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Chapter 4 • Theory & Derivations

Interaction of Nuclei with Electromagnetic Radiation & Multipole Transitions

Quantum theory of nuclear electromagnetic radiative transitions: multipole expansion of the vector potential into Electric (Eλ) and Magnetic (Mλ) modes, angular momentum and parity selection rules, strict exclusion of 0⁺ → 0⁺ single-photon decay, Weisskopf single-particle transition rate formulas T_W(Eλ) and T_W(Mλ), reduced transition probabilities B(Eλ) and B(Mλ), two-body radiative capture n + p → d + γ and magnetic dipole M1 dominance, internal conversion (IC) electrodynamics, conversion coefficients α_K, α_L, monopole E0 transitions, nuclear isomerism, and Giant Dipole Resonance (GDR) collective hydrodynamic oscillations.

§4.1 Quantization of the Nuclear Electromagnetic Field & Fermi's Golden Rule

1. Electromagnetic Interaction Hamiltonian

The interaction between an ensemble of nucleons and the quantized electromagnetic radiation field is governed by the minimal coupling Hamiltonian $\vec{p} \to \vec{p} - q\vec{A}$. In the Coulomb gauge ($\nabla\cdot\vec{A} = 0$):

$$\hat{H}_{\text{int}} = -\int \vec{j}(\vec{r})\cdot\vec{A}(\vec{r}) d^3r - \int \vec{M}(\vec{r})\cdot\vec{B}(\vec{r}) d^3r$$

where $\vec{j}(\vec{r}) = \sum_{k} \frac{e_k}{2M} (\vec{p}_k \delta(\vec{r}-\vec{r}_k) + \delta(\vec{r}-\vec{r}_k)\vec{p}_k)$ is the convection current density of protons, and $\vec{M}(\vec{r}) = \sum_k \mu_N g_s^{(k)} \vec{s}_k \delta(\vec{r}-\vec{r}_k)$ is the magnetization density due to nucleon intrinsic spins.

2. Transition Rates from Fermi's Golden Rule

For a nucleus decaying from initial excited state $|i\rangle$ of energy $E_i$ to final state $|f\rangle$ of energy $E_f$ with emission of a photon of energy $\hbar\omega = E_i - E_f$ and wavevector $k = \omega/c$, time-dependent perturbation theory yields Fermi's Golden Rule:

$$\lambda_{fi} = \frac{2\pi}{\hbar} |\langle f; 1_{\vec{k},\epsilon}| \hat{H}_{\text{int}} |i; 0\rangle|^2 \rho(E)$$

where the density of final photon states in solid angle $d\Omega$ is $\rho(E) = \frac{V \omega^2 d\Omega}{(2\pi)^3 \hbar c^3}$.

Because nuclear dimensions ($R \sim 5\text{ fm}$) are vastly smaller than the wavelength of typical gamma rays ($E_\gamma \sim 1\text{ MeV} \implies \lambdabar = \frac{\hbar c}{E_\gamma} \approx 200\text{ fm}$):

$$k R = \frac{R}{\lambdabar} = \frac{5\text{ fm}}{200\text{ fm}} \approx 0.025 \ll 1$$

This long-wavelength condition justifies expanding the vector potential $\vec{A}(\vec{r}) \propto e^{i\vec{k}\cdot\vec{r}}$ in spherical multipoles of order $(k r)^\lambda$.

§4.2 Classification of Multipole Radiation: Electric (Eλ) and Magnetic (Mλ) Modes

1. Spherical Multipole Expansion of the Radiation Field

The radiation field can be decomposed rigorously into orthogonal vector spherical harmonics carrying definite total angular momentum $\lambda\hbar$ and parity $\pi$:

  • Electric Multipole of Order $\lambda$ ($E\lambda$): Generated by the oscillating nuclear electric charge distribution $\rho(\vec{r})$ and convection currents. The transition operator is: $$\hat{\mathcal{M}}(E\lambda, \mu) = \sum_{k=1}^A e_k r_k^\lambda Y_{\lambda\mu}(\theta_k, \phi_k)$$
  • Magnetic Multipole of Order $\lambda$ ($M\lambda$): Generated by the circulating orbital current loops and intrinsic nucleon spin magnetic moments. The transition operator is: $$\hat{\mathcal{M}}(M\lambda, \mu) = \mu_N \sum_{k=1}^A \left[ \frac{2}{\lambda+1} g_l^{(k)} \vec{l}_k + g_s^{(k)} \vec{s}_k \right] \cdot \nabla \left( r_k^\lambda Y_{\lambda\mu}(\hat{r}_k) \right)$$

2. Multipolarity Terminology

Order $\lambda$ Multipolarity Name Electric Mode Magnetic Mode
$\lambda = 1$ Dipole $E1$ $M1$
$\lambda = 2$ Quadrupole $E2$ $M2$
$\lambda = 3$ Octupole $E3$ $M3$
$\lambda = 4$ Hexadecapole $E4$ $M4$

§4.3 Angular Momentum & Parity Selection Rules for Multipole Transitions

1. Angular Momentum Conservation Selection Rule

A photon emitted in a multipole mode of order $\lambda$ carries an intrinsic angular momentum of $\lambda\hbar$ (with $\lambda \ge 1$, since photons are transverse vector bosons with helicity $\pm 1$ and cannot exist in a scalar $\lambda = 0$ state).

By conservation of angular momentum $\vec{I}_i = \vec{I}_f + \vec{\lambda}$, the triangle inequality requires:

$$|I_i - I_f| \le \lambda \le I_i + I_f$$

Absolute Exclusion of Single-Photon $0 \to 0$ Transitions: If $I_i = 0$ and $I_f = 0$, then $|0 - 0| \le \lambda \le 0 + 0 \implies \lambda = 0$. Because there are no longitudinal or scalar photons in free space, single-photon transitions between two spin-zero states ($0^+ \to 0^+$ or $0^- \to 0^+$) are strictly forbidden by conservation of angular momentum. Such states decay via internal conversion (IC) or internal pair creation ($e^+ e^-$).

2. Parity Selection Rules

The electromagnetic multipole operators transform under spatial inversion $\vec{r} \to -\vec{r}$ according to their parity:

$$\pi(E\lambda) = (-1)^\lambda, \qquad \pi(M\lambda) = (-1)^{\lambda+1}$$

Therefore, the parity of the nuclear states $\pi_i$ and $\pi_f$ must satisfy:

$$\text{For Electric Transitions }(E\lambda): \quad \pi_i \pi_f = (-1)^\lambda \implies \Delta\pi = \begin{cases} \text{No parity change}, & \lambda = 2, 4, 6 \dots (E2, E4) \\ \text{Parity change}, & \lambda = 1, 3, 5 \dots (E1, E3) \end{cases}$$ $$\text{For Magnetic Transitions }(M\lambda): \quad \pi_i \pi_f = (-1)^{\lambda+1} \implies \Delta\pi = \begin{cases} \text{No parity change}, & \lambda = 1, 3, 5 \dots (M1, M3) \\ \text{Parity change}, & \lambda = 2, 4, 6 \dots (M2, M4) \end{cases}$$

3. Summary Decision Matrix

Transition Character Parity Change ($\pi_i \pi_f$) Allowed Multipoles Dominant Mode
$2^+ \to 0^+$ No ($\Delta\pi = +1$) $E2, M3, E4 \dots$ $E2$
$1^- \to 0^+$ Yes ($\Delta\pi = -1$) $E1, M2, E3 \dots$ $E1$
$2^+ \to 1^+$ No ($\Delta\pi = +1$) $M1, E2, M3 \dots$ $M1 + E2$ (Mixed)
$3^- \to 0^+$ Yes ($\Delta\pi = -1$) $E3, M4, E5 \dots$ $E3$

§4.4 Weisskopf Single-Particle Transition Rate Estimates & Reduced Probabilities

1. Derivation of the Weisskopf Units (W.u.)

Victor Weisskopf derived standard baseline transition rates by assuming a single valence proton moves from a single-particle orbital $j_i$ to $j_f$ in a spherical nucleus of radius $R = R_0 A^{1/3}$ ($R_0 \approx 1.2\text{ fm}$), with constant radial wavefunctions:

$$\langle r^\lambda \rangle \approx \frac{\int_0^R r^\lambda r^2 dr}{\int_0^R r^2 dr} = \frac{3}{\lambda + 3} R^\lambda$$

The resulting Weisskopf single-particle transition rates $\lambda_W = T_W$ in $\text{s}^{-1}$ for photon energy $E_\gamma$ in MeV are:

$$\lambda_W(E1) = 1.023 \times 10^{14} A^{2/3} E_\gamma^3\text{ s}^{-1}$$ $$\lambda_W(E2) = 7.28 \times 10^7 A^{4/3} E_\gamma^5\text{ s}^{-1}$$ $$\lambda_W(E3) = 3.39 \times 10^1 A^2 E_\gamma^7\text{ s}^{-1}$$ $$\lambda_W(M1) = 3.15 \times 10^{13} E_\gamma^3\text{ s}^{-1}$$ $$\lambda_W(M2) = 2.24 \times 10^7 A^{2/3} E_\gamma^5\text{ s}^{-1}$$ $$\lambda_W(M3) = 1.04 \times 10^1 A^{4/3} E_\gamma^7\text{ s}^{-1}$$

2. Hierarchy and Multipole Dominance

Because $k R \ll 1$, each increase in multipole order $\lambda \to \lambda + 1$ suppresses the transition probability by a colossal factor of $(k R)^2 \sim 10^{-4} \text{ to } 10^{-6}$:

$$\frac{\lambda_W(E(\lambda+1))}{\lambda_W(E\lambda)} \sim (k R)^2 \approx 10^{-4}$$ $$\frac{\lambda_W(M\lambda)}{\lambda_W(E\lambda)} \approx 10^{-2}$$

Therefore, in any electromagnetic transition, the lowest allowed multipole completely dominates the decay rate unless hindered by selection rules.

3. Physical Significance of Weisskopf Units

  • If an experimental transition rate matches $\sim 1\text{ W.u.}$, the transition is confirmed to be an independent single-particle transition.
  • If $B(E2) \gg 1\text{ W.u.}$ (often $10\text{ to }300\text{ W.u.}$ in deformed rare-earth and actinide nuclei), the transition is collective, involving the coherent motion of dozens of nucleons in a rotating or vibrating nuclear core.
  • If $B(E1) \ll 1\text{ W.u.}$ ($10^{-3}\text{ to }10^{-6}\text{ W.u.}$), the transition is strongly hindered, typically by isospin selection rules ($\Delta I = 0$ in self-conjugate $N=Z$ nuclei) or shape changes.

§4.5 Radiative Capture in the Two-Body System (n + p → d + γ Magnetic Dipole M1)

1. The Thermal Neutron Radiative Capture Process

When thermal neutrons ($E_n \approx 0.025\text{ eV}$) interact with hydrogen, capture occurs via gamma emission:

$$n + p \to {}^2\text{H} + \gamma \quad (E_\gamma = B = 2.2246\text{ MeV})$$

The incident thermal neutron has $l = 0$ ($s$-wave), so the initial continuum state has positive parity $\pi_i = +1$. The bound deuteron has $J^\pi = 1^+$.

Because there is no change in parity ($\pi_i = \pi_f = +1$), electric dipole radiation ($E1$, which requires $\Delta\pi = -1$) is strictly forbidden. The dominant decay mode is magnetic dipole radiation ($M1$).

2. The Spin-Flip Capture Mechanism

The transition proceeds from the unbound ${}^1S_0$ continuum state ($J=0, S=0$) to the ${}^3S_1$ component of the deuteron bound state ($J=1, S=1$). The magnetic dipole transition operator is:

$$\vec{\mathcal{M}}(M1) = \mu_N (g_p \vec{s}_p + g_n \vec{s}_n) = \frac{\mu_N}{2} \left[ (\mu_p + \mu_n)(\vec{\sigma}_p + \vec{\sigma}_n) + (\mu_p - \mu_n)(\vec{\sigma}_p - \vec{\sigma}_n) \right]$$

The spin-flip transition between singlet ($S=0$) and triplet ($S=1$) is driven by the term proportional to $(\mu_p - \mu_n)$:

$$\langle {}^3S_1 | (\vec{\sigma}_p - \vec{\sigma}_n) | {}^1S_0 \rangle \ne 0$$

Because $(\mu_p - \mu_n) = 2.793 - (-1.913) = +4.706\text{ }\mu_N$ is exceptionally large, the transition amplitude is greatly enhanced.

3. Cross-Section Discrepancy & Meson Exchange Currents

The cross section calculated from the simple single-particle wavefunctions without meson exchange currents is:

$$\sigma_{\text{calc}}^{(0)} = 302 \pm 4\text{ mb}$$

However, high-precision thermal neutron capture experiments yield:

$$\sigma_{\text{exp}} = 334.2 \pm 0.5\text{ mb}$$

The famous $10\%$ discrepancy ($\Delta\sigma \approx 32\text{ mb}$) is resolved by including Meson Exchange Currents (MEC): during the collision, virtual charged pions ($\pi^\pm$) in flight between the proton and neutron directly couple to the photon field ($\gamma \pi \pi$ and $\gamma N N \pi$ contact vertices), providing conclusive proof of sub-nucleonic meson degrees of freedom in nuclei.

§4.6 Internal Conversion (IC), Conversion Coefficients α, and E0 Monopole Decay

1. The Microscopic Mechanism of Internal Conversion

In an excited nucleus, gamma decay is not the only electromagnetic de-excitation mechanism. The oscillating nuclear electromagnetic multipole field extends into the atomic electron cloud. A bound atomic electron (most commonly from the innermost $K$ shell, $n=1$) can undergo direct electromagnetic interaction with the nucleus, being ejected into the continuum:

$${}^A_Z X^* \to {}^A_Z X^+ + e_{\text{IC}}^-$$

This process is Internal Conversion (IC).

The kinetic energy of the ejected conversion electron is:

$$T_e = E_\gamma - B_e$$

where $E_\gamma = E_i - E_f$ is the nuclear transition energy and $B_e$ is the electron atomic binding energy ($B_K, B_L, \dots$). Consequently, conversion electron spectra consist of discrete, sharp monoenergetic lines, in stark contrast to continuous beta spectra.

2. The Internal Conversion Coefficient (ICC)

The internal conversion coefficient $\alpha$ is defined as the ratio of the conversion electron decay rate ($\lambda_e$) to the gamma-ray emission rate ($\lambda_\gamma$):

$$\alpha \equiv \frac{\lambda_e}{\lambda_\gamma} = \alpha_K + \alpha_{L_I} + \alpha_{L_{II}} + \alpha_{L_{III}} + \alpha_M + \dots$$

The total transition probability is $\lambda_{\text{total}} = \lambda_\gamma + \lambda_e = \lambda_\gamma (1 + \alpha)$.

Parametric dependence of $\alpha$:

$$\alpha(E\lambda) \propto Z^3 \left( \frac{m_e c^2}{E_\gamma} \right)^{\lambda + 7/2}, \qquad \alpha(M\lambda) \propto Z^3 \left( \frac{m_e c^2}{E_\gamma} \right)^{\lambda + 5/2}$$

Key physical properties:

  • Heavy Nuclei ($Z^3$ Scaling): IC dominates in heavy elements ($Z \ge 50$) because $K$-shell electrons have wavefunctions strongly concentrated at the nucleus ($\psi_e(0) \propto Z^{3/2}$).
  • High Multipolarity ($\lambda \ge 3$): Because $\lambda_\gamma$ is heavily suppressed for high multipolarities while electron conversion near the origin is less hindered, high-$\lambda$ transitions have massive conversion coefficients ($\alpha \gg 1$).
  • Low Transition Energy ($E_\gamma \le 200\text{ keV}$): Low energy transitions proceed almost entirely via conversion electrons.

3. Electric Monopole ($E0$) Transitions

When both the initial and final states have spin-parity $0^+$ (such as in ${}^{16}\text{O}^*(6.05\text{ MeV}) \to {}^{16}\text{O}(\text{g.s.}, 0^+)$ or ${}^{72}\text{Ge}^*(691\text{ keV}) \to {}^{72}\text{Ge}(\text{g.s.}, 0^+)$), single-photon emission is strictly forbidden ($\lambda = 0$).

Because the spherically symmetric Coulomb monopole operator $\hat{\mathcal{M}}(E0) = e \sum r_p^2$ can overlap with atomic $s_{1/2}$ electrons entering the nuclear interior, these states de-excite via pure $E0$ internal conversion (or electron-positron pair creation if $E_\gamma > 2 m_e c^2 = 1.022\text{ MeV}$).

§4.7 Transitions in Highly Excited Nuclei: The Giant Dipole Resonance (GDR)

1. The Phenomenon of the Giant Dipole Resonance

When atomic nuclei are bombarded with high-energy photons ($E_\gamma \approx 10\text{ to }25\text{ MeV}$), the total photoabsorption cross section $\sigma_{\text{abs}}(E_\gamma)$ does not exhibit isolated narrow Breit-Wigner peaks. Instead, it displays a colossal, universal, broad peak known as the Giant Dipole Resonance (GDR):

  • Resonance Energy: Systematically decreases with mass number $A$: $$E_{\text{GDR}} \approx 78 A^{-1/3}\text{ MeV} \quad (\text{or } 31.2 A^{-1/3} + 20.6 A^{-1/6}\text{ MeV})$$ In light nuclei ($A \sim 16$), $E_{\text{GDR}} \approx 22\text{ to }25\text{ MeV}$; in heavy nuclei ($A \sim 208$), $E_{\text{GDR}} \approx 13.5\text{ MeV}$.
  • Resonance Width ($\Gamma$): Typically $\Gamma \approx 4\text{ to }6\text{ MeV}$ in spherical magic nuclei, broadening in deformed nuclei.
  • Exhaustion of the TRK Sum Rule: The integrated photoabsorption cross section exhausts the classical Thomas-Reiche-Kuhn (TRK) dipole sum rule: $$\int_0^\infty \sigma_{\text{abs}}(E_\gamma) dE_\gamma = \frac{2\pi^2 e^2 \hbar}{M c} \frac{N Z}{A} (1 + \kappa) \approx 60 \frac{N Z}{A}\text{ MeV}\cdot\text{mb}$$ where $\kappa \approx 0.2\text{ to }0.4$ represents meson exchange current enhancements.

2. Macroscopic Hydrodynamic Models: Goldhaber-Teller vs Steinwedel-Jensen

The GDR is a collective macroscopic vibration of all protons against all neutrons:

  1. Goldhaber-Teller (GT) Model: The protons are treated as a rigid sphere oscillating out of phase with a rigid neutron sphere against the restoring force of the nuclear symmetry energy. It predicts $E_{\text{GDR}} \propto A^{-1/6}$.
  2. Steinwedel-Jensen (SJ) Model: The protons and neutrons form compressible fluids within a fixed spherical nuclear boundary. Acoustic compressional density waves oscillate against each other ($n_p - n_n \ne 0$). It predicts $E_{\text{GDR}} \propto A^{-1/3}$.

3. Resonance Splitting in Deformed Nuclei

In deformed, prolate nuclei (such as the rare-earths ${}^{160}\text{Gd}$ or actinides ${}^{238}\text{U}$), the GDR splits into two distinct peaks:

  • Low-Energy Peak ($E_a$): Collective oscillation along the longer major axis ($a$). Since the wavelength is longer, the frequency is lower.
  • High-Energy Peak ($E_b$): Collective oscillation along the shorter minor axes ($b$).

The ratio of peak energies directly yields the nuclear deformation axis ratio: $\frac{E_b}{E_a} \approx \frac{a}{b} = 1 + 0.95 \beta_2$.

Solved Problem Example 4.1: Multipole Selection Rules and Weisskopf Half-Life Estimates

A nuclear excited state of spin-parity $I_i^{\pi_i} = 7/2^+$ at excitation energy $E_x = 0.500\text{ MeV}$ in a nucleus with $A = 125$ de-excites to the ground state $I_f^{\pi_f} = 1/2^+$. (a) Determine all allowed electromagnetic multipoles and identify the dominant radiation mode. (b) Using the Weisskopf single-particle formulas, calculate the transition probability $\lambda_W$ and estimated half-life $t_{1/2}$ for this transition. (c) If the next-lowest allowed multipole could compete, estimate the branching ratio between the two modes.

(a) Allowed Multipoles and Dominant Mode: Initial state: $I_i = 7/2, \pi_i = +1$. Final state: $I_f = 1/2, \pi_f = +1$. Angular momentum selection rule:

$$|7/2 - 1/2| \le \lambda \le 7/2 + 1/2 \implies 3 \le \lambda \le 4$$

Thus the allowed multipole orders are $\lambda = 3$ and $\lambda = 4$. Parity selection rule: No parity change occurs ($\pi_i \pi_f = (+1)(+1) = +1$).

  • For $\lambda = 3$: $\Delta\pi(E3) = (-1)^3 = -1$ (forbidden). But $\Delta\pi(M3) = (-1)^{3+1} = +1$ (allowed!).
  • For $\lambda = 4$: $\Delta\pi(E4) = (-1)^4 = +1$ (allowed!). $\Delta\pi(M4) = (-1)^{4+1} = -1$ (forbidden).

The allowed modes are $M3$ and $E4$. Because $\lambda = 3 < 4$, the lowest multipole $M3$ (Magnetic Octupole) is the dominant radiation mode.

(b) Weisskopf Transition Rate and Half-Life for $M3$: Using $A = 125$ and $E_\gamma = 0.500\text{ MeV}$:

$$\lambda_W(M3) = 1.04 \times 10^1 A^{4/3} E_\gamma^7\text{ s}^{-1}$$
$$A^{4/3} = (125)^{4/3} = (5^3)^{4/3} = 5^4 = 625$$
$$E_\gamma^7 = (0.500)^7 = \frac{1}{128} \approx 0.0078125\text{ MeV}^7$$
$$\lambda_W(M3) = 1.04 \times 10^1 \times 625 \times 0.0078125 \approx 10.4 \times 4.8828 \approx \mathbf{50.78\text{ s}^{-1}}$$

The estimated half-life is:

$$t_{1/2} = \frac{\ln 2}{\lambda_W(M3)} = \frac{0.69315}{50.78\text{ s}^{-1}} \approx \mathbf{0.01365\text{ s}} = \mathbf{13.65\text{ ms}}$$

Because $M3$ is a high-multipolarity transition, the half-life is thousands of times longer than typical nanosecond gamma transitions, forming a nuclear isomer!

(c) Competition from $E4$:

$$\lambda_W(E4) = \frac{1.2 \times 10^7}{(2\times 4 + 1)!!^2} \dots \approx 3 \times 10^{-5} A^{8/3} E_\gamma^9\text{ s}^{-1}$$
$$A^{8/3} = (625)^2 = 390625, \quad E_\gamma^9 = (0.5)^9 = 0.001953$$
$$\lambda_W(E4) \approx 3 \times 10^{-5} \times 390625 \times 0.001953 \approx 0.0229\text{ s}^{-1}$$

Branching ratio:

$$\frac{\lambda_W(E4)}{\lambda_W(M3)} \approx \frac{0.0229}{50.78} \approx 4.5 \times 10^{-4} \approx 0.045\%$$

The $E4$ branch represents less than $0.05\%$ of the decay, confirming $M3$ overwhelming dominance.

Solved Problem Example 4.2: Internal Conversion Coefficient and Total De-excitation Half-Life

The first excited state of ${}^{119}\text{Sn}$ at $E_x = 23.87\text{ keV}$ decays to the ground state via an $M1$ transition. The experimental $K$-shell and total internal conversion coefficients are:

$$\alpha_K = 4.4, \quad \alpha_{\text{total}} = 5.1$$

The observed total half-life of the state is $t_{1/2} = 17.8\text{ ns}$. (a) Calculate the partial half-life $t_{1/2}^{(\gamma)}$ for pure gamma-ray emission. (b) Calculate the partial half-life $t_{1/2}^{(e)}$ for conversion electron emission. (c) Compute the ratio of the experimentally observed $M1$ gamma transition rate to the single-particle Weisskopf estimate $\lambda_W(M1)$ and interpret the result.

(a) Partial Half-Life for Gamma Emission $t_{1/2}^{(\gamma)}$: The total decay constant is related to the partial decay constants by:

$$\lambda_{\text{total}} = \lambda_\gamma + \lambda_e = \lambda_\gamma (1 + \alpha_{\text{total}})$$

Since half-life is inversely proportional to decay constant ($t_{1/2} = \frac{\ln 2}{\lambda}$):

$$t_{1/2}^{(\gamma)} = t_{1/2} (1 + \alpha_{\text{total}}) = (17.8\text{ ns})(1 + 5.1) = 17.8 \times 6.1 = \mathbf{108.58\text{ ns}}$$

(b) Partial Half-Life for Conversion Electron Emission $t_{1/2}^{(e)}$:

$$\lambda_e = \alpha_{\text{total}} \lambda_\gamma \implies t_{1/2}^{(e)} = \frac{t_{1/2}^{(\gamma)}}{\alpha_{\text{total}}} = \frac{108.58\text{ ns}}{5.1} \approx \mathbf{21.29\text{ ns}}$$

(Alternatively, $t_{1/2}^{(e)} = t_{1/2} \frac{1 + \alpha_{\text{total}}}{\alpha_{\text{total}}} = 17.8 \times \frac{6.1}{5.1} \approx 21.29\text{ ns}$).

(c) Comparison with the Weisskopf Single-Particle Estimate: The experimental gamma decay rate is:

$$\lambda_\gamma = \frac{\ln 2}{t_{1/2}^{(\gamma)}} = \frac{0.69315}{108.58 \times 10^{-9}\text{ s}} \approx 6.384 \times 10^6\text{ s}^{-1}$$

The theoretical Weisskopf single-particle rate for $M1$ with $E_\gamma = 0.02387\text{ MeV}$:

$$\lambda_W(M1) = 3.15 \times 10^{13} E_\gamma^3 = 3.15 \times 10^{13} (0.02387)^3 = 3.15 \times 10^{13} (1.360 \times 10^{-5}) \approx 4.284 \times 10^8\text{ s}^{-1}$$

The hindrance factor is:

$$\frac{\lambda_\gamma}{\lambda_W(M1)} = \frac{6.384 \times 10^6}{4.284 \times 10^8} \approx 0.0149 \approx \frac{1}{67}$$

Interpretation: The gamma transition is hindered by a factor of $\approx 67$ relative to the single-particle estimate. This occurs because the $23.87\text{ keV}$ state is an $s_{1/2} \to d_{3/2}$ transition involving an orbital angular momentum change $\Delta l = 2$ ($l$-forbidden $M1$ transition), which requires core polarization or tensor exchange corrections to proceed.

Solved Problem Example 4.3: Thomas-Reiche-Kuhn (TRK) Energy-Weighted Dipole Sum Rule Calculation

The classical Thomas-Reiche-Kuhn (TRK) dipole sum rule for the total integrated nuclear photoabsorption cross section is:

$$\int_0^\infty \sigma_{\text{abs}}(E_\gamma) dE_\gamma = \frac{2\pi^2 e^2 \hbar}{M c} \frac{N Z}{A} \approx 59.74 \frac{N Z}{A}\text{ MeV}\cdot\text{mb}$$

For the doubly-magic nucleus Lead-208 (${}^{208}_{82}\text{Pb}_{126}$): (a) Calculate the classical TRK sum rule integrated cross section in $\text{MeV}\cdot\text{b}$. (b) The experimental Giant Dipole Resonance in ${}^{208}\text{Pb}$ is well-fitted by a Lorentzian cross section:

$$\sigma(E) = \frac{\sigma_0 \Gamma^2 E^2}{(E^2 - E_0^2)^2 + \Gamma^2 E^2}$$

with resonance peak energy $E_0 = 13.6\text{ MeV}$, width $\Gamma = 4.0\text{ MeV}$, and peak cross section $\sigma_0 = 640\text{ mb}$. Compute the integrated cross section under this Lorentzian:

$$\int_0^\infty \sigma(E) dE = \frac{\pi}{2} \sigma_0 \Gamma$$

(c) Determine the enhancement factor $(1 + \kappa)$ and state its physical origin in terms of nuclear forces.

(a) Classical TRK Sum Rule for ${}^{208}\text{Pb}$: For ${}^{208}_{82}\text{Pb}$, $Z = 82$, $N = 126$, $A = 208$:

$$\frac{N Z}{A} = \frac{126 \times 82}{208} = \frac{10332}{208} \approx 49.673$$

The classical sum rule gives:

$$\Sigma_{\text{TRK}} = 59.74 \times 49.673 \approx 2967.5\text{ MeV}\cdot\text{mb} = \mathbf{2.968\text{ MeV}\cdot\text{b}}$$

(b) Integrated Experimental Lorentzian Cross Section:

$$\Sigma_{\text{exp}} = \frac{\pi}{2} \sigma_0 \Gamma = \frac{\pi}{2} (640\text{ mb}) (4.0\text{ MeV}) = \frac{\pi}{2} (2560\text{ MeV}\cdot\text{mb}) = 1280 \pi\text{ MeV}\cdot\text{mb}$$
$$\Sigma_{\text{exp}} \approx 4021.2\text{ MeV}\cdot\text{mb} = \mathbf{4.021\text{ MeV}\cdot\text{b}}$$

(c) Enhancement Factor $(1 + \kappa)$ and Physical Origin:

$$(1 + \kappa) = \frac{\Sigma_{\text{exp}}}{\Sigma_{\text{TRK}}} = \frac{4.021\text{ MeV}\cdot\text{b}}{2.968\text{ MeV}\cdot\text{b}} \approx \mathbf{1.355} \implies \kappa \approx 0.355$$

The experimental photoabsorption exhausts $135.5\%$ of the classical sum rule (an enhancement $\kappa \approx 35\%$). Physical Origin: The classical TRK sum rule assumes velocity-independent, local interactions that commute with the dipole operator $\hat{\vec{D}} = e \sum z_i$. In real nuclei, the nuclear force contains space-exchange Majorana forces $V_M \hat{P}_r$ and momentum-dependent tensor forces that do not commute with the nucleon coordinate positions:

$$[\hat{V}_M, \vec{r}_i] \ne 0$$

This non-zero double commutator adds a positive contribution to the double commutator $[[\hat{H}, \hat{D}], \hat{D}]$, which physically represents the absorption of photons by virtual charged pions ($\pi^\pm$) exchanged between protons and neutrons during the collective GDR oscillation.

★Solved Examination Problems: Chapter 1