Interference by Division of Wavefront
Huygens' principle, wave superposition in complex notation, Young's double slit, fringe width & geometry, Fresnel's biprism, and Lloyd's mirror.
§1.1Huygens-Fresnel Principle, Wave Superposition and Complex Notation
1. Complex Exponential Wave Representation
In monochromatic optical analysis, real oscillatory fields are most efficiently represented using Euler's complex notation: $$\psi(\mathbf{r}, t) = \operatorname{Re} \left\{ \tilde{E}(\mathbf{r}) e^{-i\omega t} \right\} = \operatorname{Re} \left\{ E_0 e^{i(\mathbf{k} \cdot \mathbf{r} - \omega t + \phi)} \right\}$$ where $\tilde{E}(\mathbf{r}) = E_0 e^{i(\mathbf{k}\cdot\mathbf{r} + \phi)}$ is the complex amplitude (phasor), $k = \frac{2\pi}{\lambda} = \frac{\omega}{c}$ is the wave number, $\omega$ is the angular optical frequency, and $\phi$ is the initial phase constant.2. Linear Superposition of Two Coherent Optical Fields
Consider two monochromatic electromagnetic waves of identical angular frequency $\omega$ intersecting at an observation point $P(\mathbf{r})$. The individual electric field scalar amplitudes are: $$E_1 = E_{01} e^{i(\mathbf{k}_1 \cdot \mathbf{r} - \omega t + \phi_1)}, \quad E_2 = E_{02} e^{i(\mathbf{k}_2 \cdot \mathbf{r} - \omega t + \phi_2)}$$ By the principle of linear superposition in linear dielectric media, the total electric field at $P$ is the algebraic sum of the individual field vectors: $$E_{\text{total}} = E_1 + E_2 = \left( E_{01} e^{i\delta_1} + E_{02} e^{i\delta_2} \right) e^{-i\omega t}$$ where $\delta_1 = \mathbf{k}_1 \cdot \mathbf{r} + \phi_1$ and $\delta_2 = \mathbf{k}_2 \cdot \mathbf{r} + \phi_2$.3. Observable Optical Intensity and the Interference Term
Optical detectors (photodiodes, CCD sensors, human eye) cannot track instantaneous optical oscillations ($~10^{14}-10^{15} \text{ Hz}$). Instead, detectors measure the time-averaged irradiance (optical intensity) $I$: $$I = \langle |E_{\text{total}}|^2 \rangle = \frac{1}{2} E_{\text{total}} E_{\text{total}}^*$$ Substituting the complex superposition: $$I = \frac{1}{2} \left( E_{01} e^{i\delta_1} + E_{02} e^{i\delta_2} \right) \left( E_{01} e^{-i\delta_1} + E_{02} e^{-i\delta_2} \right)$$ $$I = \frac{1}{2} \left[ E_{01}^2 + E_{02}^2 + E_{01}E_{02} \left( e^{i(\delta_1 - \delta_2)} + e^{-i(\delta_1 - \delta_2)} \right) \right]$$ Using Euler's identity $e^{i\delta} + e^{-i\delta} = 2\cos \delta$, and defining the phase difference $\delta = \delta_2 - \delta_1$: $$I = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos \delta$$ where $I_1 = \frac{1}{2} E_{01}^2$ and $I_2 = \frac{1}{2} E_{02}^2$ are the intensities of the independent beams. The term $J_{12} = 2\sqrt{I_1 I_2} \cos \delta$ is the **Interference Term**.4. Conditions for Sustained, High-Contrast Interference
For stable, observable interference fringes to persist in space and time:- Monochromaticity & Frequency Matching: The interfering beams must possess identical or nearly identical frequencies ($\omega_1 = \omega_2$). If frequencies differ by $\Delta \omega$, the cross term oscillates at $\cos(\Delta \omega \cdot t)$ and time-averages to zero.
- Constant Phase Relationship (Coherence): The relative phase difference $\delta$ must remain strictly invariant over the observation time interval $T_{\text{obs}} \gg \tau_c$, where $\tau_c$ is the coherence time of the source.
- Parallel Polarization Vectors: If the electric fields are orthogonal ($\mathbf{E}_1 \perp \mathbf{E}_2$), their scalar product vanishes: $\mathbf{E}_1 \cdot \mathbf{E}_2 = 0$, giving $I = I_1 + I_2$ with zero interference modulation (Fresnel-Arago Law 1).
- Equal Amplitudes ($I_1 \approx I_2$): When $I_1 = I_2 = I_0$, the fringe visibility (contrast) reaches its theoretical maximum of unity: $$\mathcal{V} = \frac{I_{\text{max}} - I_{\text{min}}}{I_{\text{max}} + I_{\text{min}}} = \frac{4I_0 - 0}{4I_0 + 0} = 1$$ $$I(\delta) = 4I_0 \cos^2\left(\frac{\delta}{2}\right)$$
§1.2Young’s Double-Slit Experiment, Hyperbolic Fringes and Intensity Distribution
1. Geometric Path Difference Derivation
Let two parallel slits separated by center-to-center distance $d$ illuminate a screen placed at distance $D$, where $D \gg d$. Let the origin $O$ be the center of the screen, and let $P$ be a point on the screen at distance $y$ from $O$. The physical paths traveled by the two wavelets from slits $S_1(0, d/2)$ and $S_2(0, -d/2)$ to $P(D, y)$ are: $$r_1 = \sqrt{D^2 + \left(y - \frac{d}{2}\right)^2} = D \left[ 1 + \frac{\left(y - d/2\right)^2}{D^2} \right]^{1/2}$$ $$r_2 = \sqrt{D^2 + \left(y + \frac{d}{2}\right)^2} = D \left[ 1 + \frac{\left(y + d/2\right)^2}{D^2} \right]^{1/2}$$ Applying the binomial expansion $(1 + u)^{1/2} = 1 + \frac{1}{2}u - \dots$ for $y, d \ll D$: $$r_1 \approx D + \frac{(y - d/2)^2}{2D}, \quad r_2 \approx D + \frac{(y + d/2)^2}{2D}$$ The optical path difference $\Delta = r_2 - r_1$ is: $$\Delta = \frac{(y + d/2)^2 - (y - d/2)^2}{2D} = \frac{2yd}{2D} = \frac{y d}{D}$$ In angular coordinates where $\theta$ is the angle subtended at the slit midpoint: $\sin \theta \approx \tan \theta = \frac{y}{D}$, yielding: $$\Delta = d \sin \theta$$2. Constructive and Destructive Interference Conditions
The corresponding optical phase difference is: $$\delta = \frac{2\pi}{\lambda} \Delta = \frac{2\pi d y}{\lambda D}$$- Bright Fringes (Intensity Maxima): Occur when the path difference is an integer multiple of the wavelength: $$\Delta = m \lambda \implies y_m = m \frac{\lambda D}{d}, \quad m \in \{0, \pm 1, \pm 2, \dots\}$$
- Dark Fringes (Intensity Minima): Occur when the path difference is a half-integral multiple of the wavelength: $$\Delta = \left(m + \frac{1}{2}\right) \lambda \implies y_m' = \left(m + \frac{1}{2}\right) \frac{\lambda D}{d}, \quad m \in \{0, \pm 1, \pm 2, \dots\}$$
3. Linear Fringe Width (Fringe Spacing) $\beta$
The distance between any two consecutive bright or dark fringes is constant: $$\beta = y_{m+1} - y_m = \frac{(m+1)\lambda D}{d} - \frac{m\lambda D}{d} = \frac{\lambda D}{d}$$ This equation provides a direct, high-precision laboratory method for measuring the optical wavelength $\lambda = \frac{\beta d}{D}$.4. 3D Spatial Fringe Shape: Hyperboloids of Revolution
The locus of all points in 3D space with a constant path difference from two point sources $S_1$ and $S_2$ is defined by: $$|r_2 - r_1| = \text{constant} = m\lambda$$ By classical analytic geometry, this is the definition of a **hyperboloid of two sheets** having $S_1$ and $S_2$ as foci. When intercepted by a flat planar screen placed perpendicular to the central axis at $x = D$, the intersection of these hyperboloids with the plane $x = D$ produces narrow hyperbolic curves. Near the central axis ($y, z \ll D$), the vertices of these hyperbolas have extremely small curvature, appearing to high precision as straight, equispaced parallel interference fringes.§1.3Fresnel’s Biprism: Virtual Coherent Sources and Wavelength Determination
1. Optical Construction and Refraction by Biprism
A Fresnel biprism consists of two acute prisms joined at their bases, with an obtuse angle of approximately $179^{\circ}$ and two very small refracting angles $\alpha \approx 30' \approx 0.5^{\circ}$. A narrow monochromatic slit $S$ illuminated by wavelength $\lambda$ is placed at distance $u$ in front of the flat face of the biprism. Light passing through the upper half is deviated downwards by angle $\delta$, while light passing through the lower half is deviated upwards by the identical angle $\delta$. For a thin prism of refractive index $n$ and refracting angle $\alpha$, the angle of minimum deviation is: $$\delta = (n - 1)\alpha$$2. Separation Between Virtual Coherent Sources $d$
Due to refraction, the light appears to diverge from two virtual point sources $S_1$ and $S_2$ located in the plane of the original slit $S$: $$d = 2 u \delta = 2 u (n - 1) \alpha$$ Because both $S_1$ and $S_2$ originate from the same primary wavefront of slit $S$, they maintain strict mutual phase coherence.3. Fringe Width and Screen Separation
Let the distance from the slit $S$ to the micrometer eyepiece (screen) be $D$. The fringe width on the observation plane is given by the standard interference relation: $$\beta = \frac{\lambda D}{d} = \frac{\lambda D}{2 u (n - 1) \alpha}$$4. The Displacement Method for Direct Measurement of $d$
Direct physical measurement of the virtual distance $d$ (which is on the order of $0.5 - 2 \text{ mm}$) introduces significant experimental error. Fresnel solved this by inserting a convex lens between the biprism and the eyepiece. For a fixed distance $D > 4f$, there exist two conjugate positions of the convex lens that produce sharp real images of $S_1$ and $S_2$ in the focal plane of the micrometer eyepiece:- Position 1 (Magnified image separation $d_1$): $m_1 = \frac{v_1}{u_1} = \frac{d_1}{d}$
- Position 2 (Diminished image separation $d_2$): $m_2 = \frac{v_2}{u_2} = \frac{d_2}{d}$
§1.4Lloyd’s Mirror: Grazing Incidence and the Fundamental Half-Wave (\pi) Phase Shift
1. Experimental Geometry and Ray Tracing
A monochromatic primary point source $S_1$ of wavelength $\lambda$ is placed at a very small height $h$ above the plane of an optical flat front-surface mirror of length $L$. A screen is placed at distance $D$ perpendicular to the mirror plane. Light from $S_1$ propagates to the screen via two paths:- Direct Wave: Propagates directly from $S_1$ to the screen at height $y$.
- Reflected Wave: Strikes the mirror at grazing incidence and reflects to the screen, appearing to originate from the virtual mirror image $S_2$ located at depth $h$ below the mirror surface.
2. The Crucial Half-Wave Phase Discontinuity ($\pi$ Phase Jump)
From Maxwell's electromagnetic boundary conditions (Fresnel reflection equations), when an optical wave traveling in an optically rarer medium ($n_1 = 1$) reflects at the boundary of a denser medium ($n_2 > 1$) at grazing incidence (angle of incidence $\theta_i \to 90^{\circ}$): $$r_{\perp} = \frac{\cos \theta_i - \sqrt{n^2 - \sin^2 \theta_i}}{\cos \theta_i + \sqrt{n^2 - \sin^2 \theta_i}} \xrightarrow{\theta_i \to 90^{\circ}} -1 = e^{i\pi}$$ This reflection introduces an abrupt, non-geometric phase discontinuity of exactly $\pi$ radians (equivalent to an optical path penalty of $\frac{\lambda}{2}$). The net optical path difference between the reflected and direct waves arriving at height $y$ is: $$\Delta_{\text{net}} = (r_2 - r_1) + \frac{\lambda}{2} = \frac{y d}{D} + \frac{\lambda}{2}$$3. Inversion of Interference Conditions
Setting $\Delta_{\text{net}}$ equal to integral and half-integral multiples of $\lambda$:- Dark Fringes (Destructive Interference): $$\frac{y d}{D} + \frac{\lambda}{2} = \left(m + \frac{1}{2}\right)\lambda \implies y_m = m \frac{\lambda D}{d}, \quad m \in \{0, 1, 2, \dots\}$$
- Bright Fringes (Constructive Interference): $$\frac{y d}{D} + \frac{\lambda}{2} = m\lambda \implies y_m' = \left(m - \frac{1}{2}\right) \frac{\lambda D}{d}, \quad m \in \{1, 2, 3, \dots\}$$
4. The Vanishing Central Fringe at the Mirror Edge
At the point of grazing contact with the mirror surface ($y = 0$), the geometric path difference vanishes: $r_2 - r_1 = 0$. In standard Young's double-slit interference, $y = 0$ corresponds to the central **bright** maximum. However, in Lloyd's mirror, due to the $-\pi$ phase jump on reflection: $$\Delta_{\text{net}}(y=0) = 0 + \frac{\lambda}{2} = \frac{\lambda}{2} \implies I(y=0) = 0$$ Thus, the central fringe in Lloyd's mirror is **strictly dark**. When white light is used, the central fringe is completely achromatic and jet black, unambiguously proving that reflection from a denser medium induces a phase change of $\pi$ radians.📝 Chapter Worked Examples & Exercises
Complete derivations & analytical proofsThe lens magnification at conjugate positions satisfies $m_1 m_2 = 1$, making the geometric mean of the two image separations equal to the true separation of the virtual sources.
Each fringe pair occupies exactly $0.2245\text{ mm}$ on the eyepiece focal plane.
Over a $1.5\text{ cm}$ field of view, 66 bright interference bands are resolved.
The medium slows the phase velocity to $c/\mu$, adding an optical distance $(\mu - 1)t$ to the traversed arm.
The number of shifted fringes $n$ depends purely on the extra optical path divided by the wavelength.
The mica sheet has a physical thickness of $13.28$ micrometers.