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Chapter 7 • Theory & Derivations

Magnetohydrodynamic Waves & Plasma Instabilities

Comprehensive magnetohydrodynamic wave propagation and macroscopic plasma stability: linearization of the ideal MHD equations, transverse shear Alfvén waves, magnetic tension as an elastic string restoring force, Alfvén velocity, exact magnetic and kinetic energy equipartition, compressional Alfvén waves, fast and slow magnetosonic wave dispersion relations, Friedrichs phase velocity polar diagrams, classification of plasma instabilities, gravitational and acceleration-driven Rayleigh-Taylor instability, magnetic shear stabilization, Kelvin-Helmholtz shear flow instability, and macroscopic tokamak MHD instabilities including sausage, kink, and the Kruskal-Shafranov stability limit.

§7.1 Linearization of the Ideal Magnetohydrodynamic (MHD) Equations

1. The Ideal MHD System

Ideal magnetohydrodynamics treats the plasma as an electrically conducting, magnetized single fluid governed by:

$$\rho_m \left[ \frac{\partial \vec{v}}{\partial t} + (\vec{v}\cdot\nabla)\vec{v} \right] = \vec{J} \times \vec{B} - \nabla P$$ $$\frac{\partial \vec{B}}{\partial t} = \nabla \times (\vec{v} \times \vec{B})$$ $$\frac{\partial \rho_m}{\partial t} + \nabla \cdot (\rho_m \vec{v}) = 0$$ $$\nabla P = c_s^2 \nabla \rho_m, \quad \vec{J} = \frac{1}{\mu_0}\nabla \times \vec{B}, \quad \nabla\cdot\vec{B} = 0$$

where $c_s = \sqrt{\gamma P_0 / \rho_0}$ is the adiabatic sound speed.

2. First-Order Perturbation Expansion

Consider a static, homogeneous equilibrium embedded in a uniform magnetic field:

$$\vec{B} = B_0 \hat{z}, \quad \rho_m = \rho_0, \quad P = P_0, \quad \vec{v}_0 = 0$$

Applying small harmonic perturbations $\propto e^{i(\vec{k}\cdot\vec{r} - \omega t)}$:

$$-i\omega \rho_0 \vec{v}_1 = \frac{1}{\mu_0}(i\vec{k}\times\vec{B}_1)\times\vec{B}_0 - i\vec{k} P_1$$ $$-i\omega \vec{B}_1 = i\vec{k} \times (\vec{v}_1 \times \vec{B}_0)$$ $$-i\omega \rho_1 + i\rho_0 \vec{k}\cdot\vec{v}_1 = 0 \implies P_1 = c_s^2 \rho_1 = \rho_0 c_s^2 \frac{\vec{k}\cdot\vec{v}_1}{\omega}$$

§7.2 Shear Alfvén Waves: Magnetic Tension, Plucked Strings & Alfvén Velocity v_A

1. The Pure Shear Alfvén Wave

Consider incompressible perturbations ($\nabla \cdot \vec{v}_1 = 0 \implies \rho_1 = 0, P_1 = 0$) propagating along the magnetic field with $\vec{k} = k_\parallel \hat{z}$.

Let the fluid velocity perturb along $\hat{x}$: $\vec{v}_1 = v_{1x} \hat{x}$. The induction equation gives:

$$-i\omega \vec{B}_1 = i k_\parallel \hat{z} \times (v_{1x}\hat{x} \times B_0\hat{z}) = i k_\parallel B_0 v_{1x} \hat{x} \implies \vec{B}_1 = -\frac{k_\parallel B_0}{\omega} v_{1x} \hat{x}$$

The linearized momentum equation becomes:

$$-i\omega \rho_0 v_{1x} \hat{x} = \frac{1}{\mu_0}(i k_\parallel \hat{z} \times B_{1x}\hat{x})\times(B_0\hat{z}) = \frac{i k_\parallel B_0}{\mu_0} B_{1x}\hat{x}$$

Substitute $B_{1x} = -\frac{k_\parallel B_0}{\omega} v_{1x}$:

$$-i\omega \rho_0 v_{1x} = \frac{i k_\parallel B_0}{\mu_0}\left( -\frac{k_\parallel B_0}{\omega} v_{1x} \right) = -i \frac{k_\parallel^2 B_0^2}{\mu_0 \omega} v_{1x}$$

Multiplying by $i\omega / (\rho_0 v_{1x})$:

$$\omega^2 = \frac{B_0^2}{\mu_0 \rho_0} k_\parallel^2 \equiv v_A^2 k_\parallel^2$$

where the characteristic propagation speed is the famous Alfvén velocity $v_A$:

$$v_A \equiv \frac{B_0}{\sqrt{\mu_0 \rho_0}}$$

2. The Plucked Magnetic String Analogy

A shear Alfvén wave is the magnetohydrodynamic analog of transverse vibrations on a plucked violin string of tension $T$ and mass per unit length $\mu$: $v = \sqrt{T / \mu}$. In a magnetized plasma:

$$T_{\text{mag}} = \frac{B_0^2}{\mu_0}, \quad \text{Inertia} = \rho_0 \implies v_A = \sqrt{\frac{T_{\text{mag}}}{\rho_0}} = \frac{B_0}{\sqrt{\mu_0 \rho_0}}$$

Magnetic tension provides the restoring force, while fluid mass density $\rho_0$ provides the inertia. Shear Alfvén waves carry magnetic and kinetic energy in exact equipartition: $\frac{1}{2}\rho_0 v_1^2 = \frac{B_1^2}{2\mu_0}$.

§7.3 Compressional Alfvén Waves & Fast/Slow Magnetosonic Waves

1. Compressible Oblique Perturbations

When the fluid is compressible ($ abla \cdot \vec{v}_1 \ne 0$) and the wave propagates at an arbitrary angle $\theta$ relative to $\vec{B}_0$ ($\vec{k} = k_\perp \hat{x} + k_\parallel \hat{z}$, with $\cos\theta = k_\parallel / k$):

Substituting $\vec{B}_1$ and $P_1$ into the momentum equation yields the master MHD wave dispersion relation:

$$\left( \frac{\omega^2}{k^2} - v_A^2 \cos^2\theta \right) \left[ \frac{\omega^4}{k^4} - (v_A^2 + c_s^2)\frac{\omega^2}{k^2} + v_A^2 c_s^2 \cos^2\theta \right] = 0$$

2. The Three Fundamental MHD Modes

  1. Shear Alfvén Wave (Intermediate Mode): $$\frac{\omega^2}{k^2} = v_A^2 \cos^2\theta \implies \omega = k v_A \cos\theta = k_\parallel v_A$$
  2. Fast Magnetosonic Wave: $$\left(\frac{\omega}{k}\right)^2_{\text{fast}} = \frac{1}{2}\left( v_A^2 + c_s^2 + \sqrt{(v_A^2 + c_s^2)^2 - 4 v_A^2 c_s^2 \cos^2\theta} \right)$$
  3. Slow Magnetosonic Wave: $$\left(\frac{\omega}{k}\right)^2_{\text{slow}} = \frac{1}{2}\left( v_A^2 + c_s^2 - \sqrt{(v_A^2 + c_s^2)^2 - 4 v_A^2 c_s^2 \cos^2\theta} \right)$$

The phase velocities satisfy the strict hierarchy:

$$v_{ph,\text{slow}} \le v_{ph,\text{Alfvén}} \le v_{ph,\text{fast}}$$

§7.4 Friedrichs Phase Velocity Diagrams & Magnetosonic Wave Polarization

1. Friedrichs Polar Diagrams

A polar plot of phase velocity $v_{ph}(\theta) = \omega / k$ as a function of propagation angle $\theta$ relative to the magnetic field $\vec{B}_0$ is known as a Friedrichs diagram:

  • Shear Alfvén Wave: Traces two tangent circles touching at the origin along the magnetic field axis ($v_{ph} = v_A |\cos\theta|$). Phase velocity is strictly zero perpendicular to $\vec{B}_0$ ($\theta = 90^\circ$).
  • Fast Magnetosonic Wave: Traces an oval (nearly spherical) outer shell. At $\theta = 90^\circ$, it propagates at the combined magnetosonic speed: $$v_{ph,\text{fast}}(\theta=90^\circ) = \sqrt{v_A^2 + c_s^2}$$ Here, thermal acoustic pressure and magnetic pressure compress in phase, reinforcing each other.
  • Slow Magnetosonic Wave: Traces two cusped lobes inside the Alfvén circles. At $\theta = 90^\circ$, $v_{ph,\text{slow}} = 0$. Thermal and magnetic pressure compress out of phase, partially canceling.

§7.5 Introduction to Plasma Instabilities: Free Energy, Hydrodynamic vs Kinetic

1. Free Energy and Instability Mechanism

A plasma equilibrium is characterized by time-independent macroscopic state variables. If a small initial perturbation $\psi_1(t) \propto e^{-i\omega t}$ has a complex frequency $\omega = \omega_r + i\gamma$:

$$\psi_1(t) = \psi_1(0) e^{-i(\omega_r + i\gamma)t} = \psi_1(0) e^{\gamma t} e^{-i\omega_r t}$$
  • If $\gamma < 0$: The perturbation is damped; the plasma is stable.
  • If $\gamma > 0$: The perturbation grows exponentially with growth rate $\gamma$; the plasma is unstable.

Instabilities are powered by tapping reservoirs of free energy stored in the non-equilibrium plasma:

  • Spatial gradients: Density $\nabla n$, temperature $\nabla T$, or pressure gradients $\nabla P$.
  • Currents and magnetic shear: Non-zero $\nabla \times \vec{B} = \mu_0 \vec{J}$.
  • Velocity space anisotropy: Non-Maxwellian beams ($v_d > v_{\text{th}}$) or pitch angle anisotropy ($T_\perp \ne T_\parallel$).

2. Classification of Instabilities

  1. Macro-Instabilities (MHD / Hydrodynamic): Driven by macroscopic spatial gradients. Wavelengths are macroscopic ($\lambda \gg r_L$). They rapidly destroy global plasma confinement on microsecond timescales (e.g., kink, sausage, Rayleigh-Taylor).
  2. Micro-Instabilities (Kinetic): Driven by non-thermal features in velocity space. Wavelengths are microscopic ($\lambda \sim r_L, \lambda_D$). They cause anomalous cross-field transport and turbulent diffusion (e.g., two-stream, drift waves, loss cone modes).

§7.6 The Gravitational Rayleigh-Taylor Instability & Magnetic Shear Stabilization

1. The Plasma Rayleigh-Taylor Instability

Consider a dense plasma of mass density $\rho_0$ supported against gravity $\vec{g} = -g\hat{y}$ by a magnetic field $\vec{B} = B_0\hat{z}$ or by a lighter fluid below (an "inverted density gradient").

If a small rippled perturbation $y_1 \propto e^{i(k_x x - \omega t)}$ forms at the interface:

  • Ions and electrons experience opposite gravitational drifts: $$\vec{v}_g = \frac{m}{q}\frac{\vec{g}\times\vec{B}}{B^2} = -\frac{m g}{q B}\hat{x}$$
  • Positive ions drift along $-\hat{x}$; electrons drift along $+\hat{x}$.
  • At ripple crests and troughs, this differential drift accumulates positive charge on one side of a crest and negative charge on the other side.
  • This charge separation produces a perturbed electric field $\vec{E}_1$ along $\hat{x}$.
  • The resulting $\vec{E}_1 \times \vec{B}_0$ drift velocity $\vec{v}_E = \frac{\vec{E}_1\times\vec{B}_0}{B_0^2}$ is directed upward at crests and downward at troughs!

The $\vec{E}\times\vec{B}$ drift amplifies the initial perturbation, driving runaway exponential growth with classical growth rate:

$$\omega^2 = -g k \implies \gamma = \sqrt{g k}$$

2. Magnetic Field Line Bending Stabilization

If the magnetic field possesses a component along the perturbation wavevector $\vec{k}$ (so that $\vec{k}\cdot\vec{B}_0 \ne 0$), rippling the interface bends magnetic field lines. Magnetic tension opposes the deformation, modifying the dispersion relation to:

$$\omega^2 = -g k + \frac{(\vec{k}\cdot\vec{B}_0)^2}{\mu_0 \rho_0}$$

The interface is completely stabilized ($\omega^2 \ge 0$) against Rayleigh-Taylor modes whenever:

$$\frac{(\vec{k}\cdot\vec{B}_0)^2}{\mu_0 \rho_0} \ge g k$$

This magnetic line-tying and shear stabilization is essential for stabilizing solar prominences and inertial confinement fusion (ICF) implosions.

§7.7 Macroscopic Tokamak MHD Instabilities: Kink, Sausage & Kruskal-Shafranov Limit

1. Current-Driven MHD Instabilities

In a cylindrical current-carrying plasma column (Z-pinch or tokamak), perturbations are decomposed into azimuthal Fourier modes $e^{i(m\theta - k_z z)}$:

  • $m = 0$ Mode (Sausage Instability): Axisymmetric constrictions along the column. Where the radius narrows ($r < a$), the azimuthal magnetic field $B_\theta \propto I/r$ intensifies, increasing magnetic pressure $B_\theta^2 / (2\mu_0)$ and pinching the neck even tighter until the column snaps.
  • $m = 1$ Mode (Kink Instability): The entire column bends into a helix. Field lines on the inside of the bend crowd together, raising magnetic pressure, while field lines on the outside spread out, lowering pressure. The net pressure imbalance kicks the bend outward, causing violent helical disruption.

2. The Kruskal-Shafranov Stability Criterion

To stabilize the dangerous $m=1$ kink instability in tokamaks, a strong toroidal magnetic field $B_z$ (or $B_\phi$) is applied along the column. As the column kinks, it is forced to stretch the strong axial field lines, which resists the deformation via magnetic tension.

Defining the safety factor $q(r)$:

$$q(r) \equiv \frac{r B_z(r)}{R B_\theta(r)}$$

where $R$ is the major radius and $r$ is the minor radius. The column is completely stable against the fundamental external kink mode if and only if the safety factor at the plasma edge exceeds unity:

$$q(a) > 1$$

This is the celebrated Kruskal-Shafranov stability limit. It sets an absolute upper bound on the maximum toroidal current $I_p$ that can be stably driven in any tokamak:

$$I_p < \frac{2\pi a^2 B_z}{\mu_0 R}$$

Exceeding this current triggers immediate catastrophic kink disruption.

Honors Examination Worked Problems & Solutions

Rigorous step-by-step mathematical proofs and solutions to university degree examination problems.

Advanced Honors Exam Problem Example 7.1: Derivation of the Shear Alfven Wave Dispersion Relation and Magnetic-Kinetic Energy Equipartition

Consider a homogeneous, incompressible ideal MHD plasma in a uniform background magnetic field $\vec{B}_0 = B_0 \hat{z}$ with mass density $\rho_0$. Let a transverse perturbation propagate along $\vec{B}_0$ with wavevector $\vec{k} = k\hat{z}$ and fluid velocity $\vec{v}_1 = v_1 \hat{x} e^{i(k z - \omega t)}$. (a) From the linearized induction equation, find the perturbed magnetic field $\vec{B}_1$. (b) From the linearized momentum equation, derive the dispersion relation $\omega^2 = k^2 v_A^2$ and verify the Alfvén velocity formula $v_A = B_0 / \sqrt{\mu_0 \rho_0}$. (c) Compute the time-averaged kinetic energy density $\langle u_k \rangle = \frac{1}{4}\rho_0 |v_1|^2$ and magnetic energy density $\langle u_m \rangle = \frac{1}{4\mu_0}|B_1|^2$, and prove that shear Alfvén waves satisfy exact energy equipartition.

Full Rigorous Analytical Solution

(a) Perturbed Magnetic Field $\vec{B}_1$: From the linearized induction equation:

$$\frac{\partial \vec{B}_1}{\partial t} = \nabla \times (\vec{v}_1 \times \vec{B}_0)$$

With $\vec{v}_1 = v_1 \hat{x} e^{i(kz - \omega t)}$ and $\vec{B}_0 = B_0 \hat{z}$:

$$\vec{v}_1 \times \vec{B}_0 = (v_1 \hat{x}) \times (B_0 \hat{z}) = -v_1 B_0 \hat{y}$$

Taking the curl $\nabla \times (\dots) = i k \hat{z} \times (\dots)$:

$$\nabla \times (\vec{v}_1 \times \vec{B}_0) = i k \hat{z} \times (-v_1 B_0 \hat{y}) = -i k v_1 B_0 (\hat{z}\times\hat{y}) = +i k v_1 B_0 \hat{x}$$

Since $\frac{\partial \vec{B}_1}{\partial t} = -i\omega \vec{B}_1$:

$$-i\omega \vec{B}_1 = i k v_1 B_0 \hat{x} \implies \vec{B}_1 = -\frac{k B_0}{\omega} v_1 \hat{x}$$

(b) Dispersion Relation Derivation: For incompressible perturbations, $\nabla \cdot \vec{v}_1 = i k v_{1z} = 0 \implies P_1 = 0$. The linearized momentum equation is:

$$\rho_0 \frac{\partial \vec{v}_1}{\partial t} = \vec{J}_1 \times \vec{B}_0 = \frac{1}{\mu_0}(\nabla \times \vec{B}_1) \times \vec{B}_0$$

Compute the curl:

$$\nabla \times \vec{B}_1 = i k \hat{z} \times \left( B_{1x} \hat{x} \right) = i k B_{1x} \hat{y}$$

Now evaluate the Lorentz force:

$$(\nabla \times \vec{B}_1) \times \vec{B}_0 = (i k B_{1x} \hat{y}) \times (B_0 \hat{z}) = i k B_0 B_{1x} \hat{x}$$

Substitute into momentum:

$$-i\omega \rho_0 v_1 \hat{x} = \frac{1}{\mu_0} i k B_0 B_{1x} \hat{x} \implies -i\omega \rho_0 v_1 = \frac{i k B_0}{\mu_0} B_{1x}$$

Substitute $B_{1x} = -\frac{k B_0}{\omega} v_1$:

$$-i\omega \rho_0 v_1 = \frac{i k B_0}{\mu_0} \left( -\frac{k B_0}{\omega} v_1 \right) = -i \frac{k^2 B_0^2}{\mu_0 \omega} v_1$$

Divide by $-i v_1 / \omega$:

$$\omega^2 \rho_0 = \frac{k^2 B_0^2}{\mu_0} \implies \omega^2 = k^2 \left( \frac{B_0^2}{\mu_0 \rho_0} \right) = k^2 v_A^2$$

where $v_A = \frac{B_0}{\sqrt{\mu_0 \rho_0}}$ is the Alfvén velocity.

(c) Proof of Energy Equipartition: The time-averaged kinetic energy density of the fluid perturbation is:

$$\langle u_k \rangle = \frac{1}{4}\rho_0 |v_1|^2$$

The time-averaged magnetic energy density of the wave perturbation is:

$$\langle u_m \rangle = \frac{1}{4\mu_0} |B_1|^2$$

From part (a), $|B_1| = \frac{k B_0}{\omega} |v_1|$. Since $\frac{\omega}{k} = v_A = \frac{B_0}{\sqrt{\mu_0 \rho_0}}$, we have:

$$\frac{k B_0}{\omega} = \frac{B_0}{v_A} = \frac{B_0}{B_0 / \sqrt{\mu_0 \rho_0}} = \sqrt{\mu_0 \rho_0}$$

Therefore:

$$|B_1| = \sqrt{\mu_0 \rho_0} |v_1|$$

Now substitute $|B_1|$ into the magnetic energy density:

$$\langle u_m \rangle = \frac{1}{4\mu_0} |B_1|^2 = \frac{1}{4\mu_0} \left( \sqrt{\mu_0 \rho_0} |v_1| \right)^2 = \frac{1}{4\mu_0} (\mu_0 \rho_0 |v_1|^2) = \frac{1}{4}\rho_0 |v_1|^2$$

Comparing the two expressions:

$$\langle u_m \rangle = \langle u_k \rangle$$

This proves that shear Alfvén waves possess exact 50/50 equipartition between oscillating kinetic energy of the fluid and oscillating magnetic energy of the distorted field lines.

Final Answer & Physical Verification

Complete rigorous derivation and proof detailed above.

Final Answer & Physical Insight

Complete rigorous derivation and proof detailed above.

Advanced Honors Exam Problem Example 7.2: Rayleigh-Taylor Growth Rate Derivation at Inverted Plasma-Vacuum Boundary and Magnetic Line Bending Suppression

A slab of dense plasma with mass density $\rho_0$ occupies the upper half-space $y > 0$ above an evacuated region ($y < 0$), subject to downward gravitational acceleration $\vec{g} = -g\hat{y}$. The plasma is permeated by a magnetic field $\vec{B}_0 = B_0 \hat{z}$. (a) Assuming an incompressible ripple perturbation at the interface $y_1(x) = \xi_0 e^{i(k_x x - \omega t)}$, show from the linearized jump conditions that the unmagnetized gravitational Rayleigh-Taylor growth rate is $\gamma = \sqrt{g k_x}$. (b) If the magnetic field is tilted to possess a component along the wavevector $\vec{B}_0 = B_x \hat{x} + B_z \hat{z}$ so that $\vec{k}\cdot\vec{B}_0 = k_x B_x \ne 0$, show that the dispersion relation becomes:

$$\omega^2 = -g k_x + \frac{k_x^2 B_x^2}{\mu_0 \rho_0}$$

(c) For a laser-fusion pellet target where $g = 10^{13}\text{ m/s}^2$, $\rho_0 = 1000\text{ kg/m}^3$, and perturbation wavelength $\lambda = 10\;\mu\text{m}$, calculate the unmagnetized growth time $\tau = 1/\gamma$. What minimum magnetic field $B_x$ is required to completely stabilize this perturbation?

Full Rigorous Analytical Solution

(a) Unmagnetized Rayleigh-Taylor Growth Rate: In the upper half-space ($y > 0$), incompressibility requires $\nabla^2 \phi_1 = 0 \implies \phi_1(x, y) = A e^{-k_x y} e^{i(k_x x - \omega t)}$. The vertical velocity at the boundary is $v_{y1} = -\frac{\partial \phi_1}{\partial y} = k_x A = -i\omega \xi_0$. The linearized momentum equation yields the perturbed pressure at the interface:

$$P_1 = \rho_0 \frac{\omega^2}{k_x}\xi_0$$

The interface position is perturbed by $\xi(x) = \xi_0 e^{i(k_x x - \omega t)}$. The gravitational pressure jump across the perturbed interface is:

$$\Delta P_{\text{grav}} = \rho_0 g \xi_0$$

Equating the dynamic pressure to the gravitational hydrostatic jump:

$$\rho_0 \frac{\omega^2}{k_x}\xi_0 = -\rho_0 g \xi_0 \implies \omega^2 = -g k_x$$

Since $\omega^2 < 0$, $\omega = \pm i\sqrt{g k_x} = \pm i\gamma$, where the instability growth rate is:

$$\gamma = \sqrt{g k_x}$$

(b) Magnetic Shear / Line Bending Stabilization: When $\vec{k}\cdot\vec{B}_0 = k_x B_x \ne 0$, the perturbation distorts the magnetic field lines. The perturbed magnetic field inside the plasma is:

$$\vec{B}_1 = \nabla \times (\vec{\xi} \times \vec{B}_0) = i(\vec{k}\cdot\vec{B}_0)\vec{\xi} = i(k_x B_x)\xi_0 \hat{y}$$

The magnetic tension restoring force per unit volume is:

$$\vec{F}_{\text{tension}} = \frac{1}{\mu_0}(\vec{B}_0\cdot\nabla)\vec{B}_1 = \frac{1}{\mu_0}(i k_x B_x)\left( i k_x B_x \xi_0 \hat{y} \right) = -\frac{k_x^2 B_x^2}{\mu_0}\xi_0 \hat{y}$$

Integrating this restoring force across the boundary layer adds an effective positive spring constant to the interface equation of motion:

$$\rho_0 \frac{\omega^2}{k_x}\xi_0 = -\rho_0 g \xi_0 + \frac{k_x B_x^2}{\mu_0}\xi_0$$

Dividing by $\rho_0 \xi_0 / k_x$:

$$\omega^2 = -g k_x + \frac{k_x^2 B_x^2}{\mu_0 \rho_0} = -g k_x + k_x^2 v_{Ax}^2$$

where $v_{Ax} = \frac{B_x}{\sqrt{\mu_0 \rho_0}}$. Complete stability ($\omega^2 \ge 0$) is achieved if and only if:

$$\frac{k_x^2 B_x^2}{\mu_0 \rho_0} \ge g k_x \implies B_x^2 \ge \frac{\mu_0 \rho_0 g}{k_x}$$

(c) Numerical Evaluation for Laser Fusion Target: Given: $g = 10^{13}\text{ m/s}^2$ $\rho_0 = 1000\text{ kg/m}^3$ $\lambda = 10\;\mu\text{m} = 1.0\times 10^{-5}\text{ m} \implies k_x = \frac{2\pi}{1.0\times 10^{-5}} = 6.283 \times 10^5\text{ m}^{-1}$

1. Unmagnetized Growth Rate & Time:

$$\gamma = \sqrt{g k_x} = \sqrt{(10^{13}\text{ m/s}^2)(6.283\times 10^5\text{ m}^{-1})} = \sqrt{6.283\times 10^{18}} \approx 2.507 \times 10^9\text{ s}^{-1}$$

The growth e-folding time is:

$$\tau = \frac{1}{\gamma} = \frac{1}{2.507\times 10^9\text{ s}^{-1}} \approx 3.99 \times 10^{-10}\text{ s} \approx 0.40\text{ nanoseconds}$$

The perturbation grows by a factor of $e$ in less than half a nanosecond!

2. Minimum Stabilizing Magnetic Field $B_x$:

$$B_{x,\text{min}}^2 = \frac{\mu_0 \rho_0 g}{k_x} = \frac{(4\pi\times 10^{-7}\text{ H/m})(1000\text{ kg/m}^3)(10^{13}\text{ m/s}^2)}{6.283\times 10^5\text{ m}^{-1}} = \frac{1.257\times 10^{10}}{6.283\times 10^5} = 2.00 \times 10^4\text{ T}^2$$

Taking the square root:

$$B_{x,\text{min}} = \sqrt{2.00\times 10^4} \approx 141.4\text{ Tesla}$$

A magnetic field of at least 141 Tesla is required to completely suppress the Rayleigh-Taylor mode via magnetic tension.

Final Answer & Physical Verification

Complete rigorous derivation and proof detailed above.

Final Answer & Physical Insight

Complete rigorous derivation and proof detailed above.

Advanced Honors Exam Problem Example 7.3: Kruskal-Shafranov Safety Factor and Maximum Stable Current in a Cylindrical Tokamak Geometry

A medium-sized research tokamak has major radius $R = 1.50\text{ m}$, minor radius $a = 0.40\text{ m}$, and on-axis toroidal magnetic field $B_z = 2.50\text{ Tesla}$. (a) State the Kruskal-Shafranov stability condition for the $m=1$ external helical kink mode in terms of the safety factor $q(a)$. (b) Derive the formula for the maximum stable plasma current $I_{\text{max}}$ allowed before kink disruption occurs. (c) Calculate the numerical value of $I_{\text{max}}$ in Mega-amperes (MA). (d) If the experimentalist attempts to drive a current $I_p = 1.20\text{ MA}$, calculate the actual edge safety factor $q(a)$ and explain what will physically occur.

Full Rigorous Analytical Solution

(a) Kruskal-Shafranov Stability Condition: The safety factor at the plasma boundary $r = a$ is:

$$q(a) = \frac{a B_z}{R B_\theta(a)}$$

where $B_\theta(a)$ is the poloidal magnetic field generated by the plasma current. The Kruskal-Shafranov criterion states that the plasma column is stable against the dangerous $m=1$ external helical kink mode if and only if:

$$q(a) > 1$$

(b) Maximum Stable Plasma Current Formula: By Ampère's law, the poloidal magnetic field at the plasma boundary $r=a$ is:

$$\oint \vec{B}_\theta \cdot d\vec{l} = 2\pi a B_\theta(a) = \mu_0 I_p \implies B_\theta(a) = \frac{\mu_0 I_p}{2\pi a}$$

Substitute $B_\theta(a)$ into the expression for $q(a)$:

$$q(a) = \frac{a B_z}{R \left( \frac{\mu_0 I_p}{2\pi a} \right)} = \frac{2\pi a^2 B_z}{\mu_0 R I_p}$$

Applying the stability condition $q(a) > 1$:

$$\frac{2\pi a^2 B_z}{\mu_0 R I_p} > 1 \implies I_p < \frac{2\pi a^2 B_z}{\mu_0 R} \equiv I_{\text{max}}$$

where $I_{\text{max}}$ is the Kruskal-Shafranov current limit.

(c) Numerical Calculation of $I_{\text{max}}$: Given: $a = 0.40\text{ m} \implies a^2 = 0.16\text{ m}^2$ $R = 1.50\text{ m}$ $B_z = 2.50\text{ T}$ $\mu_0 = 4\pi \times 10^{-7}\text{ H/m}$ Evaluating:

$$I_{\text{max}} = \frac{2\pi (0.16\text{ m}^2)(2.50\text{ T})}{(4\pi \times 10^{-7}\text{ H/m})(1.50\text{ m})} = \frac{0.80\pi}{(6.0\pi \times 10^{-7})} = \frac{0.80}{6.0\times 10^{-7}} = \frac{4}{3} \times 10^6\text{ A} \approx 1.333 \times 10^6\text{ A}$$
$$I_{\text{max}} \approx 1.33\text{ MA}$$

The maximum stable current allowed by the Kruskal-Shafranov limit is 1.33 Mega-amperes.

(d) Evaluation at $I_p = 1.20\text{ MA}$: For $I_p = 1.20\text{ MA}$:

$$q(a) = \frac{I_{\text{max}}}{I_p} = \frac{1.333\text{ MA}}{1.20\text{ MA}} \approx 1.111 > 1$$

Because $q(a) = 1.11 > 1$, the plasma remains macroscopically stable against the $m=1$ kink mode. However, in practice, tokamaks operate with $q(a) \ge 3.0$ (known as the Greenwald-Hugill operating boundary) because higher-order resistive tearing modes ($m=2, n=1$ and $m=3, n=2$) become unstable when $q(a) < 2$, causing catastrophic major disruptions and thermal quench of the plasma into the divertor walls.

Final Answer & Physical Verification

Complete rigorous derivation and proof detailed above.

Final Answer & Physical Insight

Complete rigorous derivation and proof detailed above.