Plasma as a Fluid: The Dielectric Multi-Fluid Equations & MHD
Macroscopic fluid description of plasma: velocity moments of the Boltzmann equation, continuity equation, momentum balance with pressure tensor and collisional friction, equation of state, the plasma approximation and quasi-neutrality, fluid diamagnetic drift velocity and magnetization current, derivation of single-fluid Magnetohydrodynamics (MHD), generalized Ohm's law, magnetic induction equation, magnetic Reynolds number, Alfvén's magnetic flux-freezing theorem, magnetic pressure and tension, and the plasma beta parameter.
§4.1 Macroscopic Fluid Transition: Velocity Moments of the Kinetic Boltzmann Equation
1. From Microscopic Distribution to Fluid Fields
Tracking $10^{20}$ individual charged particles through single-particle equations of motion is computationally intractable. In the fluid description, we average over velocity space by taking moments of the phase space distribution function $f_\alpha(\vec{r}, \vec{v}, t)$:
$$\langle \chi \rangle_\alpha = \frac{1}{n_\alpha} \int \chi(\vec{v}) f_\alpha(\vec{r}, \vec{v}, t) d^3v$$The fundamental macroscopic fluid variables are:
- Number Density (Zeroth Moment): $$n_\alpha(\vec{r}, t) = \int f_\alpha(\vec{r}, \vec{v}, t) d^3v$$
- Mean Fluid Velocity (First Moment): $$\vec{u}_\alpha(\vec{r}, t) = \langle \vec{v} \rangle = \frac{1}{n_\alpha} \int \vec{v} f_\alpha(\vec{r}, \vec{v}, t) d^3v$$
- Stress Tensor (Second Moment): $$\mathbf{P}_\alpha(\vec{r}, t) = m_\alpha \int (\vec{v} - \vec{u}_\alpha)(\vec{v} - \vec{u}_\alpha) f_\alpha(\vec{r}, \vec{v}, t) d^3v$$
§4.2 Zeroth & First Velocity Moments: Fluid Continuity & Momentum Balance Equations
1. The Continuity Equation (Zeroth Moment)
Integrating the Boltzmann equation over all velocity space $d^3v$:
$$\int \left[ \frac{\partial f_\alpha}{\partial t} + \nabla \cdot (\vec{v} f_\alpha) + \frac{q_\alpha}{m_\alpha}\nabla_v \cdot \left( (\vec{E} + \vec{v}\times\vec{B})f_\alpha \right) \right] d^3v = \int \left( \frac{\partial f_\alpha}{\partial t} \right)_{\text{coll}} d^3v$$Assuming elastic collisions that conserve particle number:
$$\frac{\partial n_\alpha}{\partial t} + \nabla \cdot (n_\alpha \vec{u}_\alpha) = 0$$2. The Fluid Momentum Equation (First Moment)
Multiplying the Boltzmann equation by $m_\alpha \vec{v}$ and integrating over velocity space:
$$m_\alpha n_\alpha \left[ \frac{\partial \vec{u}_\alpha}{\partial t} + (\vec{u}_\alpha \cdot \nabla)\vec{u}_\alpha \right] = q_\alpha n_\alpha (\vec{E} + \vec{u}_\alpha \times \vec{B}) - \nabla \cdot \mathbf{P}_\alpha + \vec{R}_{\alpha\beta}$$where $\vec{R}_{\alpha\beta} = -m_\alpha n_\alpha \nu_{\alpha\beta}(\vec{u}_\alpha - \vec{u}_\beta)$ represents the inter-species collisional frictional drag.
§4.3 Second Velocity Moment, Scalar Pressure Approximations & Polytropic Equations of State
1. Scalar Pressure & The Closure Problem
Each moment equation contains the next higher moment: continuity contains fluid velocity $\vec{u}$, momentum contains the pressure tensor $\mathbf{P}$, and energy contains the heat flux tensor $\vec{Q}$. This is the famous closure problem of kinetic theory.
To close the fluid equations, we assume an isotropic velocity distribution, reducing the stress tensor to a scalar pressure:
$$\mathbf{P}_\alpha = P_\alpha \mathbf{I} \implies \nabla \cdot \mathbf{P}_\alpha = \nabla P_\alpha$$where $P_\alpha = n_\alpha k_B T_\alpha$ is the ideal gas equation of state.
2. Polytropic Equation of State
The thermodynamic response is modeled by the polytropic relation:
$$P_\alpha n_\alpha^{-\gamma} = \text{const} \iff \nabla P_\alpha = \gamma k_B T_\alpha \nabla n_\alpha$$where:
- $\gamma = 1$: Isothermal compression (rapid thermal conduction along field lines).
- $\gamma = 5/3$: Adiabatic compression in 3 dimensions ($C_p / C_v = (d+2)/d = 5/3$).
- $\gamma = 3$: Adiabatic compression in 1 dimension along strong magnetic field lines ($d=1$).
§4.4 The Plasma Approximation: Quasi-Neutrality with Non-Vanishing Electric Fields
1. The Apparent Paradox of Quasi-Neutrality
In fluid plasma physics, we universally employ the plasma approximation:
$$n_e \approx Z n_i \equiv n$$However, Poisson's equation states $\nabla \cdot \vec{E} = \frac{e(n_i - n_e)}{\varepsilon_0}$. If $n_e = n_i$, one might naively conclude that $\nabla \cdot \vec{E} = 0$, implying that electrostatic fields cannot exist inside a plasma!
2. Resolution of the Paradox
The paradox is resolved by recognizing that the fractional charge imbalance $\delta n / n = |n_i - n_e| / n_0$ required to create enormous macroscopic electric fields is vanishingly small:
$$\frac{\delta n}{n_0} = \frac{\varepsilon_0 \nabla \cdot \vec{E}}{e n_0} \sim \frac{\varepsilon_0 (E/L)}{e n_0} \sim \left( \frac{\lambda_D}{L} \right)^2 \ll 1$$Because $\lambda_D / L \sim 10^{-4}$ in typical laboratory plasmas, a fractional charge imbalance of only 1 part in $10^8$ creates millions of volts per meter! Therefore, in the fluid momentum equations we safely set $n_e = n_i = n$ everywhere except inside Poisson's equation itself. In practice, we determine $\vec{E}$ directly from the fluid equations of motion rather than from Poisson's equation.
§4.5 Fluid Drifts: Derivation of the Diamagnetic Drift Velocity v_D and Magnetization Current
1. The Steady-State Perpendicular Fluid Equation
Consider a steady-state ($\partial / \partial t = 0$), low-velocity ($(\vec{u}\cdot\nabla)\vec{u} \approx 0$), collisionless fluid equilibrium in a uniform magnetic field $\vec{B}$:
$$0 = q n (\vec{E} + \vec{u}_\perp \times \vec{B}) - \nabla P$$Taking the vector cross product with $\vec{B}$:
$$q n \vec{E} \times \vec{B} + q n (\vec{u}_\perp \times \vec{B}) \times \vec{B} - \nabla P \times \vec{B} = 0$$Using $(\vec{u}_\perp \times \vec{B}) \times \vec{B} = -B^2 \vec{u}_\perp$ and solving for $\vec{u}_\perp$:
$$\vec{u}_\perp = \frac{\vec{E} \times \vec{B}}{B^2} - \frac{\nabla P \times \vec{B}}{q n B^2} = \vec{v}_E + \vec{v}_D$$2. The Diamagnetic Drift Velocity
The second term is the diamagnetic drift velocity $\vec{v}_D$:
$$\vec{v}_D \equiv -\frac{\nabla P \times \vec{B}}{q n B^2}$$Fundamental properties of diamagnetic drift:
- Not a Single-Particle Guiding Center Drift: Individual guiding centers do not drift with velocity $\vec{v}_D$! $\vec{v}_D$ is a purely macroscopic fluid effect: in the presence of a density or pressure gradient, more particles gyrate across an area element in one direction than in the reverse, resulting in a net fluid flux.
- Charge Dependence: Ions and electrons drift in opposite directions, driving a net macroscopic diamagnetic current $\vec{J}_D$: $$\vec{J}_D = n e (\vec{v}_{Di} - \vec{v}_{De}) = -\frac{(\nabla P_i + \nabla P_e) \times \vec{B}}{B^2} = -\frac{\nabla P \times \vec{B}}{B^2}$$
§4.6 Single-Fluid Ideal Magnetohydrodynamics (MHD): Center-of-Mass Equations & Generalized Ohm's Law
1. Single-Fluid Center-of-Mass Variables
Combining electron and ion fluid equations yields the single-fluid Magnetohydrodynamic (MHD) description:
$$\rho_m \equiv n_i M_i + n_e m_e \approx n M_i, \quad \vec{v} \equiv \frac{M_i \vec{u}_i + m_e \vec{u}_e}{M_i + m_e} \approx \vec{u}_i$$ $$\vec{J} \equiv n e (\vec{u}_i - \vec{u}_e), \quad P \equiv P_i + P_e$$2. The Ideal MHD Equations
Adding the electron and ion momentum equations yields the MHD equation of motion:
$$\rho_m \left[ \frac{\partial \vec{v}}{\partial t} + (\vec{v} \cdot \nabla)\vec{v} \right] = \vec{J} \times \vec{B} - \nabla P$$Subtracting the electron equation from the ion equation (and neglecting small electron inertia terms) yields the generalized Ohm's law:
$$\vec{E} + \vec{v} \times \vec{B} = \eta \vec{J} + \frac{1}{n e}\vec{J}\times\vec{B} - \frac{1}{n e}\nabla P_e$$In ideal MHD, resistivity $\eta \to 0$, Hall effect, and electron pressure gradient terms are neglected, yielding the simple ideal Ohm's law:
$$\vec{E} + \vec{v} \times \vec{B} = 0$$§4.7 The Magnetic Induction Equation, Alfven's Flux-Freezing Theorem & The Plasma Beta
1. The Magnetic Induction Equation
Combining Faraday's law $\frac{\partial \vec{B}}{\partial t} = -\nabla \times \vec{E}$ with Ohm's law $\vec{E} = -\vec{v}\times\vec{B} + \eta \vec{J}$ and Ampère's law $\mu_0 \vec{J} = \nabla \times \vec{B}$:
$$\frac{\partial \vec{B}}{\partial t} = \nabla \times (\vec{v} \times \vec{B}) + \frac{\eta}{\mu_0} \nabla^2 \vec{B}$$The ratio of the convective (advective) term to the resistive diffusion term defines the magnetic Reynolds number $R_m$:
$$R_m \equiv \frac{|\nabla \times (\vec{v}\times\vec{B})|}{|(\eta/\mu_0)\nabla^2\vec{B}|} = \frac{v L}{\eta_m} = \frac{\mu_0 v L}{\eta}$$In high-temperature fusion plasmas and astrophysical systems ($L \sim 10^6\text{ m}$, $T \sim 10^7\text{ K}$), $R_m \gg 10^6$, rendering resistivity entirely negligible.
2. Alfvén's Flux-Freezing Theorem
When $R_m \to \infty$, the magnetic flux $\Phi = \int_S \vec{B}\cdot d\vec{S}$ through any closed fluid contour moving with the plasma velocity $\vec{v}$ is strictly conserved in time:
$$\frac{d\Phi}{dt} = 0$$This is Hannes Alfvén's Flux-Freezing Theorem: the magnetic field lines are "frozen into" the fluid and move synchronously with the plasma.
3. Magnetic Pressure, Magnetic Tension & The Plasma Beta
Using the vector identity $(\nabla \times \vec{B}) \times \vec{B} = (\vec{B}\cdot\nabla)\vec{B} - \nabla(B^2/2)$:
$$\vec{J} \times \vec{B} = \frac{1}{\mu_0}(\nabla \times \vec{B}) \times \vec{B} = -\nabla\left( \frac{B^2}{2\mu_0} \right) + \frac{(\vec{B}\cdot\nabla)\vec{B}}{\mu_0}$$The Lorentz force decomposes into:
- Magnetic Pressure: $P_{\text{mag}} = \frac{B^2}{2\mu_0}$ (isotropic perpendicular expansion force).
- Magnetic Tension: $\frac{(\vec{B}\cdot\nabla)\vec{B}}{\mu_0} = \frac{B^2}{\mu_0}\frac{\hat{R}_c}{R_c}$ (restoring force along curved field lines).
The ratio of thermal kinetic pressure to magnetic pressure is the fundamental plasma beta parameter $\beta$:
$$\beta \equiv \frac{P_{\text{thermal}}}{P_{\text{magnetic}}} = \frac{n k_B(T_e + T_i)}{B^2 / (2\mu_0)} = \frac{2\mu_0 n k_B T}{B^2}$$In tokamaks, $\beta \sim 0.05$ (low-beta magnetically dominated); in the solar photosphere, $\beta \sim 1$; and in the solar wind, $\beta \sim 1\text{ to }10$.
Honors Examination Worked Problems & Solutions
Rigorous step-by-step mathematical proofs and solutions to university degree examination problems.
Consider a slab of collisionless plasma in a uniform magnetic field $\vec{B} = B_0 \hat{z}$, with a density gradient along $\hat{x}$: $n(x) = n_0(1 + x / L_n)$, and uniform isothermal temperature $T_e = T_i = T_0$. (a) Compute the diamagnetic drift velocity $\vec{v}_D$ for electrons and ions. (b) Evaluate the macroscopic diamagnetic current density $\vec{J}_D$. (c) Compute the single-particle guiding center drift velocity $\vec{v}_{\text{gc}}$ and explain why individual guiding centers do not move while the fluid sustains a non-zero current.
(a) Diamagnetic Drift Velocities: The pressure is $P_\alpha(x) = n(x) k_B T_0$. The pressure gradient is:
The diamagnetic drift velocity formula is:
With $\vec{B} = B_0 \hat{z}$:
1. For Ions ($q = +e$):
2. For Electrons ($q = -e$):
Ions drift in the $+\hat{y}$ direction, while electrons drift in the $-\hat{y}$ direction.
(b) Diamagnetic Current Density $\vec{J}_D$:
The net current flows in the $+\hat{y}$ direction.
(c) Single-Particle Guiding Center Drift Comparison: In a spatially uniform magnetic field $\vec{B} = B_0\hat{z}$ with zero electric field ($\vec{E} = 0$):
Therefore, all single-particle guiding center drifts are strictly zero:
Physical Explanation: The individual guiding centers remain completely stationary. The non-vanishing fluid current $\vec{J}_D$ arises entirely because each gyrating particle represents a microscopic magnetic dipole of moment $\vec{\mu} = -\frac{m v_\perp^2}{2 B_0}\hat{z}$. In the presence of a density gradient, the macroscopic magnetization is non-uniform: $\vec{M}(x) = n(x) \langle \vec{\mu} \rangle = -\frac{P(x)}{B_0}\hat{z}$. By Maxwell's equations, a spatially varying magnetization produces a bound magnetization current:
This rigorously proves that the fluid diamagnetic current is identical to the microscopic magnetization current of stationary gyrating orbits.
Complete rigorous derivation and proof detailed above.
Complete rigorous derivation and proof detailed above.
Let $S(t)$ be an open surface bounded by a closed fluid contour $C(t)$ that moves along with the ideal plasma velocity field $\vec{v}(\vec{r}, t)$. The magnetic flux through $S(t)$ is $\Phi(t) = \int_{S(t)} \vec{B}(\vec{r}, t) \cdot d\vec{S}$. (a) Using Leibniz's Reynolds transport theorem for moving surfaces, express the total time derivative $\frac{d\Phi}{dt}$ in terms of $\frac{\partial\vec{B}}{\partial t}$, $\vec{v}$, and $\vec{B}$. (b) Apply Faraday's law of induction and the ideal Ohm's law $\vec{E} + \vec{v}\times\vec{B} = 0$. (c) Prove rigorously that $\frac{d\Phi}{dt} = 0$, and explain the physical consequence for plasma transport across magnetic field lines.
(a) Reynolds Transport Theorem for Magnetic Flux: For a surface $S(t)$ whose boundary contour $C(t)$ moves with velocity $\vec{v}$, the rate of change of flux consists of the intrinsic field variation plus the flux swept out by the moving boundary $d\vec{l} \times (\vec{v} dt)$:
Using the vector scalar triple product identity $\vec{A}\cdot(\vec{B}\times\vec{C}) = -(\vec{B}\times\vec{A})\cdot\vec{C}$:
Substituting this identity:
Applying Stokes' theorem to the closed line integral $\oint_C (\vec{v}\times\vec{B})\cdot d\vec{l} = \int_S [\nabla \times (\vec{v}\times\vec{B})] \cdot d\vec{S}$:
(b) Application of Faraday's Law & Ideal Ohm's Law: From Faraday's law of induction:
In ideal MHD, the electric field is governed by the ideal Ohm's law:
Taking the curl of this electric field:
Substituting into Faraday's law:
(c) Proof and Physical Consequence: Substituting the induction relation into the transport theorem:
This rigorously proves Alfvén's Theorem: the magnetic flux linking any fluid element is strictly invariant in time. Physical Consequence: In an ideal plasma, fluid particles that initially share a given magnetic field line remain permanently tied to that same field line throughout all subsequent motion. Plasma cannot diffuse across magnetic field lines, and magnetic field lines cannot slip through the plasma. Any compression, stretching, or twisting of the fluid forces an identical deformation of the embedded magnetic field lines.
Complete rigorous derivation and proof detailed above.
Complete rigorous derivation and proof detailed above.
A cylindrical plasma column of radius $a$ carries an axial current density $J_z(r) \hat{z}$ that generates an azimuthal magnetic field $B_\theta(r) \hat{\theta}$. The system is in steady-state radial magnetohydrodynamic equilibrium: $\nabla P = \vec{J} \times \vec{B}$. (a) Write down the radial component of the force balance equation in cylindrical coordinates. (b) Multiply by $r^2$ and integrate from $r=0$ to $r=a$ (with $P(a) = 0$) to derive the famous Bennett pinch relation:
where $I$ is the total axial current and $N = \int_0^a 2\pi r n(r) dr$ is the number of particles per unit length. (c) For a fusion Z-pinch with linear density $N = 2.0 \times 10^{19}\text{ m}^{-1}$ and equal temperatures $k_B T_e = k_B T_i = 5.0\text{ keV}$, calculate the critical axial current $I$ required for magnetic self-confinement.
(a) Radial Force Balance Equation: In cylindrical coordinates with radial symmetry, the pressure gradient is $\nabla P = \frac{dP}{dr}\hat{r}$. The current density is $\vec{J} = J_z(r)\hat{z}$, and the magnetic field is $\vec{B} = B_\theta(r)\hat{\theta}$. The Lorentz force is:
The radial force balance $\nabla P = \vec{J}\times\vec{B}$ requires:
From Ampère's law in integral form:
In differential form: $J_z(r) = \frac{1}{\mu_0 r}\frac{d}{dr}(r B_\theta)$. Substituting into force balance:
(b) Derivation of the Bennett Relation: Multiply both sides of $\frac{dP}{dr} = -J_z B_\theta$ by $r^2$ and integrate from $0$ to $a$:
Integrate the left side by parts with $u = r^2, dv = dP$:
At the boundaries, $r=0$ gives zero, and at $r=a$, the plasma pressure vanishes ($P(a) = 0$). Thus:
The total line-integrated thermal energy per unit length is:
Therefore, the left side evaluates to:
Now evaluate the right side: substitute $J_z = \frac{1}{\mu_0 r}\frac{d(r B_\theta)}{dr}$:
At the outer boundary $r = a$, by Ampère's law $2\pi a B_\theta(a) = \mu_0 I \implies a B_\theta(a) = \frac{\mu_0 I}{2\pi}$. Substituting this result:
Equating both sides:
Multiplying by $-8\pi^2 / \mu_0$ yields the famous Bennett pinch relation:
(c) Numerical Calculation of Critical Confinement Current: Given: $N = 2.0 \times 10^{19}\text{ m}^{-1}$ $k_B(T_e + T_i) = 5.0\text{ keV} + 5.0\text{ keV} = 10.0\text{ keV} = 10.0 \times 10^3 \times 1.6022\times 10^{-19}\text{ J} = 1.6022 \times 10^{-15}\text{ J}$ $\mu_0 = 4\pi \times 10^{-7}\text{ H/m}$ Evaluate $I^2$:
Taking the square root:
A tremendous current of approximately 800 kiloamperes is required for the self-induced magnetic field to balance internal thermal pressure.
Complete rigorous derivation and proof detailed above.
Complete rigorous derivation and proof detailed above.