Nuclear Reactions & Scattering: Optical Model, Direct/Compound Processes & Resonances
Mathematical framework of nuclear collisions: reaction kinematics, Q-values and laboratory threshold energies, phenomenological Optical Model using complex potentials U(r) = -V f(r) - i W g(r) representing non-elastic channel absorption (cloudy crystal ball), partial-wave decomposition with scattering matrix S_l = η_l e^{2iδ_l}, transmission coefficients T_l, direct reaction mechanisms (deuteron stripping and pickup) with Butler forward angular distributions, Niels Bohr compound nucleus hypothesis with independent statistical decay, continuum level densities, and Breit-Wigner single-level resonance dispersion formula with resonant-potential scattering interference.
§6.1 Nuclear Reaction Kinematics, Q-Values & Threshold Energies
1. Energetics and the Reaction Q-Value
Consider a generic two-body nuclear reaction in which projectile $a$ collides with stationary target $X$, producing ejectile $b$ and residual nucleus $Y$:
$$a + X \to Y + b \quad \text{or} \quad X(a, b)Y$$The reaction $Q$-value is defined as the difference between initial and final nuclear rest masses:
$$Q \equiv \left[ (m_a + M_X) - (m_b + M_Y) \right] c^2 = T_b + T_Y - T_a$$where $T_i$ denotes kinetic energy.
- Exoergic (Exothermic) Reaction ($Q > 0$): Nuclear mass is converted into kinetic energy. The reaction can proceed even at zero incident projectile energy ($T_a \to 0$).
- Endoergic (Endothermic) Reaction ($Q < 0$): Incident kinetic energy is converted into mass. The reaction cannot occur unless the projectile energy exceeds a minimum threshold energy $E_{\text{th}}$.
2. Derivation of the Laboratory Threshold Energy
In the center-of-mass (CM) frame, total linear momentum is zero. To create the final rest masses at threshold, the center-of-mass kinetic energy $E_{\text{cm}}$ must at least equal the mass deficit $|Q|$:
$$E_{\text{cm}} = \frac{M_X}{m_a + M_X} T_{\text{lab}} \ge |Q| = -Q$$Solving for the minimum laboratory kinetic energy of projectile $a$:
$$E_{\text{th}} = |Q| \left( \frac{m_a + M_X}{M_X} \right) = -Q \left( 1 + \frac{m_a}{M_X} \right)$$The additional energy fraction $\frac{m_a}{M_X}|Q|$ is unavoidable: it represents the center-of-mass kinetic energy that must be conserved to maintain total linear momentum.
§6.2 Phenomenological Optical Model: Complex Potential U(r) = -V - iW
1. The Cloudy Crystal Ball Model
When nucleons or composite projectiles collide with nuclei, two competing processes occur:
- Elastic Scattering: Projectile and target remain in their ground states ($a + X \to a + X$).
- Absorption / Inelastic Reactions: The projectile is removed from the elastic channel via inelastic scattering, nucleon transfer, or compound nucleus formation.
In 1954, Herman Feshbach, Charles Porter, and Victor Weisskopf introduced the Optical Model, drawing an analogy to a light wave propagating through a semi-transparent, absorbing sphere of glass (a "cloudy crystal ball").
In optics, an absorbing medium is described by a complex index of refraction:
$$\tilde{n} = n + i \kappa$$The optical wavevector becomes $k = \tilde{n} k_0 = n k_0 + i \kappa k_0$, causing the electromagnetic wave intensity to attenuate exponentially:
$$I(z) \propto e^{-2 \kappa k_0 z}$$In quantum mechanics, this spatial attenuation is produced by adding a negative imaginary potential to the Schrödinger equation:
$$U(r) = -V(r) - i W(r)$$2. The Complex Optical Potential Parameterization
Standard phenomenological optical potentials (such as the Becchetti-Greenlees and Koning-Delaroche global parameterizations) take the form:
$$U(r) = -V_R f_{\text{WS}}(r, R_R, a_R) - i W_V f_{\text{WS}}(r, R_V, a_V) + 4 i a_S W_S \frac{d}{dr}f_{\text{WS}}(r, R_S, a_S) + V_{so} \vec{l}\cdot\vec{s} \left(\frac{\hbar}{m_\pi c}\right)^2 \frac{1}{r}\frac{df_{\text{WS}}}{dr}$$where $f_{\text{WS}}(r, R, a) = [1 + \exp((r-R)/a)]^{-1}$ is the Woods-Saxon function.
- Real Depth ($V_R \approx 45\text{ to }55\text{ MeV}$): Refracts the incoming wave, determining the average phase shift and shape of diffraction oscillations.
- Volume Imaginary Depth ($W_V \approx 5\text{ to }12\text{ MeV}$): Represents absorption throughout the nuclear volume (dominant at high energies $E > 50\text{ MeV}$).
- Surface Imaginary Depth ($W_S \approx 8\text{ to }14\text{ MeV}$): Peaked strictly at the nuclear surface via $\frac{df}{dr}$. At low energies ($E < 20\text{ MeV}$), the Pauli principle prevents collisions in the nuclear interior, restricting reactions to the surface.
§6.3 Partial-Wave Analysis of the Optical Model: S-Matrix & Reaction Cross Sections
1. The Scattering Matrix (S-Matrix) with Absorption
In partial-wave scattering from a complex potential, probability is not conserved within the elastic channel alone. The asymptotic radial wavefunction for partial wave $l$ is:
$$u_l(r) \xrightarrow{r\to\infty} \frac{i}{2} \left[ e^{-i(kr - l\pi/2)} - S_l e^{i(kr - l\pi/2)} \right]$$where $S_l$ is the complex scattering matrix element ($S$-matrix). Writing $S_l$ in terms of a real phase shift $\delta_l$ and inelastic absorption parameter $\eta_l$:
$$S_l \equiv \eta_l e^{2i\delta_l}, \qquad 0 \le \eta_l \le 1$$- If there is no absorption ($W = 0$), the flux in the outgoing wave equals the incoming flux: $\eta_l = 1 \implies |S_l| = 1$ (unitary $S$-matrix).
- If absorption occurs ($W > 0$), flux is lost to other channels: $\eta_l < 1 \implies |S_l| < 1$.
- If complete absorption occurs for partial wave $l$ (black disk limit): $\eta_l = 0 \implies S_l = 0$.
2. Elastic, Reaction, and Total Cross Sections
Integrating the probability flux gives the exact partial-wave cross sections:
- Elastic Scattering Cross Section: $$\sigma_{\text{el}} = \frac{\pi}{k^2} \sum_{l=0}^\infty (2l+1) |1 - S_l|^2 = \frac{\pi}{k^2} \sum_{l=0}^\infty (2l+1) \left[ 1 + \eta_l^2 - 2\eta_l \cos(2\delta_l) \right]$$
- Reaction (Absorption) Cross Section: $$\sigma_{\text{reac}} = \frac{\pi}{k^2} \sum_{l=0}^\infty (2l+1) \left( 1 - |S_l|^2 \right) = \frac{\pi}{k^2} \sum_{l=0}^\infty (2l+1) (1 - \eta_l^2)$$ The factor $T_l \equiv 1 - |S_l|^2 = 1 - \eta_l^2$ is the transmission coefficient.
- Total Cross Section: $$\sigma_{\text{tot}} = \sigma_{\text{el}} + \sigma_{\text{reac}} = \frac{2\pi}{k^2} \sum_{l=0}^\infty (2l+1) \left[ 1 - \text{Re}(S_l) \right] = \frac{4\pi}{k}\text{Im}[f(0)]$$ (The Optical Theorem!).
Important Physical Theorem: If $\sigma_{\text{reac}} > 0$ (absorption occurs, $\eta_l < 1$), then $|1 - S_l|^2 > 0$ is unavoidable. Therefore, absorption is always accompanied by elastic scattering (shadow/diffraction scattering). You cannot have absorption without elastic scattering!
§6.4 Direct Reactions: Stripping (d, p), Pickup (p, d) & Angular Distributions
1. Characteristics of Direct Nuclear Reactions
When the incident projectile has moderate to high energy ($E \ge 10\text{ MeV/nucleon}$), a collision can proceed via a direct reaction:
- Interaction Time: Extremely brief, equal to the transit time across the nucleus: $$\tau_{\text{direct}} \sim \frac{2 R}{v} \approx \frac{10\text{ fm}}{0.2 c} \approx 1.5 \times 10^{-22}\text{ s}$$
- Peripheral Nature: Direct reactions involve only one or two valence nucleons at the surface of the nucleus; the core nucleons remain undisturbed "spectators".
- Forward-Peaked Angular Distribution: The differential cross section $\frac{d\sigma}{d\Omega}(\theta)$ is strongly peaked at forward laboratory angles ($\theta \approx 0^\circ \text{ to } 30^\circ$).
2. Stripping and Pickup Reactions
- Deuteron Stripping $(d, p)$ or $(d, n)$: The loosely bound deuteron ($B = 2.22\text{ MeV}$) grazes the target nucleus. The nuclear force captures the neutron into an empty single-particle shell model orbital $(n, l, j)$, while the proton escapes without entering the nucleus.
- Pickup Reactions $(p, d)$ or $(d, t)$: The incoming proton snatches a valence neutron from an occupied shell model orbital of the target, emerging as a deuteron.
3. Butler Theory and Spectroscopic Factors
In the semi-classical Butler theory, the transferred nucleon carries orbital angular momentum $l$ into the nucleus at impact parameter $R$:
$$\hbar l \approx p_{\text{trans}} R = q R$$where $\vec{q} = \vec{k}_i - \vec{k}_f$ is the momentum transfer vector:
$$q = \sqrt{k_i^2 + k_f^2 - 2 k_i k_f \cos\theta}$$The differential cross section is proportional to the square of the spherical Bessel function $j_l(q R)$:
$$\frac{d\sigma}{d\Omega}(\theta) \propto |j_l(q R)|^2$$Because $j_l(x)$ has its first maximum at a characteristic value $x_{\max} \approx l$:
- $l = 0$: Peak is at $\theta = 0^\circ$ ($q = 0$).
- $l = 1$: Peak is at a small finite angle $\theta_1 > 0^\circ$.
- $l = 2$: Peak is at a larger angle $\theta_2 > \theta_1$.
By simply measuring the angular position of the first maximum in $\frac{d\sigma}{d\Omega}$, experimentalists uniquely determine the orbital angular momentum $l$ of the single-particle state! The absolute cross-section magnitude yields the spectroscopic factor $S$, measuring the degree to which the state matches an unperturbed single-particle shell model state.
§6.5 Compound Nucleus Mechanism (Bohr Hypothesis) & Statistical Decay
1. The Niels Bohr Compound Nucleus Hypothesis
In 1936, Niels Bohr proposed that low-energy nuclear reactions (such as thermal or slow neutron capture) proceed through a two-stage mechanism:
$$a + X \xrightarrow{\text{Stage 1: Formation}} C^* \xrightarrow{\text{Stage 2: Decay}} Y + b$$- Stage 1 (Formation): The projectile $a$ enters the target nucleus $X$ and undergoes multiple collisions with nucleons, rapidly sharing its kinetic energy and binding energy among all $A$ nucleons. The system forms a highly excited quasi-equilibrium state called the compound nucleus $C^*$.
- Stage 2 (Statistical Decay): The compound nucleus has a long lifetime compared to direct transit times: $$\tau_{\text{compound}} \sim 10^{-18} \text{ to } 10^{-15}\text{ s} \quad \left( 10^4 \text{ to } 10^7 \times \tau_{\text{direct}} \right)$$ During this long lifetime, the energy fluctuations statistically concentrate sufficient energy on a single nucleon (or cluster) to allow it to evaporate from the nucleus.
2. Bohr's Independence Hypothesis
Because the lifetime is so long, the compound nucleus loses all memory of its mode of formation, retaining only conserved macroscopic constants of motion: total energy $E^*$, total angular momentum $J$, and parity $\pi$.
Therefore, the cross section factorizes into the formation cross section $\sigma_{\text{form}}(a+X \to C^*)$ multiplied by the decay branching ratio $P_{\text{decay}}(C^* \to Y+b) = \frac{\Gamma_b}{\Gamma_{\text{total}}}$:
$$\sigma(a, b) = \sigma_{\text{form}}(a+X \to C^*) \times \frac{\Gamma_b}{\sum_c \Gamma_c}$$3. Classic Experimental Test: Ghoshal's Experiment (1950)
S. N. Ghoshal brilliantly tested Bohr's independence hypothesis by forming the same compound nucleus ${}^{64}_{30}\text{Zn}^*$ via two completely different entrance channels at the same excitation energy ($E^* \approx 30\text{ MeV}$):
$$\text{Channel A: } p + {}^{63}_{29}\text{Cu} \to {}^{64}_{30}\text{Zn}^*$$ $$\text{Channel B: } \alpha + {}^{60}_{28}\text{Ni} \to {}^{64}_{30}\text{Zn}^*$$He measured the cross sections for three different exit channels:
$${}^{64}\text{Zn}^* \to \begin{cases} {}^{63}\text{Zn} + n \\ {}^{62}\text{Cu} + p + n \\ {}^{62}\text{Zn} + 2n \end{cases}$$Ghoshal found that the ratios of cross sections for the three exit channels were identical for both entrance reactions:
$$\sigma(p, n) : \sigma(p, pn) : \sigma(p, 2n) = \sigma(\alpha, n) : \sigma(\alpha, pn) : \sigma(\alpha, 2n)$$This landmark result provided irrefutable confirmation of the compound nucleus independence hypothesis.
§6.6 Continuum Theory & Nuclear Level Density ρ(E)
1. The Statistical Evaporation Model
At high excitation energies ($E^* > 10\text{ MeV}$), individual compound nucleus resonances overlap so densely that discrete quantum states blend into a continuum.
In the continuum regime, particle emission is modeled as statistical evaporation from a boiling droplet at nuclear temperature $T$. The kinetic energy spectrum of evaporated neutrons follows a Maxwellian-type distribution:
$$\frac{d N(E)}{d E} \propto E \exp\left( -\frac{E}{T} \right)$$where the nuclear temperature $T$ (in MeV) is related to excitation energy $E^*$ by $E^* = a T^2$.
2. Bethe's Nuclear Level Density Formula
Hans Bethe (1936) treated the nucleus as an ensemble of non-interacting Fermi gas quasiparticles. Applying the grand canonical partition function:
$$\rho(E^*) = \frac{1}{\sqrt{48} E^*} \exp\left( 2\sqrt{a E^*} \right)$$where the level density parameter $a$ is proportional to the single-particle density of states $g(\epsilon_F)$ at the Fermi surface:
$$a = \frac{\pi^2}{6} g(\epsilon_F) \approx \frac{A}{8} \text{ to } \frac{A}{10}\text{ MeV}^{-1}$$Key physical properties:
- Exponential Explosion: The level density grows exponentially with $\sqrt{E^*}$. In heavy nuclei such as ${}^{238}\text{U}$ at neutron separation energy ($E^* \approx 6.5\text{ MeV}$), $a \approx 25\text{ MeV}^{-1}$, yielding $\rho \sim 10^6\text{ levels/MeV}$ (average level spacing $D = 1/\rho \sim 1\text{ eV}$).
- Shell Effects: Near magic numbers ($Z, N = 20, 28, 50, 82, 126$), the single-particle density $g(\epsilon_F)$ drops sharply, reducing $a$ and causing level densities to be orders of magnitude lower than in mid-shell deformed nuclei.
§6.7 Single-Level Breit-Wigner Dispersion Formula & Potential Interference
1. The Single-Level Breit-Wigner Formula
Gregory Breit and Eugene Wigner (1936) derived the dispersion formula for a nuclear reaction proceeding through an isolated compound nucleus resonance state of energy $E_0$, total spin $J$, and total width $\Gamma$:
$$\sigma(a, b) = \frac{\pi}{k^2} g_J \frac{\Gamma_a \Gamma_b}{(E - E_0)^2 + (\Gamma/2)^2}$$where:
- $k = \frac{\sqrt{2\mu E}}{\hbar}$ is the incident relative wavevector.
- $g_J$ is the statistical spin factor: $$g_J = \frac{2J + 1}{(2s_a + 1)(2I_X + 1)}$$
- $\Gamma_a$ is the partial width for the entrance channel ($a + X$).
- $\Gamma_b$ is the partial width for the exit channel ($Y + b$).
- $\Gamma$ is the total resonance width: $\Gamma = \sum_c \Gamma_c = \Gamma_a + \Gamma_b + \Gamma_\gamma + \dots$
- By the Heisenberg uncertainty relation, the mean lifetime of the compound resonance is: $$\tau = \frac{\hbar}{\Gamma}$$
2. Resonant and Potential Scattering Interference
In the elastic channel ($b = a$), the total scattering amplitude is the coherent quantum sum of the hard-sphere potential scattering amplitude $A_{\text{pot}} = \frac{i}{2k}(1 - e^{2i\delta_{\text{pot}}})$ and the resonant Breit-Wigner amplitude $A_{\text{res}}$:
$$f(\theta) = f_{\text{pot}}(\theta) + f_{\text{res}}(\theta)$$For an $s$-wave resonance with potential phase shift $\delta_{\text{pot}} = -k R$:
$$\sigma_{\text{el}}(E) = \frac{\pi}{k^2} g_J \left| e^{2i\delta_{\text{pot}}} - 1 + \frac{i\Gamma_n}{(E - E_0) + i\Gamma/2} \right|^2$$ $$\sigma_{\text{el}}(E) = \frac{4\pi}{k^2}\sin^2(k R) + \frac{\pi}{k^2} g_J \frac{\Gamma_n^2 + 2\Gamma_n\Gamma\sin^2(kR) - 4\Gamma_n(E - E_0)\sin(kR)\cos(kR)}{(E - E_0)^2 + (\Gamma/2)^2}$$The cross-term produces asymmetric Fano-type interference:
- Just below the resonance energy ($E < E_0$), the resonant and potential amplitudes interfere destructively, causing the cross section to dip sharply below the potential baseline.
- Just above the resonance energy ($E > E_0$), the amplitudes interfere constructively, generating a steep peak.
Consider the endoergic reaction ${}^{14}\text{N}(\alpha, p)^{17}\text{O}$, the historical reaction used by Ernest Rutherford in 1919 to achieve the first artificial nuclear transmutation: Atomic masses: $M(^{14}\text{N}) = 14.003074\text{ u}$, $M(\alpha) = 4.002603\text{ u}$, $M(p) = 1.007825\text{ u}$, $M(^{17}\text{O}) = 16.999132\text{ u}$ ($1\text{ u} = 931.494\text{ MeV}/c^2$). (a) Calculate the reaction $Q$-value in MeV. (b) Calculate the minimum kinetic energy $E_{\text{th}}$ the incident alpha particle must possess in the laboratory frame to initiate this reaction on stationary nitrogen. (c) If an alpha particle of $E_\alpha = 7.68\text{ MeV}$ from ${}^{214}\text{Po}$ is used, what is the total kinetic energy shared by the proton and ${}^{17}\text{O}$ in the center-of-mass frame?
(a) Reaction $Q$-Value:
Because $Q < 0$, the reaction is endoergic.
(b) Laboratory Threshold Energy $E_{\text{th}}$:
The alpha particle must have at least $1.533\text{ MeV}$ of kinetic energy in the laboratory frame to initiate the reaction.
(c) Center-of-Mass Kinetic Energy for $E_\alpha = 7.68\text{ MeV}$: The center-of-mass kinetic energy of the entrance channel is:
In the exit channel:
The proton and ${}^{17}\text{O}$ share $4.78\text{ MeV}$ of kinetic energy in the center-of-mass frame.
Cadmium-113 (${}^{113}_{48}\text{Cd}$) has an enormous capture cross section for thermal neutrons due to an isolated $s$-wave ($l = 0$) compound resonance at $E_0 = 0.178\text{ eV}$ in ${}^{114}\text{Cd}^*$. The target spin is $I_X = 1/2^+$, the compound state has $J^\pi = 1^+$, the neutron partial width is $\Gamma_n = 0.65\text{ meV}$, and the radiative capture width is $\Gamma_\gamma = 113\text{ meV}$. (Scattering and fission widths are negligible, so $\Gamma \approx \Gamma_n + \Gamma_\gamma$). (a) Calculate the statistical spin factor $g_J$. (b) Determine the relative de Broglie wavelength $\lambdabar$ of the neutron at resonance energy $E_0$. (c) Calculate the peak radiative capture cross section $\sigma_\gamma(E_0)$ in barns ($1\text{ b} = 10^{-24}\text{ cm}^2$).
(a) Statistical Spin Factor $g_J$: Neutron spin $s_n = 1/2$, target nucleus spin $I_X = 1/2$, resonance spin $J = 1$:
(b) Reduced Wavelength $\lambdabar$ at Resonance: Neutron mass $m_n c^2 \approx 939.57\text{ MeV}$. At $E_0 = 0.178\text{ eV} = 0.178 \times 10^{-6}\text{ MeV}$:
(c) Peak Radiative Capture Cross Section $\sigma_\gamma(E_0)$: Total width:
At exact resonance ($E = E_0$), $(E - E_0)^2 = 0$:
Multiplying factors:
The peak capture cross section is colossal: $\approx 62{,}400\text{ barns}$! This immense cross section is why cadmium metal is widely used as a thermal neutron control rod in nuclear reactors.
Consider the compound nucleus ${}^{236}_{92}\text{U}^*$ formed by the capture of a thermal neutron on ${}^{235}\text{U}$. The excitation energy is equal to the neutron separation energy: $E^* = S_n = 6.55\text{ MeV}$. The experimental level density parameter for actinides is $a \approx 25.0\text{ MeV}^{-1}$. (a) Using Hans Bethe's Fermi gas level density formula:
calculate the total level density $\rho(E^*)$ in $\text{levels/MeV}$. (b) Compute the average energy spacing between adjacent compound resonance levels $D = 1/\rho(E^*)$ in electron-volts ($\text{eV}$). (c) Contrast this average spacing with the typical spacing of low-lying discrete single-particle shell model levels ($\sim 1\text{ MeV}$) and explain the physical origin of the colossal difference.
(a) Nuclear Level Density $\rho(E^*)$: For $E^* = 6.55\text{ MeV}$ and $a = 25.0\text{ MeV}^{-1}$:
Evaluating the exponential:
Prefactor:
Multiplying:
(b) Average Level Spacing $D$:
The average spacing between adjacent levels is only $\approx 0.35\text{ eV}$ (about one-third of an electron-volt!).
(c) Contrast and Physical Origin:
- Near the ground state ($E^* \sim 0$), nucleons occupy the lowest single-particle orbitals. Creating an excitation requires lifting a single valence nucleon across the shell gap, which costs $\Delta E \sim \hbar\omega \approx 1\text{ MeV}$. Hence $D_{\text{g.s.}} \sim 1\text{ MeV}$.
- At $E^* = 6.55\text{ MeV}$, the excitation energy can be partitioned among dozens of nucleons in an astronomical number of possible combinatorial permutations (microstates): breaking nucleon pairs, scattering across multiple sub-shells, and coupling various angular momentum components.
- By Boltzmann's statistical entropy relation $S = k_B \ln \Omega(E) = 2\sqrt{a E^*}$, the number of accessible many-particle configurations explodes exponentially ($e^{25.6} \sim 10^{11}$), cramming billions of compound states into each MeV and reducing level spacing by a factor of several million.