§5.1 Sodium Chloride (NaCl, Rock Salt) Structure: Geometry, Coordination & Polyhedra
The sodium chloride (rock salt, halite) prototype represents the preeminent $1:1$ stoichiometric ionic crystal structure. It is adopted by hundreds of ionic compounds, including all alkali halides (except $\text{CsCl}, \text{CsBr}, \text{CsI}$), alkaline earth monoxides ($\text{MgO}, \text{CaO}, \text{SrO}, \text{BaO}$), transition metal monoxides ($\text{FeO}, \text{CoO}, \text{NiO}$), and transition metal nitrides/carbides ($\text{TiN}, \text{TiC}$).
Crystallographic Lattice & Atomic Coordinates
- Space Group: $Fm\bar{3}m$ (No. 225), Hermann-Mauguin full symbol $F 4/m \bar{3} 2/m$, Pearson symbol $cF8$.
- Lattice Type: Face-Centered Cubic (FCC Bravais lattice).
- Formula Units per Unit Cell: $Z = 4$ $\text{NaCl}$ units ($4\text{ Na}^+$ and $4\text{ Cl}^-$ ions).
- Wyckoff Positions:
- $\text{Na}^+$ at Wyckoff site $4a$: $(0, 0, 0)$, $\left(\frac{1}{2}, \frac{1}{2}, 0\right)$, $\left(\frac{1}{2}, 0, \frac{1}{2}\right)$, $\left(0, \frac{1}{2}, \frac{1}{2}\right)$.
- $\text{Cl}^-$ at Wyckoff site $4b$: $\left(\frac{1}{2}, \frac{1}{2}, \frac{1}{2}\right)$, $\left(0, 0, \frac{1}{2}\right)$, $\left(0, \frac{1}{2}, 0\right)$, $\left(\frac{1}{2}, 0, 0\right)$.
This spatial arrangement is mathematically equivalent to two interpenetrating FCC sublattices displaced relative to one another along the cubic body diagonal by $\boldsymbol{\tau} = \frac{1}{2}[100]$ (or $\frac{1}{2}[111]$).
Coordination Geometry & Polyhedral Topology
- Coordination Number (CN): Both cations and anions exhibit rigorous $6:6$ octahedral coordination ($O_h$ point symmetry).
- Cation Environment: Each $\text{Na}^+$ ion is coordinated by $6$ equidistant $\text{Cl}^-$ anions forming a regular octahedron with bond length:
- Anion Environment: Each $\text{Cl}^-$ ion is symmetrically coordinated by $6$ equidistant $\text{Na}^+$ cations.
- Polyhedral Network: The crystal structure can be described as a 3D network of edge-sharing $[\text{NaCl}_6]$ octahedra. Each octahedron shares all $12$ of its edges with adjacent octahedra in three dimensions, maximizing packing density while satisfying Pauling's electrostatic valence sum rules.
§5.2 Cesium Chloride (CsCl) Structure: 8:8 Coordination & Transition Pressures
When the radius of the cation approaches that of the anion ($r^+/r^- > 0.732$), the $6:6$ coordination of the rock salt lattice becomes sterically unfavorable. The crystal stabilizes into the denser cesium chloride ($\text{CsCl}$) structural archetype.
Crystallographic Lattice & Basis
- Space Group: $Pm\bar{3}m$ (No. 221), Pearson symbol $cP2$.
- Lattice Type: Primitive Cubic (Primitive Bravais lattice, NOT BCC!).
- Formula Units per Unit Cell: $Z = 1$ $\text{CsCl}$ pair.
- Wyckoff Coordinates:
- $\text{Cs}^+$ at Wyckoff site $1a$: $(0, 0, 0)$.
- $\text{Cl}^-$ at Wyckoff site $1b$: $\left(\frac{1}{2}, \frac{1}{2}, \frac{1}{2}\right)$.
[!NOTE] Although $\text{CsCl}$ visually resembles a body-centered cubic cell, it is crystallographically primitive cubic because the atom at the corner ($\text{Cs}^+$) is chemically distinct from the atom at the center ($\text{Cl}^-$). True BCC symmetry requires identical atoms at $(0,0,0)$ and $(1/2, 1/2, 1/2)$.
Coordination & Geometric Relations
- Coordination Number (CN): $8:8$ cubic coordination.
- Each $\text{Cs}^+$ ion sits at the center of a cube formed by $8$ surrounding $\text{Cl}^-$ anions, and vice versa.
- Contact along the body diagonal of the cubic unit cell gives:
- Compounds Adopting CsCl: $\text{CsCl}, \text{CsBr}, \text{CsI}, \text{TlCl}, \text{TlBr}, \text{NH}_4\text{Cl}$ (low temperature), and intermetallic equiatomic alloys such as $\beta'\text{-CuZn}$ (brass), $\text{NiAl}$, and $\text{FeAl}$ (B2 Hume-Rothery phases).
- Pressure-Induced Phase Transitions: Under high hydrostatic pressure ($P \approx 30\text{ GPa}$ for $\text{NaCl}$), rock salt structures transition to $\text{CsCl}$ structures because 8-fold coordination yields a smaller molar volume ($\sim 5-10\%$ volume reduction), decreasing the enthalpy $H = U + PV$.
§5.3 Zinc Blende (beta-ZnS, Sphalerite) Structure: Tetrahedral Coordination & FCC Sublattice
When the radius ratio is small ($r^+/r^- < 0.414$) or when covalent directional $sp^3$ hybrid bonding dominates over pure electrostatics, binary solids crystallize in tetrahedral topologies. The two archetypes are zinc blende (cubic) and wurtzite (hexagonal).
Crystallographic Lattice of Zinc Blende (Sphalerite)
- Space Group: $F\bar{4}3m$ (No. 216), non-centrosymmetric, Pearson symbol $cF8$.
- Lattice Type: Face-Centered Cubic (FCC).
- Formula Units per Unit Cell: $Z = 4$ $\text{ZnS}$ units.
- Wyckoff Coordinates:
- $\text{S}^{2-}$ anions on FCC lattice sites $4a$: $(0,0,0), \left(\frac{1}{2},\frac{1}{2},0\right), \left(\frac{1}{2},0,\frac{1}{2}\right), \left(0,\frac{1}{2},\frac{1}{2}\right)$.
- $\text{Zn}^{2+}$ cations in half of the tetrahedral interstitials $4c$: $\left(\frac{1}{4},\frac{1}{4},\frac{1}{4}\right), \left(\frac{3}{4},\frac{3}{4},\frac{1}{4}\right), \left(\frac{3}{4},\frac{1}{4},\frac{3}{4}\right), \left(\frac{1}{4},\frac{3}{4},\frac{3}{4}\right)$.
Structural Topology & Polyhedral Condensation
- Coordination Number (CN): $4:4$ tetrahedral coordination ($T_d$ point symmetry).
- An FCC anion lattice contains $8$ tetrahedral interstitial sites per unit cell. In zinc blende, exactly $50\%$ of tetrahedral sites are occupied in an alternating ordered manner, such that all occupied tetrahedra point in the identical spatial orientation.
- The bond length along the $[111]$ body diagonal is:
- Each $[\text{ZnS}_4]$ tetrahedron shares all four of its corners with neighboring tetrahedra. No edges or faces are shared.
- Isostructural Materials: Crucial semiconductors: $\text{GaAs}, \text{InP}, \text{InAs}, \text{CdTe}, \text{ZnSe}, \beta\text{-SiC}$, and diamond/silicon/germanium (which are the homoatomic equivalents with $Fd\bar{3}m$ symmetry).
§5.4 Wurtzite (alpha-ZnS) Structure: Hexagonal Symmetry, Non-Centrosymmetric Properties & Polarity
The wurtzite archetype is the hexagonal polymorph of zinc sulfide, representing tetrahedral coordination in an HCP anion framework rather than FCC.
Crystallographic Parameters
- Space Group: $P6_3mc$ (No. 186), polar, non-centrosymmetric, Pearson symbol $hP4$.
- Lattice Type: Hexagonal.
- Formula Units per Cell: $Z = 2$ formula units.
- Wyckoff Sites:
- $\text{S}^{2-}$ at $2b$: $\left(\frac{1}{3}, \frac{2}{3}, 0\right), \left(\frac{2}{3}, \frac{1}{3}, \frac{1}{2}\right)$.
- $\text{Zn}^{2+}$ at $2b$: $\left(\frac{1}{3}, \frac{2}{3}, u\right), \left(\frac{2}{3}, \frac{1}{3}, \frac{1}{2} + u\right)$ where $u \approx 3/8 = 0.375$.
Zinc Blende vs Wurtzite: Stacking Sequence & Bond Conformation
- Stacking Sequence:
- Zinc Blende: Cubic close-packed anion layers $\dots ABCABC \dots$ along $[111]$. Tetrahedra are connected in a staggered (chair-like) trans-conformation.
- Wurtzite: Hexagonal close-packed anion layers $\dots ABABAB \dots$ along $[0001]$. Tetrahedra are connected in an eclipsed (boat-like) cis-conformation.
- Ideal Axial Ratio: For ideal close packing of hard spheres:
In real crystals (e.g., $\text{ZnO}, \text{GaN}, \text{AlN}$), electrostatic dipole interactions cause deviations: $c/a < 1.633$ and $u > 0.375$.
Spontaneous Polarization & Piezoelectricity
Because space group $P6_3mc$ lacks an inversion center and possesses a unique polar axis along the $\mathbf{c}$-axis $[0001]$, wurtzite crystals exhibit:
1. Spontaneous Electric Polarization ($P_{\text{sp}}$ along $[0001]$).
2. Piezoelectricity: Application of uniaxial mechanical stress along $\mathbf{c}$ induces an macroscopic electrostatic potential difference.
3. Piezoelectric and Optoelectronic Applications: Wide bandgap semiconductors $\text{GaN}, \text{InN}, \text{AlN}$ form the basis of blue/UV LEDs, laser diodes, and high-electron-mobility transistors (HEMTs).
§5.5 Fluorite (CaF2) Structure: 8:4 Coordination, Interstitial Voids & Fast Anion Transport
The fluorite ($\text{CaF}_2$) prototype is the archetypal structure for $1:2$ stoichiometric binary compounds where the cation is significantly larger than the anion ($r_{\text{cation}} > r_{\text{anion}}$).
Crystallographic Lattice & Atomic Coordinates
- Space Group: $Fm\bar{3}m$ (No. 225), Pearson symbol $cF12$.
- Formula Units per Cell: $Z = 4$ $\text{CaF}_2$ units ($4\text{ Ca}^{2+}$ and $8\text{ F}^-$ ions).
- Wyckoff Coordinates:
- $\text{Ca}^{2+}$ cations form an FCC lattice at site $4a$: $(0,0,0) + \text{FCC translations}$.
- $\text{F}^-$ anions occupy all eight tetrahedral interstitial sites at site $8c$:
Coordination Numbers & Interstitial Chemistry
- Coordination Ratio: $8:4$ coordination.
- Each $\text{Ca}^{2+}$ cation is coordinated by $8\text{ F}^-$ anions at the corners of a cube ($CN = 8$).
- Each $\text{F}^-$ anion is coordinated by $4\text{ Ca}^{2+}$ cations at the vertices of a regular tetrahedron ($CN = 4$).
- Interstitial Octahedral Voids:
In the fluorite lattice, all tetrahedral sites are filled by fluoride ions, but all octahedral interstitial sites at $(1/2, 1/2, 1/2)$ and $(1/2, 0, 0)$ remain completely empty.
- Fast-Ion (Superionic) Conduction:
Because $50\%$ of the cubic interstitial cages are vacant, fluorite-structured oxides (e.g., yttria-stabilized zirconia $\text{YSZ}$, ceria $\text{CeO}_2$, urania $\text{UO}_2$) exhibit exceptional oxygen vacancy mobility at elevated temperatures ($T > 600^\circ\text{C}$), functioning as the standard solid electrolytes in Solid Oxide Fuel Cells (SOFCs).
§5.6 Antifluorite (Li2O) Structure: Inversion of Cation-Anion Sublattices & Energetics
The antifluorite prototype is the direct crystallographic inverse of the fluorite lattice, adopted by $2:1$ stoichiometric compounds where small cations combine with large anions.
Crystallographic Architecture
- Space Group: $Fm\bar{3}m$ (No. 225), Pearson symbol $cF12$.
- Formula Units: $Z = 4$ units of $\text{M}_2\text{X}$ (e.g., $\text{Li}_2\text{O}, \text{Na}_2\text{O}, \text{K}_2\text{O}, \text{Li}_2\text{S}$).
- Wyckoff Positions:
- Anions ($\text{O}^{2-}$): Occupy the FCC lattice points $4a$ at $(0,0,0)$.
- Cations ($\text{Li}^+$): Occupy all eight tetrahedral interstitial sites $8c$ at $\left(\pm \frac{1}{4}, \pm \frac{1}{4}, \pm \frac{1}{4}\right)$.
Coordination & Solid-State Electrochemical Significance
- Coordination Ratio: $4:8$ coordination.
- Small cations ($\text{Li}^+$) have tetrahedral coordination ($CN = 4$).
- Large anions ($\text{O}^{2-}$) have 8-fold cubic coordination ($CN = 8$).
- Madelung Constant: Because Coulomb energy is quadratic in charge, reversing the charges changes the individual site potentials but maintains the overall electrostatic sum:
- Lithium Battery Solid Electrolytes: Antifluorite derivatives (e.g., $\text{Li}_3\text{OCl}$, $\text{Li}_2\text{S}$-based superionic conductors) exhibit high $\text{Li}^+$ mobilities through interstitial hopping pathways facilitated by vacant octahedral sites.
§5.7 Comparative Polyhedral Architectures: Corner-Sharing, Edge-Sharing & Face-Sharing Stability (Paulings Rules)
Linus Pauling (1929) formulated five empirical principles governing the stability, coordination, and polyhedral connectivity of complex ionic crystals.
Pauling's Five Rules
1. Rule 1: Coordination Polyhedron & Radius Ratio:
A coordinated polyhedron of anions is formed about each cation, the cation-anion distance being determined by the sum of crystal radii, and the coordination number by the radius ratio $r^+/r^-$.
- $r^+/r^- < 0.155$: 2-fold linear
- $0.155 - 0.225$: 3-fold trigonal planar
- $0.225 - 0.414$: 4-fold tetrahedral
- $0.414 - 0.732$: 6-fold octahedral
- $0.732 - 1.000$: 8-fold cubic
- $1.000$: 12-fold cuboctahedral (close-packed)
2. Rule 2: Electrostatic Valence Rule:
In a stable crystal structure, the electrostatic valence strength $s_i$ of each bond reaching an anion from its nearest-neighbor cations equals:
where $z_i$ is the cation charge and $\nu_i$ is its coordination number. The sum of bond valences to each anion must equal the anion charge $z_X$:
3. Rule 3: Polyhedral Connectivity (Sharing of Edges and Faces):
The presence of shared edges and especially shared faces in a coordinated structure decreases its stability. Sharing edges places highly charged cations closer together, increasing cation-cation electrostatic repulsion:
4. Rule 4: Cation Charge and Coordination Effect on Sharing:
In a crystal containing different cations, those with high valency and small coordination number tend not to share polyhedron elements with one another.
5. Rule 5: Principle of Parsimony:
The number of essentially different kinds of constituents in a crystal tends to be small.
§5.8 Structural Polymorphism, Temperature-Induced Phase Transformations & High-Pressure Transitions
Polymorphism is the capacity of a substance with a fixed chemical composition to crystallize in more than one distinct structural arrangement.
Classification of Phase Transitions
According to Ehrenfest thermodynamic criteria:
- First-Order Transitions: Discontinuous first derivative of Gibbs free energy ($\Delta V \ne 0$, $\Delta S = \Delta H_{\text{tr}}/T_{\text{tr}} \ne 0$). Associated with major structural rearrangements, bond breaking, latent heat, and hysteresis (e.g., graphite $\to$ diamond, $\text{NaCl} \to \text{CsCl}$ under pressure).
- Second-Order Transitions: Continuous $V$ and $S$, but discontinuous second derivatives (heat capacity $\Delta C_p$, thermal expansion $\Delta \alpha$, compressibility $\Delta \kappa$). Associated with order-disorder phenomena and subtle symmetry-breaking displacements without latent heat (e.g., ferroelectric Curie transition in $\text{BaTiO}_3$).
Reconstructive vs Displacive Transitions (Buerger Classification)
1. Reconstructive Transformations:
Require breaking primary chemical bonds and re-forming new coordination polyhedra. High activation energy barrier ($E_a > 100\text{ kJ/mol}$), slow kinetics, significant hysteresis, often kinetically trapped at room temperature (e.g., quartz $\to$ tridymite $\to$ cristobalite).
2. Displacive (Martensitic / Soft-Mode) Transformations:
Involve minor collective tilts or bond angle distortions of polyhedra without breaking bonds or altering nearest-neighbor topology. Zero or low activation barrier, ultrafast diffusionless kinetics (speed of sound), perfectly reversible (e.g., $\alpha$-quartz $\leftrightarrow$ $\beta$-quartz at $573^\circ\text{C}$).
Derive from first principles the critical limiting radius ratio $r^+/r^- = \sqrt{2} - 1 \approx 0.4142$ below which a 6-fold regular octahedral coordination environment becomes geometrically unstable due to anion-anion contact.
Step 1: Geometric Configuration of a Regular Octahedron
Consider a central cation of radius $r^+$ surrounded by six identical spherical anions of radius $r^-$ in an ideal octahedral geometry. Four of the anions lie in the equatorial horizontal plane $xy$, forming a square, while the remaining two anions occupy the apex positions along the $\pm z$ axes. For maximum stability:
- The central cation must touch all six anions: distance from origin to center of any anion is $d = r^+ + r^-$.
- The anions must not interpenetrate: distance between adjacent anion centers $d_{\text{anion-anion}} \ge 2r^-$.
Step 2: Critical Contact Condition in the Equatorial Plane
At the limiting radius ratio, the central cation touches the four equatorial anions simultaneously while the anions just touch one another along the perimeter of the square:
- Side of square formed by four anion centers: $s = 2r^-$.
- Diagonal of square: $D = \sqrt{s^2 + s^2} = \sqrt{(2r^-)^2 + (2r^-)^2} = \sqrt{8(r^-)^2} = 2\sqrt{2}r^-$.
The diagonal passes through the center of two opposing anions and through the central cation:
Step 3: Radius Ratio Derivation
Equating the two expressions for the diagonal:
Dividing both sides by 2:
Subtracting $r^-$ from both sides:
Dividing by $r^-$:
If $r^+/r^- < 0.414$, the cation is too small to keep the anions apart, leading to anion-anion electrostatic repulsion and driving a transition to 4-fold tetrahedral coordination.
Derive the minimum limiting radius ratio $r^+/r^- = \sqrt{3} - 1 \approx 0.7321$ required for stable 8-fold cubic coordination (as seen in the CsCl archetype).
Step 1: Geometric Model of Cubic Coordination
In 8-fold cubic coordination, a central cation of radius $r^+$ sits at the center of a cube formed by eight anions of radius $r^-$ located at the eight cube vertices. Let the edge length of the cube be $a$.
Step 2: Contact Relations
At the limiting boundary:
- Anions touch each other along the cube edges:
- The central cation touches all eight corner anions along the four body diagonals:
Since the body diagonal spans two anion radii and twice the cation radius:
Step 3: Derivation of the Limiting Ratio
Substitute $a = 2r^-$ into the body diagonal expression:
Divide by 2:
Rearrange:
For $r^+/r^- \ge 0.732$, 8-fold cubic coordination is stable. For $0.414 \le r^+/r^- < 0.732$, 6-fold octahedral coordination is favored.
Crystalline $\text{NaCl}$ has a cubic unit cell with parameter $a = 5.640\text{ Å}$. The ionic radii are $r_{\text{Na}^+} = 1.02\text{ Å}$ and $r_{\text{Cl}^-} = 1.81\text{ Å}$, with molar masses $M_{\text{Na}} = 22.99\text{ g/mol}$ and $M_{\text{Cl}} = 35.45\text{ g/mol}$.\n(a) Compute the theoretical X-ray crystal density $\rho_{\text{calc}}$.\n(b) Formulate and evaluate the Atomic Packing Fraction (APF) of the rock salt lattice.\n(c) Compare the bond length $a/2$ with the sum of ionic radii and explain the degree of contact.
Step 1: Theoretical Density Calculation
For $\text{NaCl}$, the unit cell contains $Z = 4$ formula units ($4\text{ Na}^+$ and $4\text{ Cl}^-$). Molar mass of $\text{NaCl}$:
Unit cell volume:
Mass of unit cell:
Density:
(Matches experimental density $2.165\text{ g/cm}^3$ to within $0.05\%$).
Step 2: Atomic Packing Fraction (APF)
The volume occupied by the ions (treating them as hard spheres) in one unit cell is:
Given $r_{\text{Na}^+} = 1.02\text{ Å}$ and $r_{\text{Cl}^-} = 1.81\text{ Å}$:
Unit cell volume in $\text{Å}^3$:
Packing fraction:
Step 3: Bond Length vs Radii Sum
The observed bond distance along the unit cell edge is:
Sum of Shannon ionic radii:
The discrepancy is:
This excellent agreement confirms direct cation-anion contact with negligible overlap repulsion.
Cesium chloride crystallizes in a primitive cubic lattice with $a = 4.123\text{ Å}$. Ionic radii are $r_{\text{Cs}^+} = 1.74\text{ Å}$ and $r_{\text{Cl}^-} = 1.81\text{ Å}$. Molar masses: $M_{\text{Cs}} = 132.91\text{ g/mol}$, $M_{\text{Cl}} = 35.45\text{ g/mol}$.\n(a) Compute the unit cell volume and theoretical density.\n(b) Calculate the radius ratio and verify the coordination stability.\n(c) Evaluate the atomic packing fraction and calculate the percentage volume change if $\text{NaCl}$ were to hypothetically adopt the $\text{CsCl}$ structure with identical bond lengths.
Step 1: Unit Cell Volume and Density
For $\text{CsCl}$, $Z = 1$ formula unit per primitive cell:
Unit cell volume:
Density:
(Matches experimental density $3.99\text{ g/cm}^3$).
Step 2: Radius Ratio Analysis
Since $0.9613 > 0.732$, 8-fold cubic coordination is strongly favored over 6-fold rock salt coordination, perfectly adhering to Pauling's Rule 1. Contact along the body diagonal gives theoretical lattice parameter:
Observed $a = 4.123\text{ Å}$ matches within $0.58\%$.
Step 3: Packing Fraction
Volume of ions in primitive cell:
Packing fraction:
For identical nearest-neighbor distance $d$, the volume per formula unit is:
- Rock Salt: $V_{\text{formula}}(\text{NaCl}) = 2 d^3$.
- Cesium Chloride: $V_{\text{formula}}(\text{CsCl}) = \left(\frac{2d}{\sqrt{3}}\right)^3 = \frac{8}{3\sqrt{3}} d^3 \approx 1.5396 d^3$.
Volume ratio:
The $\text{CsCl}$ lattice is significantly more compact for equal bond distances.
Gallium arsenide ($\text{GaAs}$) crystallizes in the zinc blende structure with lattice constant $a = 5.653\text{ Å}$.\n(a) Express the tetrahedral bond vectors from the $\text{Ga}$ atom at $(1/4, 1/4, 1/4)$ to its four nearest $\text{As}$ neighbors.\n(b) Prove analytically that the bond angle between any two bonds is $\arccos(-1/3) \approx 109.47^\circ$.\n(c) Calculate the interatomic $\text{Ga-As}$ bond distance and compute the atomic packing fraction given covalent radii $r_{\text{Ga}} = 1.26\text{ Å}$ and $r_{\text{As}} = 1.22\text{ Å}$.
Step 1: Bond Vectors in Zinc Blende
Consider the $\text{Ga}$ atom located at position:
Its four nearest $\text{As}$ neighbors reside on the FCC sublattice at:
The displacement vectors $\mathbf{v}_i = \mathbf{r}_i - \mathbf{r}_0$ from $\text{Ga}$ to the four $\text{As}$ atoms are:
Step 2: Proof of Tetrahedral Bond Angle
Take any pair of bond vectors, for instance $\mathbf{v}_1$ and $\mathbf{v}_2$: The dot product is:
The magnitudes are:
Therefore:
Step 3: Bond Distance and Packing Fraction
Interatomic bond distance:
Sum of covalent radii: $r_{\text{Ga}} + r_{\text{As}} = 1.26 + 1.22 = 2.48\text{ Å}$ (matches within $1.3\%$). Unit cell contains $Z = 4$ Ga and 4 As atoms:
Unit cell volume:
Packing fraction:
The open, low-density tetrahedral network ($\text{APF} \approx 34-35\%$) reflects directional $sp^3$ bonding, far below close-packed systems ($74\%$).
Derive analytically that for an ideal hexagonal close-packed anion sublattice in the wurtzite structure with equidistant nearest neighbors, the axial ratio is $(c/a)_{\text{ideal}} = \sqrt{8/3} \approx 1.63299$ and the internal coordinate parameter is $u = 3/8 = 0.37500$.
Step 1: Geometry of the Hexagonal Unit Cell
In an HCP lattice, atoms in layer A form a 2D triangular network with lattice constant $a$. Layer B rests in the triangular hollows formed by layer A at fractional coordinates $(1/3, 2/3, 1/2)$. Consider three atoms in layer A at $(0,0,0)$, $(a, 0, 0)$, and $(a/2, a\sqrt{3}/2, 0)$. These three atoms form an equilateral triangle of side $a$. The in-plane distance from each vertex to the centroid of the equilateral triangle is:
Step 2: Derivation of $c/a$ Ratio
The atom in layer B rests directly above this centroid at height $z = c/2$. Because the atom in layer B is touching all three atoms in layer A, the distance between the layer B atom and any layer A atom equals $a$:
Substitute $r_{\text{centroid}} = a/\sqrt{3}$:
Multiply by 4:
Step 3: Derivation of Internal Parameter $u$
In the wurtzite unit cell, each cation at $(1/3, 2/3, u)$ is coordinated by four anions:
- One apical anion along the $\mathbf{c}$ axis at $(1/3, 2/3, 0)$ with bond length $d_{\text{apical}} = uc$.
- Three basal anions at $(2/3, 1/3, 1/2)$, $(1/3, -1/3, 1/2)$, $(-2/3, -1/3, 1/2)$.
For a regular tetrahedron, all four bond lengths must be strictly equal:
The basal bond length squared is:
Equating to $d_{\text{apical}}^2 = (uc)^2$:
Subtract $u^2 c^2$ from both sides:
Divide by $c^2$:
Substitute $(a/c)^2 = 3/8$:
Thus, an ideal wurtzite crystal has $c/a = 1.633$ and $u = 0.375$.
Calcium fluoride ($\text{CaF}_2$) crystallizes in the fluorite structure with lattice constant $a = 5.463\text{ Å}$. Molar masses: $M_{\text{Ca}} = 40.078\text{ g/mol}$, $M_{\text{F}} = 18.998\text{ g/mol}$. Shannon radii: $r(\text{Ca}^{2+}, CN=8) = 1.12\text{ Å}$, $r(\text{F}^-, CN=4) = 1.31\text{ Å}$.\n(a) Compute the unit cell volume and theoretical crystal density.\n(b) Calculate the fractional void volume of the unit cell.\n(c) Determine the maximum radius $r_{\text{void}}$ of an interstitial sphere that can be accommodated in the vacant octahedral site $(1/2, 1/2, 1/2)$ without distorting the surrounding fluoride sublattice.
Step 1: Unit Cell Volume and Theoretical Density
The fluorite unit cell contains $Z = 4$ $\text{CaF}_2$ units ($4\text{ Ca}^{2+}$ and $8\text{ F}^-$). Molar mass:
Unit cell volume:
Density:
(Matches experimental density $3.180\text{ g/cm}^3$).
Step 2: Void Volume and Packing Fraction
Total volume occupied by the ions:
Volume of unit cell:
Atomic packing fraction:
Void volume fraction:
Step 3: Radius of the Interstitial Vacant Octahedral Void
In $\text{CaF}_2$, the vacant site at $(1/2, 1/2, 1/2)$ is coordinated by $6\text{ F}^-$ anions at distances: Distance from $(1/2, 1/2, 1/2)$ to an adjacent tetrahedral fluoride at $(1/4, 1/4, 1/4)$ is along the body diagonal of a subcube of size $a/2$:
Since $d_{\text{void-F}} = r_{\text{void}} + r_{\text{F}^-}$:
This large empty interstitial cage ($r_{\text{void}} \approx 1.06\text{ Å}$) allows easy transport of fluoride and oxide interstitials, explaining why fluorite structures act as outstanding fast-ion conductors.
Apply Pauling's second rule (Electrostatic Valence Rule, $\sum s_i = z_{\text{anion}}$) to evaluate the bond valences and structural stability of:\n(a) Rock salt $\text{NaCl}$ ($z_{\text{Na}} = +1, CN = 6$) and $\text{MgO}$ ($z_{\text{Mg}} = +2, CN = 6$).\n(b) Fluorite $\text{CaF}_2$ ($z_{\text{Ca}} = +2, CN = 8$) and Rutile $\text{TiO}_2$ ($z_{\text{Ti}} = +4, CN = 6$).\n(c) Explain why an imaginary structure where $\text{Ti}^{4+}$ has tetrahedral coordination ($CN = 4$) in an oxide with 3-fold coordinated oxygen violates Pauling's Rule 2.
Step 1: Bond Valence Strength Formulation
Pauling's electrostatic bond valence $s$ is:
For a stable crystal, the sum of bond strengths reaching each anion must satisfy:
Step 2: Evaluation of Test Structures
1. Rock Salt $\text{NaCl}$:
- $s = \frac{+1}{6} = \frac{1}{6}$
- Each $\text{Cl}^-$ is coordinated by $6\text{ Na}^+$:
Strictly satisfied.
2. Periclase $\text{MgO}$:
- $s = \frac{+2}{6} = \frac{1}{3}$
- Each $\text{O}^{2-}$ is coordinated by $6\text{ Mg}^{2+}$:
Strictly satisfied.
3. Fluorite $\text{CaF}_2$:
- $s = \frac{+2}{8} = \frac{1}{4}$
- Each $\text{F}^-$ is coordinated by $4\text{ Ca}^{2+}$:
Strictly satisfied.
4. Rutile $\text{TiO}_2$:
- $s = \frac{+4}{6} = \frac{2}{3}$
- Each $\text{O}^{2-}$ is coordinated by $3\text{ Ti}^{4+}$:
Strictly satisfied.
Step 3: Analysis of Hypothetical Case
If $\text{Ti}^{4+}$ had $CN = 4$ in an oxide where oxygen is 3-fold coordinated:
- Bond strength: $s = \frac{+4}{4} = 1.0$.
- Oxygen coordination sum:
This creates a severe overbonding of $+1.0$ valence units on oxygen ($50\%$ excess positive charge), which is electrostatically unviable according to Pauling's second rule.
At room temperature, crystalline $\text{KCl}$ undergoes a first-order polymorphic phase transition from the rock salt structure (B1) to the cesium chloride structure (B2) at hydrostatic pressure $P_{\text{tr}} = 1.95\text{ GPa}$.\n- Molar volume of B1 phase at transition: $V_{\text{B1}} = 37.50\text{ cm}^3/\text{mol}$.\n- Molar volume of B2 phase at transition: $V_{\text{B2}} = 33.38\text{ cm}^3/\text{mol}$.\n(a) Calculate the volume discontinuity $\Delta V_{\text{tr}}$ and volume strain $\Delta V/V_{\text{B1}}$.\n(b) Compute the mechanical transition work $P \Delta V_{\text{tr}}$ in $\text{kJ/mol}$.\n(c) Given that the standard internal lattice energy difference is $\Delta U_{\text{tr}} = U_{\text{B2}} - U_{\text{B1}} = +8.03\text{ kJ/mol}$, calculate the Gibbs free energy change $\Delta G_{\text{tr}}$ at $P = 0$ and at $P = P_{\text{tr}}$ (assuming negligible $T\Delta S$).
Step 1: Volume Discontinuity
Molar volumes:
Volume change:
Relative volume collapse:
Step 2: Mechanical Work Term
The work done by the applied pressure during the collapse is:
Step 3: Gibbs Free Energy Evaluation
The Gibbs free energy is defined as $G = U + PV - TS$. For this solid-state phase transition at constant $T$, $\Delta G = \Delta U + P\Delta V - T\Delta S$. Assuming negligible entropy change ($T\Delta S \approx 0$ for high-pressure reconstructive structural transitions):
1. At Zero Pressure ($P = 0$):
Since $\Delta G > 0$, the B1 (rock salt) phase is thermodynamically stable at ambient pressure.
2. At Transition Pressure ($P = P_{\text{tr}} = 1.95\text{ GPa}$):
The two phases are in exact thermodynamic equilibrium ($G_{\text{B1}} = G_{\text{B2}}$). Above $1.95\text{ GPa}$, $P|\Delta V| > \Delta U$, rendering $\Delta G < 0$, which makes the denser B2 ($\text{CsCl}$) phase the thermodynamically favored ground state.