl, phenyl, and fluoro substituents. (b) Using second-order perturbation theory, derive the mathematical relationship between the energy of the phosphorus $\sigma^*(P-R)$ LUMO and the shift in $\nu(CO)$.

Line-by-Line Solution:

(a) Calculation of Tolman $\chi$ Parameters: Tolman's formula expresses the $A_1$ frequency of $\text{Ni}(\text{CO})_3(P R_1 R_2 R_3)$ as:

\[\nu(CO) = 2056.1 + \sum_{i=1}^3 \chi_i \quad (\text{cm}^{-1})\]

where $\chi_i$ is the additive contribution of substituent $R_i$, with $\chi(t\text{-Bu}) = 0.0\text{ cm}^{-1}$ by definition.

1. For $\text{PMe}_3$ ($R_1 = R_2 = R_3 = \text{Me}$):

\[2064.1 = 2056.1 + 3\,\chi(\text{Me})\]
\[3\,\chi(\text{Me}) = 2064.1 - 2056.1 = 8.0\text{ cm}^{-1} \implies \chi(\text{Me}) = \frac{8.0}{3} \approx 2.67\text{ cm}^{-1}\]

2. For $\text{PPh}_3$ ($R_1 = R_2 = R_3 = \text{Ph}$):

\[2068.9 = 2056.1 + 3\,\chi(\text{Ph})\]
\[3\,\chi(\text{Ph}) = 2068.9 - 2056.1 = 12.8\text{ cm}^{-1} \implies \chi(\text{Ph}) = \frac{12.8}{3} \approx 4.27\text{ cm}^{-1}\]

3. For $\text{PF}_3$ ($R_1 = R_2 = R_3 = \text{F}$):

\[2110.8 = 2056.1 + 3\,\chi(\text{F})\]
\[3\,\chi(\text{F}) = 2110.8 - 2056.1 = 54.7\text{ cm}^{-1} \implies \chi(\text{F}) = \frac{54.7}{3} \approx 18.23\text{ cm}^{-1}\]

(b) Perturbation Derivation Connecting $\sigma^*(P-R)$ LUMO to $\Delta\nu(CO)$:

  1. Let $\epsilon_d$ be the unperturbed energy of the nickel $d$-orbitals, and $\epsilon_{\sigma^}$ be the energy of the phosphine $\sigma^(P-R)$ LUMO.
  2. The interaction matrix element between metal $d$ and phosphine $\sigma^(P-R)$ is $H_{d\sigma^}$.
  3. By second-order perturbation theory, the stabilization of the metal $d$-electrons due to $\pi$-backdonation into the phosphine is:
\[\Delta E_d = -\frac{|H_{d\sigma^*}|^2}{\epsilon_{\sigma^*} - \epsilon_d}\]
  1. Lowering the metal $d$-orbital energy by $\Delta E_d$ decreases the energy match and overlap with the higher-lying CO $2\pi^$ LUMO (energy $\epsilon_{\pi^(CO)}$).
  2. The fraction of electron density backdonated from nickel into the three CO ligands is proportional to:
\[\rho_{\pi^*(CO)} \approx \frac{|H_{d\pi^*}|^2}{\epsilon_{\pi^*(CO)} - (\epsilon_d + \Delta E_d)} \approx \rho_0 \left(1 - \frac{|H_{d\sigma^*}|^2}{(\epsilon_{\pi^*(CO)} - \epsilon_d)(\epsilon_{\sigma^*} - \epsilon_d)}\right)\]
  1. Because the force constant $k_{CO}$ increases linearly with the decrease in CO $\pi^$ population ($k_{CO} = k_0 - C \rho_{\pi^(CO)}$):
\[\Delta k_{CO} = + C' \frac{|H_{d\sigma^*}|^2}{\epsilon_{\sigma^*} - \epsilon_d}\]
  1. Since $\Delta \nu \approx \frac{\Delta k_{CO}}{2\mu \nu_0}$:
\[\Delta \nu(CO) \propto \frac{1}{\epsilon_{\sigma^*} - \epsilon_d}\]

When electronegative substituents like fluorine lower the energy $\epsilon_{\sigma^}$, the denominator $\epsilon_{\sigma^} - \epsilon_d$ decreases sharply, causing $\Delta \nu(CO)$ to shift to higher wavenumbers.

Advanced Example 3.8: Synthesis, Mechanism and Organic Transformations of Collman's Reagent

Disodium tetracarbonylferrate $\text{Na}_2[\text{Fe}(\text{CO})_4]$ reacts with an alkyl halide $R\text{Br}$ to yield an alkyliron intermediate (A), which upon treatment with triphenylphosphine $\text{PPh}_3$ converts to an acyliron intermediate (B). Subsequent reaction of (B) with molecular oxygen followed by acidic quench yields a carboxylic acid $R\text{COOH}$. (a) Determine the formal oxidation state and electron count of iron in $\text{Na}_2[\text{Fe}(\text{CO})_4]$, (A), and (B). (b) Formulate the detailed mechanism for the conversion of (A) to (B), and explain why this is a migratory insertion rather than direct CO addition. (c) Derive why $\text{Na}_2[\text{Fe}(\text{CO})_4]$ is termed a 'super-nucleophile' by evaluating its Pearson Hard-Soft Acid-Base (HSAB) parameters.

Line-by-Line Solution:

(a) Formal Oxidation State and Electron Count:

1. Collman's Reagent $\text{Na}_2[\text{Fe}(\text{CO})_4]$:

  • CO ligands are neutral ($L_4$). Net charge of dianion is $-2$.
\[OS(\text{Fe}) = -2 - 0 = -2 \implies \text{Fe}(-\text{II})\]
  • Iron is Group 8: $d$-electron count $= 8 - (-2) = 10 \implies d^{10}$.
  • Total valence electron count: $10 + 4(2) = 18\text{ electrons}$ (tetrahedral $T_d$).

2. Alkyliron Intermediate (A) $[R-\text{Fe}(\text{CO})_4]^-$:

  • Alkyl group is an $X$-ligand (formal charge $-1$). Net charge is $-1$.
\[OS(\text{Fe}) = -1 - (-1) = 0 \implies \text{Fe}(0) \implies d^8\]
  • Total valence electron count: $8 + 1 + 4(2) = 17$? No:
  • Neutral model: Fe(8) + R(1) + 4 CO(8) + charge(1) $= 18\text{ electrons}$ (trigonal bipyramidal $D_{3h}$).

3. Acyliron Intermediate (B) $[R\text{CO}-\text{Fe}(\text{CO})_3(\text{PPh}_3)]^-$:

  • Acyl group $R\text{CO}$ is an $X$-ligand ($-1$).
  • Three CO ligands ($L_3$) and one $\text{PPh}_3$ ($L$).
  • Fe oxidation state: $OS = 0 \implies d^8$.
  • Valence electrons: $8 (\text{Fe}) + 1 (\text{acyl}) + 6 (3\text{CO}) + 2 (\text{PPh}_3) + 1 (\text{charge}) = 18\text{ electrons}$.

(b) Mechanism of Migratory Insertion ((A) to (B)):

  1. In $[R-\text{Fe}(\text{CO})_4]^-$, iron is an 18-electron saturated center. Incoming $\text{PPh}_3$ cannot directly attack iron without violating the 18e rule.
  2. The alkyl group $R$ migrates intramolecularly to the carbon atom of a mutually cis coordinated carbonyl ligand:
\[[R-\text{Fe}(\text{CO})_4]^- \xrightarrow{k_1} [(\text{OC})_3\text{Fe}-\text{C}(=\text{O})R]^- \quad (16\text{-electron acyl intermediate})\]
  1. Migratory insertion generates a coordinatively unsaturated, 16-electron intermediate possessing a vacant coordination site.
  2. The incoming triphenylphosphine ligand rapidly coordinates into this vacant site ($k_2 \gg k_{-1}$):
\[[(\text{OC})_3\text{Fe}-\text{C}(=\text{O})R]^- + \text{PPh}_3 \xrightarrow{k_2} [(\text{Ph}_3\text{P})(\text{OC})_3\text{Fe}-\text{C}(=\text{O})R]^-\]
  1. $^{13}\text{C}$-labeling experiments confirm that the carbonyl carbon of the newly formed acyl group originates exclusively from one of the original coordinated CO ligands, proving an intramolecular alkyl migration.

(c) Super-Nucleophilicity and HSAB Analysis:

  • In $[\text{Fe}(\text{CO})_4]^{2-}$, iron carries a formal $-2$ oxidation state with a completely filled, spherical $d^{10}$ closed shell.
  • Pearson's chemical hardness parameter is defined as:
\[\eta = \frac{I - A}{2}\]

where $I$ is ionization potential and $A$ is electron affinity.

  • The energy of the HOMO (highest occupied metal $d$-orbital) in $[\text{Fe}(\text{CO})_4]^{2-}$ is exceptionally high due to the double negative charge.
  • The high polarizability and low ionization energy make $[\text{Fe}(\text{CO})_4]^{2-}$ an exceptionally soft, highly polarizable Lewis base.
  • Its Swain-Scott nucleophilicity parameter $n$ exceeds $+14$ (many orders of magnitude greater than classical nucleophiles like iodide or hydroxide).
  • Consequently, it undergoes rapid $S_N2$ oxidative addition with primary and secondary alkyl halides with clean inversion of configuration at carbon.
Advanced Example 3.9: Fluxional Carbonyl Dynamics and Coalescence in $\text{Fe}_3(\text{CO})_{12}$

Triiron dodecacarbonyl $\text{Fe}_3(\text{CO})_{12}$ possesses two bridging $\mu_2-\text{CO}$ ligands and ten terminal CO ligands in the solid state ($C_{2v}$ symmetry). In solution at room temperature, its $^{13}\text{C}$ NMR spectrum displays a single sharp singlet down to $-150^\circ\text{C}$. (a) Calculate the total valence electron count ($TVE$) and the number of metal-metal bonds for $\text{Fe}_3(\text{CO})_{12}$. (b) Explain the 'concerted bridge-opening and closing' mechanism (Cotton dynamic merry-go-round model) that renders all twelve carbonyls chemically equivalent on the NMR timescale. (c) Estimate the upper limit for the activation barrier $\Delta G^\ddagger$ of this fluxional process at $-150^\circ\text{C}$.

Line-by-Line Solution:

(a) Total Valence Electron Count and Metal-Metal Bonding:

  1. Iron is in Group 8 ($n_v = 8$):
\[3 \times \text{Fe} = 3 \times 8 = 24\text{ valence electrons}\]
  1. Twelve CO ligands donate:
\[12 \times 2 = 24\text{ electrons}\]
  1. Total Valence Electrons ($TVE$):
\[TVE = 24 + 24 = 48\text{ electrons}\]
  1. Number of Metal-Metal bonds ($m$):
\[m = \frac{18n - TVE}{2} = \frac{18(3) - 48}{2} = \frac{54 - 48}{2} = \frac{6}{2} = 3\]
  • Structure: The three iron atoms form an equilateral or isosceles triangle containing 3 single $\text{Fe}-\text{Fe}$ bonds.

(b) Cotton 'Merry-Go-Round' Dynamic Fluxional Mechanism:

  1. In the solid state, one $\text{Fe}-\text{Fe}$ edge is bridged by two $\mu_2-\text{CO}$ ligands, while the other two iron atoms each carry three terminal CO ligands, and the unique Fe atoms each carry two terminal CO ligands, breaking overall $D_{3h}$ symmetry to $C_{2v}$.
  2. In solution, the two bridging carbonyls open simultaneously to terminal positions:
\[\text{Bridged } C_{2v} \rightleftharpoons \text{Unbridged } D_{3h} \text{ intermediate} \rightleftharpoons \text{Re-bridged } C_{2v}'\]
  1. In the unbridged $D_{3h}$ intermediate (analogous to $\text{Ru}_3(\text{CO})_{12}$ and $\text{Os}_3(\text{CO})_{12}$), all twelve CO ligands are terminal.
  2. As the iron triangle rotates within the carbonyl envelope (or equivalently, as the carbonyls migrate along the triangular edges in a concerted 'merry-go-round' motion), pairs of carbonyls continuously open and close across different $\text{Fe}-\text{Fe}$ edges.
  3. This permutation rapidly exchanges bridging and terminal environments, as well as axial and equatorial sites, averaging the magnetic environment across all twelve $^{13}\text{C}$ nuclei.

(c) Upper Limit of Activation Barrier $\Delta G^\ddagger$ at $-150^\circ\text{C}$:

  1. Temperature: $T = -150^\circ\text{C} = 123.15\text{ K}$.
  2. At $-150^\circ\text{C}$, the peak remains a single sharp resonance without broadening. This implies that the exchange rate $k$ is still well above the coalescence rate:
\[k > k_c = \frac{\pi \Delta \nu}{\sqrt{2}}\]

For a typical $^{13}\text{C}$ chemical shift dispersion between bridging and terminal carbonyls of $\Delta \delta \approx 50\text{ ppm}$ at a $^{13}\text{C}$ frequency of $100\text{ MHz}$:

\[\Delta \nu = 50 \times 100 = 5000\text{ Hz}\]
\[k_c = \frac{\pi(5000)}{\sqrt{2}} \approx 1.11 \times 10^4\text{ s}^{-1}\]

Since no broadening is observed, $k(123.15\text{ K}) > 2 \times 10^4\text{ s}^{-1}$.

  1. Using the Eyring equation:
\[\Delta G^\ddagger < R T \left[ \ln\left(\frac{k_B T}{h}\right) - \ln(k) \right]\]
  • $\frac{k_B T}{h} = \frac{(1.38065 \times 10^{-23})(123.15)}{6.62607 \times 10^{-34}} = 2.566 \times 10^{12}\text{ s}^{-1}$
  • $\ln\left(\frac{k_B T}{h}\right) = \ln(2.566 \times 10^{12}) \approx 28.57$
  • $\ln(k) > \ln(2 \times 10^4) \approx 9.90$
  • Difference: $28.57 - 9.90 = 18.67$
  1. Calculating $\Delta G^\ddagger$:
\[\Delta G^\ddagger < (8.3145\text{ J/(mol}\cdot\text{K)})(123.15\text{ K})(18.67) = 1024 \times 18.67 \approx 19,100\text{ J/mol} \approx 19.1\text{ kJ/mol}\]
  • Conclusion: The activation barrier for carbonyl scrambling in $\text{Fe}_3(\text{CO})_{12}$ is extraordinarily low: $\mathbf{\Delta G^\ddagger < 20\text{ kJ/mol}}$ (less than $5\text{ kcal/mol}$), rendering the carbonyl envelope essentially a liquid-like mantle flowing effortlessly over the rigid triiron cluster core.