Unit 7: Boundary Value Problems with Cylindrical & Spherical Symmetry: Special Functions
Advanced boundary value problems in curvilinear geometries: derivation of the Laplacian in cylindrical and spherical coordinate systems, Bessel's differential equation and Frobenius series solutions for J_n(x) and Y_n(x), vibrations of circular drumhead membranes and transient radial heat conduction in solid cylinders, Legendre's differential equation and orthogonal Legendre polynomials P_n(cos θ), and multipole expansions in spherical harmonics.
§7.1 Orthogonal Curvilinear Coordinates: Cylindrical & Spherical Laplacians
1. General Metric Scale Factors
Let $(u_1, u_2, u_3)$ be an orthogonal curvilinear coordinate system related to Cartesian coordinates $(x, y, z)$. The differential displacement vector is:
where the scale factors (Lamé coefficients) are:
The gradient of a scalar field $\psi$ is:
The divergence of a vector field $\mathbf{A} = A_1 \hat{\mathbf{e}}_1 + A_2 \hat{\mathbf{e}}_2 + A_3 \hat{\mathbf{e}}_3$ is:
Combining $\nabla \cdot (\nabla \psi)$ gives the universal Laplacian in orthogonal curvilinear coordinates:
2. Cylindrical Coordinates $(r, \theta, z)$
The coordinates are $x = r\cos\theta, y = r\sin\theta, z = z$. The scale factors are:
Applying the Laplacian formula:
The Cylindrical Laplacian:
3. Spherical Coordinates $(r, \theta, \phi)$
The coordinates are $x = r\sin\theta\cos\phi, y = r\sin\theta\sin\phi, z = r\cos\theta$ (where $\theta$ is the polar colatitude and $\phi$ is the azimuthal longitude). The scale factors are:
The Spherical Laplacian:
§7.2 Bessel's Equation & Bessel Functions Jn, Yn
1. Separation of Variables in Cylindrical Geometry
Consider the Helmholtz eigenvalue equation $\nabla^2 u + \lambda u = 0$ in polar coordinates $(r, \theta)$. Assume $u(r, \theta) = R(r) \Theta(\theta)$:
Dividing by $R \Theta$ and multiplying by $r^2$:
Multiplying out the radial part:
Let $x = \sqrt{\lambda} r$. By the chain rule, this reduces to Bessel's Differential Equation of order $m$:
2. Series Solution via the Frobenius Method
Since $x = 0$ is a regular singular point, assume a generalized power series $R(x) = \sum_{k=0}^\infty c_k x^{k+s}$. The indicial equation is $s(s-1) + s - m^2 = 0 \implies s^2 - m^2 = 0 \implies s = \pm m$. For $s = +m$:
Definition 7.1 (Bessel Function of the First Kind $J_m(x)$):
The series converges absolutely and uniformly for all $x \in \mathbb{C}$.
- $J_0(0) = 1$, and $J_m(0) = 0$ for all $m \ge 1$.
- As $x \to \infty$, $J_m(x)$ behaves asymptotically as an oscillating decaying cosine wave:
Definition 7.2 (Bessel Function of the Second Kind $Y_m(x)$ / Weber Function): The second linearly independent solution is defined for non-integer $\nu$ by:
and for integer $m$ by the limit $Y_m(x) = \lim_{\nu \to m} Y_\nu(x)$. Crucially, as $x \to 0^+$, $Y_m(x)$ diverges logarithmically:
Therefore, for any physical domain containing the center axis $r = 0$, $Y_m$ must be rejected, retaining only $J_m$.
§7.3 Circular Drumhead Vibrations & Radial Cylindrical Diffusion
1. Vibrations of an Elastic Circular Drumhead
Consider a circular membrane of radius $a$ clamped at its boundary $r = a$:
Separating variables $u(r, \theta, t) = R(r) \Theta(\theta) T(t)$ yields:
- $\Theta_m(\theta) = A_m \cos(m\theta) + B_m \sin(m\theta)$ ($m = 0, 1, 2, \dots$)
- $R_m(r) = J_m(k r)$, where the boundary condition requires:
where $\alpha_{m,n}$ is the $n$-th positive zero of $J_m(x)$.
- The natural circular frequencies are:
Theorem 7.1 (Eigenmode Structure): Each normal mode $(m, n)$ of the vibrating circular membrane is given by:
The nodal lines where $u_{m,n} = 0$ at all times consist of:
- $m$ Nodal Diameters where $\cos(m\theta) = 0$.
- $n - 1$ Internal Nodal Circles where $r = \frac{\alpha_{m,k}}{\alpha_{m,n}} a$ for $k = 1, \dots, n - 1$ (plus the rim $r = a$).
§7.4 Spherical Symmetry: Legendre's Differential Equation & Polynomials
1. Axisymmetric Laplace Equation in Spherical Coordinates
When a physical potential possesses azimuthal symmetry around the $z$-axis (no dependence on $\phi$), Laplace's equation in spherical coordinates reduces to:
Assume a product solution $u(r, \theta) = R(r) \Theta(\theta)$:
2. Legendre's Differential Equation
Consider the angular ODE:
Substitute the variable $\xi = \cos\theta$ (where $\xi \in [-1, 1]$ as $\theta \in [0, \pi]$). Then $\frac{d\xi}{d\theta} = -\sin\theta$ and $\sin^2\theta = 1 - \xi^2$. The chain rule gives:
Substituting into the angular equation:
This is Legendre's Differential Equation.
Theorem 7.2 (Quantization of $\lambda$ and Legendre Polynomials): Solutions to Legendre's equation that remain finite and non-singular at both poles $\theta = 0$ ($\xi = 1$) and $\theta = \pi$ ($\xi = -1$) exist if and only if the separation constant is quantized as:
Under this quantization, the bounded solutions are the Legendre Polynomials $P_n(\xi)$:
- $P_0(\xi) = 1$
- $P_1(\xi) = \xi = \cos\theta$
- $P_2(\xi) = \frac{1}{2}(3\xi^2 - 1) = \frac{1}{2}(3\cos^2\theta - 1)$
- $P_3(\xi) = \frac{1}{2}(5\xi^3 - 3\xi) = \frac{1}{2}(5\cos^3\theta - 3\cos\theta)$
Definition 7.3 (Rodrigues' Formula):
§7.5 Multipole Expansions & Orthogonality in Spherical Harmonics
1. Orthogonality of Legendre Polynomials
Theorem 7.3 (Orthogonality Relation): On the interval $[-1, 1]$, the Legendre polynomials form a complete orthogonal set with respect to unit weight:
In terms of colatitude $\theta$:
2. Radial Solutions and General Axisymmetric Potential
For $\lambda = n(n + 1)$, the radial ODE is:
This is an Euler-Cauchy ODE with trial solutions $R(r) = r^\gamma$:
The roots are $\gamma = n$ and $\gamma = -(n + 1)$. Thus:
Theorem 7.4 (General Axisymmetric Harmonic Potential): Any axisymmetric solution to Laplace's equation $\nabla^2 u = 0$ in spherical coordinates is represented by:
- For interior problems (containing origin $r = 0$), all $B_n = 0$.
- For exterior problems (bounded as $r \to \infty$), all $A_n = 0$ (except possibly $A_0$ for potential at infinity).
3. Generating Function and Multipole Expansion
The generating function for Legendre polynomials is:
In electrostatics, the potential of a point charge $q$ at $\mathbf{r}' = (0, 0, d)$ observed at $\mathbf{r} = (r, \theta, \phi)$ with $r > d$ is:
- $n = 0$: Monopole potential $\propto 1/r$.
- $n = 1$: Dipole potential $\propto d\cos\theta / r^2$.
- $n = 2$: Quadrupole potential $\propto d^2 P_2(\cos\theta) / r^3$.
Rigorous Tiered Solved Examination Problems
Step-by-step unskipped derivations, complete proofs, and verification across Foundational, Advanced, and Honors tiers.
A long solid cylinder of radius $a$ and thermal diffusivity $\alpha$ initially has uniform temperature $T_0$. At $t = 0$, its outer surface $r = a$ is plunged into an ice bath held at zero temperature:
Assuming no dependence on $\theta$ or $z$:
- Set up the radial initial-boundary value problem.
- Find the complete Fourier-Bessel series solution $u(r, t)$.
- Determine the temperature at the center axis $r = 0$ as a function of time.
1. Radial Initial-Boundary Value Problem
The heat equation in axisymmetric cylindrical coordinates is:
subject to:
- Boundary condition: $u(a, t) = 0$
- Regularity condition: $|u(0, t)| < \infty$
- Initial condition: $u(r, 0) = T_0$ for $0 \le r < a$.
2. Separation of Variables and Bessel Expansion
Separating variables $u(r, t) = R(r) T(t)$:
- Radial equation: $r^2 R'' + r R' + k^2 r^2 R = 0$.
The general solution is $R(r) = C_1 J_0(k r) + C_2 Y_0(k r)$. Since $Y_0(k r) \to -\infty$ as $r \to 0$, regularity forces $C_2 = 0$. Thus $R(r) = J_0(k r)$. Boundary condition at $r = a$:
where $\alpha_{0,m}$ are the positive roots of $J_0(x) = 0$.
- Temporal ODE: $T_m'(t) + \alpha k_m^2 T_m(t) = 0 \implies T_m(t) = \exp\left( -\alpha \left(\frac{\alpha_{0,m}}{a}\right)^2 t \right)$.
The general solution is:
3. Fourier-Bessel Coefficients
At $t = 0$:
By the orthogonality of Bessel functions with weight $r$:
Using the Bessel recurrence identity $\frac{d}{dx}[x J_1(x)] = x J_0(x)$: Let $\xi = \frac{\alpha_{0,m} r}{a} \implies r = \frac{a}{\alpha_{0,m}}\xi \implies dr = \frac{a}{\alpha_{0,m}}d\xi$.
Substituting into $c_m$:
Therefore, the complete series solution is:
4. Center Temperature ($r = 0$)
Since $J_0(0) = 1$:
For large times, the first root $\alpha_{0,1} \approx 2.4048$ dominates:
$\blacksquare$
A grounded conducting sphere of radius $a$ is placed in an initially uniform electric field $\mathbf{E} = E_0 \hat{\mathbf{z}}$.
- Set up the boundary value problem for the electrostatic potential $\Phi(r, \theta)$ in spherical coordinates.
- Solve for $\Phi(r, \theta)$ for all $r \ge a$ using Legendre polynomials.
- Determine the induced surface charge density $\sigma(\theta)$ on the sphere.
1. Formulation of the Boundary Value Problem
In the vacuum region exterior to the sphere ($r > a$), there is no charge, so $\nabla^2 \Phi = 0$. The problem has azimuthal symmetry around the $z$-axis, so $\Phi = \Phi(r, \theta)$. Boundary conditions:
- Grounded sphere at $r = a$: $\Phi(a, \theta) = 0$.
- Far from the sphere ($r \to \infty$), the potential must approach the uniform field potential:
Thus: $\Phi(r, \theta) \to -E_0 r P_1(\cos\theta)$ as $r \to \infty$.
2. Series Solution via Legendre Polynomials
The general exterior axisymmetric solution to Laplace's equation is:
Matching the asymptotic condition as $r \to \infty$:
- For $n = 1$: $A_1 = -E_0$.
- For all $n \ne 1$: $A_n = 0$ (so the potential does not blow up faster than $r$).
Thus:
Now apply the boundary condition on the grounded sphere $r = a$:
By orthogonality of the Legendre polynomials, coefficients of each $P_n(\cos\theta)$ must vanish:
- For $n = 1$: $-E_0 a + \frac{B_1}{a^2} = 0 \implies B_1 = E_0 a^3$.
- For all $n \ne 1$: $\frac{B_n}{a^{n+1}} = 0 \implies B_n = 0$.
Therefore, the exact potential outside the sphere is:
3. Induced Surface Charge Density
By Gauss's law at a conducting boundary:
Compute the radial derivative:
Evaluating at $r = a$:
Therefore, the induced surface charge density is:
The charge density is positive on the upper hemisphere ($\theta < \pi/2$) and negative on the lower hemisphere ($\theta > \pi/2$), forming an induced dipole moment $\mathbf{p} = 4\pi \epsilon_0 a^3 E_0 \hat{\mathbf{z}}$. $\blacksquare$
Let $J_n(x)$ be the Bessel function of the first kind of integer order $n \ge 0$, and let $\alpha_{n,1} < \alpha_{n,2} < \dots$ denote its consecutive positive zeros.
- Rigorously prove the Sturm-Liouville orthogonality relation:
- Prove the normalization integral formula:
1. Proof of Orthogonality for $k \ne m$
Let $u(r) = J_n\left(\frac{\alpha_{n,k} r}{a}\right)$ and $v(r) = J_n\left(\frac{\alpha_{n,m} r}{a}\right)$, with $\lambda_k = \frac{\alpha_{n,k}^2}{a^2}$ and $\lambda_m = \frac{\alpha_{n,m}^2}{a^2}$. Both functions satisfy Bessel's differential equation in self-adjoint Sturm-Liouville form:
Multiply the first equation by $v$ and the second equation by $u$, and subtract:
Notice that:
Integrating from $r = 0$ to $r = a$:
Evaluating the boundary term:
Since $\alpha_{n,k}$ and $\alpha_{n,m}$ are roots of $J_n$, we have:
Thus the boundary term vanishes identically at both $r = a$ and $r = 0$!
Since $k \ne m$, $\lambda_k \ne \lambda_m$, which forces:
2. Proof of the Normalization Integral
To evaluate the integral when $k = m$, consider Bessel's ODE for $y(r) = J_n(k r)$:
Multiply the entire equation by $2 y'$:
Notice the derivative identities:
- $2 r^2 y' y'' + 2 r (y')^2 = \frac{d}{dr}\left[ r^2 (y')^2 \right]$
- $2 k^2 r^2 y y' = \frac{d}{dr}\left[ k^2 r^2 y^2 \right] - 2 k^2 r y^2$
- $2 n^2 y y' = \frac{d}{dr}\left[ n^2 y^2 \right]$
Substitute these into the equation:
Rearranging to isolate $2 k^2 r y^2$:
Now integrate from $r = 0$ to $r = a$:
At $r = 0$, both terms vanish. At $r = a$, since $k = \alpha_{n,k}/a$, we have $y(a) = J_n(k a) = J_n(\alpha_{n,k}) = 0$. Thus the second term vanishes at $r = a$!
Now compute $y'(a)$:
Using the Bessel recurrence relation $x J_n'(x) = n J_n(x) - x J_{n+1}(x)$: At $x = \alpha_{n,k}$, since $J_n(\alpha_{n,k}) = 0$:
Thus:
Substituting this back into the integrated formula:
Dividing both sides by $2 k^2$: