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Chapter 8 • Theory & Derivations

Reliability, Economics and Responsible Plant Design

Comprehensive university textbook unit covering fundamental principles, governing relationships, and engineering applications of Reliability, Economics and Responsible Plant Design.

§8.1 Failure modes and maintenance planning

**Core topic:** repair time and outage exposure. **Representative relation:** `Availability = MTBF/(MTBF+MTTR)`. **Case context:** unit maintenance register.

§8.2 Capacity credit and reserve planning

**Core topic:** reliability versus output statistics. **Representative relation:** `E_expected = P_rated*CF*8760`. **Case context:** high-demand-week planning scenario.

§8.3 Simple levelized energy cost

**Core topic:** cost per delivered MWh. **Representative relation:** `LCOE = annual_total_cost/E_year`. **Case context:** annualized capital and operation-cost worksheet.

§8.4 Lifecycle impacts and uncertainty

**Core topic:** consistent lifecycle normalization. **Representative relation:** `I_CO2 = m_CO2_lifecycle/E_lifetime`. **Case context:** replacement versus refurbishment comparison.

§8.5 Capstone integrated plant evaluation

**Core topic:** closing energy and decision accounts. **Representative relation:** `Residual_energy = Q_in-P_e-Q_reject-Q_other`. **Case context:** conceptual comparison of three plant options.

THREE WORKED QUESTIONS

Step-by-Step Power Plant Engineering Solutions

Three original questions connect calculations, definitions and interpretation. Open each solution to follow the reasoning.

Solved Problem Example 8.1: Calculation & Verification: Failure modes and maintenance planning

Problem Statement: In a simplified alternating failure-repair model, MTBF is 5000 h and mean repair time is 100 h. Operational availability is 5000/(5000 + 100) = **98.04%**. Planned maintenance, derated operation and common-cause failures are outside this two-number expression.

Worked Engineering Derivation:

**Verification and limitations.** Annual capacity factor is not the same quantity as availability. The result is illustrative and does not replace equipment-specific property data, measurements or professional review.

Solved Problem Example 8.2: Calculation & Verification: Capacity credit and reserve planning

Problem Statement: A 100 MW net-rated generator serves peaking demand and has annual capacity factor 25%. Its annual energy is 100 × 0.25 × 8760 = **219,000 MWh**. This output alone says nothing about the value of its availability during the 50 highest-price or highest-stress hours.

Worked Engineering Derivation:

**Verification and limitations.** Capacity credit depends on system need and the probability of resource availability at critical times. The result is illustrative and does not replace equipment-specific property data, measurements or professional review.

Solved Problem Example 8.3: Calculation & Verification: Simple levelized energy cost

Problem Statement: A project reports annualized fixed, fuel and operations cost totaling 40 million dollars and expected delivered annual energy of 800,000 MWh. Its simplified cost is $40,000,000/800,000 = **$50/MWh**. The figure is not a complete financed project LCOE unless the capital annualization, taxes, financing and other assumptions have been specified.

Worked Engineering Derivation:

**Verification and limitations.** A cheaper mean $/MWh may still fail to supply capacity, flexibility or the required environmental service. The result is illustrative and does not replace equipment-specific property data, measurements or professional review.

Solved Problem Example 8.4: Calculation & Verification: Lifecycle impacts and uncertainty

Problem Statement: A lifecycle inventory attributes 400,000 tonnes of CO2-equivalent to a project, and lifetime net energy delivery is 5,000,000 MWh. The intensity is 400,000/5,000,000 = **0.08 t CO2e/MWh**, or 80 kg/MWh. Changes to the boundary—construction, fuel supply, or end-of-life—change the result.

Worked Engineering Derivation:

**Verification and limitations.** Uncertainty and allocation choices should be visible rather than hidden in one exact-looking number. The result is illustrative and does not replace equipment-specific property data, measurements or professional review.

Solved Problem Example 8.5: Calculation & Verification: Capstone integrated plant evaluation

Problem Statement: A conceptual plant receives 400 MW(th), exports 155 MW(e), rejects 210 MW(th) through cooling, and has 25 MW(th) of other quantified losses. The unclosed energy residual is 400 − 155 − 210 − 25 = **10 MW(th)**. The analyst must investigate this residual as possible unmeasured loss, stored-energy change, or measurement error; it must not silently disappear.

Worked Engineering Derivation:

**Verification and limitations.** A closed spreadsheet is not sufficient evidence of plant safety, emissions compliance or economic viability. The result is illustrative and does not replace equipment-specific property data, measurements or professional review.