The Leontief Input-Output Economic Model
Inter-Industry Technological Matrices, The Open Leontief Equation, Hawkins-Simon Viability & Neumann Multipliers
§8.1 Economic Foundations of Inter-Industry Analysis
1. The Inter-Industry Economic Network
Wassily Leontief (1973 Nobel Laureate in Economics) developed input-output analysis to model the interdependence of industries in an economy. In an economy divided into $n$ sectors (e.g., Agriculture, Manufacturing, Energy, Transportation), the output of any one sector serves a dual role:
- Intermediate Output: Consumed by other industries (and by itself) as inputs required for production.
- Final Demand: Consumed by households, government, capital investment, or export.
2. The Flow Matrix of Transactions
Let $x_{ij}$ denote the dollar value of output from sector $i$ consumed as intermediate input by sector $j$ during a given production period.
Let $d_i$ be the external final consumer demand for sector $i$'s product.
Let $x_i$ be the total gross output produced by sector $i$. Conservation of economic output requires:
$$\mathbf{x_i = \sum_{j=1}^n x_{ij} + d_i, \quad i = 1, 2, \dots, n}$$
Total Gross Output = Total Intermediate Inputs Consumed + Final Demand.
§8.2 The Consumption (Technological) Matrix $C$
1. The Technological Coefficients
Assuming constant returns to scale and fixed production recipes, the technological coefficient $c_{ij}$ is the dollar amount of sector $i$'s goods required to produce one dollar's worth of sector $j$'s output: $$\mathbf{c_{ij} \equiv \frac{x_{ij}}{x_j} \iff x_{ij} = c_{ij} x_j}$$ The $n \times n$ matrix $C = [c_{ij}]$ is called the consumption matrix (or technological matrix).
2. Properties of the Consumption Matrix
- Every entry is non-negative: $c_{ij} \ge 0$.
- Column $j$ represents the complete cost recipe per dollar produced by industry $j$: $$\mathbf{C_{*, j} = \begin{pmatrix} c_{1j} \\ c_{2j} \\ \vdots \\ c_{nj} \end{pmatrix}}$$
- Economic Profitability Condition: In an economy where industries create value rather than destroying resources, the sum of intermediate material costs per dollar of output must be strictly less than one: $$\sum_{i=1}^n c_{ij} < 1, \quad \text{for all } j = 1, \dots, n$$ The remainder $v_j = 1 - \sum_{i=1}^n c_{ij} > 0$ represents the value added (wages, taxes, and operating profit) per dollar of production!
§8.3 The Open Leontief Production Equation
1. Derivation of the Matrix Equation
Substituting $x_{ij} = c_{ij} x_j$ into the economic conservation balance: $$x_i = \sum_{j=1}^n c_{ij} x_j + d_i \iff X = C X + D$$ where: $$X = \begin{pmatrix} x_1 \\ x_2 \\ \vdots \\ x_n \end{pmatrix} \quad (\text{Gross Output Vector}), \qquad D = \begin{pmatrix} d_1 \\ d_2 \\ \vdots \\ d_n \end{pmatrix} \quad (\text{Final Demand Vector})$$ Rewriting into canonical linear system form: $$\mathbf{(I_n - C) X = D}$$ The matrix $I_n - C$ is called the Leontief Matrix.
2. The Equilibrium Production Solution
If the Leontief matrix $I_n - C$ is invertible, the gross output required across all sectors to satisfy final demand $D$ is uniquely determined by: $$\mathbf{X = (I_n - C)^{-1} D}$$ The inverse matrix $(I - C)^{-1}$ is termed the Leontief Inverse (or Total Requirements Matrix). Its $(i, j)$-th entry represents the total dollar amount that sector $i$ must produce directly and indirectly to supply one dollar of final demand to sector $j$!
§8.4 The Hawkins-Simon Economic Viability Conditions
1. The Economic Viability Problem
In real-world economics, negative production is impossible ($X \ge 0$). An economy is defined as economically viable if for every non-negative final demand vector $D \ge 0$, there exists a unique non-negative gross production vector $X \ge 0$ satisfying $(I - C)X = D$.
2. The Hawkins–Simon Theorem
Theorem (David Hawkins & Herbert Simon, 1949): An input-output system with consumption matrix $C \ge 0$ is economically viable if and only if all leading principal minors of the Leontief matrix $I - C$ are strictly positive:
- $\Delta_1 > 0 \iff c_{11} < 1$: Sector 1 cannot consume more of its own product than it produces.
- $\Delta_2 > 0 \iff (1 - c_{11})(1 - c_{22}) > c_{12} c_{21}$: The combined direct and indirect feedback loops between sectors 1 and 2 must not consume more than their collective net capacity.
§8.5 Neumann Series Multipliers & The Dual Leontief Price Model
1. The Neumann Power Series Expansion
If the spectral radius $\rho(C) < 1$, the Leontief inverse can be expanded as a convergent geometric matrix series (the Neumann Series): $$\mathbf{(I - C)^{-1} = I + C + C^2 + C^3 + \dots = \sum_{k=0}^\infty C^k}$$ Substituting into the output equation $X = (I - C)^{-1} D$: $$\mathbf{X = D + C D + C^2 D + C^3 D + \dots}$$ Economic Multiplier Breakdown:
- $D$: Direct final consumer demand.
- $CD$: First-round intermediate inputs required by industries to produce $D$.
- $C^2 D$: Second-round inputs required to produce the intermediate inputs $CD$.
- $C^k D$: $k$-th generation indirect supply chain requirements throughout the economy.
2. The Dual Leontief Price Model
Let $P = (p_1, p_2, \dots, p_n)$ be the unit price row vector across sectors, and let $V = (v_1, v_2, \dots, v_n)$ be the value-added row vector (wages + profits per unit). The equilibrium pricing relation states that price equals intermediate material costs plus value added: $$P = P C + V \iff P(I - C) = V$$ Multiplying by the Leontief inverse from the right yields the equilibrium price structure: $$\mathbf{P = V (I - C)^{-1}}$$ This allows governments and central banks to calculate how changes in wages or energy tax ($V$) propagate throughout the entire price level of the macroeconomy!
Step-by-Step Solved Examination Problems
Comprehensive analytical derivations, multi-tier solutions (Foundational, Intermediate Exam, and Honors/Proof Challenge) with complete line-by-line verification.
A two-sector economy consisting of Energy ($E$) and Manufacturing ($M$) has consumption matrix $C = \begin{pmatrix} 0.2 & 0.4 \\ 0.3 & 0.1 \end{pmatrix}$. (a) Verify the Hawkins-Simon conditions. (b) Compute the Leontief inverse $(I - C)^{-1}$. (c) Find the gross production vector $X$ required to satisfy final demand $D = \begin{pmatrix} 100 \\ 200 \end{pmatrix}$ million dollars.
Both principal minors are strictly positive, guaranteeing that the economy is viable.
Apply the $2 \times 2$ matrix inverse formula.
Multiply the Leontief inverse by the external demand vector.
\text{Hawkins-Simon conditions are satisfied; } \mathbf{(I - C)^{-1} = \begin{pmatrix} 1.5 & 0.667 \\ 0.5 & 1.333 \end{pmatrix}}; \quad \mathbf{X = \begin{pmatrix} 283.33 \\ 316.67 \end{pmatrix}} \text{ million dollars}.
A 3-sector economy with technological matrix $C = \begin{pmatrix} 0.1 & 0.2 & 0.2 \\ 0.2 & 0.1 & 0.1 \\ 0.1 & 0.2 & 0.1 \end{pmatrix}$ has current final demand $D = \begin{pmatrix} 50 \\ 60 \\ 40 \end{pmatrix}$. If consumer demand in Sector 2 increases by 50% while others remain unchanged, compute the required change in gross output vector $\Delta X$.
Subtract consumption matrix $C$ from identity matrix $I_3$.
Only sector 2 experiences an external demand increase of 30 units.
Compute the direct and indirect multiplier impact using cofactors.
\mathbf{\Delta X \approx \begin{pmatrix} 8.81 \\ 36.63 \\ 5.10 \end{pmatrix}} \implies \text{All three sectors must expand output to support Sector 2's demand growth}.
Given an $n$-sector economy with non-negative consumption matrix $C$: (a) Prove that if the maximum column sum satisfies $\|C\|_1 = \max_j \sum_{i=1}^n c_{ij} < 1$, the spectral radius satisfies $\rho(C) < 1$, and the Neumann series $\sum_{k=0}^\infty C^k$ converges strictly to $(I - C)^{-1}$. (b) If $C = \begin{pmatrix} 0.3 & 0.2 \\ 0.1 & 0.4 \end{pmatrix}$ and the value-added vector per unit output is $V = (14, 21)$ dollars, determine the equilibrium price vector $P = (p_1, p_2)$.
Use operator norm and Gelfand's formula to prove absolute convergence of the matrix power series.
Set up the horizontal row equation $P(I - C) = V$.
Multiply the value-added row vector by the Leontief inverse.
\mathbf{P = (26.25, \; 43.75)} \implies p_1 = \$26.25 \text{ and } p_2 = \$43.75 \text{ per unit}.