Unit 7: Lines of Curvature, Asymptotic Curves & The Dupin Indicatrix
Directional geometry on surfaces: Rodrigues' formula for lines of curvature, Euler's theorem on normal curvature, the Dupin indicatrix conic sections, asymptotic directions and curves ($II = 0$), the Beltrami-Enneper theorem on the torsion of asymptotic curves ($ au = \pm \sqrt{-K}$), conjugate directions, and triply orthogonal systems.
ยง7.1 Rodrigues' Formula & Differential Equations of Lines of Curvature
1. Definition of Lines of Curvature
Definition 7.1 (Line of Curvature): A regular curve $C$ on a surface $S$ is called a line of curvature (or curvature line) if its tangent vector at every point points along a principal direction of the surface.
2. Rodrigues' Formula
Theorem 7.1 (Rodrigues' Formula, 1815): A regular curve $\mathbf{r}(t)$ on a surface $S$ is a line of curvature if and only if there exists a scalar function $\kappa(t)$ (the principal curvature) such that:
Proof: By definition, $\mathbf{r}'(t)$ is an eigenvector of the Shape Operator $S_p$ if and only if:
Recall that the Shape Operator is defined by $S_p(\mathbf{w}) = -d\mathbf{n}_p(\mathbf{w})$. Applying this to $\mathbf{w} = \mathbf{r}'(t)$:
This establishes Rodrigues' formula directly. $\blacksquare$
3. Differential Equation of Lines of Curvature
Let $d\mathbf{r} = \mathbf{r}_u \, du + \mathbf{r}_v \, dv$ and $d\mathbf{n} = \mathbf{n}_u \, du + \mathbf{n}_v \, dv$. By Rodrigues' formula, $d\mathbf{n}$ is collinear with $d\mathbf{r}$. Hence, their cross product must vanish in $\mathbb{R}^3$:
Since both $d\mathbf{n}$ and $d\mathbf{r}$ lie in the tangent plane $T_p S$, the vector $d\mathbf{n} \times d\mathbf{r}$ is parallel to the normal vector $\mathbf{n}$. Therefore:
Using the Weingarten equations to express $d\mathbf{n}$ in terms of $E, F, G$ and $L, M, N$, this determinant expands into the classical Monge-Darby determinant:
Theorem 7.2 (Differential Equation of Lines of Curvature): The lines of curvature on a surface patch satisfy the second-order quadratic ODE:
Expanding this $3 \times 3$ determinant:
Corollary 7.1 (Coordinate Curves as Lines of Curvature): The coordinate curves $u = \text{const}$ and $v = \text{const}$ form a family of lines of curvature if and only if:
In this case, the principal curvatures are simply $\kappa_1 = L/E$ and $\kappa_2 = N/G$.
ยง7.2 Euler's Theorem on Normal Curvature & Mean Curvature Invariance
1. Statement and Proof of Euler's Formula
Let $p \in S$ be a non-umbilical point ($\kappa_1 \ne \kappa_2$). Choose an orthonormal basis $\{\mathbf{e}_1, \mathbf{e}_2\}$ in $T_p S$ along the principal directions:
Any unit tangent vector $\mathbf{u} \in T_p S$ can be represented as:
where $\theta \in [0, 2\pi)$ is the angle made by $\mathbf{u}$ with the first principal direction $\mathbf{e}_1$.
Theorem 7.3 (Euler's Theorem, 1760): The normal curvature $\kappa_n(\theta)$ along the direction making an angle $\theta$ with the first principal direction is given by:
Proof: Recall from Section 5.2 that the normal curvature along a unit tangent vector $\mathbf{u}$ is:
Substituting $\mathbf{u} = \cos\theta \, \mathbf{e}_1 + \sin\theta \, \mathbf{e}_2$:
Taking the inner product with $\mathbf{u}$:
Since $\mathbf{e}_1 \cdot \mathbf{e}_1 = 1$, $\mathbf{e}_2 \cdot \mathbf{e}_2 = 1$, and $\mathbf{e}_1 \cdot \mathbf{e}_2 = 0$:
2. Orthogonal Pairs and the Invariance of Mean Curvature
Consider two mutually perpendicular tangent directions: $\theta$ and $\theta + \pi/2$. The normal curvature in the perpendicular direction is:
Adding the two normal curvatures together:
Corollary 7.2 (Invariance of Sum of Orthogonal Curvatures): For any pair of orthogonal unit tangent vectors on a surface, the sum of their normal curvatures is constant and equals twice the Mean Curvature:
ยง7.3 The Dupin Indicatrix & Osculating Quadrics
1. Construction of the Dupin Indicatrix
The Dupin indicatrix is a geometric construction in the tangent plane $T_p S$ that visually characterizes the local second-order shape of the surface. Let Cartesian coordinates $(\xi, \eta)$ be chosen in $T_p S$ along the principal directions $\mathbf{e}_1, \mathbf{e}_2$. For each direction defined by angle $\theta$ ($\xi = r \cos\theta, \eta = r \sin\theta$), plot a segment of length:
Squaring and multiplying by $|\kappa_n(\theta)|$:
Substituting $\xi = r \cos\theta$ and $\eta = r \sin\theta$:
Definition 7.2 (The Dupin Indicatrix): The Dupin indicatrix at a point $p \in S$ is the quadratic curve in $T_p S$ given by:
2. Geometric Shape Depending on Point Type
1. At an Elliptic Point ($K > 0$):
$\kappa_1$ and $\kappa_2$ have the same sign. The equation is:
This is an ellipse with semi-axes $a = 1/\sqrt{\kappa_1}$ and $b = 1/\sqrt{\kappa_2}$. If the point is an umbilic ($\kappa_1 = \kappa_2$), the ellipse becomes a circle.
2. At a Hyperbolic Point ($K < 0$):
$\kappa_1$ and $\kappa_2$ have opposite signs (say $\kappa_1 > 0, \kappa_2 < 0$). The Dupin indicatrix consists of a pair of conjugate hyperbolas:
The asymptotes of these hyperbolas are given by $\kappa_1 \xi^2 + \kappa_2 \eta^2 = 0$, which correspond to the asymptotic directions of the surface!
3. At a Parabolic Point ($K = 0, \kappa_1 \ne 0, \kappa_2 = 0$):
The equation reduces to:
This is a pair of parallel straight lines parallel to the direction of zero curvature.
ยง7.4 Asymptotic Curves & The Beltrami-Enneper Torsion Theorem
1. Asymptotic Directions and Curves
Definition 7.3 (Asymptotic Direction and Curve):
- A tangent direction $(du, dv)$ at $p \in S$ is called an asymptotic direction if the normal curvature along that direction is zero:
- A regular curve on $S$ whose tangent vector at every point points along an asymptotic direction is called an asymptotic curve (or asymptotic line).
From Euler's theorem, $\kappa_n(\theta) = \kappa_1 \cos^2\theta + \kappa_2 \sin^2\theta = 0$:
- At an elliptic point ($K > 0$): $\kappa_1 / \kappa_2 > 0$, so $\tan^2\theta < 0$, which has no real solutions. There are no asymptotic directions at elliptic points!
- At a parabolic point ($K = 0$): there is one unique asymptotic direction (along the direction of $\kappa_2 = 0$).
- At a hyperbolic point ($K < 0$): $\tan\theta = \pm \sqrt{-\kappa_1 / \kappa_2}$, yielding two distinct real asymptotic directions symmetric about the principal directions!
2. The Beltrami-Enneper Theorem
Along an asymptotic curve, $\kappa_n = \kappa \cos \theta = 0$. Assuming the space curvature $\kappa > 0$, Meusnier's theorem dictates that $\cos \theta = 0 \implies \mathbf{N} \cdot \mathbf{n} = 0$. Thus, the principal normal to the curve $\mathbf{N}$ is perpendicular to the surface normal $\mathbf{n}$! Consequently, the binormal vector $\mathbf{B} = \mathbf{T} \times \mathbf{N}$ is parallel to $\mathbf{n}$:
The osculating plane of an asymptotic curve coincides with the tangent plane to the surface!
Theorem 7.4 (Beltrami-Enneper Theorem, 1870): Let $C$ be an asymptotic curve with non-vanishing space curvature $\kappa > 0$ on a surface with negative Gaussian curvature $K < 0$. Then the torsion $\tau$ of the asymptotic curve satisfies:
Proof: Along the asymptotic curve, the binormal satisfies $\mathbf{B} = \mathbf{n}$ (up to a sign $\pm 1$). By the Serret-Frenet formulas:
Taking the norm squared:
Since $\mathbf{B} = \mathbf{n}$, $\mathbf{B}'(s) = d\mathbf{n}(\mathbf{T}) = -S_p(\mathbf{T})$. Thus:
By the fundamental form identity (Theorem 5.4):
Since the curve is asymptotic, $II(\mathbf{T}) = 0$. Since $\mathbf{T}$ is a unit vector, $I(\mathbf{T}) = 1$. Substituting these values:
Since $K < 0$, $-K > 0$, taking the square root gives:
ยง7.5 Conjugate Directions, Koenigs Nets & Triply Orthogonal Systems
1. Conjugate Directions
Definition 7.4 (Conjugate Directions): Two tangent directions $\mathbf{w}_1 = (du, dv)$ and $\mathbf{w}_2 = (\delta u, \delta v)$ at $p \in S$ are called conjugate directions if:
In coordinates, the conjugacy condition is:
Theorem 7.5 (Geometric Properties of Conjugate Directions):
- The principal directions are the only mutually orthogonal conjugate directions.
- An asymptotic direction is self-conjugate ($II(du, dv) = 0$).
- Two directions $\theta_1, \theta_2$ relative to the principal frame are conjugate if and only if:
2. Triply Orthogonal Systems & Dupin's Theorem
Definition 7.5 (Triply Orthogonal System): A system of three families of surfaces in $\mathbb{R}^3$ is called a triply orthogonal system if through each point there passes exactly one surface from each family, and the three surfaces intersect each other pairwise orthogonally.
Theorem 7.6 (Dupin's Theorem, 1813): The intersection curves of the surfaces of any triply orthogonal system are lines of curvature on all three intersecting surfaces!
Example: Confocal quadrics (ellipsoids, hyperboloids of one sheet, and hyperboloids of two sheets sharing the same focal conics) form a triply orthogonal system. By Dupin's Theorem, their curves of intersection are automatically the lines of curvature on each quadric surface!
Step-by-step rigorous derivations with unskipped proofs, categorized into Foundational Concepts, Advanced Structural Analysis, and Honors / Proof Challenge tiers.
Let $p \in S$ be a regular point with principal curvatures $\kappa_1$ and $\kappa_2$.
- By Euler's formula, the normal curvature in direction $\theta$ is $\kappa_n(\theta) = \kappa_1 \cos^2\theta + \kappa_2 \sin^2\theta$. Prove that the maximum and minimum values of $\kappa_n(\theta)$ over $\theta \in [0, 2\pi)$ are indeed $\kappa_1$ and $\kappa_2$.
- Compute the angular average of the normal curvature:
and show that this average is identically equal to the Mean Curvature $H$.
1. Extrema of Euler's Formula
Euler's formula gives:
Without loss of generality, assume $\kappa_1 \ge \kappa_2$. Rewriting $\sin^2\theta = 1 - \cos^2\theta$:
Since $0 \le \cos^2\theta \le 1$:
- When $\cos^2\theta = 1$ ($\theta = 0$ or $\theta = \pi$), $\kappa_n(\theta) = \kappa_2 + (\kappa_1 - \kappa_2)(1) = \kappa_1$ (maximum).
- When $\cos^2\theta = 0$ ($\theta = \pi/2$ or $\theta = 3\pi/2$), $\kappa_n(\theta) = \kappa_2 + (\kappa_1 - \kappa_2)(0) = \kappa_2$ (minimum).
Thus, the principal curvatures $\kappa_1$ and $\kappa_2$ are the absolute maximum and minimum of normal curvature! $\blacksquare$
2. Angular Average of Normal Curvature
Using the half-angle identities:
Substitute these into Euler's formula:
Now integrate over $\theta \in [0, 2\pi)$:
Notice that:
Therefore:
Dividing by $2\pi$:
This provides a beautiful physical and geometric interpretation: the Mean Curvature $H$ is the exact uniform average of normal curvatures over all possible directions!
Consider the standard Catenoid parametrized by:
Recall that $E = \cosh^2 u$, $F = 0$, $G = \cosh^2 u$, and $L = -1$, $M = 0$, $N = 1$.
- Set up the differential equation of asymptotic curves $II = 0$.
- Solve this differential equation explicitly to find the two families of asymptotic curves.
- Show that these two families of curves intersect at right angles everywhere on the catenoid.
1. Differential Equation of Asymptotic Curves
The condition for an asymptotic direction is:
For the catenoid, $L = -1$, $M = 0$, and $N = 1$. Thus:
2. Solving for the Families of Curves
Factor the difference of squares:
This yields two first-order ODEs:
- Family 1: $dv - du = 0 \implies \frac{dv}{du} = 1 \implies v - u = c_1$
- Family 2: $dv + du = 0 \implies \frac{dv}{du} = -1 \implies v + u = c_2$
where $c_1, c_2$ are arbitrary integration constants. These are straight diagonal lines in the $uv$-parameter plane! $\blacksquare$
3. Orthogonality of the Asymptotic Net
Let direction 1 be $(du_1, dv_1) = (1, 1) \, dt$ and direction 2 be $(du_2, dv_2) = (1, -1) \, ds$. The inner product of these tangent directions with respect to the First Fundamental Form is:
Recall that $E = G = \cosh^2 u$ and $F = 0$:
Because the inner product vanishes everywhere on the surface, the two families of asymptotic curves form an orthogonal net!
Remark: On any minimal surface ($H = 0$), $\kappa_1 = -\kappa_2$. By Euler's formula, $\kappa_n(\theta) = \kappa_1(\cos^2\theta - \sin^2\theta) = \kappa_1 \cos(2\theta) = 0 \implies 2\theta = \pm \pi/2 \implies \theta = \pm \pi/4$. Hence, on any minimal surface, the asymptotic directions bisect the principal directions and are always mutually orthogonal! $\blacksquare$
Let $S \subset \mathbb{R}^3$ be a $C^3$ regular surface with negative Gaussian curvature $K < 0$, and let $C: \mathbf{r}(s)$ be an asymptotic curve on $S$ parametrized by arc-length $s$ with space curvature $\kappa(s) > 0$.
- Prove that the binormal vector $\mathbf{B}(s)$ to the curve is collinear with the surface normal $\mathbf{n}(s)$, and determine the sign relationship.
- Differentiate $\mathbf{B}(s) = \pm \mathbf{n}(s)$ along the curve and express $\mathbf{n}'(s)$ using the Shape Operator.
- Compute the torsion $\tau(s)$ of the curve and prove that $\tau^2 = -K(s)$, so that $\tau(s) = \pm \sqrt{-K(s)}$.
1. Collinearity of Binormal and Surface Normal
Let $C: \mathbf{r}(s)$ be parametrized by arc-length. Its unit tangent is $\mathbf{T}(s) = \mathbf{r}'(s) \in T_p S$, so $\mathbf{T} \cdot \mathbf{n} = 0$. By Serret-Frenet, $\mathbf{r}''(s) = \kappa \mathbf{N}$. The normal curvature of the curve on the surface is:
Because $C$ is an asymptotic curve, $\kappa_n = 0$ by definition. Since $\kappa > 0$ by assumption:
Thus, both $\mathbf{T}$ and $\mathbf{N}$ are orthogonal to the surface normal $\mathbf{n}$. In Euclidean 3-space, the orthogonal complement of the plane spanned by $\{\mathbf{T}, \mathbf{N}\}$ is one-dimensional, spanned by the binormal $\mathbf{B} = \mathbf{T} \times \mathbf{N}$. Since $\mathbf{n}$ is orthogonal to both $\mathbf{T}$ and $\mathbf{N}$, and $\|\mathbf{n}\| = \|\mathbf{B}\| = 1$, we must have:
2. Derivative of the Normal and Binormal
Differentiating $\mathbf{B}(s) = \epsilon \, \mathbf{n}(s)$ with respect to arc-length $s$:
By the third Serret-Frenet formula (Unit 2):
On the other hand, applying the chain rule to the Gauss map:
where $S_p$ is the Shape Operator. Equating the two expressions for $\mathbf{B}'(s)$:
3. Evaluating the Torsion $\tau^2 = -K$
Taking the norm squared of both sides:
Since $\|\mathbf{N}(s)\| = 1$ and $\epsilon^2 = 1$:
Recall the fundamental form operator identity (Theorem 5.4):
Because $\mathbf{T}$ points along an asymptotic direction, $II(\mathbf{T}) = 0$. Because $\mathbf{T}$ is a unit tangent vector, $I(\mathbf{T}) = \|\mathbf{T}\|^2 = 1$. Substituting these values:
Because $S$ has negative Gaussian curvature, $K < 0$, which ensures that $-K > 0$. Taking the square root:
This remarkable theorem proves that the torsion of an asymptotic curve depends only on the Gaussian curvature of the surface at that point!