Unit 7: Special Geometries, Flat Spaces & Hypersurfaces
Advanced geometric analysis of special Riemannian manifolds and embedded submanifolds: necessary and sufficient conditions for flat Riemannian spaces R_{ijkl} = 0, existence of global Cartesian coordinate systems, conformal transformations and conformal flatness, derivation of the Weyl conformal curvature tensor C^l_{ijk} and the Cotton-York tensor in 3D, geometry of hypersurfaces M^n \subset \mathbb{R}^{n+1}, induced metrics (first fundamental form a_{\alpha\beta}), Gauss's formula, the second fundamental form b_{\alpha\beta}, Weingarten equations, principal curvatures, Mean and Gaussian curvature, and the celebrated Gauss-Codazzi-Mainardi embedding equations.
ยง7.1 Flat Riemannian Spaces, Conditions for Flatness ($R_{ijkl} = 0$), and Cartesian Coordinates
1. Definition and Characterization of Flat Manifolds
A Riemannian space $R_n$ is called flat (or Euclidean / pseudo-Euclidean) if there exists a coordinate system $(y^1, \dots, y^n)$ in which the metric tensor components are everywhere constant:
By a constant linear transformation, such a metric can always be brought to diagonal form with entries $\pm 1$:
2. The Theorem of Flatness
Theorem 7.1 (Riemann Flatness Criterion): A Riemannian manifold $(M, g)$ is locally flat if and only if its Riemann curvature tensor vanishes identically everywhere:
Proof (Necessity):
If coordinates $y^k$ exist such that $g_{ij} = \text{const}$, then all first and second partial derivatives of the metric vanish identically:
Since $R^l_{ijk}$ is a genuine $(1, 3)$ tensor, if its components vanish in the $y$-frame, they must vanish in every coordinate system $x^i$:
Thus $R_{hijk} = 0$ is strictly necessary.
Proof (Sufficiency):
Suppose $R^l_{ijk} = 0$ throughout a simply connected neighborhood. We seek $n$ independent scalar functions $y^a(x)$ such that their gradients form a parallel orthonormal frame:
This is an overdetermined system of second-order linear PDEs for $y^a$. By Frobenius's integrability theorem, a solution exists if and only if the cross-covariant derivatives commute:
Applying the Ricci identity:
Since $R^m_{ijk} = 0$, the integrability condition is satisfied identically! Thus, there exist $n$ independent coordinate functions $y^a$ satisfying $\nabla_j (\partial_i y^a) = 0$. In these coordinates, $\partial_k g_{ab} = \nabla_k g_{ab} = 0$, so $g_{ab}$ is constant everywhere. $\blacksquare$
ยง7.2 Conformal Transformations, The Weyl Conformal Curvature Tensor $C^l_{ijk}$
1. Conformal Transformations
Two metrics $g$ and $\tilde{g}$ on a manifold $M$ are called conformally equivalent if they differ only by a positive scale factor:
Conformal transformations preserve all angles between intersecting curves, but alter lengths and geodesic trajectories. A Riemannian manifold is conformally flat if it is conformally equivalent to flat Euclidean space:
2. The Weyl Curvature Tensor
Hermann Weyl (1918) asked: What geometric tensor measures the intrinsic curvature that is invariant under conformal rescalings?
Definition 7.1 (Weyl Conformal Curvature Tensor): For an $n$-dimensional Riemannian manifold with $n \ge 3$, the Weyl tensor $C^l_{ijk}$ is the totally trace-free part of the Riemann curvature tensor:
Fundamental Properties of the Weyl Tensor:
1. Trace-Free: Contracting any pair of indices with $g$ yields zero identically:
2. Conformal Invariance: Under $\tilde{g}_{ij} = e^{2\sigma} g_{ij}$, the mixed Weyl tensor is strictly invariant:
while the covariant tensor scales conformally: $\tilde{C}_{hijk} = e^{2\sigma} C_{hijk}$.
3. Conformal Flatness Theorem (Weyl, 1918):
- For $n \ge 4$: A manifold is conformally flat if and only if $C^l_{ijk} = 0$.
- For $n = 3$: The Weyl tensor vanishes identically for all metrics ($C_{hijk} \equiv 0$). Conformal flatness in 3D is instead governed by the vanishing of the Cotton-York tensor:
- For $n = 2$: Every 2D Riemannian manifold is locally conformally flat (isothermal coordinates always exist).
ยง7.3 Hypersurfaces, Induced Metrics, and Gauss's Formula
1. Geometry of Embedded Hypersurfaces
Let $M^n$ be an $n$-dimensional hypersurface embedded in an $(n+1)$-dimensional Riemannian manifold $(\tilde{M}^{n+1}, G_{AB})$. Let $x^A$ ($A = 1, \dots, n+1$) be coordinates on $\tilde{M}$, and let $u^\alpha$ ($\alpha = 1, \dots, n$) be intrinsic coordinates on $M^n$. The hypersurface is defined parametrically by:
2. The Induced Metric (First Fundamental Form)
The tangent vectors to coordinate curves on $M^n$ are:
The infinitesimal displacement on $M^n$ is $dx^A = B^A_\alpha du^\alpha$. The arc length element restricted to the hypersurface defines the induced metric (first fundamental form) $a_{\alpha\beta}$:
where:
$a_{\alpha\beta}$ is an intrinsic symmetric rank-2 covariant tensor on the hypersurface $M^n$.
3. The Unit Normal Vector and Gauss's Formula
At each point of $M^n$, there exists a unique (up to sign) unit normal vector field $N^A$ satisfying:
($\epsilon = +1$ for spacelike normals in Riemannian geometry).
Now differentiate the tangent vectors $B^A_\alpha = \frac{\partial x^A}{\partial u^\alpha}$ along the surface: The ambient covariant derivative $\tilde{\nabla}_\beta B^A_\alpha$ decomposes into components tangent to the surface and normal to the surface:
Theorem 7.2 (Gauss's Formula):
where:
- $\bar{\Gamma}^\mu_{\alpha\beta}$ are the intrinsic Christoffel symbols computed from the induced metric $a_{\alpha\beta}$.
- $b_{\alpha\beta}$ is the second fundamental form of the hypersurface.
ยง7.4 The Second Fundamental Form $b_{ij}$, Weingarten Map & Normal Curvature
1. The Second Fundamental Form $b_{\alpha\beta}$
Contracting Gauss's formula with the normal vector $N_A = G_{AB} N^B$:
Since $G_{AB} N^A B^B_\alpha = 0$, differentiating with respect to $u^\beta$:
Because $\tilde{\nabla}_\beta B^B_\alpha = \tilde{\nabla}_\alpha B^B_\beta$ in torsion-free ambient space, the second fundamental form is symmetric:
2. Weingarten Equations (The Shape Operator)
How does the normal vector $N^A$ change as we move along the hypersurface? Since $G_{AB} N^A N^B = 1$, differentiating yields $N_A \tilde{\nabla}_\alpha N^A = 0$, meaning $\tilde{\nabla}_\alpha N^A$ is purely tangent to $M^n$:
Theorem 7.3 (Weingarten Equations):
where $b^\beta_\alpha = a^{\beta\mu} b_{\mu\alpha}$ is the shape operator (or Weingarten map).
3. Principal, Mean, and Gaussian Curvatures
The shape operator $b^\beta_\alpha$ is a symmetric linear endomorphism of the tangent space $T_p M^n$.
- Its eigenvalues $\kappa_1, \kappa_2, \dots, \kappa_n$ are called the principal curvatures.
- The corresponding eigenvectors are the principal directions.
- The Mean Curvature $H$ is the normalized trace:
- For a 2D surface in $\mathbb{R}^3$, the extrinsic Gaussian curvature is the determinant:
A surface is a minimal surface if $H = 0$ (e.g. soap films, catenoids, helicoids).
ยง7.5 The Gauss-Codazzi-Mainardi Equations and Extrinsic vs Intrinsic Geometry
1. Ambient vs Intrinsic Curvature
By evaluating the commutator of ambient covariant derivatives on the hypersurface tangent vectors $B^A_\alpha$, we establish the exact connection between the intrinsic Riemann curvature $R_{\alpha\beta\gamma\delta}$ of $M^n$ and the ambient curvature $\tilde{R}_{ABCD}$ of $\tilde{M}^{n+1}$.
2. The Gauss Equation
Theorem 7.4 (The Gauss Equation):
If the ambient space is flat Euclidean space ($\tilde{R}_{ABCD} = 0$):
Gauss's Theorema Egregium (Remarkable Theorem, 1827):
For a 2D surface embedded in $\mathbb{R}^3$, setting $(\alpha, \beta, \gamma, \delta) = (1, 2, 1, 2)$:
Dividing by the metric determinant $a = \det(a_{\alpha\beta})$:
The Gaussian curvature $K$ depends ONLY on the intrinsic metric $a_{\alpha\beta}$ and its derivatives! Bending a surface without stretching or tearing (isometric deformation) preserves $K$ identically.
3. The Codazzi-Mainardi Equations
The normal component of the commutator curvature identity yields the differential compatibility conditions on the second fundamental form:
Theorem 7.5 (The Codazzi-Mainardi Equations):
In flat Euclidean ambient space ($\tilde{R} = 0$):
The covariant derivative of the second fundamental form is completely symmetric in all three indices $\alpha, \beta, \gamma$!
Together, the Gauss and Codazzi-Mainardi equations are the necessary and sufficient integrability conditions (Fundamental Theorem of Surface Theory) for a pair of symmetric tensors $(a_{\alpha\beta}, b_{\alpha\beta})$ to uniquely realize a surface in $\mathbb{R}^{n+1}$ up to rigid motions.
Rigorous Tiered Solved Examination Problems
Step-by-step unskipped derivations, complete proofs, and verification across Foundational, Advanced, and Honors tiers.
Consider the sphere of radius $R$ embedded in Euclidean $\mathbb{R}^3$ parameterized by:
- Compute the tangent basis vectors $\mathbf{B}_\theta = \frac{\partial \mathbf{r}}{\partial\theta}$ and $\mathbf{B}_\phi = \frac{\partial \mathbf{r}}{\partial\phi}$.
- Determine the first fundamental form (induced metric) $a_{\alpha\beta}$.
- Find the unit outward normal vector $\mathbf{N}$.
- Compute the second fundamental form $b_{\alpha\beta}$, principal curvatures $\kappa_1, \kappa_2$, and verify Gauss's Theorema Egregium.
1. Tangent Basis Vectors
2. First Fundamental Form $a_{\alpha\beta}$
Thus:
3. Unit Normal Vector
Check $\|\mathbf{N}\|^2 = \sin^2\theta + \cos^2\theta = 1$.
4. Second Fundamental Form and Curvatures
Using $b_{\alpha\beta} = \mathbf{N} \cdot \frac{\partial^2 \mathbf{r}}{\partial u^\alpha \partial u^\beta}$:
- $\frac{\partial^2 \mathbf{r}}{\partial\theta^2} = (-R\sin\theta\cos\phi, -R\sin\theta\sin\phi, -R\cos\theta) = -\mathbf{r} = -R\mathbf{N}$.
(Taking outward normal gives $-R$; with inward convention $+R$. Let us use inward normal $\mathbf{N} = -\frac{\mathbf{r}}{R}$ so $b > 0$):
- $\frac{\partial^2 \mathbf{r}}{\partial\phi^2} = (-R\sin\theta\cos\phi, -R\sin\theta\sin\phi, 0)$.
- Cross-derivatives $b_{\theta\phi} = 0$.
Shape operator:
The principal curvatures are:
Extrinsic Gaussian curvature:
Intrinsic Gaussian curvature from metric:
Exact agreement confirming Gauss's Theorema Egregium! $\blacksquare$$
Consider the unit 3-sphere $S^3$ with standard round metric:
- Compute the components of the Riemann curvature tensor $R_{hijk}$ and show that $S^3$ has constant sectional curvature $K = +1$.
- Calculate the Ricci tensor $R_{ij}$ and scalar curvature $R$ for $S^3$.
- Compute the Weyl conformal curvature tensor $C^l_{ijk}$ on $S^3$ and explain why it vanishes.
- Using stereographic projection, show that $S^3$ is conformally flat: find the explicit conformal factor $\Omega(r)$ such that $ds^2 = \Omega^2(r) (dr^2 + r^2 d\theta^2 + r^2 \sin^2\theta d\phi^2)$.
1. Curvature of $S^3$
Since $S^3$ is a maximally symmetric round sphere of unit radius:
with constant sectional curvature $K = 1$. $\blacksquare$
2. Ricci Tensor and Scalar Curvature
For $n = 3$:
Scalar curvature:
3. Weyl Tensor on $S^3$
In dimension $n = 3$, the algebraic definition of the Weyl tensor gives:
Substituting $R_{ij} = 2 g_{ij}$ and $R = 6$:
Indeed, in ANY 3-dimensional manifold, $C_{hijk} \equiv 0$ identically! Furthermore, since $R_{ij} = 2 g_{ij}$, $\nabla_k R_{ij} = 0$, so the Cotton tensor $C_{ijk}$ also vanishes identically:
Hence, $S^3$ is conformally flat. $\blacksquare$
4. Stereographic Projection Conformal Factor
Let $r = 2 \tan\left(\frac{\chi}{2}\right)$. Then:
Differentiating $r$:
Square of the metric element:
Thus:
This proves explicitly that the 3-sphere metric is conformally flat. $\blacksquare$
Consider the catenoid in Euclidean $\mathbb{R}^3$, parameterized by:
- Calculate the tangent vectors $\mathbf{r}_u, \mathbf{r}_v$ and the first fundamental form $a_{\alpha\beta}$.
- Determine the unit normal vector $\mathbf{N}(u, v)$.
- Compute the second fundamental form $b_{\alpha\beta}$.
- Prove that the catenoid is a minimal surface by showing that its Mean Curvature vanishes identically: $H = 0$.
- Compute the intrinsic Gaussian curvature $K(u)$ and verify that the Gauss and Codazzi equations are satisfied.
1. Tangent Basis and First Fundamental Form
Tangent vectors:
Metric components:
Hence:
2. Unit Normal Vector
Cross product:
Magnitude:
Unit normal:
3. Second Fundamental Form
Second partial derivatives of $\mathbf{r}$:
Projecting onto $\mathbf{N}$:
Thus:
4. Mean Curvature $H = 0$ (Minimal Surface)
The inverse metric is:
Mean curvature:
Because $H \equiv 0$ everywhere, the catenoid is a minimal surface! $\blacksquare$
5. Gaussian Curvature and Integrability
Gaussian curvature:
Notice that $K < 0$ everywhere (the surface is strictly saddle-shaped / hyperbolic at every point). The Gauss equation gives $R_{uvuv} = b_{uu} b_{vv} - b_{uv}^2 = (-1/c)(c) - 0 = -1$. Checking intrinsic calculation of $R_{uvuv}$ confirms exact equality. The Codazzi equations $\bar{\nabla}_v b_{uu} = \bar{\nabla}_u b_{uv}$ vanish identically since connection terms and derivatives balance to zero. This completes the rigorous verification of the catenoid geometry. $\blacksquare$