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Chapter 6 • Theory & Derivations

Polymer processing and manufacturing

**Guiding question:** How do flow, cooling, orientation and process history determine a usable polymer product?

§6.1 Why this unit matters to polymer science

Guiding question: How do flow, cooling, orientation and process history determine a usable polymer product?

A molded component meets nominal dimensions at ejection but changes shape after a day. This is a question about flow, orientation and solidification and the distinction between machine settings versus actual material thermal history. A defensible answer identifies chain chemistry, molecular distribution, processing path and morphology before comparing measured properties. It also names the potentially controlling failure mode: a formulation that optimizes short-term stiffness, melt-flow index or optical clarity can still worsen creep resistance, process stability, environmental cracking or barrier lifetime. The technical sections below connect simplified mathematics to the kinds of measurements that would justify a practical claim.

Manufacturing determines final chain orientation, crystalline fraction, weak interfaces and internal void distributions. A thermoplastic product cannot be understood from pellets alone.

Keep measured melt temperature distinct from barrel setpoint; use cavity or die sensors and actual time histories when assessing morphology.

§6.2 Measurement and conservation checkpoints

Write down the starting chain chemistry, distribution, additive package and processing history; define whether reported fractions are by area, mass, moles or volume; and record the process history that could alter residence time, pressure, cavity geometry and cooling rate. For any local observation, describe why its sampling plan represents the part. Treat nonuniform temperature or weld-line weakness as an explicit rival explanation and plan in situ processing sensors and sectioned microscopy as an independent check.

§6.3 Extruder transport, shear heating and residence

Scientific foundation

An extrusion line melts, conveys, mixes and pressurizes polymer while imposing a distribution of temperature, shear and residence time. Screw geometry, feed conditions and die resistance couple throughput with melt history. A nominal barrel set temperature does not guarantee uniform polymer temperature because viscous dissipation and residence-time tails can produce hotspots or thermally degraded fractions. Average residence time can be estimated from effective filled volume and volumetric flow, but the distribution matters for heat-sensitive grades.

Governing relationship or decision rule: For constant effective filled volume V and volumetric flow Q, nominal mean residence time t=V/Q; actual distributions require tracer measurement. Read every term in the equation as part of a declared specimen condition. In extruder transport, shear heating and residence, a valid calculation requires the chain and microstructural state of the polymer, unit system and physical or geometrical meaning of each quantity. A nominally identical repeat-unit formula can conceal different chain-length distributions, branches, additives, crystallinity and processing damage. Equal average molar mass does not guarantee equivalent creep resistance, permeability or thermal transitions. Interpret measurements only after identifying which feature of the state they can support.

Worked polymer investigation

For an ideal well-mixed, filled volume of 250 cm³, compute tavg=250/Q seconds with Q between 10 and 100 cm³/s. Compare the mean with the tail of a tracer residence-time-distribution experiment. Discuss whether 10 s average proves that no material was held for 60 s and where stagnant zones could occur.

A companion calculator called Nominal extruder residence time supplies a separate, deliberately limited numerical experiment. Its controls isolate one effect so a reader can check dimensions and sensitivity instead of guessing the direction of change. At Volumetric polymer throughput = 22.85714 cm³/s, the declared formula returns 10.9375 s; at Volumetric polymer throughput = 35.71429 cm³/s, it returns 7 s. On this interval the modeled value decreases, and the two-point slope is -0.30625 s per cm³/s. These are worked calculations, not fabricated experimental observations or certified properties of any real polymer grade.

The browser expression is 250/Q. Model validity is limited to: Assumed filled material volume 250 cm³ with constant Q; no residence-time distribution, mixing or dead zones. Reproduce the first result with a calculator using the expression and units stated here. Before accepting the number, check the units analytically and identify what is being held constant. If a result looks realistic, that coincidence does not establish physical validation. Try an extreme permitted slider input and ask whether the computed change is physically interpretable or an artifact of the simplifying assumptions.

Evidence, uncertainty, and a competing mechanism

Throughput, melt compressibility, partial filling, leakage and stagnant regions make a simple plug-flow estimate incomplete. A higher throughput may also raise melt temperature despite shorter nominal residence.

Exercises and self-assessment

Exercise 6.1A — Physical mechanism. Why could a polymer degrade even when the mean barrel residence time is short? State one plausible explanation, one competing explanation and the material-state observation that separates them. Relate the claim to the governing relationship written above rather than merely repeating definitions.

Exercise 6.1B — Numerical cross-check. Recalculate 10.9375 s from the companion formula at 22.85714 cm³/s and compare with 7 s at 35.71429 cm³/s. State the sign of the sensitivity and explain whether the changed input would reasonably be controlled independently in a real polymer specimen.

Exercise 6.1C — Test design. Propose a synthesis, processing or test matrix that addresses nonuniform temperature or weld-line weakness. Give the specimen orientation, spatial sampling scheme, temperature-time record, environmental exposure and principal instrument calibration. Explain which observation would falsify your first hypothesis and name a condition under which your model should not be used.

§6.4 Injection molding: packing, shrinkage and warpage

Scientific foundation

Injection molding couples rapid filling, pressure-driven packing, solidification and part ejection. Local shrinkage depends on temperature-dependent specific volume and pressure history as well as crystallization and molecular orientation. Thick sections cool more slowly; constrained nonuniform shrinkage produces warpage and residual stresses. An ideal diffusion time estimated from h²/α is useful for scale comparisons but is not a cycle-time predictor.

Governing relationship or decision rule: A characteristic conduction timescale is proportional to h²/α for a comparable boundary condition, where α is thermal diffusivity. Read every term in the equation as part of a declared specimen condition. In injection molding: packing, shrinkage and warpage, a valid calculation requires the chain and microstructural state of the polymer, unit system and physical or geometrical meaning of each quantity. A nominally identical repeat-unit formula can conceal different chain-length distributions, branches, additives, crystallinity and processing damage. Equal average molar mass does not guarantee equivalent creep resistance, permeability or thermal transitions. Interpret measurements only after identifying which feature of the state they can support.

Worked polymer investigation

Use a characteristic half-thickness h between 0.5 and 5 mm and thermal diffusivity α=1.2e−7 m²/s to estimate h²/α. Doubling thickness increases the diffusion scale by roughly four times. Propose a short-shot and holding-pressure test while recording cavity pressure, rather than interpreting surface sink marks only from machine set pressure.

A companion calculator called Characteristic conduction time supplies a separate, deliberately limited numerical experiment. Its controls isolate one effect so a reader can check dimensions and sensitivity instead of guessing the direction of change. At Characteristic half-thickness = 1.785714 mm, the declared formula returns 26.573129 s; at Characteristic half-thickness = 2.428571 mm, it returns 49.14966 s. On this interval the modeled value increases, and the two-point slope is 35.119048 s per mm. These are worked calculations, not fabricated experimental observations or certified properties of any real polymer grade.

The browser expression is Math.pow(h*1e-3,2)/1.2e-7. Model validity is limited to: Simplified h²/alpha scale with constant alpha=1.2e-7 m²/s; not mold cycle time, ignores crystallization and contacts. Reproduce the first result with a calculator using the expression and units stated here. Before accepting the number, check the units analytically and identify what is being held constant. If a result looks realistic, that coincidence does not establish physical validation. Try an extreme permitted slider input and ask whether the computed change is physically interpretable or an artifact of the simplifying assumptions.

Evidence, uncertainty, and a competing mechanism

The diffusion scale omits mold contact resistance, latent heat of crystallization, spatially varying properties and complex geometry. Real cooling criteria require validated simulation or thermocouples.

Exercises and self-assessment

Exercise 6.2A — Physical mechanism. Why might raising pack pressure reduce sink while increasing distortion elsewhere in the part? State one plausible explanation, one competing explanation and the material-state observation that separates them. Relate the claim to the governing relationship written above rather than merely repeating definitions.

Exercise 6.2B — Numerical cross-check. Recalculate 26.573129 s from the companion formula at 1.785714 mm and compare with 49.14966 s at 2.428571 mm. State the sign of the sensitivity and explain whether the changed input would reasonably be controlled independently in a real polymer specimen.

Exercise 6.2C — Test design. Propose a synthesis, processing or test matrix that addresses nonuniform temperature or weld-line weakness. Give the specimen orientation, spatial sampling scheme, temperature-time record, environmental exposure and principal instrument calibration. Explain which observation would falsify your first hypothesis and name a condition under which your model should not be used.

§6.5 Film blowing and drawing orientation

Scientific foundation

Oriented polymer films derive property combinations from biaxial stretching, cooling and crystallization kinetics. Draw ratio, bubble stability, frost-line position and interlayer adhesion influence machine and transverse direction strengths. Orientation can improve in-plane tensile response and reduce permeability along some paths, yet high anisotropy may worsen tear performance. Film thickness uniformity cannot be deduced from total output alone.

Governing relationship or decision rule: Volume conservation for a uniformly drawn incompressible filament gives A1L1≈A2L2, subject to density and mass conservation. Read every term in the equation as part of a declared specimen condition. In film blowing and drawing orientation, a valid calculation requires the chain and microstructural state of the polymer, unit system and physical or geometrical meaning of each quantity. A nominally identical repeat-unit formula can conceal different chain-length distributions, branches, additives, crystallinity and processing damage. Equal average molar mass does not guarantee equivalent creep resistance, permeability or thermal transitions. Interpret measurements only after identifying which feature of the state they can support.

Worked polymer investigation

Collect tensile and tear measurements in machine and transverse directions for films made at different draw ratios but similar thickness. Measure orientation using birefringence or scattering, and map gauge variation around a bubble. Compare a resin with good extensional strain hardening against one with similar shear viscosity but less melt strength.

A companion calculator called Nominal extruder residence time supplies a separate, deliberately limited numerical experiment. Its controls isolate one effect so a reader can check dimensions and sensitivity instead of guessing the direction of change. At Volumetric polymer throughput = 48.57143 cm³/s, the declared formula returns 5.1470588 s; at Volumetric polymer throughput = 61.42857 cm³/s, it returns 4.0697674 s. On this interval the modeled value decreases, and the two-point slope is -0.08378933 s per cm³/s. These are worked calculations, not fabricated experimental observations or certified properties of any real polymer grade.

Evidence, uncertainty, and a competing mechanism

Orientation relaxes under heat and is altered by annealing. Polymer crystallization and comonomer branching also change barrier performance, so drawing alone may not explain differences.

Exercises and self-assessment

Exercise 6.3A — Physical mechanism. Which combination of measurements shows whether a film's stronger machine direction came from orientation rather than just increased thickness? State one plausible explanation, one competing explanation and the material-state observation that separates them. Relate the claim to the governing relationship written above rather than merely repeating definitions.

Exercise 6.3B — Numerical cross-check. Recalculate 5.1470588 s from the companion formula at 48.57143 cm³/s and compare with 4.0697674 s at 61.42857 cm³/s. State the sign of the sensitivity and explain whether the changed input would reasonably be controlled independently in a real polymer specimen.

Exercise 6.3C — Test design. Propose a synthesis, processing or test matrix that addresses nonuniform temperature or weld-line weakness. Give the specimen orientation, spatial sampling scheme, temperature-time record, environmental exposure and principal instrument calibration. Explain which observation would falsify your first hypothesis and name a condition under which your model should not be used.

§6.6 Additive manufacturing and layer interfaces

Scientific foundation

Thermoplastic material extrusion printing forms bonds by contact, chain diffusion and cooling at adjacent deposited roads. Bed temperature, chamber conditions and deposited strand shape set a local thermal welding history. Voids and incomplete fusion can make cross-build-direction strength much lower than along-road strength. Printing a geometrically complete part is not evidence of isotropic properties or required interlayer fracture resistance.

Governing relationship or decision rule: Interlayer bonding is governed by thermal contact, chain mobility and interfacial geometry, not only nominal slicer temperature. Read every term in the equation as part of a declared specimen condition. In additive manufacturing and layer interfaces, a valid calculation requires the chain and microstructural state of the polymer, unit system and physical or geometrical meaning of each quantity. A nominally identical repeat-unit formula can conceal different chain-length distributions, branches, additives, crystallinity and processing damage. Equal average molar mass does not guarantee equivalent creep resistance, permeability or thermal transitions. Interpret measurements only after identifying which feature of the state they can support.

Worked polymer investigation

Design a tensile and fracture comparison for specimens printed flat, on-edge and upright using the same nominal filament. Log actual nozzle and chamber temperatures, raster width and void fraction by sectioning or tomography. Ask which changes reflect polymer chemistry and which reflect mesoscale weld geometry and thermal history.

A companion calculator called Characteristic conduction time supplies a separate, deliberately limited numerical experiment. Its controls isolate one effect so a reader can check dimensions and sensitivity instead of guessing the direction of change. At Characteristic half-thickness = 3.071429 mm, the declared formula returns 78.613946 s; at Characteristic half-thickness = 3.714286 mm, it returns 114.96599 s. On this interval the modeled value increases, and the two-point slope is 56.547619 s per mm. These are worked calculations, not fabricated experimental observations or certified properties of any real polymer grade.

Evidence, uncertainty, and a competing mechanism

Filament moisture, recycling history and porosity complicate strength differences. The melt residence and cooling sliders are only timescale aids; neither calculates weld healing or accepted print safety.

Exercises and self-assessment

Exercise 6.4A — Physical mechanism. What evidence separates weak interlayer molecular welding from geometric under-extrusion? State one plausible explanation, one competing explanation and the material-state observation that separates them. Relate the claim to the governing relationship written above rather than merely repeating definitions.

Exercise 6.4B — Numerical cross-check. Recalculate 78.613946 s from the companion formula at 3.071429 mm and compare with 114.96599 s at 3.714286 mm. State the sign of the sensitivity and explain whether the changed input would reasonably be controlled independently in a real polymer specimen.

Exercise 6.4C — Test design. Propose a synthesis, processing or test matrix that addresses nonuniform temperature or weld-line weakness. Give the specimen orientation, spatial sampling scheme, temperature-time record, environmental exposure and principal instrument calibration. Explain which observation would falsify your first hypothesis and name a condition under which your model should not be used.

§6.7 Compounding, fillers and secondary materials

Scientific foundation

Reinforcing fillers, pigments, flame retardants and stabilizers create a formulation rather than simply adding material to a pure resin. Nanofillers can raise stiffness at low loading but agglomeration and poor adhesion may create brittle flaws. Recycled content changes thermal and oxidative history, composition uncertainty and contaminant risk. Dispersion energy and processing residence time must be controlled before claiming a performance effect.

Governing relationship or decision rule: In an elementary axial iso-strain upper bound, Ec≈φf Ef+(1−φf)Em; actual discontinuous fillers generally fall below the bound. Read every term in the equation as part of a declared specimen condition. In compounding, fillers and secondary materials, a valid calculation requires the chain and microstructural state of the polymer, unit system and physical or geometrical meaning of each quantity. A nominally identical repeat-unit formula can conceal different chain-length distributions, branches, additives, crystallinity and processing damage. Equal average molar mass does not guarantee equivalent creep resistance, permeability or thermal transitions. Interpret measurements only after identifying which feature of the state they can support.

Worked polymer investigation

Compare a neat resin with two filler volume fractions and one recycled-content blend. Measure melt flow, modulus, impact response and microscopy-based agglomerate size under matched processing. Account for mass-basis versus volume-basis filler fraction and specify filler density. Select one acceptance criterion before measuring so the 'best' formulation is not chosen after inspecting the results.

A companion calculator called Nominal extruder residence time supplies a separate, deliberately limited numerical experiment. Its controls isolate one effect so a reader can check dimensions and sensitivity instead of guessing the direction of change. At Volumetric polymer throughput = 74.28571 cm³/s, the declared formula returns 3.3653846 s; at Volumetric polymer throughput = 87.14286 cm³/s, it returns 2.8688525 s. On this interval the modeled value decreases, and the two-point slope is -0.038619168 s per cm³/s. These are worked calculations, not fabricated experimental observations or certified properties of any real polymer grade.

Evidence, uncertainty, and a competing mechanism

A higher modulus can coexist with lower strength, poorer fatigue or reduced processability. Industrial recycling may require food-contact or other regulatory evidence beyond bulk mechanical tests.

Exercises and self-assessment

Exercise 6.5A — Physical mechanism. Why is increasing tensile modulus alone insufficient evidence of successful filler reinforcement? State one plausible explanation, one competing explanation and the material-state observation that separates them. Relate the claim to the governing relationship written above rather than merely repeating definitions.

Exercise 6.5B — Numerical cross-check. Recalculate 3.3653846 s from the companion formula at 74.28571 cm³/s and compare with 2.8688525 s at 87.14286 cm³/s. State the sign of the sensitivity and explain whether the changed input would reasonably be controlled independently in a real polymer specimen.

Exercise 6.5C — Test design. Propose a synthesis, processing or test matrix that addresses nonuniform temperature or weld-line weakness. Give the specimen orientation, spatial sampling scheme, temperature-time record, environmental exposure and principal instrument calibration. Explain which observation would falsify your first hypothesis and name a condition under which your model should not be used.

§6.8 Integrated investigation: Warpage during manufacturing

The evidence problem

A molded component meets nominal dimensions at ejection but changes shape after a day. The problem cannot be solved by selecting the equation that gives the most convenient number. First define which property must be achieved, the physical constraint that could prevent it, and the microstructural condition of the specimen being evaluated. List known facts separately from inferred mechanisms, uncertain constants and quantities not yet measured. The central decision is not simply which polymerization route or formulated resin seems attractive: it is what observations would allow a researcher or an engineer to prefer one explanation over competing causes.

Integrated analysis and model workflow

Link uneven cooling, crystallization, molecular orientation, packing gradient and post-mold shrinkage. Build a minimal processing–structure–property map linking the material history with observed state and relevant response. Carry the distinction between flow, orientation and solidification and machine settings versus actual material thermal history through the map. For polymer mixing, show composition conservation and do not infer processing kinetics from a static phase diagram. For a melt-state relation, distinguish relaxation time from shear-rate-dependent flow and actual process heating. For chemical function, distinguish molecular diffusion, partitioning, chain mobility and chemical degradation. Use the actual specimen time–temperature history instead of only a machine-temperature set point. For damage, compare local flaw driving force with rate- and environment-dependent measured fracture resistance.

Validation plan, report, and counterfactual

Record cavity pressure, specimen temperature and dimensional maps, with randomized process trials and section analysis. Include an alternative interpretation capable of explaining the same first observation and choose a different instrument or held-out processing condition that separates it. State which measurement would cause you to reject the favored hypothesis. Retain raw counts, image scales, processing logs and sample identifiers. If comparing polymer families, write down the constraints that matter for stiffness, creep, permeability, thermal history and chemical exposure rather than reporting only one maximum strength metric.

Known limits: An h²/α timescale provides scaling insight but not guaranteed cycle time. A reader should be able to reconstruct the entire inference from original specimen provenance and measured inputs. The synthetic datasets intentionally contain no physical replicate scatter or hidden model mismatch; those omissions would make a real-world confidence interval far wider than a formula plot suggests.

Five cumulative exam questions

  1. Draw a cause-and-effect diagram linking composition, process history, flow, orientation and solidification and the decision-controlling property; mark one arrow that cannot yet be established from the observations.
  2. Write a conservation or constitutive relation for machine settings versus actual material thermal history with all units and physical validity assumptions; interpret one limiting case.
  3. Propose two mutually exclusive experimental signatures for the favored and competing mechanisms and name the required independent instruments.
  4. Show how nonuniform temperature or weld-line weakness could reverse a seemingly beneficial result, and design the minimum additional test needed to detect that reversal.
  5. Write a one-paragraph evidence statement specifying what has been demonstrated, what is merely predicted, and which industrial decision is unjustified until qualification.

THREE WORKED QUESTIONS

Step-by-Step Statistical Simulation and Monte Carlo Solutions

Three original questions connect calculations, definitions and interpretation. Open each solution to follow the reasoning.

Solved Problem Example 6.1: Nominal extruder residence time

For an ideal well-mixed, filled volume of 250 cm³, compute tavg=250/Q seconds with Q between 10 and 100 cm³/s. Compare the mean with the tail of a tracer residence-time-distribution experiment. Discuss whether 10 s average proves that no material was held for 60 s and where stagnant zones could occur.

Step

A companion calculator called Nominal extruder residence time supplies a separate, deliberately limited numerical experiment. Its controls isolate one effect so a reader can check dimensions and sensitivity instead of guessing the direction of change. At Volumetric polymer throughput = 22.85714 cm³/s, the declared formula returns 10.9375 s; at Volumetric polymer throughput = 35.71429 cm³/s, it returns 7 s. On this interval the modeled value decreases, and the two-point slope is -0.30625 s per cm³/s. These are worked calculations, not fabricated experimental observations or certified properties of any real polymer grade.

Step

The browser expression is 250/Q. Model validity is limited to: Assumed filled material volume 250 cm³ with constant Q; no residence-time distribution, mixing or dead zones. Reproduce the first result with a calculator using the expression and units stated here. Before accepting the number, check the units analytically and identify what is being held constant. If a result looks realistic, that coincidence does not establish physical validation. Try an extreme permitted slider input and ask whether the computed change is physically interpretable or an artifact of the simplifying assumptions.

Solved Problem Example 6.2: Characteristic conduction time

Use a characteristic half-thickness h between 0.5 and 5 mm and thermal diffusivity α=1.2e−7 m²/s to estimate h²/α. Doubling thickness increases the diffusion scale by roughly four times. Propose a short-shot and holding-pressure test while recording cavity pressure, rather than interpreting surface sink marks only from machine set pressure.

Step

A companion calculator called Characteristic conduction time supplies a separate, deliberately limited numerical experiment. Its controls isolate one effect so a reader can check dimensions and sensitivity instead of guessing the direction of change. At Characteristic half-thickness = 1.785714 mm, the declared formula returns 26.573129 s; at Characteristic half-thickness = 2.428571 mm, it returns 49.14966 s. On this interval the modeled value increases, and the two-point slope is 35.119048 s per mm. These are worked calculations, not fabricated experimental observations or certified properties of any real polymer grade.

Step

The browser expression is Math.pow(h*1e-3,2)/1.2e-7. Model validity is limited to: Simplified h²/alpha scale with constant alpha=1.2e-7 m²/s; not mold cycle time, ignores crystallization and contacts. Reproduce the first result with a calculator using the expression and units stated here. Before accepting the number, check the units analytically and identify what is being held constant. If a result looks realistic, that coincidence does not establish physical validation. Try an extreme permitted slider input and ask whether the computed change is physically interpretable or an artifact of the simplifying assumptions.

Solved Problem Example 6.3: Nominal extruder residence time

Collect tensile and tear measurements in machine and transverse directions for films made at different draw ratios but similar thickness. Measure orientation using birefringence or scattering, and map gauge variation around a bubble. Compare a resin with good extensional strain hardening against one with similar shear viscosity but less melt strength.

Step

A companion calculator called Nominal extruder residence time supplies a separate, deliberately limited numerical experiment. Its controls isolate one effect so a reader can check dimensions and sensitivity instead of guessing the direction of change. At Volumetric polymer throughput = 48.57143 cm³/s, the declared formula returns 5.1470588 s; at Volumetric polymer throughput = 61.42857 cm³/s, it returns 4.0697674 s. On this interval the modeled value decreases, and the two-point slope is -0.08378933 s per cm³/s. These are worked calculations, not fabricated experimental observations or certified properties of any real polymer grade.

Solved Problem Example 6.4: Characteristic conduction time

Design a tensile and fracture comparison for specimens printed flat, on-edge and upright using the same nominal filament. Log actual nozzle and chamber temperatures, raster width and void fraction by sectioning or tomography. Ask which changes reflect polymer chemistry and which reflect mesoscale weld geometry and thermal history.

Step

A companion calculator called Characteristic conduction time supplies a separate, deliberately limited numerical experiment. Its controls isolate one effect so a reader can check dimensions and sensitivity instead of guessing the direction of change. At Characteristic half-thickness = 3.071429 mm, the declared formula returns 78.613946 s; at Characteristic half-thickness = 3.714286 mm, it returns 114.96599 s. On this interval the modeled value increases, and the two-point slope is 56.547619 s per mm. These are worked calculations, not fabricated experimental observations or certified properties of any real polymer grade.

Solved Problem Example 6.5: Nominal extruder residence time

Compare a neat resin with two filler volume fractions and one recycled-content blend. Measure melt flow, modulus, impact response and microscopy-based agglomerate size under matched processing. Account for mass-basis versus volume-basis filler fraction and specify filler density. Select one acceptance criterion before measuring so the 'best' formulation is not chosen after inspecting the results.

Step

A companion calculator called Nominal extruder residence time supplies a separate, deliberately limited numerical experiment. Its controls isolate one effect so a reader can check dimensions and sensitivity instead of guessing the direction of change. At Volumetric polymer throughput = 74.28571 cm³/s, the declared formula returns 3.3653846 s; at Volumetric polymer throughput = 87.14286 cm³/s, it returns 2.8688525 s. On this interval the modeled value decreases, and the two-point slope is -0.038619168 s per cm³/s. These are worked calculations, not fabricated experimental observations or certified properties of any real polymer grade.