Unit 6: Normal Curvatures, Principal Curvatures & Shape Classification
Local geometry and curvature theory: principal curvatures and principal directions as critical values of the normal curvature quadratic ratio, Gaussian curvature $K$ and Mean curvature $H$, geometric point classification (elliptic, hyperbolic, parabolic, planar, and umbilical points), minimal surfaces ($H = 0$) and soap film geometry, curvature analysis of surfaces of revolution, and the global rigidity theorem for all-umbilic surfaces.
ยง6.1 Principal Curvatures & Directions as Extrema of Normal Curvature
1. The Normal Curvature as a Rayleigh Quotient
At any regular point $p$ on a surface $S$, the normal curvature $\kappa_n$ in the direction $(du, dv)$ is:
Since scaling $(du, dv)$ by any non-zero constant $c \ne 0$ cancels out in the numerator and denominator, $\kappa_n$ depends only on the direction angle on the unit circle in $T_p S$. Because the unit circle is compact and $\kappa_n$ is a continuous function, $\kappa_n$ must attain an absolute maximum $\kappa_1$ and an absolute minimum $\kappa_2$.
Definition 6.1 (Principal Curvatures and Principal Directions): The maximum and minimum values of the normal curvature at $p$:
are called the principal curvatures of the surface at $p$. The directions in $T_p S$ along which these extreme values are attained are called the principal directions.
2. Derivation of the Principal Curvature Equation
To find the critical points of $\kappa_n$, we use the method of Lagrange multipliers: extremize $II(du, dv) = L du^2 + 2M dudv + N dv^2$ subject to the normalization constraint $I(du, dv) = E du^2 + 2F dudv + G dv^2 = 1$. Form the Lagrangian:
Taking partial derivatives with respect to $du$ and $dv$ and setting them to zero:
In matrix notation:
For non-trivial tangent directions $(du, dv) \ne (0, 0)$, the determinant of this coefficient matrix must vanish!
Theorem 6.1 (The Characteristic Equation for Principal Curvatures): The principal curvatures $\kappa$ are the real roots of the quadratic equation:
Expanding the determinant:
3. Orthogonality of Principal Directions
Theorem 6.2 (Orthogonality of Principal Directions): If $\kappa_1 \ne \kappa_2$, the corresponding principal directions are mutually orthogonal in the tangent plane $T_p S$.
Proof: The principal curvatures $\kappa_1, \kappa_2$ are the eigenvalues of the Shape Operator $S_p$, and the principal directions are the corresponding eigenspaces. By Theorem 5.1, $S_p$ is self-adjoint with respect to the first fundamental form inner product $\langle \cdot, \cdot \rangle$. For eigenvectors $\mathbf{v}_1, \mathbf{v}_2$ with $\kappa_1 \ne \kappa_2$:
Since $\kappa_1 - \kappa_2 \ne 0$, we must have $\langle \mathbf{v}_1, \mathbf{v}_2 \rangle = 0$. $\blacksquare$
ยง6.2 Gaussian Curvature K, Mean Curvature H & Quadratic Invariants
1. Definitions of Gaussian and Mean Curvature
Dividing the quadratic characteristic equation of Theorem 6.1 by $(EG - F^2)$:
Comparing this with the standard monic quadratic $\kappa^2 - 2H\kappa + K = 0$:
Definition 6.2 (Gaussian Curvature and Mean Curvature):
- The Gaussian Curvature $K$ is the product of the principal curvatures:
- The Mean Curvature $H$ is the arithmetic mean of the principal curvatures:
2. Solving for Principal Curvatures in Terms of $H$ and $K$
The quadratic equation $\kappa^2 - 2H\kappa + K = 0$ has discriminant:
Notice that:
Thus, the discriminant is always non-negative, confirming that the principal curvatures are always real numbers! The roots are:
where $\kappa_1 = H + \sqrt{H^2 - K}$ is the maximum curvature and $\kappa_2 = H - \sqrt{H^2 - K}$ is the minimum curvature.
3. Gaussian Curvature as the Jacobian of the Gauss Map
Theorem 6.3 (Gauss Map Area Ratio): Let $U \subset S$ be a small region around $p$, and let $\mathbf{n}(U) \subset S^2$ be its spherical image under the Gauss map. The Gaussian curvature $K(p)$ is the limit of the ratio of the spherical area to the surface area:
with the sign determined by whether the Gauss map preserves ($K > 0$) or reverses ($K < 0$) orientation.
Proof: The area element on the surface is $dA_S = \|\mathbf{r}_u \times \mathbf{r}_v\| \, du \, dv$. The area element on the unit sphere traced by $\mathbf{n}(u, v)$ is:
By the Weingarten equations (Section 5.3), $\mathbf{n}_u = -S(\mathbf{r}_u)$ and $\mathbf{n}_v = -S(\mathbf{r}_v)$. For any linear operator $S$ on the tangent plane, the cross product transforms as:
Taking norms:
Taking the oriented limit yields the theorem. $\blacksquare$
ยง6.3 Geometric Classification of Points: Elliptic, Hyperbolic, Parabolic & Umbilic
1. Classification by the Sign of Gaussian Curvature
The sign of the Gaussian curvature $K = \frac{LN - M^2}{EG - F^2}$ dictates the local shape of the surface relative to its tangent plane. Since $EG - F^2 > 0$, the sign of $K$ is determined entirely by the sign of the discriminant of the Second Fundamental Form: $LN - M^2$.
Definition 6.3 (Classification of Surface Points): Let $p \in S$ be a regular point:
- Elliptic Point ($K > 0$):
Both principal curvatures have the same sign ($\kappa_1 \kappa_2 > 0$). $LN - M^2 > 0$. The Second Fundamental Form $II$ is definite (positive or negative). Geometry: The surface curves away from the tangent plane in the same direction along all tangent vectors; locally, the surface lies entirely on one side of its tangent plane (like an ellipsoid or sphere).
- Hyperbolic Point ($K < 0$):
The principal curvatures have opposite signs ($\kappa_1 \kappa_2 < 0$). $LN - M^2 < 0$. The Second Fundamental Form $II$ is indefinite. Geometry: The surface is saddle-shaped; the tangent plane cuts through the surface, dividing it into two regions lying on opposite sides of the plane (like a hyperbolic paraboloid or catenoid).
- Parabolic Point ($K = 0$, but not all second coefficients vanish):
One principal curvature is zero and the other is non-zero ($\kappa_1 \ne 0, \kappa_2 = 0$). $LN - M^2 = 0$, with $L^2 + M^2 + N^2 > 0$. Geometry: The surface bends along one direction but is flat along another (like a cylinder or cone).
- Planar Point ($\kappa_1 = \kappa_2 = 0$):
Both principal curvatures vanish identically ($L = M = N = 0$). Geometry: Second-order curvature is completely flat in all directions (like a point on a flat plane).
2. Umbilical Points
Definition 6.4 (Umbilical Point): A point $p \in S$ is called an umbilical point (or umbilic) if the two principal curvatures are equal:
Equivalently, the Shape Operator is a scalar multiple of the identity: $S_p = \kappa I_{\text{id}}$.
At an umbilic:
- The normal curvature is identical in every direction: $\kappa_n(\mathbf{w}) = \kappa$ for all $\mathbf{w} \in T_p S$.
- Every tangent direction is a principal direction!
- If $\kappa_1 = \kappa_2 \ne 0$, $p$ is an elliptic umbilic (e.g., any point on a sphere of radius $1/\kappa$).
- If $\kappa_1 = \kappa_2 = 0$, $p$ is a planar umbilic.
ยง6.4 Minimal Surfaces & Zero Mean Curvature: Geometry of Soap Films
1. Definition and Physical Origin of Minimal Surfaces
Definition 6.5 (Minimal Surface): A regular surface $S$ is called a minimal surface if its Mean Curvature vanishes identically at every point:
Equivalently, the principal curvatures are equal in magnitude and opposite in sign:
Physically, by the Young-Laplace equation of fluid mechanics, the pressure difference $\Delta P$ across a soap film interface with surface tension $\sigma$ is:
When the pressure is equal on both sides ($\Delta P = 0$), the soap film spontaneously adopts a configuration with $H = 0$, minimizing its total surface area subject to the fixed boundary wire frame!
2. Properties of Minimal Surfaces
1. Gaussian Curvature is Non-Positive:
Since $\kappa_2 = -\kappa_1$, $K = \kappa_1 \kappa_2 = -\kappa_1^2 \le 0$. Therefore, every point on a minimal surface is either hyperbolic ($K < 0$) or planar ($K = 0$). There are no elliptic points on a minimal surface!
2. Minimal Surface Partial Differential Equation:
For a Monge patch $z = f(x, y)$, the condition $H = 0$ translates into Lagrange's non-linear minimal surface PDE:
3. Conformal Parametrizations and Harmonic Coordinates:
If a surface is parametrized by isothermal coordinates ($E = G = \lambda^2, F = 0$), then:
Thus, in isothermal coordinates, a surface is minimal ($H = 0$) if and only if its coordinate functions are harmonic:
3. Classical Examples of Minimal Surfaces
- The Catenoid: Discovered by Euler (1744), the only minimal surface of revolution other than the plane.
- The Helicoid: Discovered by Meusnier (1776), the only ruled minimal surface other than the plane.
- Scherk's Surface: Discovered by Scherk (1834), $z = \ln(\cos x / \cos y)$.
- Enneper's Surface: An algebraic minimal surface of degree 9.
ยง6.5 Surfaces of Revolution: Meridian & Parallel Curvatures & Beltrami's Pseudosphere
1. Parametrization of a Surface of Revolution
Let a profile curve in the $xz$-plane be parametrized by arc-length $u$:
Rotating this curve about the $z$-axis through angle $v \in [0, 2\pi)$ produces the surface of revolution:
2. First and Second Fundamental Forms
Computing the partial derivatives:
Metric coefficients:
The coordinate grid is orthogonal ($F = 0$). The unit normal is:
Second derivatives:
Taking dot products with $\mathbf{n}$:
Since $F = 0$ and $M = 0$, the coordinate curves (meridians and parallels) are lines of curvature!
3. Principal and Gaussian Curvatures
The principal curvatures along the meridians ($dv = 0$) and parallels ($du = 0$) are:
Differentiating $(f')^2 + (g')^2 = 1$ with respect to $u$:
Substituting this into $\kappa_1$:
Multiplying $\kappa_1$ and $\kappa_2$:
Theorem 6.4 (Gaussian Curvature of a Surface of Revolution): For a surface of revolution with profile curve parametrized by arc-length $u$:
4. Beltrami's Pseudosphere
Setting $K = -1/a^2$ (constant negative curvature) in $-\frac{f''}{f} = -\frac{1}{a^2}$ gives the differential equation:
The profile curve generating the pseudosphere is the tractrix:
Beltrami demonstrated in 1868 that the pseudosphere provides a concrete local model for the hyperbolic geometry of Lobachevsky and Bolyai!
Step-by-step rigorous derivations with unskipped proofs, categorized into Foundational Concepts, Advanced Structural Analysis, and Honors / Proof Challenge tiers.
Consider the torus formed by revolving a circle of radius $r > 0$ centered at distance $R > r > 0$ from the $z$-axis:
- Compute the First Fundamental Form $I$ and Second Fundamental Form $II$.
- Find the principal curvatures $\kappa_1, \kappa_2$, Gaussian curvature $K(u)$, and Mean curvature $H(u)$.
- Classify each region of the torus into elliptic, parabolic, and hyperbolic points based on the parameter $u$.
1. Partial Derivatives and Fundamental Forms
Dot products:
Thus:
Cross product and unit normal:
Dividing by $\|\mathbf{r}_u \times \mathbf{r}_v\| = r(R + r \cos u)$ (oriented inwards for positive standard convention, or outwards):
Computing second derivatives and dot products with $\mathbf{n}$:
Thus:
2. Principal, Gaussian, and Mean Curvatures
Since $F = 0$ and $M = 0$, the principal curvatures are simply the diagonal ratios:
Gaussian Curvature:
Mean Curvature:
3. Classification of Points
Because $R > r > 0$, the denominator $r(R + r \cos u) > 0$ is strictly positive for all $u$. The sign of $K(u)$ is governed entirely by the sign of $\cos u$:
1. Outer Equator / Exterior Region ($-\pi/2 < u < \pi/2$):
$\cos u > 0 \implies K > 0$. All points on the outer half of the torus are elliptic points.
2. Top and Bottom Crown Circles ($u = \pi/2$ and $u = 3\pi/2$):
$\cos u = 0 \implies K = 0$. Here $\kappa_1 = 1/r \ne 0$ and $\kappa_2 = 0$. These two parallel circles consist entirely of parabolic points.
3. Inner Equator / Interior Region ($\pi/2 < u < 3\pi/2$):
$\cos u < 0 \implies K < 0$. All points on the inner doughnut hole facing the axis are hyperbolic points (saddle-shaped). $\blacksquare$
Consider Scherk's famous surface defined explicitly by the Monge graph:
on the domain $U = (-\pi/2, \pi/2) \times (-\pi/2, \pi/2)$.
- Compute the first and second partial derivatives: $f_x, f_y, f_{xx}, f_{xy}, f_{yy}$.
- Recall Lagrange's minimal surface equation for Monge patches $z = f(x, y)$:
- Substitute the derivatives into Lagrange's equation to prove that Mean Curvature $H = 0$ everywhere on $U$, establishing that Scherk's surface is a minimal surface.
1. Partial Derivatives
The function is:
First derivatives:
Second derivatives:
2. Lagrange's Minimal Surface Condition
For a Monge surface $\mathbf{r}(x, y) = (x, y, f(x, y))^T$, the metric coefficients are:
The unit normal is $\mathbf{n} = \frac{(-f_x, -f_y, 1)^T}{\sqrt{1 + f_x^2 + f_y^2}}$. The second fundamental form coefficients are:
The Mean Curvature is:
Therefore, $H = 0$ if and only if the numerator vanishes:
3. Evaluation of the Numerator
Substitute $f_x = -\tan x$, $f_y = \tan y$, $f_{xx} = -\sec^2 x$, $f_{xy} = 0$, and $f_{yy} = \sec^2 y$:
Recall the Pythagorean trigonometric identity $1 + \tan^2 \theta = \sec^2 \theta$:
Substituting these:
Since the numerator vanishes identically:
Thus, Scherk's surface is a minimal surface! $\blacksquare$$
Let $S \subset \mathbb{R}^3$ be a connected regular surface such that every point of $S$ is an umbilical point ($\kappa_1 = \kappa_2$).
- Express the condition that $p$ is an umbilic in terms of the Shape Operator $S_p$ and the Weingarten equations.
- Differentiate the resulting relation $\mathbf{n}_u = -\lambda(u, v) \mathbf{r}_u$ and $\mathbf{n}_v = -\lambda(u, v) \mathbf{r}_v$ to prove that $\lambda(u, v) = \lambda_0$ is a constant function on any connected coordinate patch.
- Conclude that if $\lambda_0 = 0$, $S$ is an open subset of a plane; and if $\lambda_0 \ne 0$, $S$ is an open subset of a sphere of radius $R = 1/|\lambda_0|$.
1. Shape Operator and Umbilical Condition
Let $p \in S$ be an umbilical point. Then the principal curvatures coincide: $\kappa_1 = \kappa_2 = \lambda(u, v)$. Therefore, the Shape Operator is a scalar operator:
Applying this to the coordinate basis vectors $\mathbf{r}_u, \mathbf{r}_v$:
2. Differentiating and Equality of Mixed Partials
Assume $S$ is of class $C^3$, so $\mathbf{n}$ is of class $C^2$. By Clairaut's theorem, mixed partial derivatives of $\mathbf{n}$ must commute:
Computing both sides using the product rule:
Equating these expressions:
Because the surface is $C^2$, $\mathbf{r}_{uv} = \mathbf{r}_{vu}$, so the terms $-\lambda \mathbf{r}_{uv}$ cancel out on both sides:
Since the surface patch is regular, $\mathbf{r}_u$ and $\mathbf{r}_v$ are linearly independent vectors! Therefore, their scalar coefficients must both be zero:
Because the domain is connected, $\lambda(u, v) = \lambda_0 = \text{constant}$! $\blacksquare$
3. Case Analysis: Plane or Sphere
Case 1: $\lambda_0 = 0$ If $\lambda_0 = 0$, then:
Hence, the unit normal vector is constant across the entire connected surface:
Now consider the scalar function $f(u, v) = \mathbf{r}(u, v) \cdot \mathbf{n}_0$. Differentiating:
Thus $f(u, v) = c$ is constant:
This is the equation of a plane in $\mathbb{R}^3$. Therefore, $S$ is an open subset of a plane!
Case 2: $\lambda_0 \ne 0$ If $\lambda_0 \ne 0$, consider the vector-valued function:
Differentiating with respect to $u$ and $v$:
Since both partial derivatives vanish, $\mathbf{c}(u, v)$ is a constant vector $\mathbf{c}_0 \in \mathbb{R}^3$:
Taking the Euclidean norm on both sides:
Letting $R = \frac{1}{|\lambda_0|} > 0$:
This is precisely the equation of a sphere of radius $R$ centered at $\mathbf{c}_0$! Therefore, $S$ is an open subset of a sphere! $\blacksquare$