Unit 3: Classification and Canonical Reduction of Second-Order Linear PDEs
Comprehensive classification theory for second-order linear partial differential equations in two independent variables: the characteristic quadratic form and invariance of the discriminant Delta = B^2 - AC, canonical reduction of Hyperbolic equations to wave-like forms, Parabolic equations to diffusion forms, Elliptic equations to Laplace-Poisson forms, and variable-coefficient mixed-type equations exemplified by Tricomi's equation.
§3.1 General Second-Order Linear PDE: The Discriminant Δ = B² - AC
1. General Form of Second-Order Equations
The most general second-order linear (or semilinear) partial differential equation in two independent variables $(x, y)$ is:
where $A, B, C, D, E, F, G$ are real-valued continuous functions on a domain $\Omega \subseteq \mathbb{R}^2$, with $A^2 + B^2 + C^2 \ne 0$. (Note: The convention $2B$ is standard in academic mathematics so that the discriminant takes the clean form $\Delta = B^2 - AC$).
The principal part containing the highest-order derivatives is the differential operator:
Associated with $\mathcal{L}_0$ is the characteristic polynomial (quadratic form) in variables $(\xi_1, \xi_2)$:
2. Classification Criteria
Definition 3.1 (Discriminant and PDE Classification): The discriminant (or indicator) of the second-order equation is defined at each point $(x, y) \in \Omega$ by:
The PDE is classified at $(x, y)$ as:
- Hyperbolic if $\Delta(x, y) > 0$ (analogous to the hyperbola $B^2 - AC > 0$).
- Parabolic if $\Delta(x, y) = 0$ (analogous to the parabola $B^2 - AC = 0$).
- Elliptic if $\Delta(x, y) < 0$ (analogous to the ellipse $B^2 - AC < 0$).
If an equation retains the same type at all points of $\Omega$, it is of pure type; if $\Delta(x, y)$ changes sign across $\Omega$, it is of mixed type.
3. Coordinate Invariance of the Discriminant
Let $(\xi, \eta) = (\phi(x, y), \psi(x, y))$ be a non-singular $C^2$ change of variables with non-vanishing Jacobian:
By the multivariable chain rule:
Differentiating again:
Substituting into the PDE yields the transformed equation in coordinates $(\xi, \eta)$:
where the new coefficients of the principal part are:
Theorem 3.1 (Discriminant Invariance Theorem): Under any smooth non-singular coordinate transformation, the transformed discriminant satisfies:
Since $J \ne 0$, $J^2 > 0$; therefore, the sign of the discriminant is an absolute geometric invariant of the PDE.
Proof: Express the transformation in matrix form:
where $M = \begin{pmatrix} \xi_x & \xi_y \\ \eta_x & \eta_y \end{pmatrix}$ and $K = \begin{pmatrix} A & B \\ B & C \end{pmatrix}$. Taking the determinant of both sides:
Evaluating the determinants:
Multiplying by $-1$:
Since $J^2 > 0$, $\operatorname{sgn}(\Delta^*) = \operatorname{sgn}(\Delta)$. $\blacksquare$
§3.2 Hyperbolic Equations: Real Characteristics & Canonical Form
1. Characteristic Equations for Hyperbolic PDEs
For a hyperbolic PDE, $\Delta = B^2 - AC > 0$. We seek coordinates $(\xi, \eta)$ such that the diagonal second-derivative terms vanish:
Recall that:
Dividing by $\xi_y^2$ (assuming $\xi_y \ne 0$):
Along any level curve $\xi(x, y) = \text{constant}$, implicit differentiation gives $\frac{dy}{dx} = -\frac{\xi_x}{\xi_y}$. Thus, the curve $y = y(x)$ satisfies the characteristic ODE:
Solving for the characteristic slopes $\frac{dy}{dx}$:
Since $B^2 - AC > 0$, there exist two distinct families of real characteristic curves:
2. The Two Canonical Forms of Hyperbolic PDEs
Canonical Form 1 (D'Alembert Cross-Derivative Form):
Setting $\xi = \phi(x, y)$ and $\eta = \psi(x, y)$ forces $A^ = 0$ and $C^ = 0$. Dividing through by $2B^* \ne 0$, the PDE reduces to:
Canonical Form 2 (Wave Operator Form):
Introducing the rotated coordinates:
We have:
The cross-derivative transforms into:
Thus, the equation becomes the standard 1D wave operator:
§3.3 Parabolic Equations: Single Family of Characteristics & Canonical Form
1. Characteristic Degeneracy in Parabolic PDEs
For a parabolic PDE, the discriminant vanishes identically:
The characteristic equation:
has equal roots:
Therefore, there exists only one real family of characteristic curves:
This single family leaves $A^* = 0$. Furthermore, since $\Delta^ = (B^)^2 - A^ C^ = J^2 \Delta = 0$, having $A^* = 0$ immediately forces:
Both $A^$ and $B^$ vanish automatically!
2. Reduction to Canonical Form
To complete the transformation, we choose the second coordinate $\eta = \psi(x, y)$ as any arbitrary smooth function that is functionally independent of $\xi$, ensuring $J \ne 0$. (A convenient choice is often $\eta = x$ or $\eta = y$). Since $A^ = 0$ and $B^ = 0$, while $C^ \ne 0$ (otherwise $J$ would vanish), dividing by $C^$ yields:
Theorem 3.2 (Parabolic Canonical Form): Every parabolic equation can be reduced to the canonical form:
If $\Phi$ contains $u_\xi$ with non-zero coefficient, dividing produces the standard heat/diffusion form:
§3.4 Elliptic Equations: Complex Characteristics & Laplace Canonical Form
1. Complex Characteristics for Elliptic PDEs
For an elliptic PDE, $\Delta = B^2 - AC < 0$. The characteristic equation:
has no real roots. Instead, it yields two complex conjugate characteristic slopes:
Integrating these gives complex conjugate first integrals:
2. Real Canonical Reduction to Laplace Form
If we were to use the complex coordinates $\tilde{\xi} = \phi + i\psi$ and $\tilde{\eta} = \phi - i\psi$, the equation would reduce to $u_{\tilde{\xi}\tilde{\eta}} = \dots$, but the coordinates would be complex. To obtain a real canonical form, we define the real transformation:
By the chain rule relating $(\tilde{\xi}, \tilde{\eta})$ to $(\xi, \eta)$:
Thus, in the real coordinates $(\xi, \eta)$, the equation reduces to:
Theorem 3.3 (Elliptic Canonical Form): Every elliptic second-order linear PDE can be transformed into the canonical form:
which is the classical Laplace / Poisson operator $\nabla^2 u = \Phi$.
§3.5 Second-Order PDEs with Variable Coefficients: The Tricomi Equation
1. Equations of Mixed Type
When the coefficients $A(x, y), B(x, y), C(x, y)$ depend on position, the sign of the discriminant $\Delta(x, y) = B^2 - AC$ may vary across the domain, producing equations of mixed type. The boundary curve separating different types is the parabolic transition curve where $\Delta(x, y) = 0$.
2. The Tricomi Equation
The most celebrated mixed-type PDE in mathematical physics is the Tricomi equation, introduced by Francesco Tricomi in 1923 to model transonic fluid flow (aerodynamics near Mach 1):
Here $A = y, B = 0, C = 1$. The discriminant is:
Classification of Tricomi's Equation:
- In the upper half-plane $y > 0$: $\Delta = -y < 0 \implies$ Elliptic (subsonic flow, $M < 1$).
- Along the line $y = 0$: $\Delta = 0 \implies$ Parabolic (sonic transition line, $M = 1$).
- In the lower half-plane $y < 0$: $\Delta = -y > 0 \implies$ Hyperbolic (supersonic flow, $M > 1$).
Canonical Reduction in the Hyperbolic Half-Plane ($y < 0$):
The characteristic ODE is:
Taking the square root:
Integrating:
Thus, the two real characteristic coordinates are:
In these coordinates, Tricomi's equation reduces to the Euler-Poisson-Darboux form:
Notice the characteristic curves are semi-cubical parabolas with cusps touching the sonic line $y = 0$!
Rigorous Tiered Solved Examination Problems
Step-by-step unskipped derivations, complete proofs, and verification across Foundational, Advanced, and Honors tiers.
Classify the following partial differential equation and reduce it to its canonical form:
Determine its general solution.
1. Classification
The PDE is $A u_{xx} + 2B u_{xy} + C u_{yy} = 0$ where:
The discriminant is:
Since $\Delta > 0$, the equation is strictly Hyperbolic.
2. Characteristic Slopes and Coordinates
The characteristic ODE is:
This yields two characteristic slopes:
- $\frac{dy}{dx} = -1 \implies dy + dx = 0 \implies y + x = c_1 \implies \xi = y + x$
- $\frac{dy}{dx} = -3 \implies dy + 3dx = 0 \implies y + 3x = c_2 \implies \eta = y + 3x$
3. Coordinate Transformation
Let $\xi = x + y$ and $\eta = 3x + y$. Compute partial derivatives via the chain rule:
Now compute the second derivatives:
- $u_{xx} = (\partial_\xi + 3\partial_\eta)^2 u = u_{\xi\xi} + 6u_{\xi\eta} + 9u_{\eta\eta}$
- $u_{xy} = (\partial_\xi + 3\partial_\eta)(\partial_\xi + \partial_\eta) u = u_{\xi\xi} + 4u_{\xi\eta} + 3u_{\eta\eta}$
- $u_{yy} = (\partial_\xi + \partial_\eta)^2 u = u_{\xi\xi} + 2u_{\xi\eta} + u_{\eta\eta}$
Substitute into the original equation $u_{xx} - 4u_{xy} + 3u_{yy}$:
- Coefficient of $u_{\xi\xi}$: $1 - 4(1) + 3(1) = 0$
- Coefficient of $u_{\eta\eta}$: $9 - 4(3) + 3(1) = 9 - 12 + 3 = 0$
- Coefficient of $u_{\xi\eta}$: $6 - 4(4) + 3(2) = 6 - 16 + 6 = -4$
Thus:
This is the canonical form.
4. General Solution
Integrating $\frac{\partial}{\partial \xi}\left(\frac{\partial u}{\partial \eta}\right) = 0$ with respect to $\xi$:
Integrating with respect to $\eta$:
Substituting back $\xi = x + y$ and $\eta = 3x + y$:
where $f$ and $G$ are arbitrary twice-differentiable functions. $\blacksquare$
Classify the variable-coefficient partial differential equation:
in the first quadrant $x > 0, y > 0$, reduce it to canonical form, and find its general solution.
1. Classification
Here $A(x, y) = x^2, B(x, y) = 0, C(x, y) = -y^2$. The discriminant is:
Since $x > 0$ and $y > 0$, $\Delta = x^2 y^2 > 0$ strictly. The equation is Hyperbolic throughout the entire first quadrant.
2. Characteristic Slopes and Coordinates
The characteristic equation is:
Separating variables:
- $\frac{dy}{y} = \frac{dx}{x} \implies \ln y - \ln x = c_1 \implies \frac{y}{x} = C_1 \implies \xi = \frac{y}{x}$
- $\frac{dy}{y} = -\frac{dx}{x} \implies \ln y + \ln x = c_2 \implies x y = C_2 \implies \eta = x y$
3. Coordinate Transformation to Canonical Form
Let $\xi = y/x$ and $\eta = xy$. Compute partial derivatives:
By the chain rule:
Substitute into $x^2 u_{xx} - y^2 u_{yy}$:
Subtracting:
Dividing by $-4\xi\eta$ (since $\xi > 0, \eta > 0$):
This is the canonical form.
4. General Solution
Let $v = \frac{\partial u}{\partial \xi}$. The canonical equation becomes a first-order separable ODE for $v$ with respect to $\eta$:
Integrating with respect to $\eta$:
Since $v = u_\xi$:
Integrating with respect to $\xi$:
Substitute back $\xi = y/x$ and $\eta = xy$:
where $f$ and $\psi$ are arbitrary $C^2$ functions. $\blacksquare$
Consider Tricomi's equation of mixed type:
- For $y < 0$ (the hyperbolic half-plane), derive the characteristic coordinates and reduce the equation to the Euler-Poisson-Darboux canonical form.
- For $y > 0$ (the elliptic half-plane), determine the canonical transformation to the Laplace form.
- Prove that the characteristic curves in the hyperbolic region form semi-cubical parabolas that terminate tangentially on the parabolic sonic line $y = 0$.
1. Canonical Reduction in the Hyperbolic Region ($y < 0$)
Here $A = y < 0, B = 0, C = 1$. The discriminant is $\Delta = -y > 0$. The characteristic ODE is:
Taking the square root:
Integrate both sides:
Define the characteristic coordinates:
Notice that:
Compute partial derivatives:
Now evaluate $u_{xx}$ and $u_{yy}$:
Substitute into $y u_{xx} + u_{yy}$:
The terms $y u_{\xi\xi}$ and $y u_{\eta\eta}$ cancel completely!
Dividing by $4y = -4(-y)$:
Since $(-y)^{3/2} = \frac{3}{4}(\eta - \xi)$:
This is the celebrated Euler-Poisson-Darboux form.
2. Canonical Reduction in the Elliptic Region ($y > 0$)
Here $\Delta = -y < 0$. The characteristic ODE is:
Define real coordinates:
Then $\beta_y = y^{1/2}$ and $\beta_{yy} = \frac{1}{2}y^{-1/2}$. We have $u_{xx} = u_{\alpha\alpha}$ and:
Substitute into $y u_{xx} + u_{yy} = 0$:
Dividing by $y$:
This is the canonical elliptic form, equivalent to an axisymmetric Laplace equation in 5 dimensions!
3. Geometry of Characteristic Cusps
In the hyperbolic region, the characteristic curves satisfy:
As $y \to 0^-$, $x \to c$. The slope of the characteristic curve is:
Thus, every characteristic curve approaches the sonic line $y = 0$ vertically, forming a semi-cubical cuspidal edge tangent to the normal of the sonic line! $\blacksquare$