Nuclear Fission Mechanics, Energy Release & Product Yields
Exhaustive treatment of nuclear fission mechanics and phenomenology: the Bohr-Wheeler liquid drop model deformation energetics, Coulomb vs surface tension competition, fissility parameter and spontaneous fission systematics; practical nuclear fuel forms (LEU, HEU, MOX, thorium-uranium cycle, transuranic burners); asymmetric mass distribution and double-hump fission product yield curves; comprehensive energy partition accounting for prompt/delayed fragments, neutrons, gammas, neutrinos, and recoverable Q-value (200 MeV); Watt fission neutron energy spectrum derivation and characteristic mean/probable energies; prompt versus delayed neutron emission kinetics, six precursor groups, and physical significance for reactor control; thermal power, fission consumption rates, and core burnup metrics in MWd/MTU.
§3.1 The Liquid Drop Model of Fission: Deformation Energetics & Bohr-Wheeler Barrier
1. Fission Energetics and the Liquid Drop Analogy
The liquid drop model (LDM), formulated by Niels Bohr and John Archibald Wheeler (1939), models the heavy atomic nucleus as an incompressible, charged macroscopic liquid droplet with constant nuclear matter density $\rho_0 \approx 0.17\text{ nucleons/fm}^3$. The nuclear ground state represents an equilibrium configuration between two opposing forces:
- Short-range attractive nuclear force: Represented macroscopically as surface tension energy $E_s$, which acts to minimize nuclear surface area (favoring a spherical shape).
- Long-range repulsive Coulomb force: Represented as electrostatic self-energy $E_c$, which pushes protons apart and drives the nucleus toward elongated, non-spherical deformations.
2. Ellipsoidal Deformation and Fissility Parameter
Consider a spherical nucleus of radius $R_0 = r_0 A^{1/3}$ undergoing a small quadrupole deformation into a prolate spheroid with semi-major axis $a = R_0 (1 + \epsilon)$ and semi-minor axes $b = c = R_0 (1 - \frac{1}{2}\epsilon)$, preserving volume to second order in eccentricity $\epsilon$: $$R(\theta) = R_0 \left[ 1 + \alpha_2 P_2(\cos\theta) \right]$$ Expanding the surface and Coulomb energy terms in powers of the deformation coordinate $\alpha_2$: $$E_s(\alpha_2) = E_s^{(0)} \left( 1 + \frac{2}{5} \alpha_2^2 + \mathcal{O}(\alpha_2^3) \right)$$ $$E_c(\alpha_2) = E_c^{(0)} \left( 1 - \frac{1}{5} \alpha_2^2 + \mathcal{O}(\alpha_2^3) \right)$$ where the undeformed ground-state values from the semi-empirical mass formula (Weizsäcker) are: $$E_s^{(0)} = a_s A^{2/3} \approx 17.8 \times A^{2/3}\text{ MeV}, \qquad E_c^{(0)} = a_c \frac{Z^2}{A^{1/3}} \approx 0.71 \times \frac{Z^2}{A^{1/3}}\text{ MeV}$$ The change in net nuclear energy $\Delta E = \Delta E_s + \Delta E_c$ as a function of deformation $\alpha_2$ is: $$\Delta E(\alpha_2) = \alpha_2^2 \left( \frac{2}{5} E_s^{(0)} - \frac{1}{5} E_c^{(0)} \right) = \frac{1}{5} \alpha_2^2 \left( 2 E_s^{(0)} - E_c^{(0)} \right)$$
For the spherical shape to remain stable against spontaneous deformation, the coefficient of $\alpha_2^2$ must be positive ($\Delta E > 0$). When electrostatic repulsion overcomes surface tension, the sphere becomes unstable to infinitesimal perturbations ($\Delta E < 0$): $$2 E_s^{(0)} - E_c^{(0)} < 0 \implies \frac{E_c^{(0)}}{2 E_s^{(0)}} > 1$$ Substituting the Bethe-Weizsäcker coefficients: $$\frac{0.71 \times Z^2 / A^{1/3}}{2 \times 17.8 \times A^{2/3}} \approx \frac{Z^2 / A}{50.1} > 1 \implies \mathbf{\frac{Z^2}{A} \gtrsim 49\text{ to }50}$$ The dimensionless ratio $x \equiv \frac{E_c^{(0)}}{2 E_s^{(0)}} \approx \frac{Z^2/A}{(Z^2/A)_{\text{crit}}}$ is known as the Bohr-Wheeler fissility parameter. For heavy actinides such as ${}^{238}\text{U}$ ($Z^2/A \approx 35.6$) and ${}^{235}\text{U}$ ($Z^2/A \approx 36.0$), $x \approx 0.72$, meaning they are stable against spontaneous deformation at the ground state but possess a finite fission activation barrier.
3. The Fission Barrier and Saddle Point
As deformation increases beyond the harmonic quadratic regime, higher multipoles ($\alpha_3, \alpha_4$) develop necking, culminating in the saddle point—the maximum potential energy along the lowest-energy fission valley. The height of this peak above the ground state is the fission barrier $E_B$: $$E_B = E_{\text{saddle}} - E_{\text{ground}}$$ Representative fission barrier heights:
- ${}^{235}\text{U}$: $E_B \approx 5.75\text{ MeV}$
- ${}^{238}\text{U}$: $E_B \approx 6.25\text{ MeV}$
- ${}^{239}\text{Pu}$: $E_B \approx 5.50\text{ MeV}$
- ${}^{232}\text{Th}$: $E_B \approx 6.50\text{ MeV}$
§3.2 Practical Nuclear Fuels: LEU, HEU, MOX, Thorium Cycle & Transuranic Burners
1. Fuel Classification and Enrichment Regimes
Nuclear fuels in fission reactors are categorized according to isotopic composition, physical phase, and chemical matrix:
- Natural Uranium (NatU): $0.7204\%\ {}^{235}\text{U}$, $99.274\%\ {}^{238}\text{U}$, $0.0055\%\ {}^{234}\text{U}$. Used directly in heavy-water moderated reactors (CANDU, PHWR) and carbon dioxide-cooled graphite reactors (Magnox).
- Low-Enriched Uranium (LEU): Uranium enriched to $3\%\text{ to }5\%\ {}^{235}\text{U}$ by mass. Standard commercial fuel for Light Water Reactors (PWR and BWR).
- High-Assay Low-Enriched Uranium (HALEU): Uranium enriched between $5\%\text{ and }20\%\ {}^{235}\text{U}$. Crucial for advanced Small Modular Reactors (SMRs) and Generation IV fast reactors, offering high power density and extended refueling cycles without crossing proliferation safeguards.
- Highly Enriched Uranium (HEU): Uranium enriched to $\ge 20\%\ {}^{235}\text{U}$ (weapons-grade $\ge 90\%$). Restricted to naval propulsion reactors, research reactors, and space fission systems.
2. Mixed Oxide (MOX) and Plutonium Recycling
Mixed Oxide fuel consists of depleted uranium dioxide ($\text{UO}_2$) blended with recycled reactor-grade plutonium dioxide ($\text{PuO}_2$), typically containing $5\%\text{ to }9\%\ \text{Pu}_{\text{fissile}}$ (${}^{239}\text{Pu} + {}^{241}\text{Pu}$): $$\text{MOX} = (1 - x)\,\text{UO}_2 + x\,\text{PuO}_2$$ Key neutron physical consequences of MOX fuel in thermal cores:
- Hardened Neutron Spectrum: Massive capture and fission resonances of ${}^{239}\text{Pu}$ ($0.296\text{ eV}$) and ${}^{240}\text{Pu}$ ($1.056\text{ eV}$) depress the thermal flux and harden the average energy spectrum.
- Reduced Delayed Neutron Fraction: $\beta_{\text{eff}}$ decreases because $\beta({}^{239}\text{Pu}) \approx 0.00215$ compared to $\beta({}^{235}\text{U}) \approx 0.00650$, requiring tighter control rod margins.
- Increased Control Rod Absorption Requirements: Stronger thermal absorption in fuel requires higher boron concentration or enriched boron carbide ($\text{B}_4\text{C}$) control rods.
3. The Thorium-Uranium Fuel Cycle
The thorium fuel cycle exploits fertile ${}^{232}\text{Th}$ to breed fissile ${}^{233}\text{U}$: $${}^{232}_{90}\text{Th} + n \longrightarrow {}^{233}_{90}\text{Th} \xrightarrow[\beta^-, \, 22.3\text{ min}]{} {}^{233}_{91}\text{Pa} \xrightarrow[\beta^-, \, 26.97\text{ days}]{} {}^{233}_{92}\text{U}$$ The major nuclear advantage is that ${}^{233}\text{U}$ exhibits $\eta > 2.25$ across the entire thermal neutron spectrum (superior to ${}^{235}\text{U}$ at $\eta = 2.07$ and ${}^{239}\text{Pu}$ at $\eta = 2.11$), making thermal breeding feasible (e.g. in Molten Salt Breeder Reactors - MSBR). In addition, thorium fuels produce orders of magnitude fewer long-lived transuranic actinides ($\text{Np, Pu, Am, Cm}$) because six successive neutron captures are needed to reach plutonium.
§3.3 Mass Distribution and Fission Product Yields: The Asymmetric Double Hump
1. Mass Yield Curve: Bimodal vs Symmetric Cleavage
When low-energy (thermal) neutrons induce fission in ${}^{235}\text{U}$ or ${}^{239}\text{Pu}$, the nucleus splits overwhelmingly into two fragments of unequal mass. The percentage yield of fission fragments as a function of mass number $A$ is the fission product mass yield curve $Y(A)$, normalized such that: $$\sum_{A} Y(A) = 200\%$$ since each fission produces exactly two primary fission fragments.
For thermal fission of ${}^{235}\text{U}$:
- Light Fragment Peak: Centered at mass number $A_L \approx 95$ (peak yield $\sim 6.5\%$ at isotopes like ${}^{95}\text{Mo}, {}^{95}\text{Zr}, {}^{90}\text{Sr}$).
- Heavy Fragment Peak: Centered at mass number $A_H \approx 138\text{ to }140$ (peak yield $\sim 6.5\%$ at ${}^{137}\text{Cs}, {}^{135}\text{Xe}, {}^{140}\text{Ba}$).
- Symmetric Fission Valley: At $A \approx 117$, symmetric splitting is suppressed by a factor of over $600$ ($Y(117) \approx 0.01\%$).
2. Shell Effects and Energy-Dependent Peak-to-Valley Ratio
The asymmetric splitting is explained by single-particle nuclear shell model effects in the deformed nascent fragments:
- The heavy fragment favors magic numbers: $Z = 50$ (closed spherical proton shell) and $N = 82$ (closed spherical neutron shell, $A \approx 132$, e.g. ${}^{132}_{50}\text{Sn}$), which provides exceptional quantum stability.
- As incident neutron energy increases from thermal to fast ($E_n \sim 14\text{ MeV}$ in D-T fusion), excitation washes out shell effects; the central valley fills in, and the distribution shifts toward symmetric fission.
§3.4 Energy Partition of Fission: Recoverable Energy & Thermodynamic Balance
1. Microscopic Energy Partition Breakdown
When a ${}^{235}\text{U}$ nucleus captures a thermal neutron and fissions, approximately $200\text{ MeV}$ of total energy is liberated. The microscopic distribution of this energy among products is summarized below:
| Energy Component | Energy (MeV) | Fraction (%) | Recovery Mechanism |
|---|---|---|---|
| Kinetic Energy of Fission Fragments | $168 \pm 5$ | $84.0\%$ | Thermalized locally within $\sim 10\ \mu\text{m}$ in fuel |
| Kinetic Energy of Prompt Neutrons ($\nu \approx 2.43$) | $5 \pm 0.5$ | $2.5\%$ | Thermalized via elastic scattering in moderator |
| Prompt Fission Gamma Rays ($\gamma_{\text{prompt}}$) | $7 \pm 1$ | $3.5\%$ | Absorbed in fuel, cladding, coolant, shield |
| Fission Product Beta Decay ($\beta^-$) | $8 \pm 1$ | $4.0\%$ | Delayed decay heat inside fuel matrix |
| Fission Product Delayed Gamma Rays ($\gamma_{\text{delayed}}$) | $7 \pm 1$ | $3.5\%$ | Delayed decay heat in core structure |
| Antineutrinos ($\bar{\nu}_e$) | $12 \pm 2$ | $6.0\%$ | Lost entirely (escape reactor vessel) |
| Radiative Capture Gamma Rays ($(n, \gamma)$ in non-fission) | $3\text{ to }10$ | $\sim 2.5\text{ to }5\%$ | Exothermic capture in structural cladding/water |
2. Recoverable Energy per Fission ($Q_{\text{rec}}$)
The antineutrinos possess a negligible interaction cross section ($\sigma_\nu \sim 10^{-44}\text{ cm}^2$) and escape into outer space without depositing heat. Conversely, excess neutrons produced by fission are absorbed via radiative capture $(n, \gamma)$ in moderator, coolant, and structural cladding, releasing additional binding gamma energy ($\sim 3\text{ to }8\text{ MeV}$). Hence, the net recoverable thermal energy per fission event is: $$Q_{\text{rec}} = Q_{\text{total}} - E_{\bar{\nu}_e} + E_{(n,\gamma)} \approx 207\text{ MeV} - 12\text{ MeV} + 5\text{ MeV} \approx \mathbf{200 \pm 2\text{ MeV}}$$ In engineering calculations: $$1\text{ fission} \approx 200\text{ MeV} = 3.20435 \times 10^{-11}\text{ Joules} = 3.20435 \times 10^{-17}\text{ MW}\cdot\text{s}$$ $$3.12 \times 10^{10}\text{ fissions/second} \longleftrightarrow \mathbf{1\text{ Watt of thermal power}}$$
§3.5 Fission Neutron Energy Spectrum: Watt Distribution & Energetics
1. The Watt Fission Spectrum Formula
Neutrons liberated at the moment of scission (prompt fission neutrons) are emitted isotropically from rapidly moving, highly excited fission fragments. Transforming from the center-of-mass frame of the fragment to the laboratory frame results in the classical Watt distribution $\chi(E)$: $$\chi(E) = c \, e^{-E/a} \sinh\left(\sqrt{b E}\right)$$ For thermal neutron fission of Uranium-235 (${}^{235}\text{U}$), empirical parameters fitted to nuclear data (ENDF/B-VIII) are: $$a = 0.988\text{ MeV}, \qquad b = 2.249\text{ MeV}^{-1}$$ The normalization constant $c$ enforces total probability conservation: $$\int_{0}^{\infty} \chi(E) \, dE = 1 \implies c = \sqrt{\frac{4}{\pi a^3 b}} \, e^{-a b / 4}$$ An alternate, widely used analytical approximation developed by Cranberg is: $$\chi(E) = 0.453 \, e^{-1.036 E} \sinh\left(\sqrt{2.29 E}\right) \quad (E\text{ in MeV})$$ or the Maxwellian fission spectrum approximation: $$\chi_M(E) = \frac{2}{\sqrt{\pi} T^{3/2}} E^{1/2} e^{-E/T} \quad (T \approx 1.29\text{ MeV})$$
2. Mean and Most Probable Prompt Neutron Energy
The energy distribution spans eight orders of magnitude, with:
- Most Probable Energy ($E_p$): Found by solving $\frac{d\chi(E)}{dE} = 0$: $$E_p \approx \mathbf{0.73\text{ MeV}}$$
- Average (Mean) Kinetic Energy ($\bar{E}$): $$\bar{E} = \int_{0}^{\infty} E \, \chi(E) \, dE = \frac{3}{2} a + \frac{1}{4} a^2 b \approx \frac{3}{2}(0.988) + \frac{1}{4}(0.988)^2(2.249) \approx \mathbf{1.98\text{ to }2.00\text{ MeV}}$$
§3.6 Prompt vs Delayed Neutrons: Six Precursor Groups & Nuclear Control
1. Prompt Neutrons and Delayed Precursors
Over $99\%$ of fission neutrons are emitted within $\tau_{\text{prompt}} \sim 10^{-14}\text{ to }10^{-13}\text{ seconds}$ of scission—these are prompt neutrons. However, a tiny but vital fraction ($\beta \approx 0.65\%$ in ${}^{235}\text{U}$) are emitted with delays ranging from milliseconds to minutes: $$\text{Fission} \longrightarrow \text{Precursor Nuclide } ({}^{87}\text{Br}) \xrightarrow[\beta^-]{T_{1/2} = 55.6\text{ s}} \text{Emitter } ({}^{87}\text{Kr}^*) \xrightarrow[\text{prompt } n]{< 10^{-15}\text{ s}} {}^{86}\text{Kr} + n$$ The emission of the neutron itself is prompt from an excited daughter nucleus whose excitation energy exceeds the neutron separation energy ($E^* > S_n$), but the emission rate is governed strictly by the preceding beta decay half-life of the parent precursor nuclide.
2. The Six Delayed Neutron Precursor Groups
In reactor physics and point kinetics, the hundreds of distinct delayed neutron emitting fission products are grouped into six standard precursor groups according to decay constant $\lambda_i = \ln 2 / T_{1/2, i}$:
| Group $i$ | Representative Precursor | Half-Life $T_{1/2}$ (s) | Decay Const $\lambda_i\ (\text{s}^{-1})$ | Rel. Abundance $\beta_i / \beta$ | Average Energy (keV) |
|---|---|---|---|---|---|
| 1 | ${}^{87}\text{Br}$ | $55.72$ | $0.0124$ | $0.033$ | $250$ |
| 2 | ${}^{137}\text{I}$ | $22.72$ | $0.0305$ | $0.219$ | $560$ |
| 3 | ${}^{138}\text{I}, {}^{89}\text{Br}$ | $6.22$ | $0.111$ | $0.196$ | $430$ |
| 4 | ${}^{93}\text{Rb}, {}^{139}\text{I}$ | $2.30$ | $0.301$ | $0.395$ | $620$ |
| 5 | ${}^{94}\text{Rb}, {}^{140}\text{I}$ | $0.61$ | $1.14$ | $0.115$ | $420$ |
| 6 | ${}^{95}\text{Rb}$ | $0.23$ | $3.01$ | $0.042$ | $510$ |
3. Physical Role in Reactor Control
Without delayed neutrons, the average generation time between fission generations would be dictated entirely by the prompt neutron lifetime $l \sim 10^{-4}\text{ s}$ in thermal reactors ($l \sim 10^{-7}\text{ s}$ in fast reactors). For a tiny reactivity insertion $\Delta k = 0.001$, reactor power would escalate as $e^{t / (l/\Delta k)} = e^{10 t}$, multiplying by $22{,}000$ every second—rendering mechanical control rods completely ineffective! Delayed neutrons stretch the effective generation time to: $$\bar{l}_{\text{eff}} = (1 - \beta) l + \sum_{i=1}^6 \beta_i \tau_i = (1 - \beta) l + \sum_{i=1}^6 \frac{\beta_i}{\lambda_i} \approx 0.1\text{ seconds}$$ This slows reactor power transients by three orders of magnitude, allowing mechanical control rods and electronic safety circuits ample time to maintain safe steady-state operation.
§3.7 Thermal Power, Fission Rates, Fuel Consumption & Core Burnup Systematics
1. Relation Between Thermal Power and Fission Rate
If a reactor operates at steady thermal power $P$ (in Watts), the core-wide total fission rate $\dot{F}$ (fissions per second) is: $$\dot{F} = \frac{P}{Q_{\text{rec}}} = \frac{P\ [\text{W}]}{3.20435 \times 10^{-11}\ [\text{J/fission}]} \approx 3.1208 \times 10^{10} \times P\ [\text{W}]$$ For a typical $3000\text{ MW}_{\text{th}}$ commercial power plant: $$\dot{F} = 3.1208 \times 10^{10} \times (3.0 \times 10^9\text{ W}) \approx \mathbf{9.36 \times 10^{19}\text{ fissions/second}}$$
2. Fissile Fuel Consumption Rate
Each fission consumes one fissile nucleus. In addition, radiative capture without fission $(n, \gamma)$ consumes additional nuclei in ratio $\alpha \equiv \sigma_c / \sigma_f$: $$\dot{N}_{\text{consumed}} = \dot{F} (1 + \alpha) = \dot{F} \frac{\sigma_a}{\sigma_f}$$ For Uranium-235 at thermal energies, $\sigma_f \approx 585\text{ b}$, $\sigma_c \approx 99\text{ b}$, giving capture-to-fission ratio: $$\alpha \approx \frac{99}{585} \approx 0.169 \implies 1 + \alpha \approx 1.169$$ The mass consumption rate of ${}^{235}\text{U}$ per Megawatt-day ($\text{MWd}$) of thermal energy is: $$\Delta m_{\text{fission}} = \frac{1\text{ MWd} \times 86400\text{ s/d} \times 235.044\text{ g/mol}}{(3.20435 \times 10^{-11}\text{ J}) \times (6.02214 \times 10^{23}\text{ atoms/mol})} \approx \mathbf{1.05\text{ g } {}^{235}\text{U} / \text{MWd}}$$ Including radiative capture losses ($1 + \alpha$): $$\Delta m_{\text{total}} = 1.05 \times 1.169 \approx \mathbf{1.23\text{ g } {}^{235}\text{U} / \text{MWd}}$$ A $3000\text{ MW}_{\text{th}}$ plant consumes: $$\Delta m = 3000\text{ MW} \times 1.23\text{ g/MWd} \approx \mathbf{3.69\text{ kg of } {}^{235}\text{U} \text{ per day}}$$
3. Fuel Burnup Formalism
Core Burnup measures the total thermal energy extracted per unit initial mass of heavy metal fuel loaded into the reactor, conventionally expressed in Megawatt-days per Metric Ton of Heavy Metal ($\text{MWd/MTU}$ or $\text{GWd/MTU}$): $$B = \frac{\int_0^T P(t) \, dt}{M_{\text{HM}, 0}} = \frac{E_{\text{th}}}{M_{\text{HM}, 0}}$$ where $M_{\text{HM}, 0}$ is the initial mass of uranium (or uranium + plutonium) metal in metric tons ($1\text{ MT} = 1000\text{ kg}$). Commercial LWRs routinely achieve burnups of $45\text{ to }55\text{ GWd/MTU}$ ($45{,}000\text{ to }55{,}000\text{ MWd/MTU}$), corresponding to the fission of approximately $5\%$ of all initial heavy metal atoms.
Step-by-Step Solved Examination Problems
Comprehensive analytical derivations, quantitative calculations, and step-by-step examination solutions for Unit 1.
A thermal neutron strikes a Uranium-235 nucleus causing binary fission into Barium-141 and Krypton-92 with the emission of three prompt neutrons:
The precise atomic masses are:
- $m({}^1_0 n) = 1.008665\text{ u}$
- $m({}^{235}_{92}\text{U}) = 235.043930\text{ u}$
- $m({}^{141}_{56}\text{Ba}) = 140.914411\text{ u}$
- $m({}^{92}_{36}\text{Kr}) = 91.926156\text{ u}$
where $1\text{ u} = 931.494\text{ MeV}/c^2 = 1.66054 \times 10^{-27}\text{ kg}$. (a) Calculate the mass defect $\Delta m$ in atomic mass units ($\text{u}$) and kilograms ($\text{kg}$). (b) Calculate the prompt energy released $Q_{\text{prompt}}$ in $\text{MeV}$ and in Joules ($\text{J}$). (c) Assuming the two fragments are emitted back-to-back in the center-of-mass frame and conserve linear momentum, calculate the kinetic energy of the light fragment (${}^{92}\text{Kr}$) and heavy fragment (${}^{141}\text{Ba}$) if $168\text{ MeV}$ is partitioned into fragment kinetic energy.
(a) Mass Defect $\Delta m$: Initial mass of reactants:
Final mass of products:
Mass defect:
Converting to kilograms:
(b) Energy Released $Q_{\text{prompt}}$: Using Einstein's mass-energy equivalence $Q = \Delta m \cdot c^2$:
In Joules:
(c) Fragment Kinetic Energy Partition via Momentum Conservation: In the center-of-mass frame with initial momentum zero:
The ratio of kinetic energies is inversely proportional to their mass ratio:
Since $E_L + E_H = 168\text{ MeV}$:
The lighter Krypton-92 fragment receives $101.7\text{ MeV}$ ($60.5\%$ of the kinetic energy), while the heavier Barium-141 fragment receives $66.3\text{ MeV}$ ($39.5\%$).
The prompt fission neutron energy spectrum for Uranium-235 is given by the Cranberg form:
(a) Calculate the value of $\chi(E)$ at $E = 0.5\text{ MeV}$, $E = 1.0\text{ MeV}$, $E = 2.0\text{ MeV}$, and $E = 5.0\text{ MeV}$. (b) Evaluate the most probable energy $E_{\text{mp}}$ by setting $\frac{d}{dE} \ln \chi(E) = 0$. (c) What percentage of prompt fission neutrons are born with energy exceeding $E = 1.0\text{ MeV}$ (the fast fission threshold of $^{238}\text{U}$)? (Given: $\int_1^\infty \chi(E) dE \approx 0.692$).
(a) Spectrum Values at Selected Energies: Recall $\sinh(x) = \frac{e^x - e^{-x}}{2}$:
- At $E = 0.5\text{ MeV}$:
- At $E = 1.0\text{ MeV}$:
- At $E = 2.0\text{ MeV}$:
- At $E = 5.0\text{ MeV}$:
(b) Most Probable Energy $E_{\text{mp}}$: Taking the natural logarithm:
Differentiating with respect to $E$:
Testing $E = 0.72\text{ MeV}$:
Thus, the most probable neutron energy is:
(c) Fast Fission Fraction: Evaluating the integral above the fast threshold $E_{\text{th}} = 1.0\text{ MeV}$:
Approximately $69.2\%$ of all prompt fission neutrons possess sufficient kinetic energy ($> 1.0\text{ MeV}$) to induce fast fission in $^{238}\text{U}$.
A nuclear power station operates at a constant thermal power of $P_{\text{th}} = 3400\text{ MW}_{\text{th}}$ with net thermodynamic plant efficiency $\eta_{\text{th}} = 34\%$. The reactor core is initially loaded with $M_0 = 85.0\text{ metric tons}$ of heavy metal fuel in the form of low-enriched uranium dioxide ($\text{UO}_2$) with an average enrichment of $4.2\%\ {}^{235}\text{U}$ by mass. The recoverable energy per fission is $Q_{\text{rec}} = 200\text{ MeV}$. The capture-to-fission ratio for $^{235}\text{U}$ is $\alpha = 0.170$. (a) Determine the net electrical output power $P_e$ of the station in $\text{MW}_e$. (b) Calculate the daily rate of ${}^{235}\text{U}$ destroyed (by fission plus capture) in $\text{kg/day}$. (c) After an 18-month (548-day) continuous baseload operating cycle at full power, calculate the total cumulative core burnup in $\text{MWd/MTU}$ and the fraction of initial ${}^{235}\text{U}$ remaining.
(a) Net Electrical Power Output $P_e$:
(b) Daily Consumption Rate of $^{235}\text{U}$: Daily thermal energy produced:
Fission rate per second:
Number of fissions per day:
Total atoms of $^{235}\text{U}$ consumed (fission + capture):
Mass consumed per day:
(c) Cumulative Core Burnup and Fuel Inventory: Total thermal energy produced over 548 days:
Cumulative fuel burnup:
Initial mass of $^{235}\text{U}$ loaded:
Total mass of $^{235}\text{U}$ consumed over 548 days:
Remaining mass of $^{235}\text{U}$:
Fraction of initial $^{235}\text{U}$ remaining:
After 18 months, $64.3\%$ of the original Uranium-235 has been burned, with the core operating partly on bred Plutonium-239.