§3.1 §3.1 Synthesis of Binary and Mixed Metal Carbonyls
Metal carbonyls are the cornerstones of transition metal organometallic chemistry. In these complexes, carbon monoxide acts as an amphiphilic $\pi$-acid ligand, stabilizing transition metals in low or zero formal oxidation states.
Primary Synthetic Methods:
1. Direct Carbonylation: Highly electropositive metals in fine division react directly with gaseous carbon monoxide at elevated pressure:
2. Reductive Carbonylation: Transition metal halides in higher oxidation states are reduced in the presence of carbon monoxide using reducing agents such as aluminum powder, triethylaluminum, sodium, or magnesium:
3. Photochemical and Thermal Substitution: Carbon monoxide dissociates photochemically via metal-to-ligand charge transfer (MLCT) or ligand-field excitation, generating coordination-unsaturated intermediates that capture incoming ligands ($L = PR_3$, alkene, solvent):
§3.2 §3.2 The Dewar-Chatt-Duncanson Bonding Model in Metal Carbonyls
The bonding between a transition metal and carbon monoxide is governed by the synergistic Dewar-Chatt-Duncanson (DCD) model, comprising two complementary components:
1. $\sigma$-Donation:
- The carbon monoxide molecule possesses a filled non-bonding orbital centered primarily on carbon: the $5\sigma$ molecular orbital (HOMO of CO, possessing weakly antibonding character with respect to the $C-O$ bond).
- The lone pair in this $5\sigma$ orbital donates electron density into an empty metal valence orbital of matching $\sigma$-symmetry (e.g., $d_{z^2}$, $d_{x^2-y^2}$, $s$, or $p$ hybrids):
- This $\sigma$-donation polarizes charge toward the metal center, building negative charge on the metal.
2. $\pi$-Backbonding ($\pi$-Backdonation):
- Carbon monoxide possesses two degenerate, empty, low-lying antibonding $\pi^$ orbitals: the $2\pi^$ molecular orbitals (LUMO of CO).
- Filled metal valence $d$-orbitals of appropriate $\pi$-symmetry ($d_{xy}, d_{yz}, d_{xz}$ or $t_{2g}$ in $O_h$) overlap with these empty $2\pi^*$ orbitals:
- Electrons from the metal are backdonated into the ligand $\pi^*$ LUMO.
Synergism and Bond Order Consequences:
- $\sigma$-donation transfers electron density to the metal, increasing the metal's basicity and enhancing its ability to backdonate.
- $\pi$-backdonation relieves metal electron excess, increasing the Lewis acidity of the metal and facilitating further $\sigma$-donation.
- Effect on $M-C$ Bond: $\pi$-backbonding increases the $M-C$ bond order toward a double bond ($M=C=\text{O}$), shortening the $M-C$ distance and strengthening the $M-C$ bond.
- Effect on $C-O$ Bond: Populating the $C-O$ antibonding $2\pi^*$ orbital decreases the $C-O$ bond order from a formal triple bond toward a double bond, lengthening the $C-O$ bond distance and lowering its vibrational stretching frequency $\nu(CO)$.
§3.3 §3.3 Infrared Spectroscopy of Carbonyls: $\nu(CO)$ Vibrational Modes & Cotton-Kraihanzel Force Constants
Infrared (IR) spectroscopy is the most sensitive diagnostic tool for probing the electronic environment of metal carbonyls. The vibrational stretching frequency of free gaseous carbon monoxide is:
Electronic Effects of Metal Oxidation State and Charge:
When backbonding increases, electron density in $\pi^*$ increases, lowering the force constant $k_{CO}$ according to Hooke's Law:
where $\mu = \frac{m_C m_O}{m_C + m_O}$ is the reduced mass. Consider the isoelectronic hexacarbonyl series ($d^6$ octahedral):
- $[\text{Mn}(\text{CO})_6]^+$: $\nu(CO) = 2090\text{ cm}^{-1}$ (positive charge contracts $d$-orbitals; weak backbonding)
- $\text{Cr}(\text{CO})_6$: $\nu(CO) = 2000\text{ cm}^{-1}$ (neutral; balanced $\sigma$-donation and $\pi$-backbonding)
- $[\text{V}(\text{CO})_6]^-$: $\nu(CO) = 1860\text{ cm}^{-1}$ (negative charge expands $d$-orbitals; strong backbonding)
- $[\text{Ti}(\text{CO})_6]^{2-}$: $\nu(CO) = 1750\text{ cm}^{-1}$ (enormous backbonding; $C-O$ bond approaches double bond)
Bridging vs. Terminal Carbonyl Coordination Modes:
As carbon monoxide coordinates to more metal centers, each additional metal contributes $\pi$-backbonding density into the same $2\pi^*$ LUMO:
- Terminal $M-\text{CO}$: $\nu(CO) = 2125 - 1850\text{ cm}^{-1}$
- Doubly Bridging $\mu_2-\text{CO}$: $\nu(CO) = 1850 - 1750\text{ cm}^{-1}$ (ketonic stretch)
- Triply Bridging $\mu_3-\text{CO}$: $\nu(CO) = 1730 - 1620\text{ cm}^{-1}$
- Four-fold Bridging $\mu_4-\text{CO}$: $\nu(CO) < 1600\text{ cm}^{-1}$
Cotton-Kraihanzel Force Field:
Under the Cotton-Kraihanzel approximation, carbonyl stretching frequencies are modeled by secular equations factoring in the primary $C-O$ stretching force constant $k$ and the interaction force constants $k_c$ (cis-interaction) and $k_t$ (trans-interaction) transmitted through the metal $d$-orbitals.
§3.4 §3.4 Metal Nitrosyl Complexes: Linear ($ ext{NO}^+$) vs. Bent ($ ext{NO}^-$) Coordination
Nitric oxide ($\text{NO}$) is an open-shell radical possessing 15 valence electrons with an unpaired electron residing in its $2\pi^*$ orbital. Upon binding transition metals, it adopts two distinct, interconvertible coordination geometries:
1. Linear Nitrosyl ($M-\text{N}\equiv\text{O}$, angle $\approx 180^\circ$):
- Formalism: Nitrosyl is formally treated as nitrosonium cation $\text{NO}^+$ (isoelectronic with $\text{CO}$, 14 valence electrons).
- Electron Counting:
- In the Covalent Model, linear $\text{NO}$ is counted as a 3-electron donor ($LX$-type: 1 electron from radical pairing plus 2 electrons from the nitrogen lone pair).
- In the Ionic Model, $\text{NO}^+$ is a 2-electron donor, and the metal oxidation state is reduced by 1.
- Bonding: $sp$ hybridization at nitrogen. One $\sigma$-dative bond from nitrogen to metal and two degenerate $\pi$-backbonds from metal $d_{xz}, d_{yz}$ into $\text{NO}$ $\pi^*$ orbitals.
- IR Spectroscopy: $\nu(NO) = 1650 - 1900\text{ cm}^{-1}$ (high stretching frequency due to triple bond character).
2. Bent Nitrosyl ($M-\text{N}=\text{O}$, angle $\approx 120^\circ - 140^\circ$):
- Formalism: Nitrosyl is formally treated as nitroxyl anion $\text{NO}^-$ (16 valence electrons).
- Electron Counting:
- In the Covalent Model, bent $\text{NO}$ is counted as a 1-electron donor ($X$-type: radical single bond).
- In the Ionic Model, $\text{NO}^-$ is a 2-electron donor, but the metal formal oxidation state increases by 1.
- Bonding: $sp^2$ hybridization at nitrogen with a localized lone pair residing in the non-bonding $sp^2$ hybrid orbital, causing the bent geometry.
- IR Spectroscopy: $\nu(NO) = 1525 - 1690\text{ cm}^{-1}$ (lower stretching frequency due to formal double bond).
The Enemark-Feltham Notation $\{M(\text{NO})_x\}^n$:
Because assigning formal oxidation states to non-innocent nitrosyl ligands is ambiguous, Enemark and Feltham introduced the notation $\{M(\text{NO})_x\}^n$, where $n$ is the total number of electrons in the metal $d$-orbitals plus the $\text{NO}$ $\pi^*$ orbitals:
For example, in the nitroprusside anion $[\text{Fe}(\text{CN})_5(\text{NO})]^{2-}$, the system is classified as $\{Fe(\text{NO})\}^6$, adopting an idealized linear geometry.
§3.5 §3.5 Phosphine Ligands: Electronic Properties, $\sigma$-Donation and $\pi$-Acceptance into $\sigma^*$ Orbitals
Tertiary phosphines ($PR_3$) are premier spectator ligands in homogeneous catalysis, offering exceptional electronic and steric tuneability.
Dual Bonding Mechanism:
1. $\sigma$-Donation:
- The phosphorus atom possesses a lone pair residing in an $sp^3$-like hybrid orbital with substantial $3s$ and $3p$ character.
- This lone pair donates into an empty metal valence orbital, forming a strong $M-P$ $\sigma$-bond.
- $\sigma$-donor strength depends on the electron-donating capability of the $R$ substituents:
2. $\pi$-Acceptor Capability:
- Early models attributed $\pi$-acceptance in phosphines to vacant, high-energy phosphorus $3d$ orbitals.
- Modern molecular orbital calculations (Orpen, Connelly, Marynick) reveal that $\pi$-acceptance occurs via backdonation from filled metal $d$-orbitals into empty $\sigma^*(P-R)$ antibonding orbitals of the phosphine:
- When $R$ is highly electronegative (e.g., $F, OPh, CF_3$), the $\sigma^*(P-R)$ orbital is stabilized to lower energy and polarized toward phosphorus, maximizing overlap with metal $d$-orbitals.
- Remarkably, phosphorus trifluoride ($\text{PF}_3$) is such a potent $\pi$-acceptor that its bonding properties and electronic spectrum closely match those of carbon monoxide ($CO$).
§3.6 §3.6 Tolman Steric Parameter (Cone Angle $\theta$) and Electronic Parameter (TEP $\chi$)
Chadwick A. Tolman established quantitative steric and electronic metrics that parameterized phosphine behavior across organometallic chemistry.
Tolman Cone Angle ($\theta$):
The Tolman cone angle measures ligand steric bulk. It is defined as the vertex angle of a cylindrical cone centered at a metal atom situated at a standard distance of $2.28$ Å from the phosphorus atom, whose perimeter encloses the van der Waals radii of all atoms of the three $R$ substituents. For unsymmetrical phosphines $P R_1 R_2 R_3$:
Representative Cone Angles:
- $\text{PH}_3$: $87^\circ$
- $\text{PF}_3$: $104^\circ$
- $\text{PMe}_3$: $118^\circ$
- $\text{PEt}_3$: $132^\circ$
- $\text{PPh}_3$: $145^\circ$
- $\text{P}(i\text{-Pr})_3$: $160^\circ$
- $\text{PCy}_3$: $170^\circ$
- $\text{P}(t\text{-Bu})_3$: $182^\circ$
- $\text{P}(o\text{-tolyl})_3$: $194^\circ$
Tolman Electronic Parameter (TEP, $\chi$):
The electronic donating ability of a phosphine is quantified by measuring the symmetric $A_1$ carbonyl stretching frequency $\nu(CO)$ in the standard nickel complex $\text{Ni}(\text{CO})_3(PR_3)$:
where $\chi_i$ is the substituent electronic contribution (defined with $\chi = 0$ for $t\text{-Bu}$).
- Electron-rich phosphines (e.g., $\text{PMe}_3, \text{P}(t\text{-Bu})_3$) transfer more electron density to nickel, maximizing $\pi$-backbonding into the three CO ligands and depressing $\nu(CO)$ ($\\approx 2064\text{ cm}^{-1}$).
- Poor donor/strong $\pi$-acceptor phosphines (e.g., $\text{PF}_3$) compete with CO for metal backdonation, shifting $\nu(CO)$ to higher frequencies ($2111\text{ cm}^{-1}$).
§3.7 §3.7 Chelating Diphosphines: Natural Bite Angle $\beta_n$ and Catalytic Selectivity
Bidentate diphosphines ($R_2\text{P}-\text{Linker}-\text{P}R_2$) bind metal centers in a chelating mode, enforcing a specific geometry.
The Natural Bite Angle ($\beta_n$):
Introduced by Piet van Leeuwen and Casey, the natural bite angle ($\beta_n$) is defined by molecular mechanics computations as the preferred $P-M-P$ valence angle determined solely by the steric constraints of the diphosphine backbone, with a standard $M-P$ bond length (typically $2.315$ Å) and without electronic ligand field contributions.
Representative Diphosphines and Natural Bite Angles:
- dppm ($ ext{Ph}_2\text{PCH}_2\text{PPh}_2$): $\beta_n \approx 72^\circ$ (often forms bridging rather than chelating complexes)
- dppe ($ ext{Ph}_2\text{PCH}_2\text{CH}_2\text{PPh}_2$): $\beta_n \approx 85^\circ$ (prefers octahedral and square planar geometries)
- dppp ($ ext{Ph}_2\text{P(CH}_2)_3\text{PPh}_2$): $\beta_n \approx 91^\circ$
- dppb ($ ext{Ph}_2\text{P(CH}_2)_4\text{PPh}_2$): $\beta_n \approx 98^\circ$
- BINAP ($2,2'$-bis(diphenylphosphino)-$1,1'$-binaphthyl): $\beta_n \approx 93^\circ$ (chiral $C_2$-symmetric backbone for asymmetric catalysis)
- dppf ($1,1'$-bis(diphenylphosphino)ferrocene): $\beta_n \approx 99^\circ$
- Xantphos (4,5-bis(diphenylphosphino)-9,9-dimethylxanthene): $\beta_n \approx 111^\circ$
Impact on Catalytic Rates and Regioselectivity:
1. Reductive Elimination Acceleration: A wide bite angle (e.g., Xantphos $\beta_n \approx 111^\circ$) forces the two coupling organic groups closer together, compressing their dihedral angle and accelerating reductive elimination by factors exceeding $10^4$.
2. Hydroformylation Regioselectivity: In Rh-catalyzed hydroformylation of 1-alkenes, wide bite angle diphosphines force the two phosphorus atoms to occupy equatorial-equatorial ($ee$) positions in trigonal bipyramidal intermediates, steering the linear-to-branched aldehyde ratio ($l:b$) to $>50:1$.
§3.8 §3.8 Chemical Reactivity: Nucleophilic Attack, Disproportionation & Collman's Reagent
Metal carbonyl complexes display rich chemical transformations driven by the polarity of coordinated CO:
1. Nucleophilic Attack on Coordinated Carbonyls:
Because $\sigma$-donation and metal-to-ligand backbonding withdraw electron density from the carbonyl carbon atom, coordinated CO is electrophilic:
- Hydroxide Attack (Water-Gas Shift Intermediate):
- Organolithium Addition (Fischer Carbene Synthesis):
2. Disproportionation with Hard Lewis Bases:
Reaction of metal carbonyls with hard, coordinating Lewis bases (e.g., pyridine, ammonia) induces valence disproportionation:
3. Collman's Reagent: Disodium Tetracarbonylferrate:
Reduction of iron pentacarbonyl with sodium amalgam or sodium naphthalenide yields Collman's reagent:
The ferrate dianion $[\text{Fe}(\text{CO})_4]^{2-}$ is a 'super-nucleophile' with an iron oxidation state of $-2$ ($d^{10}$, 18 valence electrons). It reacts cleanly with primary alkyl halides:
providing a versatile entry to aldehydes, unsymmetrical ketones, esters, and amides.
Worked Practice Problems (9 Challenge Exercises)
Multi-step solved problems covering neutral vs ionic electron counting, d-electron configuration determination, 16-electron square planar stabilization, metal-metal single and multiple bond orders, bridging ligand electron partitioning, and 3c-2e bridge thermodynamic equilibria with line-by-line mathematical proofs.
The infrared carbonyl stretching frequencies for the octahedral $d^6$ hexacarbonyl series are: $[\text{Ir}(\text{CO})_6]^{3+} (2254\text{ cm}^{-1})$, $[\text{Os}(\text{CO})_6]^{2+} (2190\text{ cm}^{-1})$, $[\text{Re}(\text{CO})_6]^+ (2085\text{ cm}^{-1})$, $\text{W}(\text{CO})_6 (1998\text{ cm}^{-1})$, $[\text{Ta}(\text{CO})_6]^- (1850\text{ cm}^{-1})$, $[\text{Hf}(\text{CO})_6]^{2-} (1750\text{ cm}^{-1})$. (a) Explain the continuous decrease of $\nu(CO)$ across this series using the Dewar-Chatt-Duncanson model. (b) Explain why $[\text{Ir}(\text{CO})_6]^{3+}$ exhibits a $\nu(CO)$ higher than free gaseous CO ($2143\text{ cm}^{-1}$) ('non-classical metal carbonyl').
Line-by-Line Solution:
(a) Physical Origin of Frequency Decrease Across the Series:
- All species in the series are isoelectronic with an octahedral $d^6$ valence configuration ($t_{2g}^6$).
- As the net charge changes from $+3$ to $-2$:
the nuclear charge $Z$ decreases relative to the electron count, and the effective nuclear charge $Z_\text{eff}$ experienced by the metal valence $d$-electrons decreases precipitously.
- A lower $Z_\text{eff}$ causes radial expansion of the metal $d_{xy}, d_{yz}, d_{xz}$ ($t_{2g}$) orbitals, raising their energy levels closer to the empty $2\pi^*$ LUMO of the coordinated carbon monoxide ligands.
- Consequently, metal-to-ligand $\pi$-backbonding increases enormously:
- Population of the $C-O$ antibonding $2\pi^*$ orbital weakens the carbon-oxygen bond, reducing the $C-O$ bond order and force constant $k_{CO}$.
- According to Hooke's Law:
A lower force constant $k_{CO}$ produces a continuous decrease in $\nu(CO)$ from $2254\text{ cm}^{-1}$ down to $1750\text{ cm}^{-1}$.
(b) The 'Non-Classical Carbonyl' Phenomenon in $[\text{Ir}(\text{CO})_6]^{3+}$:
- In $[\text{Ir}(\text{CO})_6]^{3+}$, the high $+3$ positive charge contracts the iridium $5d$ orbitals so tightly that their energetic match and spatial overlap with CO $2\pi^*$ are virtually eliminated.
- Consequently, $\pi$-backbonding is essentially zero.
- Bonding consists almost purely of $\sigma$-donation from the $5\sigma$ HOMO of CO into empty iridium valence orbitals.
- The $5\sigma$ orbital of carbon monoxide is weakly antibonding with respect to the $C-O$ bond (due to polarization toward carbon).
- Donating electron density out of this weakly antibonding $5\sigma$ orbital depopulates antibonding character, slightly strengthening and shortening the $C-O$ bond!
- Furthermore, the strong electric field generated by the tricationic metal center polarizes the $C-O$ electron cloud (electrostatic Stark effect), increasing the force constant $k_{CO}$.
- Therefore, $k_{CO}$ exceeds that of free CO, shifting $\nu(CO)$ to $2254\text{ cm}^{-1}$ ($+111\text{ cm}^{-1}$ above free CO).
Determine the number of IR-active carbonyl stretching bands for: (a) Octahedral hexacarbonyl $\text{Cr}(\text{CO})_6$ ($O_h$ symmetry), (b) trans-dicarbonyl complex trans-$M(\text{CO})_2 L_4$ ($D_{4h}$ symmetry), (c) cis-dicarbonyl complex cis-$M(\text{CO})_2 L_4$ ($C_{2v}$ symmetry). Use symmetry group representations.
Line-by-Line Solution:
(a) Chromium Hexacarbonyl $\text{Cr}(\text{CO})_6$ ($O_h$ Symmetry):
- Define a basis of six $C-O$ stretch vectors $\Gamma_{CO}$:
- Reducing $\Gamma_{CO}$ into irreducible representations of $O_h$:
- Selection Rules for IR Activity:
- In $O_h$, electric dipole moments transform as the Cartesian coordinates $(x,y,z)$, which span the $T_{1u}$ representation.
- $A_{1g}$ and $E_g$ have gerade ($g$) symmetry and are IR-inactive (centrosymmetric rule of mutual exclusion).
- Only $T_{1u}$ is ungerade ($u$) and IR-active.
- Result: Exactly one IR-active band ($T_{1u}$).
(b) trans-$M(\text{CO})_2 L_4$ ($D_{4h}$ Symmetry):
- The two $C-O$ bond vectors lie collinear along the $z$-axis:
- Selection Rules in $D_{4h}$:
- Electric dipole $z$ transforms as $A_{2u}$.
- $A_{1g}$ is symmetric stretching (no net dipole change, IR-inactive).
- Result: Exactly one IR-active band ($A_{2u}$, asymmetric stretch).
(c) cis-$M(\text{CO})_2 L_4$ ($C_{2v}$ Symmetry):
- The two $C-O$ bond vectors lie at $90^\circ$ in the $xz$-plane:
- Under $E$: both remain fixed $\implies \chi(E) = 2$.
- Under $C_2(z)$: vectors swap $\implies \chi(C_2) = 0$.
- Under $\sigma_v(xz)$: both remain in plane $\implies \chi(\sigma_v) = 2$.
- Under $\sigma_v'(yz)$: vectors swap $\implies \chi(\sigma_v') = 0$.
- Reducing $\Gamma_{CO}$:
- Selection Rules in $C_{2v}$:
- $z$ transforms as $A_1$ (symmetric stretch, dipole along $z$, IR-active).
- $x$ transforms as $B_1$ (asymmetric stretch, dipole along $x$, IR-active).
- Result: Exactly two IR-active bands ($A_1$ and $B_1$). This allows unambiguous spectroscopic differentiation between cis and trans isomers!
Rank the following tertiary phosphines in order of increasing Tolman cone angle ($\theta$): $\text{PMe}_3, \text{P}(t\text{-Bu})_3, \text{PPh}_3, \text{PF}_3, \text{P}(i\text{-Pr})_3, \text{P}(o\text{-tolyl})_3$. Explain why $\text{P}(o\text{-tolyl})_3$ has a significantly larger cone angle than $\text{PPh}_3$ despite having the same aromatic core.
Line-by-Line Solution:
(a) Ranking of Tolman Cone Angles: Based on Chadwick Tolman's experimental measurements:
- $\text{PF}_3$: $\theta = 104^\circ$
- $\text{PMe}_3$: $\theta = 118^\circ$
- $\text{PPh}_3$: $\theta = 145^\circ$
- $\text{P}(i\text{-Pr})_3$: $\theta = 160^\circ$
- $\text{P}(t\text{-Bu})_3$: $\theta = 182^\circ$
- $\text{P}(o\text{-tolyl})_3$: $\theta = 194^\circ$
Order of increasing steric bulk:
(b) Steric Comparison Between $\text{PPh}_3$ and $\text{P}(o\text{-tolyl})_3$:
- Triphenylphosphine $\text{PPh}_3$ contains three phenyl rings attached to phosphorus. In the coordinated complex, the phenyl rings can twist like propeller blades around the $P-\text{C}_{ipso}$ bond to minimize steric interference with the metal coordination sphere, yielding an effective cone angle of $145^\circ$.
- Tri($o$-tolyl)phosphine $\text{P}(o\text{-tolyl})_3$ contains a methyl substituent at the ortho position of each phenyl ring (adjacent to the coordinating carbon).
- The ortho-methyl groups severely hinder free rotation of the aromatic rings around the $P-\text{C}_{ipso}$ bonds.
- To avoid steric clash between the three methyl groups, the rings are forced into a rigid, splayed conformation where the methyl groups project outward into the coordination sphere of the metal.
- This creates an enormous effective cone angle of $194^\circ$, making $\text{P}(o\text{-tolyl})_3$ one of the bulkiest monophosphines, capable of enforcing low coordination numbers (e.g., forming 2-coordinate $\text{PdL}_2$ complexes).
In the Cotton-Kraihanzel approximation for a cis-disubstituted octahedral tetracarbonyl complex cis-$M(\text{CO})_4 L_2$ ($C_{2v}$ symmetry), four IR bands are observed: $A_1^{(1)}, A_1^{(2)}, B_1, B_2$. (a) Formulate the secular equations relating the observed vibrational frequencies to the axial force constant $k_1$, equatorial force constant $k_2$, and trans-interaction force constant $k_t$. (b) For cis-$[\text{Mo}(\text{CO})_4(\text{PEt}_3)_2]$, the observed bands are $2015, 1915, 1895, 1880\text{ cm}^{-1}$. Calculate the force constants $k_1$ and $k_2$.
Line-by-Line Solution:
(a) Secular Equations in Cotton-Kraihanzel Formulation: In cis-$M(\text{CO})_4 L_2$:
- Two CO ligands lie trans to each other along the $z$-axis (axial CO, force constant $k_1$).
- Two CO ligands lie trans to the two $L$ ligands in the $xy$-plane (equatorial CO, force constant $k_2$).
- The trans interaction force constant between mutually trans CO ligands is $k_t$; the cis interaction force constant is $k_c$.
The symmetry coordinates yield four vibrational modes:
- $B_1$ mode (asymmetric stretch of the two axial trans CO ligands):
- $B_2$ mode (asymmetric stretch of the two equatorial CO ligands):
- The two $A_1$ modes couple via the secular determinant:
where $\lambda = 4\pi^2 c^2 \nu^2$ and $\mu = \frac{m_C + m_O}{m_C m_O} = 1.144 \times 10^{-26}\text{ kg}^{-1}$. In energy units:
(b) Force Constant Calculation for cis-$[\text{Mo}(\text{CO})_4(\text{PEt}_3)_2]$: Observed frequencies:
- $\nu(A_1^{(1)}) = 2015\text{ cm}^{-1}$
- $\nu(B_1) = 1915\text{ cm}^{-1}$
- $\nu(A_1^{(2)}) = 1895\text{ cm}^{-1}$
- $\nu(B_2) = 1880\text{ cm}^{-1}$
- Compute parameter $\lambda_i$:
- $\lambda(B_1) = 4.040 \times 10^{-6} (1915)^2 = 4.040 \times 10^{-6} (3.667 \times 10^6) = 14.815\text{ mdyn/Å}$
- $\lambda(B_2) = 4.040 \times 10^{-6} (1880)^2 = 4.040 \times 10^{-6} (3.534 \times 10^6) = 14.279\text{ mdyn/Å}$
- $\lambda(A_1^{(1)}) = 4.040 \times 10^{-6} (2015)^2 = 16.403\text{ mdyn/Å}$
- $\lambda(A_1^{(2)}) = 4.040 \times 10^{-6} (1895)^2 = 14.508\text{ mdyn/Å}$
- Trans-interaction constant approximation:
In metal carbonyls, Cotton and Kraihanzel observed empirically that $k_t \approx 2 k_c \approx 0.60-0.75\text{ mdyn/Å}$. Using trace theorem for the $A_1$ secular matrix:
Sum: $16.403 + 14.508 = 30.911\text{ mdyn/Å}$. From $B_1$: $k_1 - k_t = 14.815 \implies k_1 = 14.815 + k_t$. Substituting into $(k_1 + k_t)$: $(14.815 + 2k_t)$. With standard $k_t \approx 0.65\text{ mdyn/Å}$ and $k_c \approx 0.35\text{ mdyn/Å}$:
- Physical Interpretation: $k_1 > k_2$ ($15.47$ vs $14.63\text{ mdyn/Å}$) reveals that the equatorial CO ligands (trans to the strongly electron-donating $\text{PEt}_3$ phosphines) receive substantially greater $\pi$-backdonation from molybdenum than the axial CO ligands (trans to each other), weakening their force constant by $0.84\text{ mdyn/Å}$.
Consider the brown-ring complex $[\text{Fe}(\text{H}_2\text{O})_5(\text{NO})]^{2+}$. (a) Calculate the Enemark-Feltham notation $\{M(\text{NO})_x\}^n$ for this species. (b) The complex displays an effective magnetic moment $\mu_{eff} = 3.90\ \mu_B$, and its $\nu(NO)$ stretch appears at $1780\text{ cm}^{-1}$. Reconcile these experimental observations with the formal oxidation states $\text{Fe}(\text{I})-\text{NO}^+$ versus $\text{Fe}(\text{III})-\text{NO}^-$.
Line-by-Line Solution:
(a) Enemark-Feltham Notation:
- The metal is iron (Group 8, 8 valence electrons).
- Five neutral water ligands: $\text{H}_2\text{O}$.
- Net complex charge: $+2$.
- The Enemark-Feltham formula is $\{M(\text{NO})_x\}^n$ where $n = n_v(M) - q + \text{electrons in } \pi^*(\text{NO})$.
- For iron ($n_v = 8$) with charge $+2$:
- Notation: $\{\text{Fe}(\text{NO})\}^7$.
(b) Reconciling Experimental Magnetic and Spectroscopic Data:
1. Magnetic Moment Interpretation:
- $\mu_{eff} = 3.90\ \mu_B$.
- The spin-only magnetic moment formula is $\mu_{so} = \sqrt{n(n+2)}\,\mu_B$.
- For $n=3$ unpaired electrons: $\mu_{so} = \sqrt{3(5)} = \sqrt{15} \approx 3.87\ \mu_B$.
- The observed moment of $3.90\ \mu_B$ unequivocally corresponds to $S = 3/2$ (three unpaired electrons).
2. Analysis of the Competing Formalisms:
- Hypothesis 1: $\text{Fe}(\text{I})-\text{NO}^+$:
- $\text{Fe}(\text{I})$ has a $d^7$ configuration. In a high-spin octahedral weak water field, $t_{2g}^5 e_g^2$ gives $S = 3/2$ (three unpaired electrons).
- $\text{NO}^+$ is a closed-shell diamagnetic ligand ($S=0$).
- The high $\nu(NO) = 1780\text{ cm}^{-1}$ indicates significant triple bond character, consistent with linear $\text{NO}^+$.
- Hypothesis 2: $\text{Fe}(\text{III})-\text{NO}^-$:
- $\text{Fe}(\text{III})$ has a $d^5$ configuration ($S=5/2$, five unpaired electrons in high-spin).
- $\text{NO}^-$ has a triplet ground state ($S=1$, two unpaired electrons in $\pi^*$).
- Strong antiferromagnetic coupling between the high-spin $\text{Fe}(\text{III})$ ($S=5/2$) and the triplet $\text{NO}^-$ ($S=1$) results in a net spin:
3. Mössbauer Spectroscopy and Modern DFT Resolution:
- $^{57}\text{Fe}$ Mössbauer isomer shifts ($\delta \approx 0.72\text{ mm/s}$) show that the electron density at the iron nucleus matches high-spin $\text{Fe}(\text{III})$ ($S_1 = 5/2$) antiferromagnetically coupled to an $\text{NO}^-$ radical anion ($S_2 = 1$).
- Thus, the physical ground state is best described as high-spin $\text{Fe}(\text{III})$ antiferromagnetically exchange-coupled to $\text{NO}^-$, while historically formulated as $\text{Fe}(\text{I})-\text{NO}^+$.
In the reductive elimination of ethane from diphosphine complexes $[(\text{diphosphine})\text{Pd}(\text{CH}_3)_2]$, the relative reaction rates at $25^\circ\text{C}$ vary dramatically with the diphosphine backbone: (a) dppm ($\beta_n = 72^\circ$): relative rate $= 1$; (b) dppe ($\beta_n = 85^\circ$): relative rate $= 10^2$; (c) dppf ($\beta_n = 99^\circ$): relative rate $= 6 \times 10^4$; (d) Xantphos ($\beta_n = 111^\circ$): relative rate $= 4 \times 10^7$. Explain the physical and orbital origins of this $10^7$-fold rate enhancement.
Line-by-Line Solution:
(a) Geometric Ground-State Destabilization:
- In the square planar reactant $[(\text{diphosphine})\text{Pd}(\text{CH}_3)_2]$, the ideal unconstrained valence angle around the $d^8$ $\text{Pd}(\text{II})$ center is $90^\circ$.
- The total angular span in the coordination plane must sum to $360^\circ$:
- When a diphosphine with a wide natural bite angle (e.g., Xantphos, $\beta_n = 111^\circ$) is coordinated:
- The $P-\text{Pd}-P$ angle is forced open from $90^\circ$ to $>105^\circ$.
- This widening exerts a mechanical scissors action on the coordination sphere, compressing the opposite methyl-palladium-methyl angle $\angle(C-\text{Pd}-C)$ from $90^\circ$ down to $<80^\circ$.
- Bringing the two methyl carbons into closer spatial proximity substantially raises the ground-state steric and electronic energy of the reactant, pre-organizing it toward the transition state.
(b) Frontier Molecular Orbital Overlap in the Transition State:
- Reductive elimination of ethane ($ ext{H}_3\text{C}-\text{CH}_3$) requires direct orbital overlap between the two filled $\sigma(\text{Pd}-\text{C})$ bonding orbitals:
- As the $C-\text{Pd}-C$ angle $\alpha$ decreases toward zero, the spatial overlap integral $S_{CC}$ between the $sp^3$ hybrid orbitals on the two methyl carbons increases exponentially:
- Simultaneously, widening the $P-\text{Pd}-P$ bite angle raises the energy of the occupied metal $d_{x^2-y^2}$ and $d_{xy}$ orbitals, facilitating the required two-electron transfer from the $Pd-C$ bonds back into a non-bonding metal $d$-orbital ($ ext{Pd}(\text{II}) \to \text{Pd}(0)$).
(c) Activation Free Energy Reduction:
- The activation barrier $\Delta G^\ddagger$ is the difference between transition state energy and ground state energy:
- Wide bite angle diphosphines simultaneously raise $G_{GS}$ (via ground-state steric strain) and lower $G_{TS}$ (via superior orbital overlap), drastically lowering $\Delta G^\ddagger$:
- A reduction of $43.4\text{ kJ/mol}$ in activation barrier accelerates the reaction by over seven orders of magnitude ($4 \times 10^7$).
The symmetric $A_1$ stretching frequency of $\text{Ni}(\text{CO})_3 L$ complexes defines the Tolman Electronic Parameter. (a) For $L = \text{P}(t\text{-Bu})_3$, $\nu(CO) = 2056.1\text{ cm}^{-1}$; for $L = \text{PMe}_3$, $\nu(CO) = 2064.1\text{ cm}^{-1}$; for $L = \text{PPh}_3$, $\nu(CO) = 2068.9\text{ cm}^{-1}$; for $L = \text{PF}_3$, $\nu(CO) = 2110.8\text{ cm}^{-1}$. Calculate the Tolman $\chi$ parameters for methyl, phenyl, and fluoro substituents. (b) Using second-order perturbation theory, derive the mathematical relationship between the energy of the phosphorus $\sigma^*(P-R)$ LUMO and the shift in $\nu(CO)$.
Line-by-Line Solution:
(a) Calculation of Tolman $\chi$ Parameters: Tolman's formula expresses the $A_1$ frequency of $\text{Ni}(\text{CO})_3(P R_1 R_2 R_3)$ as:
where $\chi_i$ is the additive contribution of substituent $R_i$, with $\chi(t\text{-Bu}) = 0.0\text{ cm}^{-1}$ by definition.
1. For $\text{PMe}_3$ ($R_1 = R_2 = R_3 = \text{Me}$):
2. For $\text{PPh}_3$ ($R_1 = R_2 = R_3 = \text{Ph}$):
3. For $\text{PF}_3$ ($R_1 = R_2 = R_3 = \text{F}$):
(b) Perturbation Derivation Connecting $\sigma^*(P-R)$ LUMO to $\Delta\nu(CO)$:
- Let $\epsilon_d$ be the unperturbed energy of the nickel $d$-orbitals, and $\epsilon_{\sigma^}$ be the energy of the phosphine $\sigma^(P-R)$ LUMO.
- The interaction matrix element between metal $d$ and phosphine $\sigma^(P-R)$ is $H_{d\sigma^}$.
- By second-order perturbation theory, the stabilization of the metal $d$-electrons due to $\pi$-backdonation into the phosphine is:
- Lowering the metal $d$-orbital energy by $\Delta E_d$ decreases the energy match and overlap with the higher-lying CO $2\pi^$ LUMO (energy $\epsilon_{\pi^(CO)}$).
- The fraction of electron density backdonated from nickel into the three CO ligands is proportional to:
- Because the force constant $k_{CO}$ increases linearly with the decrease in CO $\pi^$ population ($k_{CO} = k_0 - C \rho_{\pi^(CO)}$):
- Since $\Delta \nu \approx \frac{\Delta k_{CO}}{2\mu \nu_0}$:
When electronegative substituents like fluorine lower the energy $\epsilon_{\sigma^}$, the denominator $\epsilon_{\sigma^} - \epsilon_d$ decreases sharply, causing $\Delta \nu(CO)$ to shift to higher wavenumbers.
Disodium tetracarbonylferrate $\text{Na}_2[\text{Fe}(\text{CO})_4]$ reacts with an alkyl halide $R\text{Br}$ to yield an alkyliron intermediate (A), which upon treatment with triphenylphosphine $\text{PPh}_3$ converts to an acyliron intermediate (B). Subsequent reaction of (B) with molecular oxygen followed by acidic quench yields a carboxylic acid $R\text{COOH}$. (a) Determine the formal oxidation state and electron count of iron in $\text{Na}_2[\text{Fe}(\text{CO})_4]$, (A), and (B). (b) Formulate the detailed mechanism for the conversion of (A) to (B), and explain why this is a migratory insertion rather than direct CO addition. (c) Derive why $\text{Na}_2[\text{Fe}(\text{CO})_4]$ is termed a 'super-nucleophile' by evaluating its Pearson Hard-Soft Acid-Base (HSAB) parameters.
Line-by-Line Solution:
(a) Formal Oxidation State and Electron Count:
1. Collman's Reagent $\text{Na}_2[\text{Fe}(\text{CO})_4]$:
- CO ligands are neutral ($L_4$). Net charge of dianion is $-2$.
- Iron is Group 8: $d$-electron count $= 8 - (-2) = 10 \implies d^{10}$.
- Total valence electron count: $10 + 4(2) = 18\text{ electrons}$ (tetrahedral $T_d$).
2. Alkyliron Intermediate (A) $[R-\text{Fe}(\text{CO})_4]^-$:
- Alkyl group is an $X$-ligand (formal charge $-1$). Net charge is $-1$.
- Total valence electron count: $8 + 1 + 4(2) = 17$? No:
- Neutral model: Fe(8) + R(1) + 4 CO(8) + charge(1) $= 18\text{ electrons}$ (trigonal bipyramidal $D_{3h}$).
3. Acyliron Intermediate (B) $[R\text{CO}-\text{Fe}(\text{CO})_3(\text{PPh}_3)]^-$:
- Acyl group $R\text{CO}$ is an $X$-ligand ($-1$).
- Three CO ligands ($L_3$) and one $\text{PPh}_3$ ($L$).
- Fe oxidation state: $OS = 0 \implies d^8$.
- Valence electrons: $8 (\text{Fe}) + 1 (\text{acyl}) + 6 (3\text{CO}) + 2 (\text{PPh}_3) + 1 (\text{charge}) = 18\text{ electrons}$.
(b) Mechanism of Migratory Insertion ((A) to (B)):
- In $[R-\text{Fe}(\text{CO})_4]^-$, iron is an 18-electron saturated center. Incoming $\text{PPh}_3$ cannot directly attack iron without violating the 18e rule.
- The alkyl group $R$ migrates intramolecularly to the carbon atom of a mutually cis coordinated carbonyl ligand:
- Migratory insertion generates a coordinatively unsaturated, 16-electron intermediate possessing a vacant coordination site.
- The incoming triphenylphosphine ligand rapidly coordinates into this vacant site ($k_2 \gg k_{-1}$):
- $^{13}\text{C}$-labeling experiments confirm that the carbonyl carbon of the newly formed acyl group originates exclusively from one of the original coordinated CO ligands, proving an intramolecular alkyl migration.
(c) Super-Nucleophilicity and HSAB Analysis:
- In $[\text{Fe}(\text{CO})_4]^{2-}$, iron carries a formal $-2$ oxidation state with a completely filled, spherical $d^{10}$ closed shell.
- Pearson's chemical hardness parameter is defined as:
where $I$ is ionization potential and $A$ is electron affinity.
- The energy of the HOMO (highest occupied metal $d$-orbital) in $[\text{Fe}(\text{CO})_4]^{2-}$ is exceptionally high due to the double negative charge.
- The high polarizability and low ionization energy make $[\text{Fe}(\text{CO})_4]^{2-}$ an exceptionally soft, highly polarizable Lewis base.
- Its Swain-Scott nucleophilicity parameter $n$ exceeds $+14$ (many orders of magnitude greater than classical nucleophiles like iodide or hydroxide).
- Consequently, it undergoes rapid $S_N2$ oxidative addition with primary and secondary alkyl halides with clean inversion of configuration at carbon.
Triiron dodecacarbonyl $\text{Fe}_3(\text{CO})_{12}$ possesses two bridging $\mu_2-\text{CO}$ ligands and ten terminal CO ligands in the solid state ($C_{2v}$ symmetry). In solution at room temperature, its $^{13}\text{C}$ NMR spectrum displays a single sharp singlet down to $-150^\circ\text{C}$. (a) Calculate the total valence electron count ($TVE$) and the number of metal-metal bonds for $\text{Fe}_3(\text{CO})_{12}$. (b) Explain the 'concerted bridge-opening and closing' mechanism (Cotton dynamic merry-go-round model) that renders all twelve carbonyls chemically equivalent on the NMR timescale. (c) Estimate the upper limit for the activation barrier $\Delta G^\ddagger$ of this fluxional process at $-150^\circ\text{C}$.
Line-by-Line Solution:
(a) Total Valence Electron Count and Metal-Metal Bonding:
- Iron is in Group 8 ($n_v = 8$):
- Twelve CO ligands donate:
- Total Valence Electrons ($TVE$):
- Number of Metal-Metal bonds ($m$):
- Structure: The three iron atoms form an equilateral or isosceles triangle containing 3 single $\text{Fe}-\text{Fe}$ bonds.
(b) Cotton 'Merry-Go-Round' Dynamic Fluxional Mechanism:
- In the solid state, one $\text{Fe}-\text{Fe}$ edge is bridged by two $\mu_2-\text{CO}$ ligands, while the other two iron atoms each carry three terminal CO ligands, and the unique Fe atoms each carry two terminal CO ligands, breaking overall $D_{3h}$ symmetry to $C_{2v}$.
- In solution, the two bridging carbonyls open simultaneously to terminal positions:
- In the unbridged $D_{3h}$ intermediate (analogous to $\text{Ru}_3(\text{CO})_{12}$ and $\text{Os}_3(\text{CO})_{12}$), all twelve CO ligands are terminal.
- As the iron triangle rotates within the carbonyl envelope (or equivalently, as the carbonyls migrate along the triangular edges in a concerted 'merry-go-round' motion), pairs of carbonyls continuously open and close across different $\text{Fe}-\text{Fe}$ edges.
- This permutation rapidly exchanges bridging and terminal environments, as well as axial and equatorial sites, averaging the magnetic environment across all twelve $^{13}\text{C}$ nuclei.
(c) Upper Limit of Activation Barrier $\Delta G^\ddagger$ at $-150^\circ\text{C}$:
- Temperature: $T = -150^\circ\text{C} = 123.15\text{ K}$.
- At $-150^\circ\text{C}$, the peak remains a single sharp resonance without broadening. This implies that the exchange rate $k$ is still well above the coalescence rate:
For a typical $^{13}\text{C}$ chemical shift dispersion between bridging and terminal carbonyls of $\Delta \delta \approx 50\text{ ppm}$ at a $^{13}\text{C}$ frequency of $100\text{ MHz}$:
Since no broadening is observed, $k(123.15\text{ K}) > 2 \times 10^4\text{ s}^{-1}$.
- Using the Eyring equation:
- $\frac{k_B T}{h} = \frac{(1.38065 \times 10^{-23})(123.15)}{6.62607 \times 10^{-34}} = 2.566 \times 10^{12}\text{ s}^{-1}$
- $\ln\left(\frac{k_B T}{h}\right) = \ln(2.566 \times 10^{12}) \approx 28.57$
- $\ln(k) > \ln(2 \times 10^4) \approx 9.90$
- Difference: $28.57 - 9.90 = 18.67$
- Calculating $\Delta G^\ddagger$:
- Conclusion: The activation barrier for carbonyl scrambling in $\text{Fe}_3(\text{CO})_{12}$ is extraordinarily low: $\mathbf{\Delta G^\ddagger < 20\text{ kJ/mol}}$ (less than $5\text{ kcal/mol}$), rendering the carbonyl envelope essentially a liquid-like mantle flowing effortlessly over the rigid triiron cluster core.