Physics / Nuclear Physics II Hadron Symmetries & Nuclear Forces 100% Free Open Access
Chapter 7 • Theory & Derivations

Elementary Particles I: Fundamental Interactions, Symmetries & Quark Model

Systematic survey of the subatomic particle realm: classification of the four fundamental interactions (gravitational, weak, electromagnetic, strong), mediation by spin-1 gauge bosons (γ, W±, Z0, gluons), quantum conservation laws (baryon number, lepton flavor numbers, strangeness, isospin, and hypercharge), Deep Inelastic Scattering (DIS) establishing quarks as point-like fractionally charged partons, asymptotic freedom and Cornell confinement potential, discrete spacetime symmetries (Parity P, Charge Conjugation C, Time Reversal T), historical discovery of parity non-conservation in 60Co beta decay, and neutral kaon oscillations revealing subtle CP violation and the Sakharov conditions for cosmological baryogenesis.

§7.1 The Four Fundamental Interactions & Gauge Mediators

1. Classification of Fundamental Physical Forces

Modern fundamental physics recognizes four distinct interactions through which all matter in the universe influences and transforms itself. In quantum field theory, each interaction is mediated by the virtual exchange of vector (spin-1) or tensor (spin-2) gauge bosons:

Interaction Mediator (Gauge Boson) Spin / Parity $J^P$ Rest Mass Relative Strength ($\sim 1\text{ fm}$) Effective Range
Strong (QCD) 8 Gluons ($g$) $1^-$ $0$ $\alpha_s \approx 1$ $\sim 10^{-15}\text{ m}$ (confinement)
Electromagnetic (QED) Photon ($\gamma$) $1^-$ $0$ $\alpha = \frac{e^2}{4\pi\varepsilon_0\hbar c} \approx \frac{1}{137}$ $\infty$ ($1/r^2$ Coulomb potential)
Weak (Flavor) $W^+, W^-, Z^0$ $1^-$ $M_W = 80.4, M_Z = 91.2\text{ GeV}/c^2$ $\alpha_W \approx 10^{-5}\text{ to }10^{-6}$ $\frac{\hbar}{M_W c} \approx 2.5 \times 10^{-18}\text{ m}$
Gravitational Graviton ($G$, hypothetical) $2^+$ $0$ $\alpha_G = \frac{G M_p^2}{\hbar c} \approx 6 \times 10^{-39}$ $\infty$ ($1/r^2$ Newtonian)

2. Characteristic Time Scales and Cross Sections

The vast disparity in coupling constants directly dictates the lifetimes of decaying particles and reaction cross sections:

  • Strong Decays: Mediated in characteristic nuclear transit times: $$\tau_{\text{strong}} \sim \frac{R_{\text{nuc}}}{c} \approx \frac{1.4\text{ fm}}{3 \times 10^{23}\text{ fm/s}} \approx 10^{-23}\text{ s}, \qquad \sigma_{\text{strong}} \sim 10\text{ to }100\text{ mb}$$ Examples include hadron resonance decays such as $\Delta(1232) \to N + \pi$ and $\rho(770) \to \pi + \pi$.
  • Electromagnetic Decays: Photon emission or pair creation: $$\tau_{\text{EM}} \sim 10^{-16}\text{ to }10^{-20}\text{ s}, \qquad \sigma_{\text{EM}} \sim 1\text{ to }100\text{ }\mu\text{b}$$ Examples include neutral pion decay $\pi^0 \to \gamma + \gamma$ ($\tau = 8.5 \times 10^{-17}\text{ s}$) and nuclear gamma transitions.
  • Weak Decays: Flavor-changing transitions mediated by massive $W^\pm$ or $Z^0$: $$\tau_{\text{weak}} \sim 10^{-6}\text{ to }10^{-13}\text{ s}\text{ (or longer for beta decay)}, \qquad \sigma_{\text{weak}} \sim 10^{-38}\text{ to }10^{-44}\text{ cm}^2$$ Examples include free muon decay $\mu^- \to e^- + \bar{\nu}_e + \nu_\mu$ ($\tau = 2.2 \times 10^{-6}\text{ s}$), charged pion decay $\pi^+ \to \mu^+ + \nu_\mu$ ($\tau = 2.6 \times 10^{-8}\text{ s}$), and neutron beta decay $n \to p + e^- + \bar{\nu}_e$ ($\tau = 879\text{ s}$).

§7.2 Quantum Numbers, Conservation Laws & Gell-Mann-Nishijima Formula

1. Additive and Multiplicative Quantum Numbers

Subatomic particle processes are strictly regulated by internal conservation laws originating from continuous gauge symmetries (via Noether's theorem) or discrete space-time and internal transformations:

Quantity Strong Electromagnetic Weak Associated Symmetry / Group
Energy / Momentum $(E, \vec{p})$ YesYesYes Spacetime translations (Poincaré)
Angular Momentum $\vec{J}$ YesYesYes Spatial rotations $SO(3)$
Electric Charge $Q$ YesYesYes $U(1)_{\text{EM}}$ local gauge phase
Baryon Number $B$ YesYesYes $U(1)_B$ global phase
Lepton Numbers $L_e, L_\mu, L_\tau$ N/AYesConserved (except $\nu$-oscillations) $U(1)_{L_i}$ global phases
Total Isospin $I$ YesNo ($\Delta I = 0, \pm 1$)No $SU(2)_I$ flavor symmetry
Isospin Component $I_3$ YesYesNo ($\Delta I_3 = \pm 1/2$) $U(1)_{I_3}$ subgroup of $SU(2)$
Strangeness $S$ / Hypercharge $Y$ YesYesNo ($\Delta S = 0, \pm 1$) $U(1)_S$ flavor phase
Parity $\mathcal{P}$ YesYesViolated maximally Spatial inversion $\vec{x} \to -\vec{x}$
Charge Conjugation $\mathcal{C}$ YesYesViolated maximally Particle $\leftrightarrow$ antiparticle swap

2. The Gell-Mann-Nishijima Formula

In the 1950s, Murray Gell-Mann and Kazuhiko Nishijima established an algebraic relation connecting electric charge $Q$ (in units of $e$), third component of isospin $I_3$, baryon number $B$, and strangeness $S$: $$Q = I_3 + \frac{B + S}{2} = I_3 + \frac{Y}{2}$$ where the strong hypercharge $Y$ is defined as: $$Y \equiv B + S + C + B' + T$$ incorporating charm $C$, bottomness $B'$, and topness $T$ for heavier quark generations.

For the nucleon doublet ($p, n$): $B = 1, S = 0 \implies Y = 1$: $$Q_p = (+1/2) + \frac{1}{2} = +1, \qquad Q_n = (-1/2) + \frac{1}{2} = 0$$ For the strange lambda hyperon $\Lambda^0$: $I=0, I_3 = 0, B = 1, S = -1 \implies Y = 0$: $$Q_\Lambda = 0 + \frac{0}{2} = 0$$ For the sigma triplet ($\Sigma^+, \Sigma^0, \Sigma^-$): $I=1, B = 1, S = -1 \implies Y = 0$: $$Q_{\Sigma^+} = +1 + 0 = +1, \quad Q_{\Sigma^0} = 0, \quad Q_{\Sigma^-} = -1$$

§7.3 Deep Inelastic Scattering, Asymptotic Freedom & Quark Confinement

1. Deep Inelastic Scattering (DIS) and the Parton Model

In the late 1960s at SLAC, high-energy electron-proton scattering experiments revealed that at colossal four-momentum transfer $Q^2 \equiv -q^2 > 1\text{ GeV}^2$, electrons scatter elastically off point-like, spin-$1/2$ constituents within the proton: $$e^- + p \to e^- + X$$ Defining the four-momentum transfer $q^\mu = k^\mu - k'^\mu$ and proton target four-momentum $P^\mu$: $$Q^2 \equiv -q^2 = 4 E E' \sin^2(\theta/2), \qquad \nu \equiv \frac{P \cdot q}{M_p} = E - E' \text{ (in lab frame)}$$ The dimensionless Bjorken scaling variable is: $$x \equiv \frac{Q^2}{2 P \cdot q} = \frac{Q^2}{2 M_p \nu}, \qquad 0 < x \le 1$$ In Richard Feynman's infinite momentum frame, $x$ represents the fraction of the proton's total longitudinal four-momentum carried by the struck constituent ("parton").

In the deep inelastic limit ($Q^2 \to \infty, \nu \to \infty$ with $x$ fixed), the structure functions depend only on $x$ rather than $Q^2$ and $\nu$ independently: $$F_1(x, Q^2) \longrightarrow F_1(x), \qquad F_2(x, Q^2) \longrightarrow F_2(x) \quad \text{(Bjorken Scaling)}$$ Furthermore, the Callan-Gross relation $F_2(x) = 2x F_1(x)$ proved experimentally that the constituents have intrinsic spin $s = 1/2$.

2. The Cornell Static Potential and Color Confinement

Unlike QED, where the electric force weakens as $1/r^2$ at large distances, the strong interaction between quarks exhibits two extraordinary non-perturbative phenomena:

  1. Asymptotic Freedom: At short distances ($r \ll 0.1\text{ fm}$ or high momentum transfer $Q^2 \to \infty$), the running strong coupling constant $\alpha_s(Q^2)$ diminishes logarithmically: $$\alpha_s(Q^2) = \frac{12\pi}{(33 - 2 n_f) \ln\left( Q^2 / \Lambda_{\text{QCD}}^2 \right)}$$ Quarks behave as virtually free, non-interacting particles inside the nucleon core.
  2. Color Confinement: As quarks are pulled apart ($r > 0.5\text{ fm}$), non-Abelian gluon self-interactions squeeze color field lines into a narrow flux tube (string) of constant energy per unit length.

The heavy quark-antiquark ($c\bar{c}, b\bar{b}$) interaction is accurately parameterized by the Cornell potential: $$V_{\text{Cornell}}(r) = -\frac{4}{3}\frac{\alpha_s}{r} + \kappa r$$ where:

  • $-\frac{4}{3}\frac{\alpha_s}{r}$ is the short-range one-gluon exchange Coulomb-like term with color Casimir factor $C_F = 4/3$.
  • $\kappa r$ is the long-range confining string tension, where $\kappa \approx 1\text{ GeV/fm} \approx 1.6 \times 10^5\text{ N}$ (a colossal mechanical tension of $16\text{ metric tons}$!).

When the energy stored in the flux tube exceeds the threshold to create a light quark-antiquark pair ($2 m_q c^2 \approx 2 m_\pi c^2$): $$\Delta E = \kappa \Delta r \ge 2 m_q c^2$$ the flux tube snaps ("hadronization"), producing two color-singlet hadrons ($q\bar{q}'$ mesons). Isolated, free quarks are never observed in isolation in nature.

§7.4 Constituent Quark Model: Flavors, Baryon Spin-Flavor Wavefunctions & Color

1. The Three Light Flavors

In the Gell-Mann-Zweig model, all known hadrons are color-singlet bound states composed of constituent quarks:

Flavor Symbol Spin $s$ Charge $Q/e$ Baryon $B$ $I$ $I_3$ Strangeness $S$ Constituent Mass
Up$u$$1/2$$+2/3$$+1/3$$1/2$$+1/2$$0$$\approx 330\text{ MeV}/c^2$
Down$d$$1/2$$-1/3$$+1/3$$1/2$$-1/2$$0$$\approx 330\text{ MeV}/c^2$
Strange$s$$1/2$$-1/3$$+1/3$$0$$0$$-1$$\approx 500\text{ MeV}/c^2$

2. The $\Delta^{++}$ Paradox and the Discovery of Color $SU(3)_C$

The $\Delta^{++}(1232)$ baryon has spin $J = 3/2$, electric charge $+2$, and consists of three up quarks: $|uuu\rangle$. In the ground state ($L = 0$):

  • Spatial state: Symmetric under particle exchange ($\psi_{\text{space}}(1,2,3)$ symmetric).
  • Flavor state: $|uuu\rangle$ is manifestly totally symmetric.
  • Spin state: $|J=3/2, M=3/2\rangle = |\uparrow\uparrow\uparrow\rangle$ is manifestly totally symmetric.
Hence, the total wavefunction $\Psi = \psi_{\text{space}} \otimes \chi_{\text{spin}} \otimes \phi_{\text{flavor}}$ is completely symmetric under interchange of identical fermions, directly violating Pauli's Spin-Statistics Theorem!

To resolve this crisis, Oscar Greenberg, Yoichiro Nambu, and Moo-Young Han proposed that each quark flavor carries an additional three-valued degree of freedom called Color Charge: Red ($R$), Green ($G$), Blue ($B$). The overall baryon wavefunction is: $$\Psi_{\text{baryon}} = \psi_{\text{space}} \otimes \chi_{\text{spin}} \otimes \phi_{\text{flavor}} \otimes \xi_{\text{color}}$$ All physical hadrons must be color singlets (colorless invariant under $SU(3)_C$). For a three-quark baryon, the unique color singlet is totally antisymmetric: $$\xi_{\text{color}} = \frac{1}{\sqrt{6}} \left( |RGB\rangle - |RBG\rangle + |BRG\rangle - |BGR\rangle + |GBR\rangle - |GRB\rangle \right) = \frac{1}{\sqrt{6}} \epsilon_{ijk} |q_i q_j q_k\rangle$$ Because $\xi_{\text{color}}$ is antisymmetric, the total product $\Psi_{\text{baryon}}$ is totally antisymmetric under identical fermion exchange, brilliantly preserving Fermi-Dirac statistics!

§7.5 Discrete Symmetries: Parity Inversion P & Discovery of Parity Violation

1. The Spatial Parity Operator $\mathcal{P}$

Spatial parity $\mathcal{P}$ represents reflection of coordinates through the origin: $$\mathcal{P}: \vec{x} \longrightarrow -\vec{x}, \qquad \vec{p} \longrightarrow -\vec{p}, \qquad \vec{L} = \vec{r}\times\vec{p} \longrightarrow +\vec{L}, \qquad \vec{S} \longrightarrow +\vec{S}$$ True vectors ($\vec{x}, \vec{p}$) are odd under parity, whereas axial vectors (pseudovectors like spin $\vec{S}$ and magnetic field $\vec{B}$) are even under parity: $$\mathcal{P} \vec{r} \mathcal{P}^{-1} = -\vec{r}, \qquad \mathcal{P} \vec{S} \mathcal{P}^{-1} = +\vec{S}$$ The scalar product of a polar vector and an axial vector is a pseudoscalar: $$\mathcal{P} (\vec{S} \cdot \vec{p}) \mathcal{P}^{-1} = (+\vec{S}) \cdot (-\vec{p}) = -(\vec{S} \cdot \vec{p})$$ Any physical observable proportional to $\vec{S} \cdot \vec{p}$ changes sign under spatial reflection. If a physical interaction is invariant under $\mathcal{P}$, no pseudoscalar observable can have a non-zero expectation value.

2. The $\theta$-$\tau$ Puzzle and Madame Wu's 1957 Experiment

In the mid-1950s, two particles designated $\theta^+$ and $\tau^+$ had identical masses and lifetimes, yet decayed into final states of opposite parity: $$\theta^+ \longrightarrow \pi^+ + \pi^0 \quad (P = +1), \qquad \tau^+ \longrightarrow \pi^+ + \pi^+ + \pi^- \quad (P = -1)$$ Tsung-Dao Lee and Chen-Ning Yang recognized that while parity conservation had been exhaustively verified in strong and electromagnetic interactions, no experiment had tested it in weak decays.

In 1957, Chien-Shiung Wu (Madame Wu) along with the National Bureau of Standards polarized ${}^{60}\text{Co}$ nuclei ($J^\pi = 5^+$) at cryogenic temperatures ($T \approx 0.01\text{ K}$) using a strong magnetic field $\vec{B}$: $${}^{60}_{27}\text{Co} \longrightarrow {}^{60}_{28}\text{Ni}^* + e^- + \bar{\nu}_e$$ The beta decay transition is a pure Gamow-Teller transition ($5^+ \to 4^+$), requiring the emitted electron and antineutrino spins to align parallel to the nuclear spin: $\vec{S}_e \uparrow\uparrow \vec{J}$.

Wu measured the angular distribution of emitted beta electrons relative to the nuclear polarization axis: $$I(\theta) = 1 + A \frac{v}{c} \cos\theta = 1 + A \frac{\vec{J} \cdot \vec{p}_e}{J E_e}$$ where $\theta$ is the angle between the nuclear polarization $\vec{J}$ and electron momentum $\vec{p}_e$. Experimentally, electrons were emitted predominantly opposite to the nuclear spin axis ($A \approx -1$). Reversing the magnetic field $\vec{B} \to -\vec{B}$ flipped the emission asymmetry. This direct measurement of a non-zero pseudoscalar $\langle \vec{J} \cdot \vec{p}_e \rangle \neq 0$ proved definitively that parity is maximally violated in weak interactions ($V - A$ theory).

§7.6 Charge Conjugation C, Time Reversal T & The CPT Theorem

1. Charge Conjugation Operator $\mathcal{C}$

Charge conjugation replaces every particle with its corresponding antiparticle while preserving spacetime coordinates, spin, and momentum: $$\mathcal{C} |p\rangle = |\bar{p}\rangle, \qquad \mathcal{C} |e^-\rangle = |e^+\rangle, \qquad \mathcal{C} |\nu_L\rangle = |\bar{\nu}_L\rangle$$ Only neutral particles that are their own antiparticles (such as $\gamma, \pi^0, \eta, \rho^0$) can be eigenstates of $\mathcal{C}$: $$\mathcal{C} |\gamma\rangle = -|\gamma\rangle \quad (C_\gamma = -1), \qquad \mathcal{C} |\pi^0\rangle = +|\pi^0\rangle \quad (C_{\pi^0} = +1)$$ Because $C$ is conserved in electromagnetic interactions: $$\pi^0 \longrightarrow \gamma + \gamma \implies C_{\text{final}} = (-1)(-1) = +1 \quad \text{(Allowed)}$$ $$\pi^0 \centernot\longrightarrow \gamma + \gamma + \gamma \implies C_{\text{final}} = (-1)^3 = -1 \quad \text{(Strictly Forbidden, branching ratio } < 3 \times 10^{-8}\text{)}$$

2. Failure of $\mathcal{C}$ and $CP$ Invariance in Weak Interactions

In the Standard Model, weak charged currents couple exclusively to left-handed fermions ($h = -1$) and right-handed antifermions ($h = +1$): $$\mathcal{C} |\nu_L\rangle = |\bar{\nu}_L\rangle \quad \text{(Does not exist in SM!)}$$ Therefore, the weak interaction violates $\mathcal{C}$ maximally. However, applying the combined operation $\mathcal{CP}$: $$\mathcal{CP} |\nu_L\rangle = |\bar{\nu}_R\rangle \quad \text{(Physically observed!)}$$ For several years, it was believed that while $\mathcal{C}$ and $\mathcal{P}$ individually fail, the combined symmetry $\mathcal{CP}$ was exact.

3. The CPT Theorem

The $CPT$ Theorem (Lüders, Pauli, Bell, Schwinger) is a mathematical theorem of axiomatic quantum field theory stating that any local, Lorentz-invariant quantum field theory with a Hermitian Hamiltonian must be invariant under the anti-unitary combined operation $\mathcal{CPT}$: $$\mathcal{CPT} \mathcal{H}(x) (\mathcal{CPT})^{-1} = \mathcal{H}(-x)$$ Direct, inescapable consequences of exact $CPT$ invariance include:

  1. Particles and antiparticles have identical rest masses: $m_p = m_{\bar{p}}$ (tested to $1$ part in $10^{10}$).
  2. Particles and antiparticles have identical total decay lifetimes: $\tau_{\mu^+} = \tau_{\mu^-}$.
  3. Particles and antiparticles possess equal and opposite electric charges and magnetic dipole moments: $q_{\bar{p}} = -q_p, \mu_{\bar{p}} = -\mu_p$.
If $CP$ is violated in nature, then by the $CPT$ theorem, time-reversal invariance $\mathcal{T}$ must be violated by an identical compensating amount.

§7.7 Neutral Kaon Oscillations, CP Violation & Cosmological Baryogenesis

1. Neutral Kaon Strangeness Oscillations ($K^0 - \bar{K}^0$ Mixing)

Neutral kaons are produced as strangeness eigenstates via strong interactions: $$\pi^- + p \longrightarrow K^0 + \Lambda^0 \quad (S = +1), \qquad \pi^+ + p \longrightarrow \bar{K}^0 + K^+ + p \quad (S = -1)$$ where $|K^0\rangle = |d\bar{s}\rangle$ and $|\bar{K}^0\rangle = |\bar{d}s\rangle$. Under charge conjugation and parity: $$\mathcal{CP} |K^0\rangle = -|\bar{K}^0\rangle, \qquad \mathcal{CP} |\bar{K}^0\rangle = -|K^0\rangle$$ Because weak second-order box diagrams involving $W^\pm$ and virtual $u, c, t$ quarks connect $K^0 \leftrightarrow \bar{K}^0$ ($\Delta S = 2$), strangeness is not conserved in decay.

The $CP$ eigenstates are linear superpositions: $$|K_1^0\rangle = \frac{1}{\sqrt{2}}\left( |K^0\rangle - |\bar{K}^0\rangle \right) \quad (CP = +1), \qquad |K_2^0\rangle = \frac{1}{\sqrt{2}}\left( |K^0\rangle + |\bar{K}^0\rangle \right) \quad (CP = -1)$$ A two-pion state $|\pi\pi\rangle_{l=0}$ has $CP = +1$, whereas a three-pion state $|\pi\pi\pi\rangle_{l=0}$ has $CP = -1$. Due to available phase space, $K_1^0 \to 2\pi$ decays $\sim 600$ times faster than $K_2^0 \to 3\pi$: $$\tau_S \equiv \tau(K_1) \approx 0.895 \times 10^{-10}\text{ s} \quad (c\tau_S \approx 2.68\text{ cm})$$ $$\tau_L \equiv \tau(K_2) \approx 5.11 \times 10^{-8}\text{ s} \quad (c\tau_L \approx 15.3\text{ m})$$

2. The Cronin-Fitch Discovery of CP Violation (1964)

If $CP$ were an exact symmetry, a beam of neutral kaons traveling several meters would consist of $100\%$ pure $K_2^0$ ($CP = -1$), which could never decay into $2\pi$ ($CP = +1$). In 1964 at Brookhaven, James Cronin and Val Fitch directed a neutral kaon beam into a spark chamber spectrometer $17\text{ meters}$ downstream (over $500 K_S$ decay lengths). Out of $22,700$ decays, they observed $45$ clear instances of: $$K_L^0 \longrightarrow \pi^+ + \pi^-$$ proving that the physical long-lived state $K_L^0$ is an impure mixture with a tiny $CP = +1$ admixture: $$|K_S^0\rangle = \frac{|K_1^0\rangle + \epsilon |K_2^0\rangle}{\sqrt{1 + |\epsilon|^2}}, \qquad |K_L^0\rangle = \frac{|K_2^0\rangle + \epsilon |K_1^0\rangle}{\sqrt{1 + |\epsilon|^2}}$$ The empirical CP violation parameter is: $$|\epsilon| \approx (2.228 \pm 0.011) \times 10^{-3}, \qquad \arg(\epsilon) \approx 43.5^\circ$$

3. Andrei Sakharov's Conditions for Baryogenesis (1967)

The universe today is composed overwhelmingly of matter rather than antimatter (baryon-to-photon ratio $\eta \equiv n_B / n_\gamma \approx 6 \times 10^{-10}$). In 1967, Andrei Sakharov demonstrated that generating a net baryon asymmetry from an initially symmetric Big Bang requires three fundamental conditions:

  1. Baryon Number ($B$) Violation: Non-perturbative electroweak sphaleron processes or GUT gauge boson decays ($X, Y \to q q, q l$).
  2. $\mathcal{C}$ and $\mathcal{CP}$ Violation: Without $C$ and $CP$ violation, reactions producing excess baryons would proceed at exactly equal rates to reactions producing excess antibaryons, yielding net $\Delta B = 0$.
  3. Departure from Thermal Equilibrium: In strict thermodynamic equilibrium, the CPT theorem guarantees that the equilibrium densities of particles and antiparticles are identical, wiping out any generated asymmetry.
Solved Problem Example 7.1: Quantum Number Conservation and Reaction Feasibility Analysis

Determine whether each of the following subatomic reactions or decays is allowed or forbidden by the fundamental conservation laws. If allowed, specify the dominant interaction (Strong, Electromagnetic, or Weak). If forbidden, identify all violated conservation laws: (a) $\pi^- + p \longrightarrow K^0 + \Lambda^0$ (b) $p + p \longrightarrow p + \Sigma^+ + K^0$ (c) $\Lambda^0 \longrightarrow p + \pi^-$ (d) $\Sigma^0 \longrightarrow \Lambda^0 + \gamma$ (e) $\mu^- \longrightarrow e^- + \gamma$

(a) $\pi^- + p \longrightarrow K^0 + \Lambda^0$:

  • Electric Charge $Q$: $(-1) + (+1) = 0$; $0 + 0 = 0$. Conserved ($\Delta Q = 0$).
  • Baryon Number $B$: $0 + 1 = 1$; $0 + 1 = 1$. Conserved ($\Delta B = 0$).
  • Lepton Numbers $L_i$: All $0$. Conserved.
  • Strangeness $S$: $0 + 0 = 0$; $(+1) + (-1) = 0$. Conserved ($\Delta S = 0$).
  • Isospin $I, I_3$: $\pi^-(1, -1), p(1/2, +1/2) \implies I_3 = -1/2$. Final: $K^0(1/2, -1/2), \Lambda^0(0, 0) \implies I_3 = -1/2$. Conserved. Total $I = 1/2$ is accessible in both channels.

Conclusion: Allowed via the Strong Interaction (associated production of strange hadrons).

(b) $p + p \longrightarrow p + \Sigma^+ + K^0$:

  • Electric Charge $Q$: $1 + 1 = 2$; $1 + 1 + 0 = 2$. Conserved.
  • Baryon Number $B$: $1 + 1 = 2$; $1 + 1 + 0 = 2$. Conserved.
  • Strangeness $S$: Initial: $0 + 0 = 0$. Final: $\Sigma^+(S = -1)$, $K^0(S = +1) \implies S_{\text{final}} = -1 + 1 = 0$. Conserved ($\Delta S = 0$).
  • Isospin $I_3$: Initial: $+1/2 + 1/2 = +1$. Final: $p(+1/2) + \Sigma^+(+1) + K^0(-1/2) = +1/2 + 1 - 1/2 = +1$. Conserved ($\Delta I_3 = 0$).

Conclusion: Allowed via the Strong Interaction.

(c) $\Lambda^0 \longrightarrow p + \pi^-$:

  • Electric Charge $Q$: $0 \to (+1) + (-1) = 0$. Conserved.
  • Baryon Number $B$: $1 \to 1 + 0 = 1$. Conserved.
  • Strangeness $S$: Initial $S = -1$; Final $0 + 0 = 0 \implies \Delta S = +1$.

Because $\Delta S = +1 \neq 0$, the strong and electromagnetic interactions are strictly forbidden. However, charged weak currents allow $|\Delta S| = 1$ flavor transitions ($s \to u + W^-$). Conclusion: Allowed via the Weak Interaction (lifetime $\tau = 2.6 \times 10^{-10}\text{ s}$).

(d) $\Sigma^0 \longrightarrow \Lambda^0 + \gamma$:

  • Electric Charge $Q$: $0 \to 0 + 0$. Conserved.
  • Baryon Number $B$: $1 \to 1 + 0 = 1$. Conserved.
  • Strangeness $S$: Initial $S = -1$; Final $S = -1 \implies \Delta S = 0$. Conserved.
  • Isospin: Initial $\Sigma^0$ has $I = 1, I_3 = 0$. Final $\Lambda^0$ has $I = 0, I_3 = 0$. Thus $\Delta I = 1, \Delta I_3 = 0$.

The photon carries $\Delta I = 0, 1$ in electromagnetic transitions. Conclusion: Allowed via the Electromagnetic Interaction (lifetime $\tau = 7.4 \times 10^{-20}\text{ s}$).

(e) $\mu^- \longrightarrow e^- + \gamma$:

  • Electric Charge $Q$: $-1 \to -1 + 0$. Conserved.
  • Muon Lepton Number $L_\mu$: Initial $L_\mu = +1$; Final $L_\mu = 0 \implies \Delta L_\mu = -1$.
  • Electron Lepton Number $L_e$: Initial $L_e = 0$; Final $L_e = +1 \implies \Delta L_e = +1$.

Individual lepton flavor numbers are violated. Conclusion: Strictly Forbidden in the Minimal Standard Model (experimental branching ratio limit $< 4.2 \times 10^{-13}$ via MEG experiment).

Solved Problem Example 7.2: Quantitative Parity Violation in Polarized Cobalt-60 Beta Decay

In Madame Wu's 1957 parity violation experiment, ${}^{60}\text{Co}$ nuclei undergo pure Gamow-Teller allowed beta decay:

$${}^{60}_{27}\text{Co} (J^\pi = 5^+) \longrightarrow {}^{60}_{28}\text{Ni}^* (J^\pi = 4^+) + e^- + \bar{\nu}_e$$

The differential angular distribution of beta electrons emitted at angle $\theta$ relative to the nuclear spin polarization vector $\vec{J}$ is:

$$I(\theta) = 1 + \mathcal{A} \frac{v}{c} \cos\theta$$

where $\mathcal{A}$ is the beta asymmetry parameter and $v/c$ is the electron velocity in units of $c$. (a) For a pure Gamow-Teller transition $J \to J - 1$, standard $V-A$ electroweak theory predicts:

$$\mathcal{A} = -\frac{1}{J + 1}$$

Evaluate $\mathcal{A}$ for the decay of ${}^{60}\text{Co}$ ($J = 5$). (b) A beta electron is emitted with kinetic energy $T_e = 150\text{ keV}$. Given the electron rest mass $m_e c^2 = 511\text{ keV}$, calculate the velocity ratio $v/c$. (c) Assuming nuclear polarization $P = \langle J_z \rangle / J = 0.65$ was achieved, calculate the forward-to-backward counting ratio:

$$\mathcal{R} \equiv \frac{I(0^\circ)}{I(180^\circ)}$$

and discuss why this ratio proves parity violation.

(a) Asymmetry Parameter $\mathcal{A}$: For a pure $J \to J - 1$ transition with $J = 5$:

$$\mathcal{A} = -\frac{1}{5 + 1} = -\frac{1}{6} \approx \mathbf{-0.1667}$$

(Note: If the nuclear polarization is defined with respect to the initial parent spin vector, the electron angular distribution scales with the polarization fraction $P$.)

(b) Relativistic Velocity $v/c$ for $T_e = 150\text{ keV}$: Total relativistic energy of the electron:

$$E = T_e + m_e c^2 = 150\text{ keV} + 511\text{ keV} = 661\text{ keV}$$

Lorentz factor:

$$\gamma = \frac{E}{m_e c^2} = \frac{661}{511} \approx 1.2935$$

Velocity ratio:

$$\frac{v}{c} = \sqrt{1 - \frac{1}{\gamma^2}} = \sqrt{1 - \frac{1}{(1.2935)^2}} = \sqrt{1 - \frac{1}{1.6732}} = \sqrt{1 - 0.5976} = \sqrt{0.4024} \approx \mathbf{0.6343}$$

(c) Forward-to-Backward Counting Ratio $\mathcal{R}$: Including the degree of polarization $P = 0.65$:

$$I(\theta) = 1 + P \mathcal{A} \frac{v}{c} \cos\theta$$
$$P \mathcal{A} \frac{v}{c} = (0.65) \times (-0.1667) \times (0.6343) \approx -0.0687$$

Evaluating at $\theta = 0^\circ$ (forward, parallel to $\vec{J}$) and $\theta = 180^\circ$ (backward, antiparallel to $\vec{J}$):

$$I(0^\circ) = 1 - 0.0687 = 0.9313$$
$$I(180^\circ) = 1 - 0.0687(-1) = 1 + 0.0687 = 1.0687$$

The forward-to-backward ratio is:

$$\mathcal{R} = \frac{I(0^\circ)}{I(180^\circ)} = \frac{0.9313}{1.0687} \approx \mathbf{0.871}$$

Parity Violation Demonstration: Under spatial inversion $\vec{x} \to -\vec{x}$, the polar momentum vector flips ($\vec{p}_e \to -\vec{p}_e$) while the axial spin vector remains unchanged ($\vec{J} \to +\vec{J}$). Thus, parity reflection transforms $\theta \to 180^\circ - \theta$, mapping forward emission into backward emission. If parity were conserved, the physical law would require $I(\theta) = I(180^\circ - \theta)$, demanding $\mathcal{R} = 1.000$. The measured ratio $\mathcal{R} = 0.871 \neq 1$ definitively demonstrates that nature distinguishes between left-handed and right-handed coordinate systems!

Solved Problem Example 7.3: Neutral Kaon Mass Splitting and Strangeness Oscillation Frequency

The long-lived and short-lived neutral kaon states have experimentally measured lifetimes:

$$\tau_S = 0.895 \times 10^{-10}\text{ s}, \qquad \tau_L = 5.11 \times 10^{-8}\text{ s}$$

and an exceptionally tiny mass difference:

$$\Delta m \equiv m_L - m_S \approx 3.484 \times 10^{-12}\text{ MeV}/c^2 = 3.484 \times 10^{-6}\text{ eV}/c^2$$

(a) Convert the mass difference $\Delta m$ into an oscillation frequency $\Delta\omega = \Delta m c^2 / \hbar$ in radians per second ($\text{rad/s}$). (b) Evaluate the dimensionless ratio $\Delta m / \Gamma_S$, where $\Gamma_S = \hbar / \tau_S$ is the total decay width of the short-lived kaon. (c) Suppose a pure $K^0$ beam ($S = +1$) is produced at $t = 0$. Neglecting CP violation ($\epsilon = 0$), the probability of finding a $\bar{K}^0$ ($S = -1$) at proper time $t$ is:

$$P(\bar{K}^0, t) = \frac{1}{4}\left[ e^{-\Gamma_S t} + e^{-\Gamma_L t} - 2 e^{-\frac{\Gamma_S + \Gamma_L}{2} t} \cos\left( \frac{\Delta m c^2}{\hbar} t \right) \right]$$

Calculate the proper time $t_{\text{max}}$ (in units of $\tau_S$) at which the probability of detecting $\bar{K}^0$ reaches its absolute maximum, and evaluate $P(\bar{K}^0, t_{\text{max}})$.

(a) Oscillation Frequency $\Delta\omega$: Given $\hbar = 6.5821 \times 10^{-16}\text{ eV}\cdot\text{s}$:

$$\Delta\omega = \frac{\Delta m c^2}{\hbar} = \frac{3.484 \times 10^{-6}\text{ eV}}{6.5821 \times 10^{-16}\text{ eV}\cdot\text{s}} \approx \mathbf{5.293 \times 10^9\text{ rad/s}}$$

The neutral kaon oscillates between $K^0$ and $\bar{K}^0$ at over 5 billion radians per second!

(b) Dimensionless Ratio $\Delta m / \Gamma_S$: Decay width of $K_S$:

$$\Gamma_S = \frac{\hbar}{\tau_S} = \frac{6.5821 \times 10^{-16}\text{ eV}\cdot\text{s}}{0.895 \times 10^{-10}\text{ s}} \approx 7.354 \times 10^{-6}\text{ eV}$$

Comparing $\Delta m c^2$ with $\Gamma_S$:

$$\frac{\Delta m c^2}{\Gamma_S} = \frac{3.484 \times 10^{-6}\text{ eV}}{7.354 \times 10^{-6}\text{ eV}} \approx \mathbf{0.4738} \approx \frac{1}{2}$$

Remarkably, $\Delta m \approx 0.5 \Gamma_S$. This means the mass splitting between $K_L$ and $K_S$ is almost exactly half the decay width of $K_S$, allowing the kaon to complete approximately half an oscillation cycle before the short-lived component decays away!

(c) Time of Maximum $\bar{K}^0$ Probability: Since $\tau_L \approx 570 \tau_S$, over the timescale $t \sim \text{few } \tau_S$ we have $\Gamma_L \ll \Gamma_S$ and $e^{-\Gamma_L t} \approx 1$. Let $x \equiv t / \tau_S = \Gamma_S t$ and $\delta \equiv \frac{\Delta m}{\Gamma_S} \approx 0.474$:

$$P(\bar{K}^0, x) \approx \frac{1}{4}\left[ e^{-x} + 1 - 2 e^{-x/2} \cos(\delta x) \right]$$

Taking the derivative with respect to $x$ and setting to zero:

$$\frac{dP}{dx} \propto -e^{-x} + e^{-x/2} \cos(\delta x) + 2 \delta e^{-x/2} \sin(\delta x) = 0$$

Dividing by $e^{-x/2}$:

$$e^{-x/2} = \cos(\delta x) + 2 \delta \sin(\delta x)$$

Substituting $\delta = 0.4738$: Solving numerically: At $x = 0$: $e^0 = 1 = 1 + 0$ (minimum $P=0$). For small $x$, $1 - x/2 \approx 1 - \frac{1}{2}\delta^2 x^2 + 2\delta^2 x \implies$ increases. Testing values: At $x = 4.0$:

  • $e^{-2.0} \approx 0.1353$
  • $\delta x = 0.4738 \times 4.0 = 1.895\text{ rad} \approx 108.6^\circ$
  • $\cos(1.895) \approx -0.3188$
  • $\sin(1.895) \approx 0.9478$
  • RHS $= -0.3188 + 2(0.4738)(0.9478) = -0.3188 + 0.8981 = 0.5793$

Testing $x = 4.8$:

  • $e^{-2.4} \approx 0.0907$
  • $\delta x = 2.274\text{ rad} \implies \cos(2.274) \approx -0.6457, \sin(2.274) \approx 0.7636$
  • RHS $= -0.6457 + 2(0.4738)(0.7636) = -0.6457 + 0.7236 = +0.0779$

The exact root is at $t_{\text{max}} \approx 4.75 \tau_S$. Evaluating the probability at $t_{\text{max}}$:

$$e^{-4.75} \approx 0.00865, \qquad e^{-2.375} \approx 0.0930$$
$$\cos(0.4738 \times 4.75) = \cos(2.250\text{ rad}) \approx -0.6282$$
$$P(\bar{K}^0, t_{\text{max}}) \approx \frac{1}{4}\left[ 0.0087 + 1.000 - 2(0.0930)(-0.6282) \right] = \frac{1}{4}\left[ 1.0087 + 0.1168 \right] = \frac{1.1255}{4} \approx \mathbf{0.281} = \mathbf{28.1\%}$$

A beam that started as pure $K^0$ evolves so that after $4.75$ lifetimes of $K_S$, $28.1\%$ of the surviving kaons are antikaons $\bar{K}^0$!

★Solved Examination Problems: Chapter 1